Great review. Looks like a very high efficiency converter. What is the idle power with no load? It appears that most of the loss is in the reverse polarity diode! What happens to efficiency if you short it out?
the idle current is determined by the main switching converter chip. It shows on page 5, to be www.ti.com/lit/ds/symlink/tps40057.pdf to be max 3mA. The output mosfet will go off when there is not current at output.. I did not try short circuiting the output. As it seems there not over power or current protection.
I assume reverse polarity protection is a series schottky diode on input. At 5A the loss in this diode will be 1 to 2W. If you short diode then efficiency will improve.
Yes, they used this schottky diode www.taitroncomponents.com/catalog/Datasheet/SS58.pdf with 00.67 or 0.79 ( I forgot which diode) but 5 x 0.7 =3.5W dissipation of power. It could be improved
@@robojax First, thanks for very good review. As for the reverse polarity protection diod, the best solution is to short it, especially when the input power supply voltage is close to 9 V. In my device, I powered this buck from 12 V SMPS and the short increases the efficiency back to >90% range. Secondly, the datasheet claims that there is some short protection (external I limit control resistor), but I did not test it yet. But I will have because I want to power sensitive device (single board computer) so a crowbar or some overvoltage protection is needed.
hello, this is very vague. There are 100s of such module. you need to know the operating range of voltage at input and output and also the required current.. search my channel for this or visit eBay and AliExpress and find something there.
thank you for the review Jack. Great one
You are welcome.
Great review. Looks like a very high efficiency converter. What is the idle power with no load? It appears that most of the loss is in the reverse polarity diode! What happens to efficiency if you short it out?
the idle current is determined by the main switching converter chip. It shows on page 5, to be www.ti.com/lit/ds/symlink/tps40057.pdf to be max 3mA. The output mosfet will go off when there is not current at output..
I did not try short circuiting the output. As it seems there not over power or current protection.
I assume reverse polarity protection is a series schottky diode on input. At 5A the loss in this diode will be 1 to 2W. If you short diode then efficiency will improve.
Yes, they used this schottky diode www.taitroncomponents.com/catalog/Datasheet/SS58.pdf with 00.67 or 0.79 ( I forgot which diode) but 5 x 0.7 =3.5W dissipation of power. It could be improved
@@robojax First, thanks for very good review.
As for the reverse polarity protection diod, the best solution is to short it, especially when the input power supply voltage is close to 9 V. In my device, I powered this buck from 12 V SMPS and the short increases the efficiency back to >90% range.
Secondly, the datasheet claims that there is some short protection (external I limit control resistor), but I did not test it yet. But I will have because I want to power sensitive device (single board computer) so a crowbar or some overvoltage protection is needed.
Hello sir, pls recommend a buck converter which has cc & cv adj... ? Cheers...
hello, this is very vague. There are 100s of such module. you need to know the operating range of voltage at input and output and also the required current.. search my channel for this or visit eBay and AliExpress and find something there.
Wow, great video, thanks for your sharing. :D
You are welcome.
Great review, thanks.
You are welcome.
Good sir
Than you.