8b)Jan-2020-QP-Laplace Transform of periodic Signal

Laplace Transform of non-sinusoidal waveform. Waveform synthesis is explained in easiest way.

[@syedhussain4496]

Shouldn't it be 1-e^TS at 13:25? Can you explain if I'm wrong?

[@VBDclasses]

Hello Syed happy for your reply. Yes you are right, in hurry i forgot to write that term. Thank you.

[@piggypiggy855]

Thank you for this video sir .

[@Suraj-g8g]

Then what is correct answer ​@@VBDclasses

[@VBDclasses]

@@syedhussain4496 yes you are absolutely right. Small mistake. I will correct it

[@Mr.ghost.edits45]

Sir can't understand pls help me in introduction 😢

[@Faidakadango]

Great sir, but why is the magnitude of the signal at x2(t)=-2

[@Rutuja05S]

At x(2)t why magnitude is taken as -2

[@VBDclasses]

Magnitude of signal is +1, to being it to -1, we need to add -2.

[@karthikkv7585]

Omg . Sir you are great!

[@VBDclasses]

Thank you kartik. All the best. Do well.

[@bhavan45]

Sir Why the magnitude is -2?

[@virupaxidalal5258]

Because by adding -2 to +1 we get -1 .

[@meerasabmulla4646]

​@@virupaxidalal5258 sir I can't understand could you explain once time for -2

[@srsniperlord7085]

@@virupaxidalal5258 can u clear this doubt ..?

[@piev4166]

shouldn't the magnitude of one cycle of the periodic signal end at +1 x(t) magnitude instead of 0? that should make the last part of signal +2u(t-2T) and not +u(t-2T), right?

[@----deep------2659]

Kattli show video hai yr

[@KarthikBelli-h3q]

Can u send your mail sir

[@VBDclasses]

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