I have a question maybe a noob question. If this dielectric liquid turns into steam that is basically water, how is it possible that it does not mix with the special liquid?
Hi Carlos, thank you for your question. In the video we refer to the vapor form as steam. This term steam is not a 100% accurate in describing what actually occurs. The working fluid (in this case Freon) vaporizes. It is not steam but the vapor form of the fluid. We use the term steam - which describes the vapor form of water - to help viewers visualization of what is occurring in the system, by referencing a fluid phase change that is common.
@@AdvancedCoolingTech Thank you for your answer it means that before close the container tank is needed to extract the oxigen? or do a air vacuum inside?
Hi Manolo, we have a lot more technical content on our website, visit www.1-act.com/innovations/pumped-two-phase-cooling/ for more information on this topic!
2:59 in this video - you use a 250W pump to remove a 80KW heat load? So the COP = 80,000/250 = 320? This is hard to believe when you compare this number with a typical automotive AC loop of a COP of 2 ~3.
I have a question maybe a noob question. If this dielectric liquid turns into steam that is basically water, how is it possible that it does not mix with the special liquid?
Hi Carlos, thank you for your question. In the video we refer to the vapor form as steam. This term steam is not a 100% accurate in describing what actually occurs. The working fluid (in this case Freon) vaporizes. It is not steam but the vapor form of the fluid. We use the term steam - which describes the vapor form of water - to help viewers visualization of what is occurring in the system, by referencing a fluid phase change that is common.
@@AdvancedCoolingTech Thank you for your answer it means that before close the container tank is needed to extract the oxigen? or do a air vacuum inside?
I do noto understando
Hi Manolo, we have a lot more technical content on our website, visit www.1-act.com/innovations/pumped-two-phase-cooling/ for more information on this topic!
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2:59 in this video - you use a 250W pump to remove a 80KW heat load? So the COP = 80,000/250 = 320? This is hard to believe when you compare this number with a typical automotive AC loop of a COP of 2 ~3.
the cop is 0, or -0.03. they are using a 250W pump to circulate the waste heat outside of a device.