Methods for preparing buffers | Acids and bases | AP Chemistry | Khan Academy

Поделиться
HTML-код
  • Опубликовано: 23 авг 2021
  • Keep going! Check out the next lesson and practice what you’re learning:
    www.khanacademy.org/science/a...
    In this video, we'll explore two common methods for preparing buffer solutions. In the first approach, a certain amount of a weak acid (or weak base) is neutralized with a strong base (or strong acid), forming a conjugate acid-base pair in solution. In the second approach, a weak acid (or weak base) is combined with a salt containing its conjugate base (or conjugate acid). View more lessons or practice this subject at www.khanacademy.org/science/a...
    Khan Academy is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We offer quizzes, questions, instructional videos, and articles on a range of academic subjects, including math, biology, chemistry, physics, history, economics, finance, grammar, preschool learning, and more. We provide teachers with tools and data so they can help their students develop the skills, habits, and mindsets for success in school and beyond. Khan Academy has been translated into dozens of languages, and 15 million people around the globe learn on Khan Academy every month. As a 501(c)(3) nonprofit organization, we would love your help!
    Donate or volunteer today! Donate here: www.khanacademy.org/donate?ut...
    Volunteer here: www.khanacademy.org/contribut...

Комментарии • 8

  • @kofibiney3654
    @kofibiney3654 2 года назад +2

    How do you write the equation of the reaction that occurs between the weak base and the salt of its conjugate acid ?

  • @faraz5234
    @faraz5234 2 года назад +1

    👍

  • @Hydragrequan
    @Hydragrequan 2 года назад +1

    For the second example are you sure you can jump straight to using the HH equation? Because how do we know the substances are at equilibrium?

    • @Hydragrequan
      @Hydragrequan 2 года назад

      Either way thank you guys so much for all the help over the years

    • @levkochergin3208
      @levkochergin3208 2 года назад

      it's not a reversible reaction, so equilibrium will be when the limiting reactant is exhausted, so once the 0.05 mol of OH- ions are used up

    • @Hydragrequan
      @Hydragrequan 2 года назад +1

      @@levkochergin3208 alright I think get it, thank you

  • @vmstejas2004
    @vmstejas2004 Год назад +2

    calculation mistakes ... no problem we got the concepts 🙂

  • @epicmath5113
    @epicmath5113 2 года назад

    First