Gangigooga it represents a value that satisfies the equation: if you look at Lagrange’s reminder theorem the remainder takes the form h^2/2* second derivative evualuated at theta for some suitable theta
what does it even mean to say "the order of error" ? Like I know its of the form "O(h^p)" , but what does that even mean? Anything would be much appreciated.
Clear message, clear structure, easy to understand, thank you
The way the truncation error is defined can vary depending on the author
What is theta representing?
Gangigooga it represents a value that satisfies the equation: if you look at Lagrange’s reminder theorem the remainder takes the form h^2/2* second derivative evualuated at theta for some suitable theta
what does it even mean to say "the order of error" ?
Like I know its of the form "O(h^p)" , but what does that even mean? Anything would be much appreciated.
It refers to the order of the first Taylor Expansion term which isn't accounted for by the numerical approximation.
it means how quickly the error drops as h is reduced. so order h error drops linearly with h, order h^2 drops quadratically with h and so on.
What is haych?
;)
I almost dont get what he was saying hahah