Размер видео: 1280 X 720853 X 480640 X 360
Показать панель управления
Автовоспроизведение
Автоповтор
Do you happen to have intermediate steps for the 'just solve for X, its easy' at 8.32? Can't figure it out. Thanks anyway, amazing videos :)
You mean the mathematics?
I think you made a mistake when in the second order reaction you put (-kCa^2) in the integral instead of kCa^2.
+Lawrence Yes; i should fix it! There are other comments as well; you may review them =) thanks for the tip
@@ChemicalEngineeringGuy I was just about to say the same thing!! -ra = KCa2, so kCa2 goes in the denominator, NOT -kCa2
dx/(1-x)^2 = x/(1-x) right? there is no negative sign, -x/(1-x) is incorrect, I checked is.
+Remon Balzer you are correct; I must fix it!
Hello I dont really understand the term of the v with a dot over it, could you tell me what is it exactly please?
Volumetric Flow Rate, M3/h or cm3/s or L/min etc
6:31 why does the integrate of 1/(1-x) equal to - ln ? Why is there negative sign?
Hi, that is the way the integral is given, those can be found on the integral tables
in 2ed order u don't change the sing of (K) u but (-k) I think u must but (v=(v/KCA0)
+mohammed al-amoudi depends on how you use rate of reaction.. I used -ra therefore I need to use K
+Chemical Engineering Guy yeah I think Mohammed is right, there is the lost minus haha
Do you happen to have intermediate steps for the 'just solve for X, its easy' at 8.32?
Can't figure it out. Thanks anyway, amazing videos :)
You mean the mathematics?
I think you made a mistake when in the second order reaction you put (-kCa^2) in the integral instead of kCa^2.
+Lawrence Yes; i should fix it! There are other comments as well; you may review them =) thanks for the tip
@@ChemicalEngineeringGuy I was just about to say the same thing!! -ra = KCa2, so kCa2 goes in the denominator, NOT -kCa2
dx/(1-x)^2 = x/(1-x) right? there is no negative sign, -x/(1-x) is incorrect, I checked is.
+Remon Balzer you are correct; I must fix it!
Hello I dont really understand the term of the v with a dot over it, could you tell me what is it exactly please?
Volumetric Flow Rate, M3/h or cm3/s or L/min etc
6:31 why does the integrate of 1/(1-x) equal to - ln ? Why is there negative sign?
Hi, that is the way the integral is given, those can be found on the integral tables
in 2ed order u don't change the sing of (K) u but (-k) I think u must but (v=(v/KCA0)
+mohammed al-amoudi depends on how you use rate of reaction.. I used -ra therefore I need to use K
+Chemical Engineering Guy yeah I think Mohammed is right, there is the lost minus haha