Lecture 07: Evaluation of Limit of Function of Two Variable

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  • Опубликовано: 2 ноя 2024

Комментарии • 12

  • @subhash8766
    @subhash8766 2 года назад +5

    Sir your lectures are awesome. You explained all methods in single video.

  • @chinthasaicharan4371
    @chinthasaicharan4371 3 года назад +3

    Other normal RUclipsrs getting subs than from a IIT which is better than all private RUclipsrs

  • @DEEPAKKUMARSINGH-C-
    @DEEPAKKUMARSINGH-C- 3 года назад +4

    Thnk u so much sir 🙏🙏 no ads this channel.

  • @GeetaPriyanka-b6d
    @GeetaPriyanka-b6d Год назад +3

    it was really helpful sir

  • @lone_Traveller_101
    @lone_Traveller_101 2 года назад +6

    in 16:30 u said that by y=mx is fixing as straight line...but in the polar coordinate system also x and y are fixed paths for different values of r n theta as circles only...so how in former case or in y = mx path,limit evaluated is wrong?

  • @aryanmusicacademy944
    @aryanmusicacademy944 3 года назад +3

    I have infinitely many doubts in every question, like in example 5 .. we just took a case that x and y are related to each other as x^2 + y^2 = 1 but if we take a different value like x = r*sin(theta) and y = r*sin(PHY) .. then how will we get the value 0 .. here it is not mentioned that x and y are related...

    • @subhrasen1395
      @subhrasen1395 3 года назад +4

      still it will be zero..as the factor r in numerator will be there...which when r tends to 0 will be 0.

    • @subhajitghosh8221
      @subhajitghosh8221 3 года назад

      Dear Sir, thank you very much .

    • @Richa_cute
      @Richa_cute 2 года назад

      Watch videos on polar coordinates or polar transformation of cartesian coordinate system. Your doubts will be cleared!

  • @reetiranjansahoo
    @reetiranjansahoo 2 года назад

    Ex-1 and Ex-5 are same but answers are not same how ?

    • @thehawk69
      @thehawk69 Год назад +2

      in ex-1 denominator has x^4 whereas in ex-5 denominator has x^2