Jigyasa3: Does light not exist?🤯 E=mc² Explained!

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  • Опубликовано: 11 ноя 2024

Комментарии • 11

  • @lalitmehta2433
    @lalitmehta2433 Год назад +1

    Wow good to see you on a different educational series 👌

  • @manavikakhanna4281
    @manavikakhanna4281 Год назад +1

    Really enjoying this series of bite sized information on such interesting topics!

  • @lalitmehta2433
    @lalitmehta2433 Год назад +1

    Very nice and informative beta keep up the desired work for future 👍

  • @brba
    @brba Год назад +1

    How can you have momentum if there is no mass?

    • @timebeforespace
      @timebeforespace  Год назад

      Hello,
      Please take a look at the response to the comment from @rayraycthree5784. Also, please subscribe to the channel. I'll make a video on your question as many people have questions similar to this. Thanks for watching!

    • @timebeforespace
      @timebeforespace  Год назад

      This might help: ruclips.net/video/UoN2GQw3akM/видео.html

  • @rayraycthree5784
    @rayraycthree5784 Год назад +1

    What the heck? Dont understand, the equation looks like a solution for the sum of two right angle vectors and since momentum = mass * velocity, the second squared term under square root looks identical to m*c^2 and is also zero, the total energy is still zero. Seems like gibberish, what is the author trying to say?

    • @timebeforespace
      @timebeforespace  Год назад

      Thank you for your comment. Here is the explanation to your comment:
      1. The video is intended as a very brief answer to question of massless particles' existence like that of photon. The aim is to interest the audience to be curious and question known facts.
      2. A photon is a quantum of light. You are absolutely correct in noticing that momentum is mass*velocity. But this is what quantum mechanics is not. The old classical interpretation of momentum stops being the correct one in the world of quantum particles and thus momentum in this world cannot be replaced by the formula mass*velocity.
      3. Lastly, the correct form of momentum comes out from observing the wave-particle duality which gives p=h/lambda where h is the Planck's constant and Lambda is the wavelength of light. This is one of the very first relationships that established wave(wavelength)-particle(momentum) duality.
      Summarizing, the momentum is not zero as any light will have a specific wavelength which in turn gives it a momentum and hence redeem the conclusion of the video.
      I hope this helps!

    • @timebeforespace
      @timebeforespace  Год назад

      This will help: ruclips.net/video/UoN2GQw3akM/видео.html