Three point bending

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  • Опубликовано: 16 дек 2024

Комментарии • 24

  • @chinonsoude
    @chinonsoude 5 лет назад +4

    your moment summation for region B-C at 2:44 should be 1/2Fx + F(x-L/2), i think

    • @youpjmiiitube
      @youpjmiiitube 4 года назад +1

      You're correct, but his final moment equation (below the summation equation) is correct

    • @thesweetnotes
      @thesweetnotes 2 года назад +1

      thank you! I thought i was going crazy for a second.

  • @vaibhavmehta2756
    @vaibhavmehta2756 7 лет назад

    Can you please tell me that which test will show more strength- a 3 point or a 4 point bending test and why? Can we do some modifications in these tests to obtain purely shear cracks and not the flexural cracks?
    Furthermore, can you please explain me again the lines from 4:39 to 4:52?

  • @PeterBaumgart1a
    @PeterBaumgart1a 3 месяца назад

    Does the roller diameter have an influence (varied "within reason")?

    • @jdomann
      @jdomann  3 месяца назад +1

      Within reason... it depends. What properties of your material are you attempting measure?
      In general, using a larger diameter will increase the contact area at each roller. As a result, you will decrease contact stress directly around where the rollers touch your sample.
      Assuming you're 'far enough' away from the rollers, you should see little impact (i.e., Saint-Venant's principle should take over).
      If you need to know exactly how much impact the choice has (and quantify things like 'far enough'), then you can get a good estimate with a 2D elastostatics model. A 2D linear elastic FEM (or BEM) model of 3 point bending should converge almost instantly (even on an old laptop). This is likely a tutorial model in most commercial software. I'd also be surprised if a few minutes of googling didn't reveal matlab code you could download, at which point you'd just need to setup the problem.

    • @PeterBaumgart1a
      @PeterBaumgart1a 2 месяца назад

      @@jdomann Trying to measure fracture, force and displacement just before it occurs, and calculate the max stress at that moment.

  • @shoboyjr
    @shoboyjr 7 лет назад

    Really good explanation

  • @madscientist4247
    @madscientist4247 4 года назад

    Very well explained. Thank you.

  • @TheBeesKneess
    @TheBeesKneess 10 лет назад +1

    Thank you so much for these videos!!!!! :D

  • @radinradev
    @radinradev 2 месяца назад

    thank you man

  • @nomipakistanli
    @nomipakistanli 2 года назад

    excellent

  • @vinh-tungle4609
    @vinh-tungle4609 4 года назад

    It is very useful. Thanks so much.

  • @2302weijian
    @2302weijian 11 лет назад

    Can we determine Young's modulus from bending test?

    • @johndomann1609
      @johndomann1609 11 лет назад

      ASTM D790 - 10
      Standard Test Methods for Flexural Properties of Unreinforced and Reinforced Plastics and Electrical Insulating Materials

    • @johndomann1609
      @johndomann1609 11 лет назад

      ASTM C1161 - 13
      Standard Test Method for Flexural Strength of Advanced Ceramics at Ambient Temperature

  • @jasperschuringa4
    @jasperschuringa4 9 лет назад +1

    I think you made a mistake in your calculation at 2:48, shouldn't the sum of the moments at the cut be ..+F(x-1/2L)+M?

    • @jdomann
      @jdomann  9 лет назад

      jasper schuringa For some reason it appears the 1/2 isn't showing up in the video, and left a nice gap in its place (there's also a good chance I just forgot it!). However, the subsequent equation does take that 1/2 into account.

  • @LunarFlare91
    @LunarFlare91 8 лет назад

    at 2:50 sum M_cut = 0 = -0.5Fx + F(x-0.5L) + M

    • @jdomann
      @jdomann  8 лет назад

      Marc C thanks for catching that! Fortunately I corrected that mistake by the next line.

  • @CabalaCicero
    @CabalaCicero 8 лет назад

    Thank you.

  • @shirleyxian310
    @shirleyxian310 7 лет назад

    Thanks!

  • @willpaes
    @willpaes Год назад

    I love you