Dr Peyam, it's incredible how your work from a very distant place from my place (Brazil) can do so much for students like me from here. I really need to thank you.
I spent an hour struggling with these questions and then I found your video. 😭😭😭 I'm so glad I did. Now I have 0 problem solving these types of question.
Awesome integral! While I still can't do double integrals like that I'm glad this time I could atleast understand it, a simple but elegant solution. Hey Dr. Peyam, what do you think about michael atiyah's supposed proof of the rieman hypothesis? I haven't watched his whole video on it, and I really want it to be true, but I've seen some skepticism of it on the internet
Haha, I’m torn because I don’t think it’s something that’ll be proven in our lifetime, but on the other hand Michael Atiyah is a really smart and famous mathematician! Let’s see what the math community says; don’t trust the internet anyway!
I have no clue what the Todd function is, and couldn't find any info on it. How "obscure" was it? How did he pulled that off? The proof he presented doesn't really convince me aswell, however, if it turns out it IS, it is a turnover in history, a BIG history in turnover. I hope that I can study his proof in the future more in-depth. However, I think the best is to wait a bit for the time being.
I cry all night when Dr Peyam doesn't upload lol (that was a funny joke Dr Peyam; I hope people don't cry over integrals (especially unsolvable ones either) )
I also proved that the Lebeasgue measure, cardinality, ect. of the set of differentiable almost everywhere functions is the same as that of the set of real numbers.
@@drpeyam Ohh okay cool! So we pretty much always work it out first and if it's impossible we erase all our work and then change the order and start again? (I hope that makes sense!)
actually it is posisble without fubini's thoerem because you can just do this ∫_0^1∫_x^1sin(y^2)dydx, let f(x) be an anti derivitive of sin(x^2) with respect to x with the constant set to 0 ∫_0^1∫_x^1sin(y^2)dydx=∫_0^1f(1)-f(x)dx=f(1)-∫_0^1f(x)dx ∫_0^1f(x)dx=xf(x)]_0^1-∫_0^1 x*f'(x)dx=f(1)-0f(0)-∫_0^1 x*f'(x)dx=f(1)-∫_0^1 x*sin(x^2)dx f(1)-∫_0^1 x*sin(x^2)dx=f(1)-1/2*∫_0^1 2x*sin(x^2)dx=f(1)-1/2*∫_0^1 sin(u)du=f(1)-1/2*(-cos(u)]_0^1) =f(1)-1/2*(-cos(1)-(-cos(0))=f(1)-1/2(1-cos(1)) D(-cos(x^2)/2)=-(-sin(x^2)/2)*(2x)=xsin(x^2) -cos(1^2)/2--cos(0^2)/2=(1-cos(1))/2 =f(1)-∫_0^1 x*sin(x^2)dx==f(1)-(f(1)-1/2(1-cos(1)))=f(1)-f(1)+1/2(1-cos(1))=1/2*(1-cos(1)
Hey there! I love your channel and I came here to ask you for help. Could you solve the definite integral of (x-1)^n/sqrt(1-x^2) between 0 and 1 where n is a positive integer ? Thank you very much for your videos !
Looks like Dr Peyam had a tea with papa Fubinni
Indeed! It was delicious, but he kept changing the order of the flavors 😂
Dr. Peyam's Show LoL
This needs to be posted
I can already hear people cracking
FUBINI
Dr Peyam, it's incredible how your work from a very distant place from my place (Brazil) can do so much for students like me from here. I really need to thank you.
1:53 THAT is an extremly nice and intuitive way for describing the region....
There's just something about his vibe , like , WOW ! You genuinely deserve the best in life . Does anyone else see this ?
I spent an hour struggling with these questions and then I found your video. 😭😭😭 I'm so glad I did.
Now I have 0 problem solving these types of question.
Loved your passion for teaching 😎😎
Kfc hates when you change your order but i see you have no fear lol
Love the video
😂😂😂
your smile is very contagious. thanks for the vid
5:50 ahhhh so that's the whole reason you change the order of integration. Thank you
8:27 A Math quickie is my favorite type of quickie
thanks man, straight to the point and well explained
Thank you!!!
Thank you. Your videos are really helpful for us... Colegio de Postgraduados, Chapingo, Edo. de México.
Nice Video! Solving integrals is allways fun!
Thank you for your thorough explanation! helped me a lot!
amazing explanation sir........... love from India
Fubini's theorem is the most useful theorem out there
I like your videos and your humour sense!
Your classes are just assume 👌🏻👌🏻👌🏻👌🏻👌🏻. I love to learn from you and become a greatest fan of your classes.
thank you for helping me prepare for integration exam
Great, thanks a lot Dr. Peyam. (outside has to be a constant. thank you)
thanks a lot from belgium!
Teachers like him actually exist
I take that as a compliment :)
if you could just see the teachers here in India......
you would know why I like you so much
OMG DR Peyam,They just dropped the restriction on your class,I enrolled :).
YAAAAAAAAAAAY!!!! See you on Friday 🙂🙂🙂
Hi dr peyam. Do more videos on real analysis plz because I love it!!!!!!
More videos to come! And there’s a whole playlist if you’re interested
I love your energy, sir. thanks so much for the explanation!
Hi, love your videos
I’ll try :) There are some other ones on my channel
omg thanks for this incredible explanation it helped me a lot
amazing, you explained the hows and the whys, perfect
I love your energy
Thank you Dr. Peyam, this helped a lot for my take home calculus exam! You're the man.
Amazing, congrats!!
smooth going and very clever!
This was so helpful thank you!!
Awesome integral! While I still can't do double integrals like that I'm glad this time I could atleast understand it, a simple but elegant solution. Hey Dr. Peyam, what do you think about michael atiyah's supposed proof of the rieman hypothesis? I haven't watched his whole video on it, and I really want it to be true, but I've seen some skepticism of it on the internet
Haha, I’m torn because I don’t think it’s something that’ll be proven in our lifetime, but on the other hand Michael Atiyah is a really smart and famous mathematician! Let’s see what the math community says; don’t trust the internet anyway!
I have no clue what the Todd function is, and couldn't find any info on it. How "obscure" was it? How did he pulled that off? The proof he presented doesn't really convince me aswell, however, if it turns out it IS, it is a turnover in history, a BIG history in turnover. I hope that I can study his proof in the future more in-depth. However, I think the best is to wait a bit for the time being.
I cry all night when Dr Peyam doesn't upload lol
(that was a funny joke Dr Peyam; I hope people don't cry over integrals (especially unsolvable ones either) )
LMAO 😂😂😂
if the region is under the x axis, will it become positive?or negative?
I also proved that the Lebeasgue measure, cardinality, ect. of the set of differentiable almost everywhere functions is the same as that of the set of real numbers.
Does make sense an integral of a diferential in the argument of a function? Ex: integral of sin(dθ)
It’s more of a notation in measure theory and probability: If m is a measure, then m(dx) means integral with respect to dm
Dr. Peyam's Show wow cool, thanks! i even thought it wasnt something yet, hahaha
nice one! thank you!
btw I
Thanks ❤️
Hey Dr Peyam, I was wondering if you can please tell me how do I know when to change the order of integration? It's not making any sense to me.
If the function is impossible to integrate
@@drpeyam Ohh okay cool! So we pretty much always work it out first and if it's impossible we erase all our work and then change the order and start again? (I hope that makes sense!)
Yep
@@drpeyam Awesome! Thank you so much for your time Dr Peyam :)
COMPLEX DOUBLE INTEGRAL AND SWITCHING OF x AND y!! :3
Awwww shit! It's getting real!
2:34, you cheated us. You said "lets add some fun" but you added a bar.
But how you indentify yourself?
is the integral impossible without Fubini's theorem? or is the integral, sin(y^2), impossible with respect to y?
Yeah, it’s one of those functions with no (elementary) antiderivatives
ah I see, thank you!
actually it is posisble without fubini's thoerem because you can just do this
∫_0^1∫_x^1sin(y^2)dydx,
let f(x) be an anti derivitive of sin(x^2) with respect to x with the constant set to 0
∫_0^1∫_x^1sin(y^2)dydx=∫_0^1f(1)-f(x)dx=f(1)-∫_0^1f(x)dx
∫_0^1f(x)dx=xf(x)]_0^1-∫_0^1 x*f'(x)dx=f(1)-0f(0)-∫_0^1 x*f'(x)dx=f(1)-∫_0^1 x*sin(x^2)dx
f(1)-∫_0^1 x*sin(x^2)dx=f(1)-1/2*∫_0^1 2x*sin(x^2)dx=f(1)-1/2*∫_0^1 sin(u)du=f(1)-1/2*(-cos(u)]_0^1)
=f(1)-1/2*(-cos(1)-(-cos(0))=f(1)-1/2(1-cos(1))
D(-cos(x^2)/2)=-(-sin(x^2)/2)*(2x)=xsin(x^2)
-cos(1^2)/2--cos(0^2)/2=(1-cos(1))/2
=f(1)-∫_0^1 x*sin(x^2)dx==f(1)-(f(1)-1/2(1-cos(1)))=f(1)-f(1)+1/2(1-cos(1))=1/2*(1-cos(1)
Hey there! I love your channel and I came here to ask you for help. Could you solve the definite integral of (x-1)^n/sqrt(1-x^2) between 0 and 1 where n is a positive integer ? Thank you very much for your videos !
sir integration of sin is equal to - cos right .....?then why r u right integration of sin is equal to sin ?i'm confused🧐🤔🤔
thank you
THANK YOU
totally agree
thanks!!
Cool
no more one direction with multivariable calculus? thank god, no more one direction :P
im male lol
Thank you