Formation of Partial Differential Equation (By elimination of arbitrary constants)

[@mayankmalviya64]

The last example was quite good.....!!

[@chirugummala6606]

Your voice is too sweet to hear mam..

[@JoeYapzor]

Thanks ma'am, you made it simpler

[@Rouge1995]

👍👍

[@Gstvo21]

thank you this was really helpful

[@ninadajari8826]

I have a doubt, how should I contact you?

[@maths.tutor4u172]

mention you query here

[@binauralbeats8779]

IN THE LAST EXAMPLE WE CAN DO BY NOT GOING TO 2ND ORDER PDE.
IN PD with t equation just reduce it by put z =c e^(-wt) sin(wt) and you got w=-Zt/Z
And from equation 1 we got value of C and put there value of w
At last put these 2 in given equation and we got our 1st degree PDE

[@maths.tutor4u172]

here w is also arbitrary constant and we need to eliminate as in the formation of pdf we only have dependent, independent variables and their partial derivatives no arbitrary constants

[@maths.tutor4u172]

thats y i illustrated this example as our first approach is to retrieve pde from lowest possible order but if elimination of arbitrary constant cannot be done by al possible first order pd we exent it to next order

[@yatenderthakur3104]

Thanks mam

[@sunilKumar-je9dy]

Mam ,there was one mistake in 8:57,.
2(x-a)(-a)

[@maths.tutor4u172]

partial diff is w.r.t. x, and a is constant, so no (-a) multiplication is there { derivative of (x-a)^2= 2(x-a)(1)}

[@Sunnykumar-i1e4w]

Mam , Thank you for this informative video. I have one doubt in last question that you told in theory portion that if no of arbitrary constants is equal to no of independent variables then order of partial differential equation will be equal to 1 but in last question (No of independent variables = No of arbitrary constants =2, Order=2), it is not validating the theory. Why?

[@maths.tutor4u172]

Agreed but if the elimination is not possible then we can extend it to next order like as in last example . You can rectify the last part missing in note 1 we can say if the number of arb constant =no. of variables the pdf formed will be of 1st order or higher.

[@sunilKumar-je9dy]

Otherwise it's a nice explanation

[@smartprincelilawat1313]

thanks

[@sameermath9326]

Can I connect with you

[@vommibhaskarlalmehar3808]

HOW TO SOLVE X^2/a^2+Y^2/b^2+Z^2/c^2=1 using this method