Numericals on Hardy Weinberg principle

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[@tanyakansal1396]

Directly 2pq will give 0.48 !

[@shubhashispaul9138]

@Abhi Panchal because according to hardy Weinberg principle p2+2pq+q2=1.....where 2pq represents the frequency of occurrence of heterogeneous alleles in a population when no genetic drift or gene flow take place

[@vishnuvardhareddy9833]

@@shubhashispaul9138 👍👍👍

[@boardonroad1646]

yeah, it's so simple

[@biologyforlife4656]

I also thought why he is rotating the simple thing

[@buddy8998]

Similarly in que 2 also...We know 360/1000 are AA so A^2 = 0.36 hence A=0.6...Damm easy why did he confused people

[@scienceclasses9663]

Good morning bhaiya. Bhaiya can you please make a separate playlists in which you include all the topics of the various chapters which are out of ncert textbooks but important for NEET and AIIMS. That will really help us to focus on that very well. Because I completed my ncert and want to focus on topics which are not in ncert but comes in NEET. Please reply bhaiya

[@superbscientist743]

Hellw Vipin Ji .. In Hardy Weinberg equation, the no. of heterozygotes is multiplied by 2.
The equation is *a2 + b2 + 2ab = 1.*
So don't you think that 0.52 after being subtracted from 1 should be divided by 2 in the end ??

[@akhiladas100]

@Diksha Tripathi
Actually we shouldn't divide 0.52 by 2.
It's because in punnet square we get one dominant homozygous, one recesive homozygous and TWO DOMINANT HETEROZYGOUS

[@superbscientist743]

@@akhiladas100 Thanks. But I'm sorry, I couldn't understand. Why to construct Punnet square when we have the simple Hardy-Weinberg equation for this type of question ?

[@weird_anjalii]

I have the same doubt dear

[@nick-dv6gg]

Diksha Tripathi no

[@bidishakumari7095]

Same doubt

[@sirichandanadarnam8443]

Tq so much my dear brother
From South India

[@ipsitapujari]

In the fst que we can easily put the formula of 2pq to get the answer right?

[@moxa8294]

Sir in 1st numerical we have to find Ab and the eq is a2 +b2+2ab=1
So .36+.16+2ab=1
.52+2ab=1
2ab=.48
Then to get ab it should bw divided by
.48÷2= .24
Sirr plzz answerr itt i am confused

[@karanarya7949]

You cannot deviate simple you use. 2pq put the value p and q

[@moxa8294]

Tysm

[@RoshanAA10]

Nice one

[@ajaysaxena939]

Great questions sir.... can we have some more questions...your explanation was awesome sir
Sir is this is the only pattern of questions asked from Hardy Weinberg equation?

[@jothimanilakshmanan4556]

As usual it helped me so much
Thank you Vipin for this help

[@manirajcharan8795]

In second question we can directly found it by =√360/1000

[@sportsworld24x73]

In 1st question... A^2 +b^2 + 2Ab = 1... Will not divide 0.48 by 2 ????

[@nikhilnaga9107]

Even I have same doubt

[@nakulnandi7707]

yes why its not divided....

[@jyotidesai5506]

No of heterozygotes are 2pq and not pq so you need not divide by 2

[@ruchitanandusose9947]

A very pleasant Morning bhai
One live session with you plz
Thank you so much bhai👍😊💞

[@happysoul7304]

👍❤️ thanking

[@khushimittaliya3808]

Thanku soooo much for helping us in our exams

[@iml5504]

Good morning bhaiyya 🤓😊....
Tysm for the lecture.....😇😇

[@rizwanafarukh1057]

Finally got this concept with much clarity...thank you Sir🙏

[@harsh-xb3cx]

Bhaiya but hardy weinberg principle me to heterozygote 2pq hota hai .kya hme divided by 2 nhi krna

[@aasthakamra1628]

Sir you are best cos of your videos i got to understand whole evolution

[@shiprasinghrajput9744]

Very good morning bhaiya🌿🍀☕☕..... have u beautiful day🌼🌷🌷🌷💟💟💟💟💟💟😘😘😘😘

[@induv6110]

Gm morning my dear bro 😊thank you bro

[@rajendra5063]

You are great man .your explanation is NC.cell biology karna sir next chapter

[@jaweriashabbir6755]

It was Informative.
thanks😇

[@deepjyotidas2052]

Sir lekin formula mai to p²+q²+2pq=1 tha par numerical kuy p²+q²+pq=1 se kiye? Plz answer

[@perumalteacher7278]

Make video on excretory products and their elimination

[@aashimapopli1505]

Bhai will you please provide a sheet of all scientists and their works given in ncert biology

[@rajvi5562]

Thanks.. For trick ..

[@dharapatel6489]

BEST TRICK EVERRRRR !!!!!!!!!!!!!1

[@Indianstudentvlogs100M]

Awesome broo..thanq so ..much..bro..

[@sayedsaheelahammed7136]

tq so much sir big fan of you

[@dr_kiddo-mbbs]

Bhi in Q1 ,no. Of heterozygots is 2pq=2 into 0.4 into 0.6=0.48.
Just in one step😊

[@veenadevi6715]

Thank you

[@varshakulkarni9014]

Sir please give videos early there is less time to complete remaining chapter for NEET2019

[@vishnuvardhareddy9833]

Did you got seat

[@aafiatherisingstar1016]

Thankyou sir...very helpful ❣️🌸

[@priyav227]

Thank you sir

[@aneeshraam9568]

thankyou now i am able to solve these questons

[@rishabhkaushik9360]

Thanks Sr for ur efforts on our request 😅😍😍😘😘😘🙏🙏🙏

[@kaleshamasthan6817]

Clear way of explaining bro , than q very much 👏👏👍👍

[@gulshansingh2166]

finally i complete this chap frm ur heplful viedo

[@sudhir11361]

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[@suryamishra7918]

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[@sawaidanratnu6793]

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[@shiprasinghrajput9744]

Thank u soo much bhaiya🙏 for wonderful lecture nd OSM numerical... .📝📝📝🌺🌺🌺⛄✨.👌👌👍👍👍👍💟💟💟💟😘😘😘😘

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[@dr_kiddo-mbbs]

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[@iffathashmi1336]

Aap ne book main jo picture di h hardy principal k neeche woh nahi bataya

[@dhanshreerajput9852]

Good morning sir🤗🤗 thanks for lecture👌👌💐

[@reddykausthuba1324]

Thanks a lot now I can do it with out any mistake

[@owaisosman6703]

Thanks bhai evolution ache se hogaya...bcz of uh

[@dr_abhi14]

Will you be able to finish the syllabus by December? Then the preparation will become easier.
Thanks for the videos. They're great.

[@mehakmehak5005]

Thank you so much sir very helpful for neet 2020

[@Khushboo-y9r]

Thank you 🙏

[@anshupriya3762]

Hello sir...gud morning 🙏...thanks a lot for video❤️

[@sanghapal1111]

Heatly Thank You So Much Bhaiya 💖💖💖💖🙏🙏🙏🙏🙏

[@nishigandhakamble7107]

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[@muskan6470]

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[@THEFORTHKILLER4]

🙏🙏🙏👍

[@misskhan8328]

Oh my god sir is looking very diff

[@IrfanAnsari-mw3bs]

Thank u sir u made this chapter so easy

[@pradeep1772]

Very useful videos sirr

[@ggmadhavi8502]

Thanks Sir For helping us for exam may God Bless you 🙏 😊

[@neerjaanand6984]

If out of 200 ,150 have round seeds and remaining 50 have wrinkled seed. What would be value of AA??

[@neerjaanand6984]

I mean how can we calculate total no of heterozygous and homozygous individuals??

[@Sabakaushar21]

Thank you so much sir 🥺❤️😌

[@amarandia7526]

Bhai plzzz give a video of flying adaptation of birds

[@ritulata1711]

Thank you 😘

[@akhileshwaran483]

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[@Conscious_creator.]

Awesome trick!

[@KP-fr5hm]

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[@poorankwdal3340]

Thank you sir so much for your video

[@shraddhabagshi]

Your videos are the best

[@niraldesai1523]

Very easy

[@ravichandar2142]

THANKYOU SO MUCH BHAIYA .

[@Rakesh-wd3zl]

💓

[@komalkomalgurehaya7816]

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[@sitaramgoswami1683]

Awesome

[@rohitdutta7625]

Thank you so much sir☺️❤️💕🙏

[@pramodmaurya6224]

Thanku sir.... Excellent explanation...😇😇😇🤗🤗🤗

[@bhagwatlondhe7739]

Wow! Best

[@mohdtaha9341]

Good morning...
Thanks u sooooo much sir ☺️😊

[@kritikatomer8862]

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[@priyajangdebaott5963]

Amazing💫 the things I needed to know

[@ritikasingh8809]

Thank you so much sir🙌

[@nehabookiology1415]

Good morning sir,thankyou so much sir🙏👍

[@karanarya7949]

What's your neet result neha

[@kuriouskid1285]

@@karanarya7949 😁

[@Brainfoodgk]

Same question arise in my mind
NEET result neha?????

[@sunnytenpe7480]

Please help sir in ploblem :
In a population with equilibrial condition,3360 individuals out of 4000 are tongue roller ,then what will be the number of individual with heterozygous condition"

[@maheshkamat4448]

3360 are tongue rollers ( AA + Aa) and hence 640 are non tongue rollers (aa)
Therefore f (aa) = q(squared) = 640/4000 = 0.16
Therefore q ( freq of allele a ) = 0.4
Therefore p = 1 - q = 1 - 0.4 = 0.6
Therefore p(squared) = freq of AA = 0.6 (squared) = 0.36
Now according to H-W principle
p2 + 2 pq + q2 = 1
0.36 + 2pq + 0.16 = 1
Therefore 2pq ( freq of Aa) = 0.48
Therefore Num of heterozygotes = 2pq (freq of heterozygotes) × 4000 (total individuals)
= 1920
Hope that helps! @Sunny Tenpe

[@ritikashaw28]

There are two populations of birds having AA=600, Aa=200 and aa=200. In another population, AA=400, Aa=400 and aa=200. If 20% of the homozygous recessive trait containing birds and 25% homozygous dominant type birds migrate from population I to population II, what will be the new gene frequencies in the population II ?
What is the solution of this? Plz help me i need solution

[@supriyoacharjya19]

Options?

[@dr_kiddo-mbbs]

Thank you bhii

[@akritinahar4535]

Really awsmmm...totally clear

[@rachanasaroya9545]

Thanks sir

[@rudrapratap3294]

full playlist done 26.07.2023

[@fitbrothers2998]

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[@shafiyanoor3967]

Trick to remember evolution of plant forms in evolution chapter..plz

[@øvø-b4b]

Thank you sir🙏

[@ehteshamahmed3026]

Good morning Sir.

[@subratdubey2038]

Keep it up.
Good

[@bhavanisiripalli2772]

Thanks alot sir ji

[@tabishahmad5839]

sir aap great ho ...thank u

[@patelrajen7354]

Thank you so much sir 👍😊

[@VatsavaiLakshmiPrasanna]

Good morning 😃😄

[@ayushisingh6403]

Thanks a lot,👌👌👌😊😊

[@itsmeasthasingh9974]

Thnku sir

[@shubhankarpatil7033]

Bhaiiya aise numericals kitne marks ke liye ate hain CBSE boards main???