"break" & "continue" Statements in Python #10

[@programizstudios]

🔥Finding it Damn Hard to Understand Python?
Learn to code-the right way-with interactive lessons, quizzes & challenges. Build a strong programming base; it's IMPORTANT!
Try Programiz PRO for Free: bit.ly/interactive-py

[@Abeedalamkhan]

To be Honest i was very very scared of programming, i am watching your Videos since last week and now i am writing few lines of codes just because of you.
Thank you so much
Your are diong a good job

[@ppirsjsh505]

languages=["phyton","java","swift","C","C++"]
for character in languages:
if character=="C++" or character=="swift":
continue
print(character)

[@pachakutiq266]

languages = [ "Python" , "Java" , "Swift" , "C" , "C++"]
for a in languages:
if a == "Swift":
continue
if a == "C++":
continue
print(a)

[@kishansindhi5181]

Are bhai output nahi aa raha

[@pachakutiq266]

@@kishansindhi5181 really? What's ur error? I'll see if I can help..

[@basirsaboor2367]

can you do it by input function. plz!

[@basirsaboor2367]

input the language by the user

[@nikanayo]

for languages in ['Python', 'Java', 'Swift', 'C', 'C++']:
if (languages == 'Swift'or languages == 'C++'):
continue
print(languages)

[@prajilshrestha7995]

Thumbnail: Feeling cute, might teach python later :D

[@RedBull.RedBull]

I don't understand your comment.. how you feel the cute? Teaching Python later to whom?

[@scout7947]

@@RedBull.RedBull look at the thumbnail of the video and it will explain it

[@rudrakshchatterjee]

😂

[@glennswhiffmontage9397]

@@RedBull.RedBull didn't understand the assignment.

[@akshaymanta55]

🤣🤣🤣 nailed it!

[@KulbirAhluwalia]

Everything is perfect, just keep your head stable when you speak. Thank you.

[@gj18p420]

for i in range(10):
language = str(input("Enter a language: "))
if language == "Swift" or language == "c++":
continue
print(language)

[@shadanakhtar5095]

But bro have a doubt that should i watch your video or study from the website and i think video is best because my brother is learning from the website and it take a lot of times but in video you explain soo nicely and fast

[@amine2010amine]

The best Channel to learn python

[@keerthanasaini3167]

languages = ["Python", "Java", "Swift", "C", "C++"]
for language in languages:
if language == "Swift" or language == "C++":
continue
print(language)

[@Footballeditz900]

languages = ["Python","Java","Swift","C","C++"]
for i in languages:
if i == languages[2] or i == languages[4]:
continue
else:
print(i)

[@ozguravan9714]

languages=["pyhton","java","c","c++","swift"]
for tongue in languages:
if tongue=="swift":
continue
elif tongue=="c++":
continue
else:
print(tongue)

[@johnhaythorpe1063]

Hi, I am loving the course. But this lesson appears to be out of order when I use the playlist to access the programs, it is appearing before lesson 9, instead of after. I am taking notes and practicing every exercise you demonstrate and then I vary my code a bit to see that I understand what you have taught. Thank you for this great series

[@mdiftekhar6876]

languages=["python","java","swift","c","c++"]
for i in languages:
if i=="swift":
continue
if i=="c++":
continue
print(i)
print("h")

[@kanika1]

languages =["Python", "Java", "C", "Swift", "C++"]
for character in languages:
if character == "Swift" or character =="C++":
break
print(character)
Or......
languages =["Python", "Java", "C", "Swift", "C++"]
for character in languages:
if character == "Swift" or character =="C++":
continue
print(character)

[@pinkshoelace8388]

I do not recommend the first solution, it will work in this case because Swift and C++ are the last values in the list, but if one of them was the first item on the list then the loop would break and none of the languages would be printed.

[@kanika1]

@@pinkshoelace8388 yes i agree. I realised this when I progressed in python. Thanks for spotting :-)

[@muradali1231]

If I type-
"if item == 3:
break"
after "print(item)" it gives Indentation error. Does anybody know why this happens.

[@jodezod]

If it says indentation error then you probably messed up somewhere on the indentations

[@gemrwx]

languages = ["Python", "Java", "Swift", "C", "C++"]
for item in languages:
if item == "Swift" or item == "C++":
continue
else:
print(item)

[@programizstudios]

The logic you are trying to use is correct> However, there is an error in the test condition. Change the test condition to:
item == "Swift" or item == "C++"

[@gemrwx]

@@programizstudios Thanks

[@upulithaperera4847]

@@programizstudios but isn't it the same thing sir?

[@victorycoconut]

Wait! I'm using your Learn Python app and it is really helpful!

[@kamrulhassan1219]

why used float number here? if we use int number what will happened

[@shaileshsingh1445]

Wow you are such a great mentor , really helping to build basics :) God Bless you :)

[@Aravindblaze95]

languages = ["Python", "Java", "Swift", "C", "C++"]
result =[]
for language in languages:
if language in ["Swift"]:
continue
if language in ["C++"]:
break
result.append(language)
print(f"The Output is {result}")

[@Aravindblaze95]

The Output is ['Python', 'Java', 'C']

[@harshad9203]

languages = ['python', 'java', 'swift', 'C', 'C++']
for item in languages:
if item == 'swift' or item == 'C++':
continue
print(item)
-- Programming Task Answer --

[@beans4114]

languages = [ “python” , “Java” , “swift” , “C” , “C++” ]
for i in languages:
if i == “C++”:
continue
elif i == “swift”:
continue
print(i)

[@nandupagere5764]

language = ["Python", "Java", "Swift", "C", "C++"]
for item in language:
if item=="Swift" or item=="C++":
continue
print(item)

[@riturajritweek681]

languages=["python","java","c","c++","swift"]
exclude=["java","c"]
for i in languages:
if i in exclude:
continue
else:
print(i)

[@santoshkapse3359]

languages = ["Python", "Java", "Swift", "C", "C++"]

for langauge in languages:
if language == "Swift" or language == "C++":
continue
print(langauge)
output :- Traceback (most recent call last):

NameError: name 'language' is not defined

[@emrandafadar4445]

I can't understand this one but how about this :- languages = ["python", "java"', " Swift", "C"', " C++"]
Print(languages [0])
Print(languages [1])
Print(languages [3])

[@pavelboldin7227]

I forgot about OR, so my code is:
languages = [ ]
for language in languages:
if language == 'swift':
continue
if language =='C++':
break
print(language)

[@avachavoshi574]

Thank you!

[@demetrepanjakidze3787]

languages = ["Python", "Java", "Swift", "C", "C++"]
list=[]
for _ in range(len(languages)):
if languages[_] == "Python" or languages[_] == "Java" or languages[_] == "C":
list.append(languages[_])
print(list)

[@bhavishibansal2573]

lang=["Python","Java","Swift","C","C++"]
lang.remove("Swift")
lang.remove("C++")
print(lang)

[@voytox]

you should use loop and what is thought in this vid

[@GiulioVonKerman]

What means float(input())?
Thanks!

[@VikasChauhan-ue2th]

Float means decimal numbers like 10.6, 9.0, 4.89, etc.
If you try "int" instead of "float" it will only give you integer values like 10, 9, 4 and not the decimal values.

[@f.a5148]

my like turned your video from 1.4k to 1.5k

[@ticklingtick9292]

I just love your head from both side.Perfect explanation.💯

[@Markjairus95]

languages=["python","java","swift","c","c++"]
print(languages[0,1,3])

[@ines7257]

thank u!

[@SahilShaikh-7]

language = ['python','java','swift','c','c++']
new_language = [ ]
for i in language:
if i == "swift" or i == 'c++':
continue
else:
new_language.append(i)
new_language will be ['python', 'java', 'c']

[@wnttknwmrthngs3360]

Is this acceptable?
lang = ["Python", "Java", "Swift", "C", "C++"]
for i in lang:
if i == lang[2]:
continue
if i == lang[4]:
continue
print(i)

[@ivanpaulmendoza4248]

where the fuck did the for and in range come from there is no tutorial for that in this series

[@kismet4904]

Loving this series, I have learned a lot in such a short amount of time :D keep it up!

[@didio.1791]

languages = ['python','java','swift','c','c++']
for language in languages:
if language == 'swift' or language == 'c++':
continue
print(language)

[@ramraj4047]

languages=["python","java","swift","c","c++"]
for i in range (len(languages)):
if(i==2 or i==4):
continue
print(languages[i])

[@irynahryma2605]

I've been treing this code for several times, it doesn't skip the languages 2 and 4. I've tried other examples with "break" and "continue", and it worked. Am I doing something wrong?

[@SampannaAryal]

@@irynahryma2605
a=["Python", "Java", "Swift", "C", "C++"]
for i in a:
if i.upper()=="SWIFT" or i.upper()=="C++":
continue
print(i)

[@saureetchakrabarti3913]

languages = ["Python", "Java", "Swift", "C", "C++"]
for language in languages:
if language == "Swift" or language == "C++":
continue
print(language)

[@DigitalAcademyOnline]

Learning Python is something you would like to get in your skills, but you do not know where to start? This NEW channel will help you out leaning Python Programming from scratch - for complete Beginners, Intermediate and Advanced Levels

[@kevinlavoie2800]

languages = 'Python', 'Java', 'Swift', 'C', 'C++'
for language in languages:
if language == 'Swift':
continue
elif language == 'C++':
continue
print(language)

[@cezartofan1791]

#lol, we think almost the same:
languages=("Python","Java","Swift","C","C++")
for language in languages:
if language=="Swift" or language=="C++":
continue
print(language)

[@kartikeshwarhingole6007]

thank you sir I was able to complete your home work.

[@sunakshiranjan3308]

just one word- Awesome! Your channel is a very big help to me. Thanks :)

[@moustafamedhat4189]

for languages in ['Python','Swift','C++','C','Java']:
if languages =='Swift' or languages=='C++':
continue
print(languages)

[@Mamata171]

tq

[@oogook8153]

Thanks for clearing my confusion, it was really helpful but take care of your head don't move it so much it might "Break" and you may not be able to "Continue" with such series.

[@misterduck4527]

you didn't turn your head enough

[@georgemorrison1814]

I am new in programing . After several attempts, I found out the answer on the Github repository is wrong. Correct code should be
list = ["Python", "Java", "Swift", "C", "C++"]
for item in list:
if item == "Swift" or item =="C++"
continue
print(item)

[@georgemorrison1814]

Sorry it is right, I realized my mistake

[@limingyin5094]

you forgot to put : at the end of the if item == "Swift" or item =="C++":

[@reqssss]

languages = ["Python", "Java", "Swift", "C", "C++"]
for language in languages:
if language == "Swift" and "C++":
continue
print(language)

[@torsoto23]

languages = ["Python", "Java", "Swift", "C", "C++"]
without break&continue:
for i in languages:
if i != "Swift" and i !="C++":
print(i)
with break&continue:
for i in languages:
if i == "Swift":
continue
if i == "C++":
continue
print(i)

[@vaishalidixit4871]

THANK YOU SIR
HERE IS THE CODING TASK
languages = ["PYTHON","JAVA","SWIFT","C","C++"]
for i in languages:

if i == "C++" or i == "SWIFT" :
continue

print (i)

[@debebebelaye1881]

my_list = ["python", "Java", "Swift", "C", "C++"]
for i in my_list:
if i == "Swift" or i == "C++":
continue
print(i, end=",")

[@thelegendarysummersky3189]

for languages in ['Python', 'Java', 'Swift', 'C', 'C++']:
if (languages == 'Swift' or languages == 'C++'):
continue
print("Language is: ", languages)

[@some0ne308]

#Question_answer
language = ["Python", "Java", "Swift", "C", "C++"]
for p_language in language:
if p_language == "Swift":
continue
if p_language == "C++":
continue
print(p_language)

[@lakshanj.kumara7648]

languages=("Python" , "java" , "Swift" ,"C","C++")
for language in languages:
if language=="Swift" or language=="C":
continue
print(language)

[@girishgh9793]

languages=["c++","c","phyton","swift","rust"]
for language in languages:
if language == "swift" or language == "c++":
continue
print(language)

[@zainulabdeen7074]

languages = ["Python","Java","swift","C","C++"]
for i in languages:
if i=="swift" or i=="C++":
continue
print(i)

[@rajeshdubey1260]

#Can you create a program so that all items of the language are printed except swift and C++
# language=["Python","Java","Swift", "c","c++"]
language=["Python","Java","Swift","C","C++"]
for i in language:
if i=="Swift":
continue
elif i=="C++":
continue
else:
print(i)

[@majidalich2947]

languages = ['Python', 'Java', 'C', 'Swift', 'C++']
for i in languages:
if i == 'C++' or i == 'Swift':
continue
else:
print(i)

[@kevinekene3765]

languages = 'Python', 'Java', 'Swift', 'C', 'C++'
for language in languages:
if language == 'Swift' or language== 'C++':
continue
print(language)

[@sravankanagandla6147]

languages = ["Python", "Java", "Swift", "C", "C++"]
for i in languages:
if i=='Swift' or i=='C++':
continue
print(i)

[@anukaran3438]

lang = ['python','java','swift','c','c++']
for i in lang:
if (i==lang[2]) or (i==lang[4]) :
continue
else:
print(i)

[@ayonbiswas4186]

[print(i) for i in ["python", "java", "swift", "c++", "c"] if i!="swift" and i!="c++"]

[@man0cash]

thank you for this video it was helpful :)

[@DoryRutayisire]

why can't we just use an if statement instead of a while loop at 3:34?

[@losikanicholas5105]

Y r we using or during the comparison

[@SUMANKUMAR-nt2ur]

Sir when next video will post

[@3zez2025]

lang = ["python","java","swift","c","c++"]
for x in lang:
if (x == "java"):
continue
elif (x == "c++"):
continue
print(x)

[@nickjankovic2210]

Great tutori, very professional and easy to follow. The only problem I have is ....I do not know where to find this "link below" where I can check the solution to exercizes at the end of each tutorial.

[@programizstudios]

Hi Nick,
You can find solutions to the exercise tasks in this link: github.com/programiz/python-course/

[@soumadeepdas7610]

where is the github link sir?

[@dymonn]

lang = ["Python", "Java", "Swift", "C", "C++"]
for item in lang:
if item == "Swift" or item == "C++":
continue
print(item)

[@anandshankarm777]

languages = ["Python", "Java", "Swift", "C", "C++"]
print(languages[0])
print(languages [1])
print (languages [3])

[@hijushajahan5263]

languages = ["Python", "Java", "Swift", "C", "C++"]
for i in languages:
if i == "Swift" or i == "C++":
continue
print(i)

[@divyaahirkar9183]

languages = [ " python" , " java" , " swift", " c" , " c++"]
for language in langyages :
print ( language)
if language =" swift" or language = " c++"
break

[@adammunawar2806]

thisset = {'python', 'java', 'c', 'swift', 'c++'}
for x in thisset:
print(x)
if x == 'switf' 'c++':
continue

[@Jayashreee624]

I have written the same code just changed the variable " item" into "digits" at 2:36 but I am getting

[@beksaylor]

Love your videos..and website...thanks so much for all that you and your team do...

[@codestone4911]

Nice Tutorial

[@banerjeekrishna5230]

Thalakai oopadam aaparaa babu

[@NehaGupta-if7se]

Thank u so much sir...

[@sandipansarkar9211]

nice explanation

[@gabrielnino2892]

No thank you! ❤

[@abdu47137]

I appreciate you man, thanks for these tutorials

[@prathmeshborse2898]

😇

[@Avinashsingh-lz3ey]

languages = ["Python", "Java", "Swift", "C", "C++"]
for language in languages:
if language == "Swift" or language == "C++":
continue
print(language)

[@awesomeiram]

but u just ripped-off that other comment tho

[@joyceadhiambo9977]

Dude you are an excellent teacher...am now enjoying coding
languages=['python','java','swift','c','c++']
for language in languages:
languages=['python','java','swift','c','c++']
if language==('swift'):
continue
if language==('c++'):
break
print(language)

[@bharadwajs3475]

Op sir. With your 1video I can understand easily.
I think you are a South Indian🇮🇳👳. I hope you will continue posting more videos regarding python. ❤❤

[@Anonymous-tt7yi]

Yup, I am pretty sure because his first software job was in Hyderabad, India.

[@lastonline2614]

he is from nepal bro...

[@anonymousboss824]

Binod

[@ClickNBuild]

I love this series . It so good

[@freeprivatetutor]

Why Break and continue are giving no output? Just blank, not any warning,
Write exactly same but no output, only the end has printed