Air Standard Cycles | Otto Cycle | P-v and T-s diagram of Otto Cycle | Numerical on Otto Cycle

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  • Опубликовано: 26 янв 2025

Комментарии • 29

  • @locuspointofyourcareer
    @locuspointofyourcareer  4 года назад +3

    Dear All, there is mistake made by me in the Numerical explained in video lecture.
    There is a calculation mistake due to which answers got differ.
    Steps/Process & formula are same & right,
    only correction is in the values of T3, P3, T4, P4, QR & Wnet.
    Correct Answers are;
    T3 = 2195.5 K
    P3 = 58.54 bar
    T4 = 955.64 K
    P4 = 3.185 bar
    QR = 470.093 kJ/kg
    Wnet = 609.906 kJ / kg
    Thnx for support
    I will try that such mistake will not repeat.

  • @anukritisinghrathaur5362
    @anukritisinghrathaur5362 4 года назад +3

    All videos are awesome. Deserve more views n like. Keep uploading.

  • @vmaithani1092
    @vmaithani1092 4 года назад +2

    Sir ji keep uploading all the videos all are having best content,explanation,and example.

  • @RajendraSingh-gl8bv
    @RajendraSingh-gl8bv 4 года назад +2

    Very very nice

  • @RohitSingh-le1lk
    @RohitSingh-le1lk 3 года назад +1

    Very nice sir👌👌👌👌👌👌👌👌👌👌👌

  • @locuspointofyourcareer
    @locuspointofyourcareer  4 года назад +2

    Answers of 1st Assignment Numerical
    Swept Volume = 17671.45 cc
    Compression Ratio = 12.04
    Efficiency = 63%
    Engine type = Over square Engine

  • @PradeepSingh-nr3ed
    @PradeepSingh-nr3ed 4 года назад +1

    Very well explained. keep uploading

  • @locuspointofyourcareer
    @locuspointofyourcareer  4 года назад +2

    Answer of 2nd Assignment Numerical
    Net Work done = 837.197 kJ/ kg
    Efficiency = 56.47 %
    Mean effective pressure = 11 bar.

  • @Shobhnathpal-dm2qb
    @Shobhnathpal-dm2qb 3 года назад +1

    very nice sir

  • @vmaithani1092
    @vmaithani1092 4 года назад +2

    👌👌👌👌👌👌

  • @sandhya22819
    @sandhya22819 4 года назад +1

    Explained nicely 👍

  • @AdityaKumar-ps7zv
    @AdityaKumar-ps7zv 2 года назад +1

    Silly mistakes doesn't matters but the simplicity of numerical and topic explanation matters.

  • @sarkaribuzz8848
    @sarkaribuzz8848 Год назад +1

    Sir 1st numerical me compression ratio se direct effeciency find karke workdone nhi find kr sakte kya

  • @9211Rider
    @9211Rider 3 года назад +1

    Why heat rejection is shorter line??

    • @locuspointofyourcareer
      @locuspointofyourcareer  3 года назад

      Because Amount of heat supply is much higher than heat rejected. That's why heat rejection line will be shorter than heat supply line

  • @anukritisinghrathaur5362
    @anukritisinghrathaur5362 4 года назад +1

    Answer of 1st numerical
    Compression Ratio = 12.04
    Efficiency = 62.96 %
    Engine is Over Square Engine.

  • @anukritisinghrathaur5362
    @anukritisinghrathaur5362 4 года назад +1

    Sir 2nd Numerical Question samajh nhi aa rha h

    • @locuspointofyourcareer
      @locuspointofyourcareer  4 года назад +1

      Koi baat nhi, I will explain all Assignment numerical step vise in Part - 6 , video lecture I.e. Dual Cycle and Discussion of Home work Assignment numerical Practice.

    • @anukritisinghrathaur5362
      @anukritisinghrathaur5362 4 года назад

      @@locuspointofyourcareer ok sir, I waiting 4 part - 6 video

  • @PradeepSingh-nr3ed
    @PradeepSingh-nr3ed 4 года назад +1

    1st Numerical Answer
    r = 12
    Efficiency = 62.8 %
    Engine = Qver Square engine used for high speed vehicles.
    2nd Numerical Answer
    work done = 1946 J/kg
    Efficiency = 56.47%
    mean effective pressure = 11 bar