Signal Flow Graphs (Solved Problem 2)

[@sahanasingh8580]

Your channel is serving a lot of purpose for students pls continue uploading lecture videos!

[@siddharth7261]

1. 100
2. Option b

[@gunjankumar240]

1.Ans 1800/18=100
2.Ans B.

[@ss-tp6mz]

For question 1.)
P1=400; DEL1=2
P2=200; DEL2=5
DEL=18

[@chandruloki6900]

right , so answer will (800+1000)/18=100

[@abhishekrai9607]

how to get dell1 and dell 2 pls tell

[@ano777g]

how did you get del=18? i got it as 14

[@ss-tp6mz]

@@abhishekrai9607 I solved it 2 years ago, now I don't remember sorry.

[@ano777g]

@@ss-tp6mz oh its okay

[@halaimam4147]

2. Option (b)

[@Rising_sun_408]

2Q. Option B.

[@kirtikansal7388]

a) 1800/18= 100
b) 1/s

[@Azakadune]

Question 2? It’s 1/s. Idk why people saying it’s B, but I know for a fact all (3) loops touch. They share the inner two nodes.

[@DiyExperimento1]

You know the right answer then tell me bro

[@bethel5414]

There’s only two loops in total, not three

[@Abrar_Jamil_4323]

​@@bethel5414 isn't there three loops? I think we all are missing that?
R(s) >node 1>follow the top path>go left using bottom path>go right > go left using bottom path> node 1
So isn't that a loop?
Yoy

[@theone7550]

I had a wrong concept about these, you just helped me to correct it.

[@snehashrivastav1630]

Homework Answers:
Ans 1: 100
Ans 2: Option B

[@PunmasterSTP]

Solved problem 2? More like "These videos are great, through and through!" Thanks again for making and sharing such amazing content.

[@rraghavendra]

1. 100
2. 1/S

[@power4436]

Sir , are you uploading videos for all the syllabus

[@arintiwari3150]

for 1, ans=100
for 2,ans=b option

[@kanpurunplugged9970]

More please

[@ANIMALSBIRDSWORLD.9357]

Really I waiting for this chaneel updated ...when it's come then I will be open must it to see

[@3dgiftz]

Informative video

[@Azakadune]

“It is equal to 2 right?” “No”
Cheeky bugger… my heart dropped lol.

[@mohdfahad4343]

thanks a lot its really been a big help, keep doing...

[@chetan8577]

Plz make a course on DSA using C++

[@LIVE_LIVELY]

Homework Problems Answers
1) 100
2) Option B

[@debolinasardar1438]

For 2nd qs op B but , the value of ∆={(2^4+2.s^2+1)/s^4}, is it ?

[@3dgiftz]

I like EEE but because of this corona situation I wasn't able to join college😔

[@PunmasterSTP]

I am very sorry to hear that, and I hope that you can pursue your studies soon!

[@Rising_sun_408]

1Q. C/R=100

[@mayank.17-n]

100 and 1/S

[@162-gcet-tahamehraj5]

Plzz upload videos more quickly.

[@sanskarkumar6484]

thanks Sir🙏❤

[@prithamaitha4670]

2nd answer option 1

[@saipranathi7206]

1. 900/7
2.B

[@venkatalokesh1117]

I think 1st might be wrong

[@narendrap7437]

Can you tell how it came 1st question answer

[@sahilyadav5662]

both are wrong ....i think

[@nimitgarg2531]

@@venkatalokesh1117 1 st ka answer 100 aa rha h

[@eee_29_rahul49]

For question 2 )
p1=1/S^3 ;p2=1/s
Del1=1 ; del2=1
del=s^2+2 / s2
Since there is one " two non touching loops" L1 L2

[@the_math_tutor]

But the answer is not there

[@cgopalreddychitimi6189]

thereis no non touching loop ans is 1/s

[@sameermeshram3062]

Upload control system more videos

[@arifmp3284]

4:10 there is one more loop right? a-b-c-d-b-a

[@chandangupta4226]

that's what I too think

[@tarunjangam7159]

@@chandangupta4226 b is touching twice

[@simomohamed4191]

that is not a valid route because b appears 2 times

[@kirankumar3768]

There are total 5 individual loops right

[@PunmasterSTP]

How so?

[@nuwanatthanayake]

Great..

[@percy_asaga]

Isn’t there supposed to be a 4th loop with a loop gain of [1/s*6*1/s*(-4)*(-2)]?

[@aaqibrashidle6655]

Yes

[@aneetakushwaha9058]

Ans 1: 1800/11
Ans 2: (s^2+1)/s(s^2+2)
Is it right?

[@sahilyadav5662]

nope both the answers are wrong

[@ginnasomeshwar5068]

@@sahilyadav5662 🤣🤣

[@harshsiddhapura487]

@@sahilyadav5662 400/9 is the answer of first one. Is that correct ?

[@davidtobi4184]

What if we weren't given the graph, just equations

[@sibanshmohapatra1406]

7.15 doubt

[@132saqibmaqbool5]

Can anyone please solve the ∆ in prob 2

[@kalyanigawande4061]

There is fourth loop may be possible.

[@swastikdey7498]

Yes, shouldn't there be a fourth loop ? The gain of which would be (1/s) × (1/s) × -2 × -8 = 16/s^2 ?

[@chandangupta4226]

​@@swastikdey7498there will be a fourth loop but you wrote the wrong gain
it would maybe
(1/s)*6*(1/s)*(-4)*(-2)

[@sameermeshram3062]

Ques. 2) gate 2006, IIT Kharagpur
Ans:- option B = (S2 + 1)/S(S2 + 2)

[@nandyalanaveenreddy7598]

In second home work question can we take a-d-b-c-a as one loop (consider a,b,c,d as nodes from starting)

[@sameermeshram3062]

@@nandyalanaveenreddy7598 Individual loop :- L1= a - b - c -a
L2= b - c - d - b
Then, Compared to both the loops there is b and c are common node ..so hence it is Touching loop and here not any Non - Touching loop present.

[@nandyalanaveenreddy7598]

@@sameermeshram3062 I was asking can we take L3 as a-d-b-c-a as it starts and end at "a" if we can't take it as L3 I want to know reason

[@sameermeshram3062]

@@nandyalanaveenreddy7598 yes, option (a) is correct....L3= a - d - b - c - a also consider... thanks bro

[@nandyalanaveenreddy7598]

@@sameermeshram3062 yeah bro Even I got option A ,do u have any idea when will they provide remaining lectures

[@khookengsuen1428]

6:48 why isn't L1 and L3 two non-touching loops?

[@ginnasomeshwar5068]

Because we removed forward path so the 1 node of L1 was removed
So we didn't take that loop

[@FredsFolly]

I think non-touching refers to not touching the forward path

[@anilmeena7349]

non touching means in any condition they can't share any common node.

[@alinedelacruz8957]

Answer to Question 1 : P1 = 200 Delta 1 = 2
P2 = 400 Delta 2 = 5
Delta = 18
200x2+ 400x5/18 = 2400/18
C(s)/R(s) = 133.33

[@arintiwari3150]

u might have made some mistake

[@sudhanshupatil7439]

p1 is 400 and p2 is 200