I paused the video and tried another method. I noticed x^1/3 so i move 2. To the other side and factored. Got x^1/3(x^2-3) = -2 X^1/3 = -2 X= -8 X^2 -3 = 2 x^2 = 1 X= 1 I know my answer is wrong but can anyone tell me a different way to solve thi aside from themethod shown in this video. Also what might have gone wrong in my calculations.
Substitute when you're not sure how to proceed without substitution and you can see a substitution that makes the problem easier (noticing that both x terms had 1/3 in their exponents' denominators is the key here)
It's just a quadratic equation in disguise. Since you ultimately see two copies of x^(1/3), one of which is squared, you can just substitute a = x^(1/3). This means x^(2/3) is replaced with a^2, and x^(1/3) is replaced with a. Solve for a, and then cube to get the final results.
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He’s The Magician of Comprehension
the way you write on the board is satisfying
I agree! That 💩 is 🔥!
gae
I'm very happy that there are people on Earth who understand and enjoy this type of thing.
We NEED YOU.
Love that method a lot.
Good video, nice to know there are teachers like you!
It was not immediately obvious to me that this is a hidden quadratic.
Very useful! Thank you for sharing!
"Substitution is the Key" was the clue I needed.
x = 1
x = 8
He’s so effective - I get it so easily in one shot !
When I saw your video it's made me to subscribe it❤
I absolutely love this stuff!
Awesome
Awesome!
Putting a variable inside a variable 🤯
This is really interesting! I hope my math teacher won't see this
Short and simple ❤
Best MATHEMATICIAN
Very good
Please write the title of the math problem you are trying to solve.
Your the best math teacher ever
👏
Did it,a bit different,same solutions
Bendiciones por siempre
Your in great shape man!
Excelente
For some reason my inner self said Tritone sub
How 3a could be substituted for 2 if a is x 1/3 wouldn't that mean (a)3 = (x 1/3)3??
Actually got this question in my maths exam😂
I paused the video and tried another method. I noticed x^1/3 so i move 2. To the other side and factored. Got x^1/3(x^2-3) = -2
X^1/3 = -2
X= -8
X^2 -3 = 2
x^2 = 1
X= 1
I know my answer is wrong but can anyone tell me a different way to solve thi aside from themethod shown in this video. Also what might have gone wrong in my calculations.
I think u did it right, u just messed up a step “x^2-3=2” its suppose to equal -2
How did it turn into a quadratic equation. I mean, why is the 1st 'a' squared when a=x?
a is not equal to x. He let a=x^1/3. so then x^2/3 becomes a^2 and the equation is quadratic. Hope that helps.
@mathslove51 ok yh
I realised that when I watched it for the 3rd time
But when to substitute and when not to
Substitute when you're not sure how to proceed without substitution and you can see a substitution that makes the problem easier (noticing that both x terms had 1/3 in their exponents' denominators is the key here)
@@cybersoul3371 thanks
It only comes with practice. There is no hard and far rule for that.
Ta
I would show 8th grade students 2^3.585.
x^2/3-3x^1/3+2=0
x^1/3=y
y^2-3y+2=0
y=[3+-rq(9-8)]/2
y=[3+-1]/2
y1=2 y2=1
x^1/3=2
(x^1/3)^3=2^3
x=8
x^1/3=1
(x^1/3)^3=1^3
x=1
I don't understand line 4
@@noname-ed2un la formula per risolvere le equazioni di grado2
Can you explain a little bit more
Scusi -4ac
I dont understand
It's just a quadratic equation in disguise. Since you ultimately see two copies of x^(1/3), one of which is squared, you can just substitute a = x^(1/3). This means x^(2/3) is replaced with a^2, and x^(1/3) is replaced with a. Solve for a, and then cube to get the final results.
x^⅔-3x^⅓+2=0
(x^⅓)²-3x^⅓+2=0
Let y=x^⅓
y²-3y+2=0
(y-2)(y-1)=0
y-2=0
y=2
x^⅓=2
x=8 ❤
y-1=0
y=1
x^⅓=1
x=1 ❤