Great video, thank you. So basically, if youre quiz asks "what intervals is f(x) is conacave up/down" and they give you a graph of f'(x), just remember that when f'(x) has a negative slope, f(x) is concave down; when it is positive, then f(x) is concave up.
wow this was very helpful, it was very difficult for me to understand this (idk why probably i was making it very complicated in head) after watching this i did got more of a clear understanding (still having troubles, but i manage to pass) thank u a lot this really help :)
I would say be careful saying "decreasing" when you really mean negative. The first derivative test is based on negative and positives. The increasing and decreasing is related to the 2nd derivative. Other than that, good video.
Im confused on why you started in the negative y-axis for the last graph. Since the slope of y' is positive at the beginning shouldn't you start the graph on a positive y value instead of a negative one?
kinda misleading. whether a function is increasing or decreasing has NOTHING to do with its position relative to the x axis. u determine if its increasing or decreasing by looking at the y values
the y of the derivative equals the slope of the original. so if the graph of the derivative below the x axis that means the slope of the original was negative, and same goes for when the derivative graph is above the x axis.
Actually, the derivative of sine x is cosine x , not -cosine x. you drew the graph correctly but stated it wrongly ......the derivative of cosine x is actually -sine x, but the verse is not true.
He stated it correctly. He drew the graph of -cos(x) given sin(x) because he was graphing the antiderivative, not the derivative. It's similar to thinking: "The derivative of ___ will produce sin(x)?" And the answer is -cos(x). He stated, quote: "The derivative of -cos(x) gives sine" and that is true.
Finally a video that's not with a straight line as the derivative -_-
Great video, thank you. So basically, if youre quiz asks "what intervals is f(x) is conacave up/down" and they give you a graph of f'(x), just remember that when f'(x) has a negative slope, f(x) is concave down; when it is positive, then f(x) is concave up.
Guys he did it right, just stated it wrongly :) The original function is -cosine x so the derivative is sinx
wow this was very helpful, it was very difficult for me to understand this (idk why probably i was making it very complicated in head) after watching this i did got more of a clear understanding (still having troubles, but i manage to pass) thank u a lot this really help :)
I would say be careful saying "decreasing" when you really mean negative. The first derivative test is based on negative and positives. The increasing and decreasing is related to the 2nd derivative. Other than that, good video.
Thank you for this video! Have a Calc Exam tomorrow
LOL watching this for 137
A version with the 2nd derivative would be nice
You can do it, by finding the first derivative and working in from there
OMG. You don't know how much this video helped me. Thank you sooooooo much!!!!!
Im confused on why you started in the negative y-axis for the last graph. Since the slope of y' is positive at the beginning shouldn't you start the graph on a positive y value instead of a negative one?
THUS HELPED A LOT! MY EXAM IS IN 2 HOURS! Wish me luck.
have you passed that exam?
Did you pass that exam?
Soo what happened.........
"aboot" literally my favorite accent
Bro, you are a máster, loved this
Actually u can't find the function as there would be infinite solutions... U just know general shape of the curve 😅
He is correct:
The Original function is -cosx
- d/dx[cosx] = - (-sinx)= sinx ✔️✔️
that difference in cos(x) has arose due to addition of any constant c bcoz when constant is added to some function it shifts towards right dude
I committed a bit error there that the graph shifts right when any constant is subtracted not when it is added
I committed a bit error there that the graph shifts right when any constant is subtracted not when it is added
ayo thank you i’m boutta take a test
same man
How’d it go
strawhelyperfectx 85 on an AP class test not too bad lol
@@strawhelyperfectx i got a 92 i’m content ✨
ruclips.net/video/XPCgGT9BlrQ/видео.html 💐
Just finished my AP calc ab exam reviewing everything I forgot lol
it is not clear for me, sir, you skip many steps for some reason, please fix it
Misusing the term "inflection" in first example.
ruclips.net/video/XPCgGT9BlrQ/видео.html 💐
I RECOGNIZE THIS VOICE FROM CHEM
Sounds like Chemist Nate😊
Thank you sooo so much! 💕
Karie Janet fr tho, this helped a lot
this shit is so fucking hard. harder than formal defn of a limit.
kinda misleading. whether a function is increasing or decreasing has NOTHING to do with its position relative to the x axis. u determine if its increasing or decreasing by looking at the y values
the y of the derivative equals the slope of the original. so if the graph of the derivative below the x axis that means the slope of the original was negative, and same goes for when the derivative graph is above the x axis.
ruclips.net/video/XPCgGT9BlrQ/видео.html 💐
2:40-2:52
Wait I have a question isn't the minimum in the first function also an inflection point?
ruclips.net/video/XPCgGT9BlrQ/видео.html 💐
Actually, the derivative of sine x is cosine x , not -cosine x.
you drew the graph correctly but stated it wrongly
......the derivative of cosine x is actually -sine x, but the verse is not true.
Moustafa Mohamed wrong
Sure? Revise your calculus book.
math.com
He stated it correctly. He drew the graph of -cos(x) given sin(x) because he was graphing the antiderivative, not the derivative. It's similar to thinking: "The derivative of ___ will produce sin(x)?" And the answer is -cos(x). He stated, quote: "The derivative of -cos(x) gives sine" and that is true.
thanak u
here f'(x)=sin x so f(x)=cos x not -cos x
here f(x) =cos(x) +c more precisely
Do you know calculus?