Hi, just wanted to mention that I myself am an instructor in an completely different subject for 9 years. and you're really one of the best teachers I've ever seen. Cheers
Awesome videos! at 4:22 you mention that the F perpendicular has no effect because this example is not including friction. I think it would have been worth while to mention that in a real life situation the Force of friction would have been reduced by the perpendicular force, and would have affected the total distance travelled by conserving some of the energy.
Hey! I think it might be a silly question, but I have a problem understanding the case where the cart is initially going to the left and is then subject to a force that pulls it to the right. In this case, the cart's displacement is to the right and the force is to the right so why is work negative? In my opinion the cart, should have continued with a decreasing speed to the left, till v=0 (then work0. No?
what about when the velocity is constant? how to measure work and kinetic energy and power of a mass that is having constant velocity (same velocity while initial and final)? thank you very much! (i like a lot your videos)
we can have work with constant velocity in these contexts: - where there is some friction involved, - where there is some climbing involved., - where there is a mixture from the two above.
![What is Kinetic Energy & Work-Energy Theorem in Physics? - [1-8]](http://i.ytimg.com/vi/oQhVituqavM/mqdefault.jpg)
Hi, just wanted to mention that I myself am an instructor in an completely different subject for 9 years. and you're really one of the best teachers I've ever seen.
Cheers
Love the overdub.
Good Job Bozeman, this video is much clearer than others I have seen on the same topic. I enjoyed the questionnaire at the end.
Awesome videos! at 4:22 you mention that the F perpendicular has no effect because this example is not including friction. I think it would have been worth while to mention that in a real life situation the Force of friction would have been reduced by the perpendicular force, and would have affected the total distance travelled by conserving some of the energy.
Thank you for this amazing lesson, sir! All the best.
Thank you so much sir. You helped us to recover our lack of knowledge.
I wish I found you earlier ;-;
Thank You.🍎
The classes are so helpful.🐝
best video explanation on this topic
Thank you very much for the Thai subtitles
Thank you so much, your explanation are so intelligible
Very helpful, thank you very much for making this video!
plz will you explain the proof of that theorem using derivative..?
Asanti sana kwa hii vidaa👍
What if w is zero and k.e changes
Hey!
I think it might be a silly question, but I have a problem understanding the case where the cart is initially going to the left and is then subject to a force that pulls it to the right. In this case, the cart's displacement is to the right and the force is to the right so why is work negative?
In my opinion the cart, should have continued with a decreasing speed to the left, till v=0 (then work0. No?
+Hermione Granger I dont think you're hermoine. 10 points for slytherin!!!
+Michael Negussie Boii I know you aint talkin with yo Goofy Goober Lookin Ass, looking like a Giraffe with no head ass boii.
Absolute legend
what about when the velocity is constant? how to measure work and kinetic energy and power of a mass that is having constant velocity (same velocity while initial and final)? thank you very much! (i like a lot your videos)
we can have work with constant velocity in these contexts:
- where there is some friction involved,
- where there is some climbing involved.,
- where there is a mixture from the two above.
6:54 Lol
Appreciate that.
SALEM PHYSICS BABY WHOOOOOO MR ANDERSON DONT EVEN COME CLOSE TO MY BOI WINTERER
Thanks
thank you!
Thanks! :)
nice sir
Lmao the dircetional motion is cos32 * 9.6
what exactly is energy?
Eww… fix the greenscreen, man.