Integral of sqrt(1 - sin 2x)
HTML-код
- Опубликовано: 7 фев 2025
- In this video we will solve integral of sqrt(1 - sin 2x) w.r.t x by using simple trigonometry identities. To solve this, first we will have to get rid of the square root. To do that, we have to convert 1 - sin 2x into a perfect square.
Following is the URL of the video explaining the derivation of trigonometric identity sin 2x = 2sin x cos x
• sin 2x | sin(2x) | Ide...
Other topics for the video are:
Integral of square root of 1 - sin 2x
What is the integral of sqrt(1 - sin 2x)?
How to find integral of sqrt(1 - sin 2x)?
How to evaluate integral of sqrt(1 - sin 2x)?
You can email me at raviranjans@gmail.com
You can follow me on facebook. My facebook account is / raviranjankumarsingh.73
أنا عربي لم افهم اللغة لكني فهمت من الخطوات شكراً ❤
I am an Arab. I did not understand the language, but I understood from the steps. Thank you
You are welcome!
Shouldn't the answer be like
(Sinx + cosx)sgn(cosx - sinx) + c
As the √(sinx-cosx)² opens up with a mod sign
True ... We r among the few who know this
@@trueblood541 us bro us🤜🤛🏽
Can you please explain how?
I understood the answer but didn't understand the way of representing the answer.
Why you have written sgn b/w both the answers?
@@approxy..Yes same doubt please tell
What if sinx>cosx ???
That is why solution is wrong and we will take signum function
How can you open sinx -cosx) ^2 under the root as sinx -cosx
It will open with |sinx -cosx| and then the right answer will be sinx +cosx)sgn(cosx-sinx) 🎉🎉
Sir sin^2 x + cos^2 x - 2sinx cosx can also be written as (sinx - cosx)^2 and in that case ans is coming negative of ur answer
Basically the answer is absolute of cos x + sin x.
Answer has to be positive.
طلاب السادس عود هم موجودين هنا
sir in the identity part...instead of cosx-sinx sinx -cosx if we do anwer is coming -ainx-cos x....since its square root we can write as (cox-sinx)^2 or (sinx-cosx)^2...both correct rigth??? but ans is coming diff
Yes. The answer is basically absolute value of cos x - sin x.
Okay 👍🏻👍🏻
@@SonuNigam-bw5tb Thank you!
Sir if we use tan expansion of sin2x formula then i'm getting diffrent answer. please explain why???
Actually answer is |cos x + sin x| + C
If you are using tan x expansion then the integrand must be inform of square root of (((1 - tan x)^2)/sec^2 x)
You can change it to square root of (((tan x - 1)^2)/sec^2 x)
As
(1 - tan x)^2 = (tan x - 1)^2
You will get same answer as I got.
in many questions You can get different types of answer with different methods
@@nimish6762 No, answer is same |cos x + sin x| + C
if we solve by taking sinx-cosx then shall we get the same marks in the exam???
No
@@marrryam5845 My exams got over very earlier 😁 .... But thanks I will keep it in my mind.
😂
Thx sir -from Iraq
You are welcome!
भगवान आपको हमेशा खुश रखे।
Thank you and same for you!
Thanks for your solution
I m very glad ....🤗
You are welcome!. May God give you lots of happiness!
Tq so much sir ❤️ love from karnataka
You are welcome!
Why can't we take (sinx-cosx)whole squared instead of (cosx-sinx) whole squared
Of course you can take.
Sir you should have written mod of cosx - sinx and not just cosx - sinx.
Yes.
@@RaviRanjanKumarSingh sir so will that affect the answer. I think it will add something
@@atharvabane3124 Sorry! In haste I made the above comment.
The answer is abs(cos x - sin x) + C.
great .. brief and efficient
Marvellous explaination 😊😇.....
Thank you!
Sir what abt 1/underoot 1-sin2x ?
Thanks🙏🙏🙏🙏🙏🙏
You are welcome!
What'd be the answer if it was int 1√(1-sin2x) dx...
Is this int 1/√(1-sin2x) dx
Guys help me plz -2sinxcosx is replaced by what coz l won't see it at the end of solution
Why cosx-sin x whole square why not sinx-cosx whole square???
just to get positive result
basically it should have been mod
@@RaviRanjanKumarSingh if we make it (sinx-cosx)^2 then the result will be {-cosx-sinx+c}
@@fardinnihal2283 the result is an absolute value of cos x + sin x
Bro actual me √(x²) = |x| , hota hai, aur mod hamesha hi positive hota hai, isliye mod ko hatane ke liye pahle se hi positive value le lene se mod nahi lagana padta
Thanks sir.
You are welcome!
Thanks sir lots of love and Reception for you.
Thnks good explanation
Good method 👍
Thank you!
thank you 💓
You are welcome!
Thank you good explanation
You are welcome!
Bro mod bhi toh lena padta hai😶
Root se nhikalne ke baad
Imdefinite me nhi
Pls can u make a video on moment of inertia
May be some day. But not now.
Ok sir thanks
@@yafoelise4241 You are welcome!
Why not sinx-cosx
Just to avoid negative sign. The answer is abs(cos x - sin x) + C.
What if 2x_2cos.cosx
This is no mathematics
Thank you, sir.🙏
You are welcome!
Correct answer is -cosx - sinx +c
where is mod
@@gopalkrishan3997 Yes it should have
Wrong
اصعب شي تكامل الدوال المثلثية
I didn't get you. Please write in English.
@@RaviRanjanKumarSinghmy bad I was talking to my friend who will going to see this video. And thanks you for teaching us science that teachers couldn't teach it to us
@@alhaji1595 You are welcome!
It is wrong solution
Can check the answer in the respective first book also
Mod ko kha gya kya
🤬#&$@®•
Thank you sir
You are welcome!
Why not sinx-cosx
Yes you can go with it.
@@RaviRanjanKumarSingh but then sign will be different
-cosx-sinx+c would be the answer
@@beautytiwari8339 The actual answer is |sin x + cos x| + C
@@RaviRanjanKumarSingh oh kay got it 👍 square root always gives mod 👍👍