Thanks for sharing this information. Though it has a mistake in estimating the electronegativity of the O atom, it is useful collectively (with queries asked by viewers).
Why are you using the first ionization energy of Oxigen if in AgO? If you had Ag2O, Should you use the second ionization energy for Oxigen and the first ionization energy for Silver? Do you have any references I can check? Thanks in advance.
Your method is full of errors. This is not how we calculate the electronegativity of the compound. It is the geometric mean of the electronegativities for individual elements but not the arethmetic mean.
Thanks for sharing this information. Though it has a mistake in estimating the electronegativity of the O atom, it is useful collectively (with queries asked by viewers).
To calculate the electronegativity of Oxygen you selected the wrong columns. Please check and let us know.
Why are you using the first ionization energy of Oxigen if in AgO?
If you had Ag2O, Should you use the second ionization energy for Oxigen and the first ionization energy for Silver?
Do you have any references I can check?
Thanks in advance.
Sir what is 4.5 used in conduction band edge formula ....kindly reply it's urgent sir
I have the same doubt
Ee = 4.50 eV is the energy of free electrons on the hydrogen scale
Sir electronegativity of oxygen is 3.44
But u had taken 4. 44 why??
what if we are using Sr0.5Ti0.5O3
what is 96.48?
you have put electronegativity of both O and Ag equal, why?
I think it was just a mistake.
Your method is full of errors. This is not how we calculate the electronegativity of the compound. It is the geometric mean of the electronegativities for individual elements but not the arethmetic mean.