As this video is a bit longer than usual, so I would encourage you all to use the time-stamps given in the description for the different topics covered in the video.
This is the EXPLANATION of the Physics and mathematics 2 year Associate in Science degree in Electrical / Electronics engineering students do not learn. Thank You for this LECTURE.
summary: RC becomes dv/dt *C +Vc/(RC) = 0, which simplifies to Vc(t) = Ae^(-t/(RC)), where V(0) = A so Vc(t) = Ve^(-t/(RC)) -> Voltage decreases from positive towards 0 exponentially within 5 RC time constant, while Current increases from negative towards 0 RL become di/dt+ R/L*i = 0, which is I*e^(-Rt/L), or, V/R-V/R... -> Voltage increases from 0 and reaches a value within 5 time constant
Great video! Just one question, I couldn't hear clearly when it was mentioned what Q = V/L was (during the force response of RL circuit). Anyone knows what was said?
What you are saying is true when the input is a sinusoidal signal. For DC, in steady state, the reactance of the capacitance will be infinite and will act as an open circuit. Therefore, the entire voltage will appear across the capacitor. Or in other words, the capacitor will charge up to voltage V. Therefore, at t=0-, Vc = V. I hope it will clear your doubt.
For finding the Req, we are actually finding the Thevenin's equivalent impedance seen through the capacitor. So, all the independent sources will be considered zero. That means R1 will get short-circuited. Hence, Req= R2|| R3. I hope it will clear your doubt.
@@preethishivani1567 and have you gone through the thevenin's theorem? I think you should go and revisit the topic then come back. You'll understand why we shorr circuited the system
In RLC cirtuits there are cases like under damped, critically damped and over damped. In RL or RC circuit can we consider something similar ? like all circuits are either over damped or citically damped ?
If an initially charged inductor current is given say 1amp and it is connected directly to a voltage and resistor of 1v and 1 ohm respectively,how do u know if inductor gets charged or discharged.im getting wrong answer
Thank you so much for posting these videos Sir. They really help us a lot but can you provide a pdf link to some selected questions in the description, cause we can start practicing after seeing the video.
Dear Sandeep, I have already made a video on the solved problems for RL and RC circuit. In which I have also given pdf file link in the description for problems, which you can practice on your own. Here I am providing the link for the same. ruclips.net/video/zDcXt9Vx34o/видео.html I hope, it will help you.
For a series RL circuit supplied from a voltage source, discuss in details how the resistance affects the circuit current response. Support your discussion with numerical illustrations (both equations and plots) assuming inductance of 0.5 H and supply voltage of 100 V. Use suitable values of R (on your choice)
Is shortcut method is helpful for all kind of circuit like source free circuit, forced circuit? And is this applicable to any time like t=0, t= infinity?
It can be used for first order RC and RL circuit. Many examples have been solved based on that. Please check the network analysis playlist on the channel. You will get it.
To find the equivalent resistance, we have assumed all the independent sources in the circuit as zero. So, V1 got short-circuited. It means it has zero resistance. R1 is connected in parallel to the short circuit. When you connect any resistance in parallel to a zero-ohm resistor (or short circuit), the equivalent resistance will be zero. So, R1 will get vanished from the equivalent circuit. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS sir I noticed that You have taken independent voltage source as a short circuit in this video and independent current source as a open circuit in the next video. Can you please explain it why did used them or are those the basic methods to find thevinan's equivalent resistance?
Sir, here at 22.00 you have discussed shortcut method. I need to know that how could we reach to the general equation. V =Vfinal+(initial-final) e^-t/T
the solution of the differential equation consists of two parts. The complementary function and the particular integral. The complementary function gives the transient response while the P.I gives the steady-state output. The equation V = Vfinal + (Vintial - final)e^(-t/T), represents the same thing. In short, it is the shortcut way to find the output for thefirst-orderr circuits.
It will act as an active element. But at time t=0+, the direction of the current will remain the same. So, if you see the polarity of the voltages, it will as shown in the diagram. And if you apply the KVL, it will be Vr + VL = 0. I hope it will clear your doubt.
Could you pls explain the Ex taken @6.56: if cap to be discharged at 5uS ; whose required cap is 1nF with 1K ohm resistor ; but what is voltage rating of capacitor since our equation is VC(t)=Ve-(t/RC) ? and what if Cap voltage is increased to some level with 1nF( example) , does discharge time also increases? , pls explain with example
with the given values of R and C, the required time for charging and discharging will remain the same. e.g if the supply voltage to the RC circuit is 1V in one case and 3V in second case, then the required time to charge the capacitor will remain the same. The thing is, in case of the 3V the current in the RC circuit is more. So, although it appears, it requires more time, but it will take the same time. I hope it will clear your doubt. If you still have any doubt, then do let me know here.
hi, very nice ! what i dont get is that (in vc transint without source ) if the current starts going from positive to negative then we get from kirchoff voltage law that vc - vR = 0 . (not vc+vR = 0 )
The thing is during the analysis, you just assume that the current is flowing in specific direction. And after the circuit analysis, if you get the negative value of current, then it simply means that the current is flowing in the opposite direction. So, here in the source free response, since the current was flowing in the clockwise direction at t=0-, so it has been assumed that, at t=0+ also, it will flow in the same direction. But here, we will get the negative value of current. It means that, the current is flowing in the opposite direction. So, both ways, you will get the correct result. I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS I'm not quite sure.. It works in other occasions but here when I perform the analysis I get vc= ve^(t/τ) instead of of ve^(-t/τ). I'm not really sure, maybe I'll get it as is because my exam period starts at the end of this week. Your series was so helpfull
@@NikhilKumar-jq5fk but what's the reason? Is it because the current tends to take the path of least resistance so it ignores the R in parallel to the short circuit?
To find the Thevenin's equivalent resistance, all the independent sources should be first made zero. So, voltage source will act as short circuited. (That means the its equivalent resistance is zero). And as R1 is in parallel with this voltage source (which is now acting as short circuit), so effectively it will also get short circuited. I hope it will clear your doubt.
Yes, for AC source the response of the circuit will be different. For AC sinusoidal signal, in steady state, the voltage and current across linear elements (R, C and L) will also be sinusoidal but has different amplitude and the different phase. Such analysis is known as the sinusoidal steady-state analysis. Again for more information, you can check my video on phasor diagram of RL, RC and RLC circuits. And still, if you have any doubt then do let me know here.
Here we are talking about the transients. And t=0+ is the time, just the switch is turned off. And that time, capacitor opposes the instantaneous change of voltage. So, the voltage across the capacitor will be the V volt. But eventually, this charge across the capacitor will be get discharged through a resistor. And it is visible in the discharging curve. (at 6:00) I hope it will clear your doubts.
Transient represents the change in the steady-state condition of the circuit (Voltage and current). So, it could be when you suddenly apply the voltage or current to the circuit or suddenly remove the source. Or it could be when you change the voltage or current suddenly in the circuit. And sometimes if you introduce new circuit components or remove some portion of the circuit suddenly from the existing circuit, that will also change the voltage or current. So, in short as transient of the circuit represents the sudden change of voltage or current in the circuit, a source has to be there in transient questions. I hope it will clear your doubt.
There is a separate video on the solved examples and few examples for the practice is also given in the description of that video. Please check that video. Here is the link: ruclips.net/video/zDcXt9Vx34o/видео.html
For clearing Concepts, network analysis by Van Valkenburg is a good book. If you want more solved examples for practice then that point of view Network Analysis and synthesis by Ravish R Singh is a good book.
To find R (equivalent) Thevenin's equivalent resistance has been found. And for that, the voltage source is short-circuited. (All the independent sources should be zero). As R1 is in parallel with the voltage source, it will also get short-circuited. Hence R1 is also 0.
For that circuit, let's say we want to find the voltage across the capacitor. Now, initially, the capacitor is fully discharged. So, Vc(0+)=0, and in steady-state or at t= infinity voltage will be R3*V/(R3+R2). And let's say it as Vx. Equivalent resistance for the RC time constant has already been found. Req= R2||R3 So, equation for capacitor voltage will be, Vc(t)= Vx -Vx*e^(-t/ReqC) Where Req= R2||R3 and Vx= R3/(R2+R3) I hope its clear to you.
Definitely helped! You’ve summarized 2 hours of tedious (back and forth) lecturing into 20 minutes!Thank you!
As this video is a bit longer than usual, so I would encourage you all to use the time-stamps given in the description for the different topics covered in the video.
I need notes for transient analysis,do you have notes?i badly need them so can you please?
My man i wouldn't have done half of my exams without an indian teacher expaining it on youtube, you're a life saver
Casually explaining in 30 minutes what my professor utterly fails to explain in 3 months.
Lol😂
😂😂😂😂😂😂😂😂😂😂😂😂😂
same😂
syllabus kaise pura hota hai bhai tumhara?
You mean to say that your lecturer spent 3 months just to teach this particular topic. 🙄
Thanks a lot...what my lecturer couldn't teach in 4 months, you taught me in half hour
👍🏻👍🏻
You mean to say that your lecturer spent 4 months just to teach this particular topic. 🙄
@@kapilumrania 😅
🙄🙄
It is all about listening
You have done the best possible task by explaining this it covers my total portion of 20 marks from 100
This is the EXPLANATION of the Physics and mathematics 2 year Associate in Science degree in Electrical / Electronics engineering students do not learn. Thank You for this LECTURE.
You are very genius and intelligent, thank you for your good work.
i have no words to appreciate your excellence in teaching!👌👌 this video literally saved me
Another excellent video, thank you for doing this on your own time. You must be very motivated.
Thank You Very much.
I was getting too much problems to understand this, but now it is totally clear for me.
Thankyou SOOO much!!! Please make more videos for EEE students of higher sem also...You are amazing!!
SLOW AND SPEEEDY WINS THE RACE..TIME LENGTH IS GOOD AND SUITABLE..IT IS CONCEPTUAL..
I GOT HELP FOR PSC EXAMES..THANX ALOT
Great job! It is much better than our lecturer's explainings.
You tube is better than school. thank you
You are understanding in very easy method thanks 👍
summary:
RC becomes dv/dt *C +Vc/(RC) = 0, which simplifies to Vc(t) = Ae^(-t/(RC)), where V(0) = A so Vc(t) = Ve^(-t/(RC))
-> Voltage decreases from positive towards 0 exponentially within 5 RC time constant, while Current increases from negative towards 0
RL become di/dt+ R/L*i = 0, which is I*e^(-Rt/L), or, V/R-V/R...
-> Voltage increases from 0 and reaches a value within 5 time constant
You are really talented guy upload video based on electrical subjects
This helped incredibly... thank you
Explained better than my online teacher
What an explanation truly commendable ❤️❤️
Thank you so much for such a simple solution for this topic
wow... you really explained this in a way were i finally understood it...
Nice video super sir 👌👌👌👌
Great video! Just one question, I couldn't hear clearly when it was mentioned what Q = V/L was (during the force response of RL circuit). Anyone knows what was said?
U explained very well sir i can understand easily thank u so much sir
Really helped a lot in exam preparation
You are better than my professor
Super super super super sir what a explain thanks a lot sir
Please upload some more problems and on Fourier series problems in these circuits
Sir how at t = 0- , Vc = V ?
The resistor and capacitor are in series so there will be voltage division.
Sir, please explain. 1:56
What you are saying is true when the input is a sinusoidal signal. For DC, in steady state, the reactance of the capacitance will be infinite and will act as an open circuit. Therefore, the entire voltage will appear across the capacitor. Or in other words, the capacitor will charge up to voltage V. Therefore, at t=0-, Vc = V.
I hope it will clear your doubt.
This was a huge help! Thanks!
Sir, at 2:39, why should Vc goes to zero? is it because it's source free? So, if it there was source of voltage V1, will at t=infinty, V=V1?
Yes, that's true. I have already covered it at 12:19.
How did you find Rthevenin? How can you tell R2 is parallel to R3? (they don't seem to share the same 2 nodes)
Same doubt
Same doubt
Extremely well made. Thank you so much!!
Thanks so much for such a great explanation!
One question: in the >1 Resistor part: what happened to R1 in your Req analysis?
By the way: BRILLIANT Explanation, thank you so much!
For finding the Req, we are actually finding the Thevenin's equivalent impedance seen through the capacitor.
So, all the independent sources will be considered zero. That means R1 will get short-circuited.
Hence, Req= R2|| R3.
I hope it will clear your doubt.
i still didnt understand why r1 got short-circuited
@@preethishivani1567 and have you gone through the thevenin's theorem? I think you should go and revisit the topic then come back. You'll understand why we shorr circuited the system
Very strong explanations 👍
In RLC cirtuits there are cases like under damped, critically damped and over damped. In RL or RC circuit can we consider something similar ? like all circuits are either over damped or citically damped ?
Best video to clear my concept of rl and rc bcuz i searched for about a day in books and ask my teacher but nothing worked
If an initially charged inductor current is given say 1amp and it is connected directly to a voltage and resistor of 1v and 1 ohm respectively,how do u know if inductor gets charged or discharged.im getting wrong answer
Thank you so much for posting these videos Sir. They really help us a lot but can you provide a pdf link to some selected questions in the description, cause we can start practicing after seeing the video.
Dear Sandeep, I have already made a video on the solved problems for RL and RC circuit. In which I have also given pdf file link in the description for problems, which you can practice on your own.
Here I am providing the link for the same.
ruclips.net/video/zDcXt9Vx34o/видео.html
I hope, it will help you.
Thank you for the video.
thanku sir i really understand the concept of Rc and RL circuit gd job sir...keep it up
For a series RL circuit supplied from a voltage source, discuss in details how the resistance affects the circuit current response. Support your discussion with numerical illustrations (both equations and plots) assuming inductance of 0.5 H and supply voltage of 100 V. Use suitable values of R (on your choice)
Is shortcut method is helpful for all kind of circuit like source free circuit, forced circuit?
And is this applicable to any time like t=0, t= infinity?
It can be used for first order RC and RL circuit. Many examples have been solved based on that. Please check the network analysis playlist on the channel. You will get it.
@@ALLABOUTELECTRONICS k brother
Class was fantastic
Is charging time and discharging time same for a battery?.....coz both are 5RC
Plz help this one out.....
Sir please explain us in the last part of this video how the resistance R1 get short circuited
To find the equivalent resistance, we have assumed all the independent sources in the circuit as zero. So, V1 got short-circuited. It means it has zero resistance. R1 is connected in parallel to the short circuit. When you connect any resistance in parallel to a zero-ohm resistor (or short circuit), the equivalent resistance will be zero. So, R1 will get vanished from the equivalent circuit.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS sir I noticed that You have taken independent voltage source as a short circuit in this video and independent current source as a open circuit in the next video. Can you please explain it why did used them or are those the basic methods to find thevinan's equivalent resistance?
Thank u so much ...it is very helpful ....shortcut method is queit easy to remember😇😊😊
The video is about 30 minutes but it tooks 2 hours for me to understand the concept
Thank you very much it helped me a lot
Sir, here at 22.00 you have discussed shortcut method. I need to know that how could we reach to the general equation.
V =Vfinal+(initial-final) e^-t/T
the solution of the differential equation consists of two parts. The complementary function and the particular integral.
The complementary function gives the transient response while the P.I gives the steady-state output. The equation V = Vfinal + (Vintial - final)e^(-t/T), represents the same thing.
In short, it is the shortcut way to find the output for thefirst-orderr circuits.
Why is the particular integral equal to Vc when t goes to infinity?
Awesome explanation
This is an excellent video It helped me a lot
But during source free responce inductor is acting like an active element so we write vl=vr but you wrote vl+vr=0 ?
It will act as an active element. But at time t=0+, the direction of the current will remain the same. So, if you see the polarity of the voltages, it will as shown in the diagram. And if you apply the KVL, it will be Vr + VL = 0.
I hope it will clear your doubt.
Could you pls explain the Ex taken @6.56: if cap to be discharged at 5uS ; whose required cap is 1nF with 1K ohm resistor ; but what is voltage rating of capacitor since our equation is VC(t)=Ve-(t/RC) ? and what if Cap voltage is increased to some level with 1nF( example) , does discharge time also increases? , pls explain with example
with the given values of R and C, the required time for charging and discharging will remain the same.
e.g if the supply voltage to the RC circuit is 1V in one case and 3V in second case, then the required time to charge the capacitor will remain the same.
The thing is, in case of the 3V the current in the RC circuit is more. So, although it appears, it requires more time, but it will take the same time.
I hope it will clear your doubt. If you still have any doubt, then do let me know here.
can you please tell me the name of the book which you follow ...please
Very well explained..... thanks brother
Sir please do a video on three phase circuits,pleasee...I love your videos,they are very helpful for my exams, thank you sir for all your efforts
Great job... Loved it...
What a good video. Thank you very much
You are a hero man!!! ❤🔥
You are a hero!
hi, very nice ! what i dont get is that (in vc transint without source ) if the current starts going from positive to negative then we get from kirchoff voltage law that vc - vR = 0 . (not vc+vR = 0 )
The thing is during the analysis, you just assume that the current is flowing in specific direction. And after the circuit analysis, if you get the negative value of current, then it simply means that the current is flowing in the opposite direction. So, here in the source free response, since the current was flowing in the clockwise direction at t=0-, so it has been assumed that, at t=0+ also, it will flow in the same direction. But here, we will get the negative value of current. It means that, the current is flowing in the opposite direction. So, both ways, you will get the correct result. I hope, it will clear your doubt.
@@ALLABOUTELECTRONICS I'm not quite sure.. It works in other occasions but here when I perform the analysis I get vc= ve^(t/τ) instead of of ve^(-t/τ). I'm not really sure, maybe I'll get it as is because my exam period starts at the end of this week. Your series was so helpfull
2.54 appling kvl, why does not V =iR?, voltage difference between resistor is V, isn't it?
Vr is the voltage drop across the resistor. And Vr = I*R.
Sir... what is the equation di/dt + p = Q mean...????
Wonderful explanation
Thank you life saver ! Your channel is awesome.
Very helpful, thank you very much !
Wow this video helped me a lot! I just have 1 question, at 25:10, why does R1 get short circuited?
I think
When voltage is short-circuited Resistance parallel to that voltage must be neglected,
So R1 is neglected there
@@NikhilKumar-jq5fk but what's the reason? Is it because the current tends to take the path of least resistance so it ignores the R in parallel to the short circuit?
To find the Thevenin's equivalent resistance, all the independent sources should be first made zero. So, voltage source will act as short circuited. (That means the its equivalent resistance is zero). And as R1 is in parallel with this voltage source (which is now acting as short circuit), so effectively it will also get short circuited.
I hope it will clear your doubt.
@ALLABOUTELECTRONICS thank you for the explanation about short corcuit in thevinin theorem😊
sir, plz explain how did u get that eq at 22:26
I have one question there is any difference between AC source and DC source on RC and RL circuit, please answer me withdrawing
Yes, for AC source the response of the circuit will be different. For AC sinusoidal signal, in steady state, the voltage and current across linear elements (R, C and L) will also be sinusoidal but has different amplitude and the different phase. Such analysis is known as the sinusoidal steady-state analysis.
Again for more information, you can check my video on phasor diagram of RL, RC and RLC circuits.
And still, if you have any doubt then do let me know here.
no so good but its nice for me
At t=0 voltage across c shouldn't be V as it is in series with a resistance ...so voltage should be distributed in C and R as well
Here we are talking about the transients. And t=0+ is the time, just the switch is turned off. And that time, capacitor opposes the instantaneous change of voltage. So, the voltage across the capacitor will be the V volt. But eventually, this charge across the capacitor will be get discharged through a resistor. And it is visible in the discharging curve. (at 6:00)
I hope it will clear your doubts.
@@ALLABOUTELECTRONICS thank you i had the same doubt
You have done an amazing job bro ........ Keep it up
sir . where are you from ????
please can you explain why at infinity capacitor is open and inductor is short?
I have already explained it in the separate video.
Here is the link:
ruclips.net/video/3YinmbkU0DE/видео.html
Excellent video. Sir can I be able to consult you if I have some problems which I'm unable to solve
Yes.
How can I reach you?
Can I get your email or whatsapp number?
You can mail me. You will find the email in the about section of the channel.
@@ALLABOUTELECTRONICS I don't find it, can you share it here via comment
Thank you sir . You helped me so much
Why is R1 also short circuited can someone answer.
وربي انك اسطورة يا صديق
Is this the same as time-domain analysis for the first order?
Yes.
Sir why do we add a current or voltage source while solving transient Questions
Transient represents the change in the steady-state condition of the circuit (Voltage and current). So, it could be when you suddenly apply the voltage or current to the circuit or suddenly remove the source. Or it could be when you change the voltage or current suddenly in the circuit. And sometimes if you introduce new circuit components or remove some portion of the circuit suddenly from the existing circuit, that will also change the voltage or current. So, in short as transient of the circuit represents the sudden change of voltage or current in the circuit, a source has to be there in transient questions.
I hope it will clear your doubt.
Where can I find the examples solved based on this concept? .. Plz help 😅
There is a separate video on the solved examples and few examples for the practice is also given in the description of that video.
Please check that video.
Here is the link:
ruclips.net/video/zDcXt9Vx34o/видео.html
Sir did you use the linear DE?
Nice Presentation,, Excellent!!!
I am a neet aspirant and here to understand basics ,let's see if it's beneficial,ik it's not meant for us
yeh makes sense
Thanks ❤️
Isnt Ae^-t/tau the formula for ic(t)
Which is best book for circuit analysis
For clearing Concepts, network analysis by Van Valkenburg is a good book.
If you want more solved examples for practice then that point of view Network Analysis and synthesis by Ravish R Singh is a good book.
5:58 is that a belch in the background?
😂😂😂😂😂😂😂😂😂
It's like he took roasted groundnuts before making the video 😂😂😂😂😂
Great
Helped a lot.Thanks
In the last for finding R (equivalent) , why R1 is short circuited..anyone explain..
To find R (equivalent) Thevenin's equivalent resistance has been found. And for that, the voltage source is short-circuited. (All the independent sources should be zero). As R1 is in parallel with the voltage source, it will also get short-circuited. Hence R1 is also 0.
@@ALLABOUTELECTRONICS Thanks a lot , sir...
sir pls tell me why r1 is short circuit
thank you so much sir, this topic was a big burden but thanks to your teaching, it's all clear :) god bless you
any transcript available?
what happened to r1 resistance in calculating thevenins resistance
It was short circuited so it does not contribute to equivalent resistance
Is this for dipolma students??
Yes, it will be helpful to them as well.
very nice explanation .. can you give the answer of circuit made in the last where more than one resistor was connected
For that circuit, let's say we want to find the voltage across the capacitor. Now, initially, the capacitor is fully discharged. So, Vc(0+)=0, and in steady-state or at t= infinity voltage will be R3*V/(R3+R2). And let's say it as Vx.
Equivalent resistance for the RC time constant has already been found. Req= R2||R3
So, equation for capacitor voltage will be, Vc(t)= Vx -Vx*e^(-t/ReqC)
Where Req= R2||R3 and Vx= R3/(R2+R3)
I hope its clear to you.
17:05 how did he get any of those numbers...
By putting the value of t= RC, 2RC, 3RC and so on in the equation, you will get those numbers