I teach this at a Community College here in Alabama. If you notice that where you talked about 30 ranges and Col. "C" says to add 15 to that number. Actually you are doing that with 5 -29 ranges as well. 20 ranges will be 35 kw, 14 ranges will be 29. You can memorize Col. "C" if you can remember the first 4 KW's, 8, 11, 14, 17. The rest are just adding 15 to the number of ranges.
Nice video with a lot of samples,. there is one sample missing. I am doing a calculation with a 14.3 KW range/oven and a 8Kw double oven. I am assuming the 14.3Kw range/oven as per note 1 = to 8.8KW and the 8KW double oven as 6.4KW as per column B and adding the values. is that right?
That would not be a typical example, it would be an example you desire to be solved however...LOL...Since nothing in Table 220.55 for this one fits in a nifty calculation I would say yes that is how I would calculate it.
Thanks for answering. Your videos are great. Shockingly, that's real life. I got in my house a combo microwave/oven rated at 8kw on the nameplate and a range/oven rated at 14.2 kW. I happen to be adding a pool/gazebo. The city rejected my drawings because I used the optional method. The existing system has a combo meter panel with 2 subpanels. The gazebo panel will be a subpanel in one of the existing panels. The standard method is giving higher numbers than the optional. But I am assuming 100% of the loads on the gazebo panel, which includes pool equipment. I can not find demand factors for supnels in the NEC. I'm not sure if I can calculate the loads for the new Gazebo subpanel together with the existing panel so I can use factors for lighting/receptacles and pool equipment as fixed in place appliances.
There is nothing in the NEC that says you can't use the optional method if you desire to re-evaluate all the loads as if it was a new installation and then add the new loads into the mix and see what size it demands. Now, to determine existing loads and how you treat new loads then you would use 220.83 which is located in the Part IV for optional method. So, your electrical inspector clearly is not educated on the process. It seems to me just using 220.83(A) would be the best course of action. Now, there is also an allowance in 220.87 but it demands obtaining some values from your utility and they sometimes can be "complex" as they don't cooperate well in some areas. But you most certainly should be able to use 220.83(A) to sort out the capacity available for the existing loads.
We don't do FREE very often. As it says, this is a Freeview of videos in our annual subscription program. We leave the majority of the FREE stuff for others to post. However, now and then I share an exclusive video on RUclips. Part 1 is only available to our subscribers at www.electricalcodeacademy.com
I teach this at a Community College here in Alabama. If you notice that where you talked about 30 ranges and Col. "C" says to add 15 to that number. Actually you are doing that with 5 -29 ranges as well. 20 ranges will be 35 kw, 14 ranges will be 29. You can memorize Col. "C" if you can remember the first 4 KW's, 8, 11, 14, 17. The rest are just adding 15 to the number of ranges.
Thanks Paul for the video on Range load calculations. I really appreciate the work you do
Glad you like them!
thank you for the video; it was very useful. I'm a student and learning this stuff now.
Best explanation ever!
This is great no body’s explaining this material this is what counts
Thanks!
I Learned something today!
That's A Good Day!
Hey brother Paul thanks for the video
You bet
is there a video on 3 phase wjth single phase ranges?
Yep....but I doubt it's on this free platform anymore.
Actually I did keep it free - ruclips.net/video/qKX4TOE_UgE/видео.html
@@MasterTheNEC it's usually on the master exam.
When will the 2023 NEC Fast Trax be released? Getting ready to study for that Master's test!
It is on Pre-Order right now. We expect to begin emailing course info by July 21, 2023. Pre-Orders will be the first inline.
How many amps 15kw one electric range? How to calculate?
This is covered in Part 1 of this Range Calculation Series. You can find it at fasttraxtube.com
Nice video with a lot of samples,. there is one sample missing. I am doing a calculation with a 14.3 KW range/oven and a 8Kw double oven. I am assuming the 14.3Kw range/oven as per note 1 = to 8.8KW and the 8KW double oven as 6.4KW as per column B and adding the values. is that right?
That would not be a typical example, it would be an example you desire to be solved however...LOL...Since nothing in Table 220.55 for this one fits in a nifty calculation I would say yes that is how I would calculate it.
Thanks for answering. Your videos are great. Shockingly, that's real life. I got in my house a combo microwave/oven rated at 8kw on the nameplate and a range/oven rated at 14.2 kW. I happen to be adding a pool/gazebo. The city rejected my drawings because I used the optional method. The existing system has a combo meter panel with 2 subpanels. The gazebo panel will be a subpanel in one of the existing panels. The standard method is giving higher numbers than the optional. But I am assuming 100% of the loads on the gazebo panel, which includes pool equipment. I can not find demand factors for supnels in the NEC. I'm not sure if I can calculate the loads for the new Gazebo subpanel together with the existing panel so I can use factors for lighting/receptacles and pool equipment as fixed in place appliances.
There is nothing in the NEC that says you can't use the optional method if you desire to re-evaluate all the loads as if it was a new installation and then add the new loads into the mix and see what size it demands. Now, to determine existing loads and how you treat new loads then you would use 220.83 which is located in the Part IV for optional method. So, your electrical inspector clearly is not educated on the process. It seems to me just using 220.83(A) would be the best course of action. Now, there is also an allowance in 220.87 but it demands obtaining some values from your utility and they sometimes can be "complex" as they don't cooperate well in some areas. But you most certainly should be able to use 220.83(A) to sort out the capacity available for the existing loads.
@@MasterTheNEC Thanks for answer me again. do you have a video you can point me in with explanation on the optional method and the 220.83a?
ruclips.net/video/HgYQOFgxiGk/видео.htmlsi=1_wZC3-y3SV1zuZj
Where is part one?
We don't do FREE very often. As it says, this is a Freeview of videos in our annual subscription program. We leave the majority of the FREE stuff for others to post. However, now and then I share an exclusive video on RUclips. Part 1 is only available to our subscribers at www.electricalcodeacademy.com