Final Result Will Blow Your Mind!

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  • Опубликовано: 24 дек 2024

Комментарии • 27

  • @ناصريناصر-س4ب
    @ناصريناصر-س4ب День назад +15

    The easiest way is to notice that 7+√50=7+5√2=(1+√2)³ and likewise 7-√50=(1-√2)³ and from that ³√(7+√50)+³√(7-√50)=1+√2+1-√2=2

    • @ImmortalityVenerable
      @ImmortalityVenerable День назад

      7+5√2 ≠ (1+√2)³ ?

    • @ImmortalityVenerable
      @ImmortalityVenerable День назад

      Nvm it does. That's really smart how did you work that out

    • @ناصريناصر-س4ب
      @ناصريناصر-س4ب День назад +4

      ​@@ImmortalityVenerable7+5√2=1+3√2+6+2√2=
      (1)³+3(1)²(√2)+3(1)(√2)²+(√2)³ =(1+√2)³[(a+b)³=a³+3a²b+3ab²+b³]
      7-5√2=1-3√2+6-2√2=(1-√2)³

    • @ImmortalityVenerable
      @ImmortalityVenerable День назад +1

      @ناصريناصر-س4ب That's crazy👏👏

    • @brain_station_videos
      @brain_station_videos  День назад +3

      This is really good! Thanks for sharing :)

  • @Alanpoeta
    @Alanpoeta День назад +4

    Alternative solution based on the knowledge of the depressed cubic formula (which is probably the way the problem was generated):
    -q/2=7
    q=-14
    (q/2)²+(p/3)³=50
    49+p³/27=50
    p³=27
    p=3
    x³+3x-14=0 (guess and check using rational root theorem)
    (x-2)(x²+2x+7)=0
    Determinant = 2²-4*1*7 = -24 < 0
    x=2 is only solution

  • @pratyushkhandelwal7138
    @pratyushkhandelwal7138 День назад +2

    my mind is really blown 🔥🤯 Nice one

  • @madhupr984
    @madhupr984 13 часов назад +1

    Very good method

  • @Masteroogway-e4i
    @Masteroogway-e4i День назад +3

    Damn, isn't there a shorter and easiar way?

    • @ناصريناصر-س4ب
      @ناصريناصر-س4ب День назад

      The easiest way is to notice that 7+√50=7+5√2=(1+√2)³ and likewise 7-√50=(1-√2)³ and from that ³√(7+√50)+³√(7-√50)=1+√2+1-√2=2

    • @Masteroogway-e4i
      @Masteroogway-e4i День назад

      @ناصريناصر-س4ب 🫡

    • @musicsubicandcebu1774
      @musicsubicandcebu1774 День назад +1

      So first you make the assumption that the expression under the cube root ( 7+√50) can be expressed as a cube (a+b)³. Is this always true? Or if not, how would you know to look for it?

    • @ناصريناصر-س4ب
      @ناصريناصر-س4ب День назад

      Yes, in most cases you can express it as a cube, the sum or difference of two terms. If not, then the real root of the equation cannot be determined in the way the professor did, and he found the apparent solution x=2.​@@musicsubicandcebu1774

    • @ناصريناصر-س4ب
      @ناصريناصر-س4ب 23 часа назад

      Yes, in most cases you can express it as a cube, the sum or difference of two terms. If not, then the real root of the equation cannot be determined in the way the professor did, and he found the apparent solution x=2.​@@musicsubicandcebu1774

  • @arifariffulislam2246
    @arifariffulislam2246 День назад +1

    I wish oneday i will be able to solve those.
    Your chanel is really helping

  • @Omar.0009
    @Omar.0009 20 часов назад +3

    Bro I'm serious no joke I did it without solving anything, I made it like an equation simplified it so 1=1 but then put the + that I changed before in = and the answer was 2 (I'm 15)

    • @Masteroogway-e4i
      @Masteroogway-e4i 14 часов назад +1

      Yep it's actually a question for 14-15 years old.

  • @nenetstree914
    @nenetstree914 7 часов назад

    2

  • @oODeinoOo
    @oODeinoOo 2 часа назад

    Looks like oversimplifying to me

  • @Thampuran-o9o
    @Thampuran-o9o День назад

    👍👍👍