Dividing and Simplifying Complex Numbers

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  • Опубликовано: 14 янв 2025

Комментарии • 46

  • @abbymahon3983
    @abbymahon3983 5 лет назад +5

    This guys teaching me better than my actual teacher.

  • @paullea2674
    @paullea2674 5 лет назад +1

    you're out here doin gods work

  • @heathermiller5413
    @heathermiller5413 8 лет назад +4

    You 'freakin' rock!!! Thank You SOOOO much!

  • @jonathanwegner2168
    @jonathanwegner2168 9 лет назад +1

    Very helpful and very well explained, thanks!

  • @MaSSaDFTW
    @MaSSaDFTW 9 лет назад +1

    You sir are a legend , thank you so very much dude :)

  • @КристианКръстев-ц3к

    Great vid, mate

  • @TAEMEME
    @TAEMEME 7 лет назад +1

    THANKS A LOT 🅱️, my algebra teacher doesn't explain clearly and I finally understood this

  • @jordanjohn9889
    @jordanjohn9889 9 лет назад +24

    " square wrut"

  • @16incounting24
    @16incounting24 8 лет назад +2

    wouldn't the last problem be 3-i ?

  • @francismusenge945
    @francismusenge945 2 года назад

    Excellent

  • @codyfrancom5701
    @codyfrancom5701 10 лет назад

    I have a question , on the ones with powers why can't you you raise it to a power of 2 and the multiply for example (i squared) raised to the power of 7.5 making it -1

  • @lucasleroux706
    @lucasleroux706 6 лет назад

    thanks again . great vid

  • @davidpitones3946
    @davidpitones3946 5 лет назад

    Thank you for the help! This was very useful :D

  • @ajaypanicker7562
    @ajaypanicker7562 10 лет назад +1

    thank you sir............

  • @MartyBrandl
    @MartyBrandl  11 лет назад

    Can you help me out on what is wrong?

  • @rosemariegrey7534
    @rosemariegrey7534 6 лет назад

    Thank you sir you helped my confusion to ease

  • @ResanChea
    @ResanChea 7 лет назад

    Thank you bro, didnt get how to solve the second ones

  • @equimanthorn6185
    @equimanthorn6185 5 лет назад

    Thank you!

  • @meh2063
    @meh2063 6 лет назад +1

    An easier way to solve -4i^13 is to divide the power of i by 4
    U take the remaining number of division and conider it as the power of i
    So 13 divided by 4 is 3
    Remaining number is 1
    Which is the power of i
    -4i^13=-4i^1=-4i

    • @MartyBrandl
      @MartyBrandl  6 лет назад

      That's absolutely true! Thanks for sharing your explanation!

  • @yobmathias3921
    @yobmathias3921 6 лет назад

    thanks you are great

  • @shasvinshaz9989
    @shasvinshaz9989 7 лет назад

    what if the denominator is like (i-1)^2

    • @shasvinshaz9989
      @shasvinshaz9989 7 лет назад

      how to conjugate them

    • @MartyBrandl
      @MartyBrandl  7 лет назад +1

      Shasvin Shaz The key is getting the i term(s) to cancel so if you were to multiply by (i + 1)^2 and foiled (i - 1)(i + 1) twice I think you would be set!
      I hope that helps! :-)

    • @shasvinshaz9989
      @shasvinshaz9989 7 лет назад

      thanks bro

  • @evelina.gukasyan
    @evelina.gukasyan 9 лет назад

    thank u!!

  • @adls04
    @adls04 6 лет назад

    Thanks man

  • @lucidof3002
    @lucidof3002 8 лет назад

    ty

  • @thee-21hunnit24
    @thee-21hunnit24 7 лет назад +4

    square rut?????????????

  • @rainsinz
    @rainsinz 10 лет назад

    You do them the hard way. For example i^24 = i^4 we know this because we divide the power by 4 and whatever the remainder is will be the new power we go by. We should already know I^1....... i^4 by memory so just convert in your head. Example i^100 = i^4 and i^4 is obviously 1.

    • @MartyBrandl
      @MartyBrandl  10 лет назад

      Very true! Thanks for sharing! :-)

  • @williamssyndromefamilynetwork
    @williamssyndromefamilynetwork 10 лет назад

    Is the reason why it became 2 - i instead of 3-i because the 2nd 1 in the last step was to be multiplied by i and not added in with the rest of the real numbers?

    • @MartyBrandl
      @MartyBrandl  10 лет назад

      I find it easiest to think about it as combining like terms. Imagine it was 1 - x + 1, that would simplify to 2 - x.
      I hope that helps! :-)

  • @tjforrester9939
    @tjforrester9939 8 лет назад +9

    "Square Ruut"

  • @bobbailey7024
    @bobbailey7024 7 лет назад

    On questions 3 and 4 why didn't you just divide the exponent(s) by 4 and work out i from the remainder as the pattern repeats? i^0 = 1, i^1 = i, i^2 = -1, i^3 =-i, i^4 = 1, i^5 = i^1. i^4001 = i^1 =i You made it far too complicated where there was no need.

    • @MartyBrandl
      @MartyBrandl  7 лет назад +1

      Bob Bailey That's true. I just wanted to show how it could be worked out only knowing that the square root of -1 is i. Thanks for your thoughts!

  • @paolanarvaez8370
    @paolanarvaez8370 6 лет назад

    Is Anyone else watching this before a final?

  • @flynnryder6723
    @flynnryder6723 7 лет назад

    thank you

  • @flynnryder6723
    @flynnryder6723 7 лет назад

    please i really want you to help me with my math. can i get your what whatsapp line so that you can help me at a time need.
    i have really understood this very well that why i need you help please. Am Sebastian from Ghana

  • @alexpolakis2016
    @alexpolakis2016 8 лет назад

    Square wraught

  • @ungracefullyhere
    @ungracefullyhere 12 лет назад +4

    "square rut" hahaa

  • @GH-gs6yn
    @GH-gs6yn 6 лет назад

    Its good but I hate mathematics ☹️☹️☹️☹️☹️☹️☹️☹️🙁☹️☹️☹️☹️☹️

    • @MartyBrandl
      @MartyBrandl  6 лет назад

      G H Not everyone needs to love math. It's great to live in a world where people like different things. Perhaps this helps you to just appreciate math, even if you don't like it? :-)

    • @GH-gs6yn
      @GH-gs6yn 6 лет назад

      Ok i will agree that 👍🏻👍🏻👍🏻

    • @adls04
      @adls04 6 лет назад

      There are two types of people in this world.... those who love math and those who dont know they love math