Finding C programming hard? We’ve got you! 🚀Get 60% off on Programiz PRO Lifetime Plan this Black Friday-pay once for skills that last forever. Don’t miss out, it’s a limited-time offer! 👉Grab your discount now: bit.ly/blkfriday-24-yt
Your work is immaculate efficient and you are truly an inspiration. I was not doing well at all at University of but now you have given Me new hope. Thank you!!!
@@user-tz1wb2gt7n actually wound up in Fall: 1B in the "C" programing and 1C for Calculus dropped psychology, But in Spring '23 all A's for 4classes 12 semester hours the 2nd Semester, I left that University to become a pilot all A's Fall Semester start ground and flight ✈️ labs Jan '24, Thanks for asking! Hope you are well and thank you for being there.
/* Can you create a program to check whether a number is positive or negative or 0? To create this program, create a variable named number and assign a double value to it based on the user input. Then using an if statement, check if the number variable is positive or negative or 0. > If number is positive, print"The number is positive" > If number is negative, print"The number is negative" > If number is 0, print "The number is Zero" */ #include int main() { double number; printf("Please write your number and I will let you know if its positive number, zero, or negative number: "); scanf("%lf", &number); if (number < 0){ printf("The number is negative."); } else if (number == 0){ printf("The number is Zero."); } else if (number > 0){ printf("the number is positive."); } return 0; }
Thank youuu it was helpfull int main() { double number; printf("Enter The Number:"); scanf("%lf",&number); if (number>0){ printf("The Number is Positive!"); } else if(number
I'm a 1st year college student in computer science engineering, I'm leaving this commrnt to keep track of my developpement and to stay motivated. 8/11, I'm able to make a c language program with if statement
A real beginner - #include int main(){ double number; printf("Enter any number "); scanf("%lf", &number); if(number>=1){ printf("The number is positive"); }else if(number
PROGRAMIZ QUIZ ANSWER: OPTION(A) Inside if PROGRAMMING TASK GIVEN BY MAM: #include int main() { double num1; printf("Enter a number here: "); scanf("%lf", &num1); if (num1>0){ printf("The number is positive."); } else if (num1==0){ printf("The number is neutral(It is 0)."); } else { printf("The number is negative."); } return 0; }
Mam these videos are very useful. Thank you for helping us. If possible please make a series on c++ language and dsa in it. this will be very benificial for me and many more like me. Thank you.]
#include int main() { double number; printf ("Enter a number:"); scanf ("%lf", &number); if (number>0){ printf ("The number %0.2lf is positive",number); } else if (number
#include int main() { int a=-5; if (a0){ printf("The number is positive"); } else { printf("The number is 0"); } return 0; } Mam,Your classes are very helpful us thank you so much mam
my answer for the question at the end: #include int main() { int number = -1; if(number == 0) printf("zero"); else if(number > 0) printf("positive"); else if(number < 0) printf("negative"); return 0; }
Programming task :--- #include int main() { double number; printf("Enter number : "); scanf("%lf",&number); if (number > 0) printf("The number is positive"); else if(number < 0) printf("The number is negative"); else if(number == 0) printf("The number is zero"); return 0; }
// Online C compiler to run C program online /*This is a program to check whether a number is a positive, negative or a zero.*/ #include int main() { double number; printf("Enter any number: "); scanf("%lf", &number); if(number>0) { printf("The number %.2lf is positive.",number); } if(number==0) { printf("The number %.2lf is Zero.",number); } if(number
#include #include int main() { double number ; printf("Input number:"); scanf("%lf",&number); if(number > 0){ printf("The number is positive"); } if(number == 0){ printf("The number is zero"); } if(number < 0){ printf("The number is negetive"); } }
Option A : Inside if -------------------------------------------------------------- #include int main() { int num; printf("Enter A Number: "); scanf("%d", &num); if (num == 0) { printf("The Number Is Zero"); } else if (num > 0) { printf("The Number Is Positive"); } else { printf("The Number Is Negative"); } return 0; }
Answer to quiz is A #include int main() { // Write C code here double number; printf("what is your number? "); scanf("%lf", &number); if(number > 0){ printf("The number is positive"); } if(number < 0){ printf("The number is negative"); } if(number ==0){ printf("The number is 0"); } return 0; }
ANSWERS Task: double number; printf("please enter a number: "); scanf("%lf", &number); if (number > 0) { printf("this number is positive"); } else if (number < 0) { printf("this number is negative"); } else { printf("this number is 0"); } Quiz: inside if
#include int main() { double number; printf("enter the number:"); scanf("%lf", &number); if(number > 0){ printf("the number is positive"); } else if(number < 0){ printf("the number is negative"); } else if(number == 0){ printf("the number is zero"); } return 0; } the program u asked to do by us
int num; printf("enter a number: "); scanf("%d",&num); if (num < 0 ) { printf("the number i s nagative "); } else if ( num >0 ) { printf("the number is possitive "); } else if (num = 0) { printf("the number is zero"); } else { printf("you not entered a number plz inte a number "); }
here the answer for your task mam thanks for teaching c easily #include int main() { double num; printf("enter the number :"); scanf("%lf", &num); if(num > 0) { printf("positve"); } if(num == 0) { printf("the number is 0"); }
#include int main() { double number; printf("Enter your number : "); scanf("%lf",&number); if(number>0){ printf("The number is positive"); } else if(number
// Online C compiler to run C program online #include int main() { // Write C code here double number; printf("Enter the number here:"); scanf("%lf", &number); if(number>0){ printf("The number is positive");
} else if(number == 0){ printf("The number is 0"); } else{ printf("The number is negative"); }
return 0; } OUTPUT: Enter the number here: -18 The number is negative
My solution- #include int main() { double input; printf(Enter decimal: ); scanf("%lf",&input); if (input == 0){ printf("The number is 0."); } else if(input>0){ printf("The number is positive."); } else{ printf("The number is negetive."); } return 0; }
#include int main(){ int num; printf("Enter the any number: "); scanf("%d", &num); if (num>0){ printf("THE NUMBER IS POSITIVE"); } else if (num==0){ printf("THE NUMBER IS ZERO"); } else{ printf("THE NUMBER IS NEGATIVE"); } return 0; } answer 11:37
//to display whether the entered number is positive or negative #include int main() { double number; printf("enter the number: "); scanf("%lf", &number); if (number > 0){ printf("The entered number is positive"); } else if (number < 0){ printf("The entered number is negative"); } else { printf("The entered number is zero"); } return 0; }
@@arhitjoseph9681 a%2=1 ! (a%2==0) condition is true because a%2 is not equal to zero, so body of if statement exicuted , hence we can say , "inside if" printed .
#include int main() { double number; printf("Enter a number: "); scanf("%lf", &number); if (number > 0) { printf("The number is positive"); } else if (number < 0) { printf("The number is negative"); } else { printf("The number is 0"); } return 0; } 12:05
// Online C compiler to run C program online #include int main() { double number; printf("Enter a number:\t"); scanf("%lf", &number); if(number > 0){ printf("the number is positive"); } else if (number == 0){ printf("the number is zero"); } else if (number < 0){ printf("the number is negative"); } return 0; }
// program to check the number is +ve , -ve or 0 #include int main() { float num; printf("Enter the number "); scanf("%f",&num); if(num>0) { printf("It is positive number "); } else if(num
// Online C compiler to run C program online #include int main() { double age ; printf("pls enter the age "); scanf("%lf",&age); printf("the value of age is %lf",age); if (age>0) { printf(" the number is positive"); } else if (age
its inside if, because the ! is logical not true and since the operative number is 0 than its right, unless the operative number is not 0. correct me if I missed something.
Finding C programming hard? We’ve got you!
🚀Get 60% off on Programiz PRO Lifetime Plan this Black Friday-pay once for skills that last forever. Don’t miss out, it’s a limited-time offer!
👉Grab your discount now: bit.ly/blkfriday-24-yt
Qq
OKAY THANK YOU
Answer is A : Inside if
answer is B
You explain a lot better than my professor from college. Thanks for making things easier!
how you did after 11 months?
i do not know why university Professors are making these easy lessons so much difficult and unbearing, Thank you @programiz
#include
#include
//déclaration of variable
int main() {
double number;
printf("enter a double number");
scanf("%lf",&number);
if(number>0){
printf("number is positive");}
else if(number
Good job
else if(number
@@danieldaniekl6222 Have you understood the question?
The guy followed the instructions of the question but you ...
The answer is A: inside if
Also love your tutorials they're amazing. Keep it up👍
no the answer will be inside else because a%2=1
@@purpleocean5670but it has the not symbol (!) so it's reversed
Ma'am, these lectures are very helpful.
Your work is immaculate efficient and you are truly an inspiration.
I was not doing well at all at University of but now you have given
Me new hope.
Thank you!!!
Mind If I ask how you did ?
@@user-tz1wb2gt7n actually wound up in Fall: 1B in the "C" programing and 1C for Calculus dropped psychology, But in Spring '23 all A's for 4classes 12 semester hours the 2nd Semester, I left that University to become a pilot all A's Fall Semester start ground and flight ✈️ labs Jan '24, Thanks for asking! Hope you are well and thank you for being there.
/*
Can you create a program to check whether a number is positive
or negative or 0?
To create this program, create a variable
named number and assign a double value to it based on the user
input. Then using an if statement,
check if the number variable is positive or negative or 0.
> If number is positive, print"The number is positive"
> If number is negative, print"The number is negative"
> If number is 0, print "The number is Zero"
*/
#include
int main() {
double number;
printf("Please write your number and I will let you know if its
positive number,
zero, or
negative number:
");
scanf("%lf", &number);
if (number < 0){
printf("The number is negative.");
}
else if (number == 0){
printf("The number is Zero.");
}
else if (number > 0){
printf("the number is positive.");
}
return 0;
}
God bless u ma’am. I love how she explains things very fluently ✍🏾
Thank youuu it was helpfull
int main() {
double number;
printf("Enter The Number:");
scanf("%lf",&number);
if (number>0){
printf("The Number is Positive!");
}
else if(number
I'm a 1st year college student in computer science engineering, I'm leaving this commrnt to keep track of my developpement and to stay motivated.
8/11, I'm able to make a c language program with if statement
Better explanation than my professor teacher😊
my life saviour...u made me develop interest in c by taking away my aversion..thanks mam
The cutest programming teacher ever. Thanks for making it easier to understand.
I tried to watch different video on the topic but this one is different and concise.
Thank you ms!
Thank you so much for this video ma.... The answer is A (inside if)
int main() {
double number;
printf("Enter the number: ", number);
scanf("%lf", &number);
if(number>0){
printf("positive number");
}
else if(number
A real beginner -
#include
int main(){
double number;
printf("Enter any number
");
scanf("%lf", &number);
if(number>=1){
printf("The number is positive");
}else if(number
one of the best c tutorials i have ever seen!!😊😊
Wow, This video Really Helped me in understanding the if/else statements in C. Thank You @programiz for these lessons, God Bless You
it made my course very easy to compete and in very short time mam
Thank you for giving your knowledge for students like us mam
Wonderful Explanation with very short examples which are easy to follow.
PROGRAMIZ QUIZ ANSWER: OPTION(A) Inside if
PROGRAMMING TASK GIVEN BY MAM:
#include
int main() {
double num1;
printf("Enter a number here: ");
scanf("%lf", &num1);
if (num1>0){
printf("The number is positive.");
}
else if (num1==0){
printf("The number is neutral(It is 0).");
}
else {
printf("The number is negative.");
}
return 0;
}
really helpful course , simple and effective explanation
Mam these videos are very useful. Thank you for helping us. If possible please make a series on c++ language and dsa in it. this will be very benificial for me and many more like me. Thank you.]
Thank you mam, you have explained wonderfully 😊
If Else Statements in c simplified thanks for making it easier
🙂🙂🙂🙂🙂🙂🙂🙂🙂
answer is A (inside if).....I love your channel by the way....keep it up.!
inside if , thank you teacher, you are the best
#include
int main() {
double number;
printf ("Enter a number:");
scanf ("%lf", &number);
if (number>0){
printf ("The number %0.2lf is positive",number);
}
else if (number
#include
int main()
{
int a=-5;
if (a0){
printf("The number is positive");
}
else {
printf("The number is 0");
}
return 0;
}
Mam,Your classes are very helpful us thank you so much mam
I love this video ❤️, I understood it perfectly well
So easy to understand thanks
thank you programiz. the answer to the quiz question is option A
This course is really very helpful...plz increase the video frequency.
Thank you! We appreciate your thoughts.
Maam you are very resourceful and helpful. Im following in Papua New Guinea
Am inspired and it is wonderful
Please can you make videos too on C++,java and python?
Amazing explanation
been learning a lot. also the phone application has good notes to refer to
thank you for the explanation
Thank you so much🙂
my answer for the question at the end:
#include
int main() {
int number = -1;
if(number == 0)
printf("zero");
else if(number > 0)
printf("positive");
else if(number < 0)
printf("negative");
return 0;
}
Programming task :---
#include
int main()
{
double number;
printf("Enter number : ");
scanf("%lf",&number);
if (number > 0)
printf("The number is positive");
else if(number < 0)
printf("The number is negative");
else if(number == 0)
printf("The number is zero");
return 0;
}
// Online C compiler to run C program online
/*This is a program to check whether a number is a positive, negative or a zero.*/
#include
int main()
{
double number;
printf("Enter any number: ");
scanf("%lf", &number);
if(number>0)
{
printf("The number %.2lf is positive.",number);
}
if(number==0)
{
printf("The number %.2lf is Zero.",number);
}
if(number
#include
int main(void) {
double tempareture=-12;
if(tempareture>=1){
printf("tempareture pasitive");
}
else if(tempareture
her smile in start of video and at last oh my god just beautiful
#include
#include
int main()
{
double number ;
printf("Input number:");
scanf("%lf",&number);
if(number > 0){
printf("The number is positive");
}
if(number == 0){
printf("The number is zero");
}
if(number < 0){
printf("The number is negetive");
}
}
thanks a lot maam , your videos are very helpful
thanks, really nice to hear this
Option A : Inside if
--------------------------------------------------------------
#include
int main()
{
int num;
printf("Enter A Number: ");
scanf("%d", &num);
if (num == 0)
{
printf("The Number Is Zero");
}
else if (num > 0)
{
printf("The Number Is Positive");
}
else
{
printf("The Number Is Negative");
}
return 0;
}
Ma'am plz upload videos fast it will be beneficial
It,s amazing
thank you for your efforts
Mam plz upload videos daily
You are the best. You made fall inlove with proogramming
Love Your Voice ☺
Yeah yeah! 😊 its amazing lecture, the lecture was supper explicit
Thanks, l like your working background, it's clear, l wish it can be clearer
Answer to quiz is A
#include
int main() {
// Write C code here
double number;
printf("what is your number? ");
scanf("%lf", &number);
if(number > 0){
printf("The number is positive");
}
if(number < 0){
printf("The number is negative");
}
if(number ==0){
printf("The number is 0");
}
return 0;
}
A. because the ! will evaluate the if condition to true thereby making the program print "inside if"
I love the simplicity
ANSWERS
Task:
double number;
printf("please enter a number: ");
scanf("%lf", &number);
if (number > 0) {
printf("this number is positive");
}
else if (number < 0) {
printf("this number is negative");
}
else {
printf("this number is 0");
}
Quiz:
inside if
Video is helpful and understadable~~thanksss a lot
u make c easy
inside if
great work
Answer is Inside if
#include
int main() {
double number;
printf("enter the number:");
scanf("%lf", &number);
if(number > 0){
printf("the number is positive");
}
else if(number < 0){
printf("the number is negative");
}
else if(number == 0){
printf("the number is zero");
}
return 0;
} the program u asked to do by us
Please upload a series tutoring java script
int num;
printf("enter a number: ");
scanf("%d",&num);
if (num < 0 ) {
printf("the number i s nagative ");
}
else if ( num >0 ) {
printf("the number is possitive ");
}
else if (num = 0) {
printf("the number is zero");
}
else {
printf("you not entered a number plz inte a number ");
}
here the answer for your task mam thanks for teaching c easily
#include
int main()
{
double num;
printf("enter the number :");
scanf("%lf", &num);
if(num > 0)
{
printf("positve");
}
if(num == 0)
{
printf("the number is 0");
}
else if(num
Ma'am, it would have been nice to finish the course a little early
Thank you! We appreciate your thoughts. We post video every week on Wednesday. So stay tuned for next video.
#include
int main()
{
double number;
printf("Enter your number : ");
scanf("%lf",&number);
if(number>0){
printf("The number is positive");
}
else if(number
If possible please make similar tutorials for java and kotlin
#include
int main() {
printf("Thank you programiz team");
return 0;
}
Very helpful
Thanks a lot
// Online C compiler to run C program online
#include
int main() {
// Write C code here
double number;
printf("Enter the number here:");
scanf("%lf", &number);
if(number>0){
printf("The number is positive");
}
else if(number == 0){
printf("The number is 0");
}
else{
printf("The number is negative");
}
return 0;
}
OUTPUT:
Enter the number here: -18
The number is negative
Nice 👍
Ma'am, it would be nice to post a video a week early
It is helpful,upload more videos mam
answer is "Inside if" option:A
option A
extremely helpful. keep it up!
b) inside else
My solution-
#include
int main() {
double input;
printf(Enter decimal: );
scanf("%lf",&input);
if (input == 0){
printf("The number is 0.");
}
else if(input>0){
printf("The number is positive.");
}
else{
printf("The number is negetive.");
}
return 0;
}
#include
int main(){
int num;
printf("Enter the any number: ");
scanf("%d", &num);
if (num>0){
printf("THE NUMBER IS POSITIVE");
}
else if (num==0){
printf("THE NUMBER IS ZERO");
}
else{
printf("THE NUMBER IS NEGATIVE");
}
return 0;
}
answer
11:37
The answer is option A
//to display whether the entered number is positive or negative
#include
int main()
{
double number;
printf("enter the number: ");
scanf("%lf", &number);
if (number > 0){
printf("The entered number is positive");
}
else if (number < 0){
printf("The entered number is negative");
}
else {
printf("The entered number is zero");
}
return 0;
}
Q. What is the output of the following code?
#include
int main() {
int a = 5;
if (!(a % 2 == 0)) {
printf("Inside if");
}
else {
printf("Inside else");
}
return 0;
}
Output:-) inside if
A. Inside if
insideif
@@my_talks01 how bro?
@@arhitjoseph9681 a%2=1
! (a%2==0) condition is true because a%2 is not equal to zero, so body of if statement exicuted , hence we can say , "inside if" printed .
#include
int main()
{
double number;
printf("Enter a number: ");
scanf("%lf", &number);
if (number > 0)
{
printf("The number is positive");
}
else if (number < 0)
{
printf("The number is negative");
}
else
{
printf("The number is 0");
}
return 0;
}
12:05
#include
int main()
{
double number;
printf("Enter a number: ");
scanf("%lf",&number);
if(number>0)
printf("The number is positive");
else if(number
double number=20.8;
if(number>0){
printf("The number is positive");
}
else if(number
I really inspired to your lecture ❤
Can we use ( else ) again n again ?
Can I ask, if you are going to run a program of if else statement uhhmm it's not needed to put a user input to it? Orrr yeah need to, I'm confuse😅
// Online C compiler to run C program online
#include
int main() {
double number;
printf("Enter a number:\t");
scanf("%lf", &number);
if(number > 0){
printf("the number is positive");
}
else if (number == 0){
printf("the number is zero");
}
else if (number < 0){
printf("the number is negative");
}
return 0;
}
thanks 💥😍
// program to check the number is +ve , -ve or 0
#include
int main()
{
float num;
printf("Enter the number
");
scanf("%f",&num);
if(num>0)
{
printf("It is positive number
");
}
else if(num
// Online C compiler to run C program online
#include
int main() {
double age ;
printf("pls enter the age
");
scanf("%lf",&age);
printf("the value of age is %lf",age);
if (age>0)
{
printf("
the number is positive");
}
else if (age
its inside if, because the ! is logical not true and since the operative number is 0 than its right, unless the operative number is not 0. correct me if I missed something.
#include
int main(void) {
// Variable deceleration
int num;
// User inputs
printf("Enter a number : ");
scanf("%d",&num);
// Condition 01
if(num > 0) {
printf("number %d is positive",num);
}
// Condition 02
else if(num < 0){
printf("number %d is negative",num);
}
// Condition 03
else if(num == 0){
printf("number %d is equal to 0",num);
}
}