Gibbs-Helmholtz Equation | Physical Chemistry I | 053

[@humor5211]

Thanks for the video.
In the last equation of the integral form, are the deltaGt2 and deltaGt1 going to be the same because of the assumption that deltaG is independent on T? I believe it's not but I don't know why...

[@ahmedmohamed7793]

Hallo,
Thank you for all videos in physical chemistry.
In this video you forget put T times 2

[@muthyalupappu1478]

TQ so much 🙂

[@duaaali3461]

11:00 where did the negative sign go?

[@ProfessorDerricotte]

Hey Duaa, looks like I dropped the negative sign one step too early! My apologies. The negative sign should still be in front if Delta H in that step where I take the integral. The final integral form is still correct, keeping in mind that the integral of 1/x^2 is - 1/x, so the negative sign would cancel out leaving you with the final integral form of the Gibbs-Helmholtz expression.

[@ShivamNM]

Nice bro

[@ProfessorDerricotte]

Thanks