All of your videos are a helpful,thorough and easy to understand valuable resource especially for someone like me who isn't an engineer. Keep up the good work!
Brosky, I agree with all the answers except from the velocity. I find that the velocity is 2.9fps. Please do correct me if I am wrong: v = Q/A the formula in use. v = (4gpm*231/60)/(π/4(d)²) this gives us the answer in inches per second. v = then divide 34.8584 by 12 to get feet per second. Thus v = 2.9048 OR 2.9.
Area is correct. d of .75 in yields A of .4417 in2. 4 gpm is 924 in3 per min which is 15.4 in3/s 15.4 in3/s divided by .4417in2 is 34.9in/s which is 2.9fps
Your lecturers have been super fun...keeping me sharp during covid👍🏾👌🏾👌🏾
All of your videos are a helpful,thorough and easy to understand valuable resource especially for someone like me who isn't an engineer. Keep up the good work!
Very nice. Glad you're making use of them. Also, check out the free study guides I'm starting to post at: www.cgcc.edu/study-guides
You are one smart dude!!
thank you for this lesson ;
Velocity 2.17 fps
PH 1.365 hp
Pm 0.91 hp
efficiency 66.5%
Qa 30 gpm
Qb 4 gpm
Brosky, I agree with all the answers except from the velocity.
I find that the velocity is 2.9fps.
Please do correct me if I am wrong:
v = Q/A the formula in use.
v = (4gpm*231/60)/(π/4(d)²) this gives us the answer in inches per second.
v = then divide 34.8584 by 12 to get feet per second.
Thus v = 2.9048 OR 2.9.
@@DanielKatundu-y8t I hope we can all be educated on this cause I have V=0.757fps JIM HELP PLZ
@@superxtroid5712 D# is tracking. v=2.9fps.
@@bigbadtech When it comes to finding the area through diameter , I did A= pi/4•d^2 , which gave me 0.44 . Did i use the wrong formula?
Area is correct. d of .75 in yields A of .4417 in2.
4 gpm is 924 in3 per min which is 15.4 in3/s
15.4 in3/s divided by .4417in2 is 34.9in/s which is 2.9fps
i wish the calculations could be in metric.
Metric is convinient.
4,62 in3/s