life was so beautiful when this video was published ....😊 now life is confined and wierd ....i dont even know what is going to happen? and will i be able to do good ? I WANT TO GO BACK IN TIME ....agar kisi ke paas time machine ho to bata naa ...:(
+Kumar Sambhav In problem it is specified that blocks are moving with uniform acceleration state so the spring elongation is constant and its not changing than only it can happen...
Physics Galaxy Sir thank u very much for clearing my doubts I m really blessed o have u as my Mentor...U r making Physics as it was never before...Your dedication for Physics is visible as being such a busy person u r replying to students whom u dont even know....Hats Off
I am amazed srr by ur teaching ...u made it crystal clear for me in just 10 min Thank u so much srr for such a great explaination and plz keep helping us ... with more such videos
At 9:12, the tension in that wire should be in opposite direction I assume? Because tension always act away from point of contact(i.e, on the surface of pulley)?
thanks sir again....8/6/24.. another method of 7:45.. accn of centre of mass of system=60/25.. that is (m1a1+m2a2)/m1+m2. so (10a+15*2)/25... a=3m/ssq..
Sir at 9:23 😬, sir is the force applied on spring taken as the tension due to 30kg body and not mg? That makes sense but I just want to confirm sir Pls reply sir And thank you so much for your videos sir. I was so depressed while learning physics before, but not now.
Tension is in both direction and at both ends of spring kx is acting in opposite direction to tension as ends are massless and at massless bodies net forces are always balanced... thats why T=kx
hm bhai bana lo..nhi to sab bhul jayoge bad me .. chaho to coaching ko ignore kr skte ho physics ke liye.. just iske bad onion physics jrur dekh lena@AdityaSinha-ed3uw
What problem you are facing that you need to specify... the question is directly solved by writing dynamic motion equations of the two blocks and spring force is equal to tension here...
Sir, in last example the spring is pulled by tension force in both direction, so why have we not considered total extension as 2x after balancing force on both sides of spring? Sir please reply.
the spring isn't being pulled here both blocks are moving in uniform acceleration so there isnt any concept of it being pulled from both directions. Remember, both blocks are moving uniformly so whatever elongation is there is constant.
Sir in 2nd example why did you state that both blocks will have same acceleration? Wouldn’t the 30kg block go down by distance of the string goes down + the distance X the spring is stretched?
if the massles string is attached between both the blocks then both of them would have the same acceleration because they both are displaced by equal distances. so similarly if we use the same concept here where do we get it wrong
In last question acceleration of both the bodies are kept same i.e. 'a' but in the second last question both the bodies had different acceleration. Both are connected by a spring. Someone kindly correct me where i am wrong
Sir if I am unable to solve this example videos, does that mean I need to work on my concepts or are these examples just for the demonstration of different methods of solving the problem. And sir if I watch all the videos from this channel and solve all questions taught throughout lectures, will that be enough.
Dont confuse yourself. Always treat the spring force of a fully streched spring similar to the tension force of string. Because they behave exactly the same way.
Sir plz explain both T nd kx applied on both ends of spring? Why T is acting upward near the pulley bcoz T always acts away from the contact point... Plz explain
sir the first example how you wrote the equation 60 - kx = 15 x 2 as in according to the formula f = - kx then how you came to this equation pls explain this sir .
@@ashishchauhan2335 no we have considered the spring to be massless here if There is a for on a massless object its acceleration will be infinite so we will have to take a spring with mass then
sir when in a situation a spring and in another a string is cut .but one end being supported by a spring in which a spring is cut and string when it is cut. How to then calculate acceleration what will be the diff in magnitude of spring and tension instantaneously.the system in each case was firstly in equilibrium
If you think about it it’s common sense Think it that way Imagine having a rock tied by a rubber band, the rubber band have the tendency to pull it up so the Tension will be pointing ☝🏼 up
जब स्प्रिंग कट करोगे तो स्प्रिंग फ़ोर्स भी जीरो हो जायेगा. जब स्प्रिंग ही नहीं होगा तो स्प्रिंग फ़ोर्स कैसे आएगा. हाँ अगर कोई दूसरा धागा कट कर दिया तो उसी समय सारे धागों का टेंशन जीरो हो जायेगा लेकिन स्प्रिंग का टेंशन इंस्टैंटली जीरो नहीं होगा
When u will cut the spring spring force will be zero as there will be no spring. But if u cut any other string(not spring) then tension in all the strings which are connected to that string below the point of cut will instantly become zero but tenssion in the spring (if any) below the string which is cut will not become zero
Please make a video on- To what height a spring will rebounce after compression when it is released from a height 'h'. If the one end of the spring is tied with mass m1 and the other with mass m2.
Do not post same query repeatedly... it distracts other viewers... if you are using a common public platform then always respect and take care of interests of other users also...
You need to watch our theory videos in proper sequence of this topic... All Physics topics are already covered in our more than 4000 theory and concept videos with illustrations... You can watch these through our channel playlists or our website in properly organized way at www.physicsgalaxy.com or through our mobile app 'Physics Galaxy'
Very nice video sir... Sir I have a question.. Say we have two blocks of equal masses connected to the two ends of a spring of spring constant K and the whole system is kept on a smooth horizontal frictionless table. Now we apply two equal pulling forces on both the masses and as a result both the masses get displaced by (x) metre say.. Naturally the spring will extend by 2x metre. Now we apply the energy conservation principle Elastic potential energy stored in the spring = Net amount of work done on both the blocks Now, Elastic potential energy stored in the spring = 1/2*k*(2x) ^2 = 2kx^2 Net amount of work done on both the blocks = 1/2*k*x^2+1/2*k*x^2 = kx^2 But these two values are not equal Sir please explain why??
You missed the kinetic energy gained in the two blocks which is maximum at equilibrium position and at extreme position forces are not balanced so blocks will start moving in inward direction... think again on the situation!!!
Sir very clear explanation about the topic sir thank you
Thanks Venkatesh, don't forget to subscribe!
@@physicsgalaxyworld Are these lecture enough for neet.
@@arjuntiwari93 yep
oh sir wat a gr8 teacher u r...!..litrally hats off to d way u deleiver d concepts of phy in few secs....
agree... he is awesome
life was so beautiful when this video was published ....😊 now life is confined and wierd ....i dont even know what is going to happen? and will i be able to do good ? I WANT TO GO BACK IN TIME ....agar kisi ke paas time machine ho to bata naa ...:(
What happens
Kuch din aram karo
wow sir...idk whether you will be reading this but just like u said...u made me love physics...now it is in the top of my favorite list
Sir in the 2nd example why have u taken the accn. of both the blocks equal whereas there is also a spring in between them ?
+Kumar Sambhav In problem it is specified that blocks are moving with uniform acceleration state so the spring elongation is constant and its not changing than only it can happen...
Physics Galaxy Sir thank u very much for clearing my doubts I m really blessed o have u as my Mentor...U r making Physics as it was never before...Your dedication for Physics is visible as being such a busy person u r replying to students whom u dont even know....Hats Off
4:47 first time seeing sir making a spelling mistake and then cutting it
I understood this very well by seeing
thanks ashish sir
Sir....in spring forces u did not cover parallel spring force type concepts.... plz explain such type also sir...... ur lectures are very useful
this is late but for those looking at this, he has covered it in SHM.
@@kavinravi5390 and it is also not required in NLM,it has application in SHM so it is covered in that
@@swayamprakashkar9664 yes that's correct
Wow Beautifully Explained
Thanks To All PG Team
I am amazed srr by ur teaching ...u made it crystal clear for me in just 10 min
Thank u so much srr for such a great explaination and plz keep helping us ... with more such videos
god bless you sir
what if the acceleration is not uniform sir...... will then the blocks have same acceleration??
At 9:12, the tension in that wire should be in opposite direction I assume? Because tension always act away from point of contact(i.e, on the surface of pulley)?
Exactly
thanks sir again....8/6/24.. another method of 7:45.. accn of centre of mass of system=60/25.. that is (m1a1+m2a2)/m1+m2. so (10a+15*2)/25... a=3m/ssq..
This mans writing teaching and drawing is on fleet omg.
what is fleet?
@Ayan Kashyap
Means really good. Complimenting his straight lines and legible writing
@@kauze8063 fleet is used in a sentence such as a fleet of ships. Did you by any chance misspell fleek
@@kauze8063 bro that's fleek not fleet, khudki angrezi kharab dusro ko bata rahe hai lol
@@anotheridiotd7703 he/she probably misspelled it
thank you so much sir such a great explanation
tq so much sir ur concept made physics so interesting and easy ,,I m lucky to have a mentor like u ,tq so much sir ....
Sir at 9:23
😬, sir is the force applied on spring taken as the tension due to 30kg body and not mg?
That makes sense but I just want to confirm sir
Pls reply sir
And thank you so much for your videos sir. I was so depressed while learning physics before, but not now.
Sir is spring force is example of reaction force to our action of compression
Plz reply
Yes...
Sir, in the last example tension in the spring is in the both directions upward and down.. so why we have not taken equation as
2T=kx.
Tension is in both direction and at both ends of spring kx is acting in opposite direction to tension as ends are massless and at massless bodies net forces are always balanced... thats why T=kx
+Physics Galaxy Thank you sir......
@@physicsgalaxyworld sir and if spring is not massless then what would be the equation
to the point videos. thanks sir
Beautifully explained with examples ....
Your lectures give both concept and confidence.
jee 2024 aspirant?
@@aksaxena1000 yes
@@prithvishm then 11th ki playlist me kaise? 12th ka syllabus khtam ho gya?
@@prathammathura optics tk ka ho gaya
hm bhai bana lo..nhi to sab bhul jayoge bad me .. chaho to coaching ko ignore kr skte ho physics ke liye.. just iske bad onion physics jrur dekh lena@AdityaSinha-ed3uw
Thankyou very much sir ...this topic is really tough.... satisfied with explaination🙏🙏👍
Thank you sir.
It was very helpful.
sir, you are doing a great job
Sir plz say in second example restoring force is acting due to weight or tension
both !!
T on one end and mg on other end
plz give me a detailed description of ex 2 that u did as early as possible
What problem you are facing that you need to specify... the question is directly solved by writing dynamic motion equations of the two blocks and spring force is equal to tension here...
Sir, in last example the spring is pulled by tension force in both direction, so why have we not considered total extension as 2x after balancing force on both sides of spring?
Sir please reply.
the spring isn't being pulled here both blocks are moving in uniform acceleration so there isnt any concept of it being pulled from both directions. Remember, both blocks are moving uniformly so whatever elongation is there is constant.
@@kavinravi5390 thenks yr whosoever u may be...it was my doubt also😁
Sir in 2nd example why did you state that both blocks will have same acceleration? Wouldn’t the 30kg block go down by distance of the string goes down + the distance X the spring is stretched?
if the massles string is attached between both the blocks then both of them would have the same acceleration because they both are displaced by equal distances. so similarly if we use the same concept here where do we get it wrong
string is not stretchable but spring can be stretched... thats the difference...
In last question acceleration of both the bodies are kept same i.e. 'a' but in the second last question both the bodies had different acceleration. Both are connected by a spring.
Someone kindly correct me where i am wrong
For which grade are those exercises?
Sir if I am unable to solve this example videos, does that mean I need to work on my concepts or are these examples just for the demonstration of different methods of solving the problem.
And sir if I watch all the videos from this channel and solve all questions taught throughout lectures, will that be enough.
You basics are very poor they are very simple question just to revise and make weak points clear
THANKS YOU VERY MUCH SIR
Thank you sir
Sir, why did you not take the opposite direction of Spring in 2nd example?
Dont confuse yourself. Always treat the spring force of a fully streched spring similar to the tension force of string. Because they behave exactly the same way.
Sir plz explain both T nd kx applied on both ends of spring? Why T is acting upward near the pulley bcoz T always acts away from the contact point... Plz explain
sir the first example how you wrote the equation 60 - kx = 15 x 2 as in according to the formula f = - kx then how you came to this equation pls explain this sir .
after watching his viedo physic become just like a game 🤯🤯🤯🤯
8:42 I think T here should be downward
Sir what if we stretch one end of the string and other end of the string with different forces
Then also net force will be in one direction. That will be in direction of greater force.
@@ashishchauhan2335 no we have considered the spring to be massless here if There is a for on a massless object its acceleration will be infinite so we will have to take a spring with mass then
@@madihasiddiqui4540 oh plz understand his question. He is actually talking about the external force on spring mass system.
@@ashishchauhan2335 oh ok then i thought he was asking what would happen if we strech a massless spring with unequal force👍
how are finding the gravitational forces sir
pl specify your query... do you want to ask how we measure gravitational forces or anything else...
Sir in last example in general.....the block of mass 30 kg is carry on the. Block of 40 kg !! Is it possible??
is it possible that they move with same acc just after they are released
sir when in a situation a spring and in another a string is cut .but one end being supported by a spring in which a spring is cut and string when it is cut. How to then calculate acceleration what will be the diff in magnitude of spring and tension instantaneously.the system in each case was firstly in equilibrium
This concept is covered in our booster classes of dynamics... you can search and watch these...
Physics Galaxy sir are they available on youtube
Sir in the 2nd question, why is the tension acting upwards, doesn't tension always act away?
Sir but in second example at pulley why u have shown tension in upward direction as it has to be downward
If you think about it it’s common sense
Think it that way
Imagine having a rock tied by a rubber band, the rubber band have the tendency to pull it up so the Tension will be pointing ☝🏼 up
Amazing sir
Sir agar friction presnt ..
Thank you so much .This video has helped me a lot.
Abin Antony neet preparation???
Harsh Abishek yes
Harsh Abishek yes
Bhai itna content kafi h neet ke liye? Aur channel kaisa h? I am class 11 student so I need some tips friend
@@HA-ty2om Bhai bawal chij hai
I recognize that handwriting from
Anywhere. The slader god
huh?
At 7.40 force is applied box have less acceleration than second .how it can
Sir but in book F = - Kx is given
-ve sign is used to show restoring nature of force...
Sir suggest me any way to study I am not able to concentrate for more than 10hours day on my studies
more than 10 hrs a day is not required for any exam...
I want to get cse sir so I need to work harder than it?
thank you sir it is helpful to me
Sir Am neet aspirant I have watched your all lectures of NLM . Are these sufficient I will also practise question .
is spring force is potential energy
spring force is due to the potential energy stored in it... force can never be potential energy...
Sir spring ki force ke saath kya hota h jab usko cut karte h.plz sir as soon as u can
जब स्प्रिंग कट करोगे तो स्प्रिंग फ़ोर्स भी जीरो हो जायेगा. जब स्प्रिंग ही नहीं होगा तो स्प्रिंग फ़ोर्स कैसे आएगा. हाँ अगर कोई दूसरा धागा कट कर दिया तो उसी समय सारे धागों का टेंशन जीरो हो जायेगा लेकिन स्प्रिंग का टेंशन इंस्टैंटली जीरो नहीं होगा
@@ashishchauhan2335 idk hindi 😐
When u will cut the spring spring force will be zero as there will be no spring. But if u cut any other string(not spring) then tension in all the strings which are connected to that string below the point of cut will instantly become zero but tenssion in the spring (if any) below the string which is cut will not become zero
@@ashishchauhan2335 thnkx
Ok😮
We are watching it after 8 years
Which pen do you use
what difference it will make... physics will remain physics....
Savage Ashish Sir
@@physicsgalaxyworld he was just curious to know cuz sir's writing is so goof, L YT tech team
sir at the end points the tension and spring force are in opp. direction?
thank you
Where are you now☺
Why the net sum of forces acting on string must be 0? I dont understand
Already covered in theory videos that on massless bodies net sum of all forces is always zero...
@@physicsgalaxyworld Thank you pg team for replying, it cleared my doubt🙏🙏🙏🙏🙏❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
Please make a video on-
To what height a spring will rebounce after compression when it is released from a height 'h'. If the one end of the spring is tied with mass m1 and the other with mass m2.
similar cases are already accounted in our advance illustrations...
i could not understand T=kx part
draw FBD of spring
T on one end and kx on other end
T - kx = m a = 0 ; m=0 as spring is massless
thnx Sir 4 ds video it's really good nd helpfull
are pg booster classes available.
Do not post same query repeatedly... it distracts other viewers... if you are using a common public platform then always respect and take care of interests of other users also...
sir, how can we find out the elongation of spring by both the blocks after some time.sir, please reply to my answer.
You need to watch our theory videos in proper sequence of this topic...
All Physics topics are already covered in our more than 4000 theory and concept videos with illustrations... You can watch these through our channel playlists or our website in properly organized way at www.physicsgalaxy.com or through our mobile app 'Physics Galaxy'
Sir if the accn is uniform so why we can use a=0 and from the first eqn we got value of x
acceleration is uniform(constant) but not zero...
Physics Galaxy thanks sir
Very nice video sir...
Sir I have a question..
Say we have two blocks of equal masses connected to the two ends of a spring of spring constant K and the whole system is kept on a smooth horizontal frictionless table. Now we apply two equal pulling forces on both the masses and as a result both the masses get displaced by (x) metre say.. Naturally the spring will extend by 2x metre.
Now we apply the energy conservation principle
Elastic potential energy stored in the spring = Net amount of work done on both the blocks
Now,
Elastic potential energy stored in the spring = 1/2*k*(2x) ^2 = 2kx^2
Net amount of work done on both the blocks = 1/2*k*x^2+1/2*k*x^2
= kx^2
But these two values are not equal
Sir please explain why??
You missed the kinetic energy gained in the two blocks which is maximum at equilibrium position and at extreme position forces are not balanced so blocks will start moving in inward direction... think again on the situation!!!
this they would have sale acc
Pl specify what you wish to ask ?
sir in the first example why have u taken different acceleration for 10 kg and 15 kg block
because force on both blocks are different...
sir still my concept is not getting clear. sir the spring is equally stretched on both the sides. so their displacements must be equal
Not necessary, one end can be kept fixed and other end is displaced...
sir iam btech graduate from low level private engg. college can i get job as physics faculty in good coaching institute
Thanks Sir 😊
God bless u sir