Titration of a strong acid with a strong base | Chemistry | Khan Academy

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  • Опубликовано: 13 янв 2025

Комментарии • 38

  • @113-n1q
    @113-n1q 8 лет назад +55

    i can pretend i understand it

  • @mbtisocialclub
    @mbtisocialclub 6 лет назад +7

    This video is perfect . Very well explained and right to the point . Easy to understand compared to my chem prof ...

  • @Hakseng127
    @Hakseng127 8 лет назад +11

    plz mention end point, indicators, buffer region, nd equivalance point too

  • @icassipops
    @icassipops 6 лет назад +6

    that's the very first "not that helpful" "complex" khan academy video i've ever watched but anyway thanks for the effort

  • @pasha1339
    @pasha1339 10 месяцев назад

    This man is the best. Thank youuuuuuuuuuuuuu

  • @b-b-ntheboy5613
    @b-b-ntheboy5613 3 года назад +1

    Thank you very much it was exactly what i was looking for

  • @nurlybektoktarov469
    @nurlybektoktarov469 3 года назад +5

    Lifehack: put it at the speed 1.5 and Khan Academy will speak like normal human 😄

    • @Chirp-chirp
      @Chirp-chirp Год назад

      Really? I feel like he speaks so much faster in the chem videos compared to the math ones

  • @OctobrTea
    @OctobrTea 3 года назад +1

    thank you soooooooooooooooooooooooooooooooooooooooooooooooooo much

  • @chamyke
    @chamyke 7 лет назад +3

    Thanks for the video it is very useful:) I have an other (for me easier ) way to find the concentration of H3O+.
    You have all in all 20 ml of HCl , it will be added 10 ml of NaOH which is 1/2 of the whole amount.
    So you can say: [H3O+] = 0,5*1/2* 20ml/30ml = 0,167
    PH = -log (0,167)= 0,777

  • @zidamv1944
    @zidamv1944 3 года назад

    very well explained sir ! thank you

  • @ran9628
    @ran9628 6 лет назад

    Thanks!

  • @emilys.8347
    @emilys.8347 4 года назад +1

    Is it possible to titrate a strong base (analyte) with a strong acid (titrant)??

    • @peybak
      @peybak 4 года назад +2

      Yes, the curve will be the opposite of this one, meaning that the starting pH will be high.

  • @khattakfarhan9854
    @khattakfarhan9854 7 лет назад

    thank you so much sir

  • @kimmadarimot9868
    @kimmadarimot9868 4 года назад

    hello just want to ask. Is the hydronium ion concentration of a strong acid titrated with a strong base equal to the concentration of the strong base at the equivalent point?

    • @sabaakbar7427
      @sabaakbar7427 3 года назад +1

      At end point/ eq.point conecentration of hydronium ion is more than conetration of base in that case that is why solution is acidic in nature because all base moles have been neutralized with moles of acid but acid moles are more than base

  • @dayanacheong901
    @dayanacheong901 8 лет назад

    can the calculation of the titration of strong base and strong acid use the handerson hasselbalch eqn?

    • @jakobj58
      @jakobj58 8 лет назад +1

      no. you can only use the henderson.hasselbalch equation for weak acids because every molecule of the acid is deprotonated. the equation would then be: ph= pks - log(0/A-)
      -> ph = pks - log (0). log (0) is not defined

    • @cry_csgo
      @cry_csgo 6 лет назад

      Nina Dobrev that's the formula for finding pH

    • @갱갱항상
      @갱갱항상 3 года назад

      No. The Henderson eq is used ONLY for buffers

  • @rustyshackelford3590
    @rustyshackelford3590 8 месяцев назад

    The MCAT can go to hell for making us do this without a calculator.

  • @esa2236
    @esa2236 8 лет назад +4

    Thanks so much for the video, but I think all the extra explanation like converting ml to L is very excessive if this video was made for students in organic chemistry....

    • @TheRelentlessPPL
      @TheRelentlessPPL 8 лет назад +4

      Skid some do this in high school so let it be Mr. Chemistry

    • @brainphelps1994
      @brainphelps1994 8 лет назад +3

      no skid is right if you're doing this in high school and don't know how to convert moles and mL and all that crap you are the anomaly. The conversions are tedious

  • @kristinmcelroy5356
    @kristinmcelroy5356 8 лет назад

    how do i find Ka from this

    • @benhardsim8629
      @benhardsim8629 5 лет назад +3

      i know i am 2 years late , but maybe its gonna be useful for someone else .
      you cannot find the Ka because this is a strong acid and base solution .

    • @abdulmunimjundurahman7923
      @abdulmunimjundurahman7923 3 года назад

      @@benhardsim8629 After 1 years you helped someone with the same question.

  • @laraibkhan9102
    @laraibkhan9102 4 года назад

    anybody help me in solving some chemistry problems ASAP ??

  • @arbindapandey1711
    @arbindapandey1711 5 лет назад

    I didn't understood why the concentration of H3O+ was also 0.500M.

    • @beneastman9244
      @beneastman9244 5 лет назад

      Strong acids completely dissociate in aq solutions. So, the concentration of H3O+ is going to equal whatever the concentration of HCl is because there is no base added yet.

    • @beneastman9244
      @beneastman9244 5 лет назад +1

      In other words, every single H+ that was once bound to Cl- is now bound to H2O.

  • @stoneluo8986
    @stoneluo8986 4 года назад

    why cant you just get khan to explain ...

  • @filipdepay4155
    @filipdepay4155 4 года назад

    pozdrawiam 8 grupe !

  • @terrencegreen755
    @terrencegreen755 3 года назад +1

    thank you!

  • @khattakfarhan9854
    @khattakfarhan9854 7 лет назад

    thank you so much sir

  • @khattakfarhan9854
    @khattakfarhan9854 7 лет назад

    thank you so much sir

  • @priyankapal5599
    @priyankapal5599 3 года назад

    Thank u so much sir