The (2kN/m * 20 m) represents the force resultant of the entire distributed load. The 10m is the arm for the moment, which represents the distance from A to the force resultant.
The moment distribution method is another good way (maybe best?) to analyze statically indeterminate beams and frames by hand....there are also the slope-deflection equations. There are videos for these techniques in my structural analysis playlist.
This video was very good; yet very simple. Can you post a video where you have a 2nd degree indeterminacy showing all the work without using the equations from standard shapes that came from the book. Thank you
Thank you so much, StructureFree! This video helped a lot to understand what superposition and compatibility for statically indeterminate beams means. Keep up the amazing work! :)
is it possible for you to do a truss example? using the flexibility method, also, I couldn't find anything about support settlements, can you explain the concept ? thank you, great channel. It has everything that I need.
Hi Can you please explain how to calculate the deformation equation for each sub-structure? Should I treat each sub-structure as a seperate problem (finding the reactions,singularity equations etc...) and then at the end compare the displacements at a certian point?
Sir, I'm a civil engineering student. I have an assignment from my lecturer related to this question. In the data, there was live load and dead load for the uniform distributed load. From what i learn, when we calculating the deflection of a beam, we only use the unfactored live load (does not add the 40% safety factor). In this case, do i need to use an unfactored live load, or should i use factored live load?
Sir.. there is a confusion here..as i know bending moment is either maximum or minimum where there is shear force gets zero .but Here maximum bending moment occurs at support where shear force is zero. It should be at distance of 0.374 from support ..please clear my doubt. Sir .
Thanx for the detailed method. But I have a question. At 7:26 the equation of equilibrium of moments, the moment from the distributed load. From where it came - (2kN / m) (20m) (10m)? Should not it be - ((2kN / m) (20 m) ^ 2) / 2? I understand that is the same but why did you use it?
Yes, Ax = 0 since there is no loading in the horizontal direction. Ax would not equal 0 if there was a horizontal load. The pin support at A would prevent the beam from rolling. Hope that helps.
Yes it helps :) Thank you a lot by the way for the video, the amazing explanations and your answer. This video just made me win enormous time that I could spend looking in the litterature. Is there another way to decompose the beam ? Actually, I'm dealing with a spar for an aircraft wing that is fixed in its two ends (weird wing), and after decomposing I can't find the deformations in my simple case in the books, so I was wondering if there are different ways to decompose the beam, or only one ?
How do you see that the number of reactions are 4? I am looking at it and only seeing 3 types of reactions (vertical, horizontal and uniformly distributed load). Kind regards
Would you please do an example of an indeterminate structure, Sheeting Calculation, for a beam(12ft) with 3 supports(4.75ft center to center), uniform load(700.96PSF), with overhangs(1.5ft and 1ft) on both ends. I don't understand how to do the Moment Digram and I think it would be a good real world useful example.
structurefree My goal is to find the max moment along the beam. I'm designing sheeting for a trench and my method of doing this calculation requires the max moment along the beam and location of that moment. I'm able to get through the shear digram, but i'm having trouble with the moment digram.
I think I got these off of charts and tables in the appendices of my mechanics book. You could always use double integration, virtual work, conjugate beam, mom-area, or others to calculate deflections.
Amazing videos. Are there algebraic solutions for the reaction forces of such a 2-equal span, UDL beam? There are for point loads. I'm having a dickens of a time coming up with an algebraic solution, even using some calculus. ANYONE?
The (2kN/m * 20 m) represents the force resultant of the entire distributed load. The 10m is the arm for the moment, which represents the distance from A to the force resultant.
I'm about to ball on this exam now!! thanks daddy
Shoutout to Farshard coming from Javi and Isaac. Structure Free, keep being a homey and thanks for the videos!
Not homeless, therefore homey.
structurefree Haha I just saw this, but I meant "Homie". Homie, someone who is more than just an acquaintance but instead a dear friend.
You're the best! You saved my final project
The moment distribution method is another good way (maybe best?) to analyze statically indeterminate beams and frames by hand....there are also the slope-deflection equations. There are videos for these techniques in my structural analysis playlist.
This video was very good; yet very simple. Can you post a video where you have a 2nd degree indeterminacy showing all the work without using the equations from standard shapes that came from the book. Thank you
Thank you! I wish for more complicated continuous beam.
where did you find the 384 and the 48? and what kind of material is this beam constructed with? Trying to solve something similar with timber.
very simple and easy to understand instructions .. great ...liked it
Thank you so much, StructureFree! This video helped a lot to understand what superposition and compatibility for statically indeterminate beams means. Keep up the amazing work! :)
is it possible for you to do a truss example? using the flexibility method,
also, I couldn't find anything about support settlements, can you explain the concept
?
thank you, great channel. It has everything that I need.
hey Farshad bro, homework is due tomorrow! we need it right now.
Is there any video, when you use the moment-area method, to calculate reactions and deflections on a indeterminate beam?
Mar Agu no, but if you know how to find reactions and draw the shear and moment diagrams, then the process is the same.
Hi
Can you please explain how to calculate the deformation equation for each sub-structure?
Should I treat each sub-structure as a seperate problem (finding the reactions,singularity equations etc...) and then at the end compare the displacements at a certian point?
Sir, I'm a civil engineering student. I have an assignment from my lecturer related to this question.
In the data, there was live load and dead load for the uniform distributed load.
From what i learn, when we calculating the deflection of a beam, we only use the unfactored live load (does not add the 40% safety factor).
In this case, do i need to use an unfactored live load, or should i use factored live load?
+Shawn Hon typically deflection calcs use service loads (or unfactored) loads.
+structurefree Thanks a lot.
Sir.. there is a confusion here..as i know bending moment is either maximum or minimum where there is shear force gets zero .but Here maximum bending moment occurs at support where shear force is zero. It should be at distance of 0.374 from support ..please clear my doubt. Sir .
Thanx for the detailed method. But I have a question. At 7:26 the equation of equilibrium of moments, the moment from the distributed load. From where it came - (2kN / m) (20m) (10m)? Should not it be - ((2kN / m) (20 m) ^ 2) / 2? I understand that is the same but why did you use it?
Question: Can you remove any support or load when configuring the superposition?
Main Shark yes, as long as it makes the structure statically determinate.
can i solve the problem by same method if the span AB and BC has different udl?
these videos are so good, thanks man!
edballs thank you! please like me on facebook.com/structurefree
Thank you, it was great, please can you do the same problem in moment distribution method? So we can learn it also.
may i ask u , how do u get the deflection for B & redundant B ??
Thank you for this video;
I guess the Ax=0 in this case. If yes, how can it prevent the beam from rolling ? I mean what's its purpose ?
Yes, Ax = 0 since there is no loading in the horizontal direction. Ax would not equal 0 if there was a horizontal load. The pin support at A would prevent the beam from rolling. Hope that helps.
Yes it helps :) Thank you a lot by the way for the video, the amazing explanations and your answer. This video just made me win enormous time that I could spend looking in the litterature.
Is there another way to decompose the beam ? Actually, I'm dealing with a spar for an aircraft wing that is fixed in its two ends (weird wing), and after decomposing I can't find the deformations in my simple case in the books, so I was wondering if there are different ways to decompose the beam, or only one ?
why is there a moment at the mid roller support?
Thank you so much for these videos.
How do you see that the number of reactions are 4? I am looking at it and only seeing 3 types of reactions (vertical, horizontal and uniformly distributed load). Kind regards
+Theperkerify I guess that the uniform load doesn't count?
Can you perhaps do the same example but this time with 4 supports would be really helpful to me
how about determining its natural frequency? How one does that in this kind of system?
can you kindly let me know which method should we use when the redundancy is more than 3 in indeterminate beams
We can use Matrix Analysis Method..:P
That is not a structural analysis 2 method bro :p
Would you please do an example of an indeterminate structure, Sheeting Calculation, for a beam(12ft) with 3 supports(4.75ft center to center), uniform load(700.96PSF), with overhangs(1.5ft and 1ft) on both ends. I don't understand how to do the Moment Digram and I think it would be a good real world useful example.
what do you mean by "sheeting calculation"? a roof? moment distribution method?
structurefree My goal is to find the max moment along the beam. I'm designing sheeting for a trench and my method of doing this calculation requires the max moment along the beam and location of that moment. I'm able to get through the shear digram, but i'm having trouble with the moment digram.
Thanks from Brazil!!!!
hello, and question: how do u get the equation 0= (-5wl^4/384EI)+By*(L^3/48EI) for compatibility relationship. so important for me. thank u ~~
I think I got these off of charts and tables in the appendices of my mechanics book. You could always use double integration, virtual work, conjugate beam, mom-area, or others to calculate deflections.
+structurefree i still don't know where did you get the 384 and 48 here :3
Amazing videos.
Are there algebraic solutions for the reaction forces of such a 2-equal span, UDL beam? There are for point loads.
I'm having a dickens of a time coming up with an algebraic solution, even using some calculus. ANYONE?
thnks sir..:) ...can u do another example?? like fixed at the right and 2 roller support..:)..it wud be more nicer if so..:)
Question: what if I have a second degree redundancy?? plz answer
+Lina Alsarhan you'll have two compatibility equations.
+structurefree can you solve an example about second degree redundancy please
thanks man. U are a lifesaver
just thank you
Good one.. Thanks
How would you solve a beam that is indeterminate to the 2nd degree? (New video maybe? please?)
AYY YOU THE MANNNNNNNNNNN!!!!!!!
+Samuel Wickstrom "you da mang" -T. Montana
a)Finding R(b),R(c) and Slope(a) with ONLY 3 Rows and 4 Columns:Integral Method .
R(b)=25 R(c)=7.5 Slope(a)=125/3
Great stuff! :D
Right. I should have guessed. Thank you)
wow... confused for so long. Not anymore.
Thank you for your video
please can you make your background black
Regards
You sir are a fucking hero.... i would leave my gf to be with you
+Cat Master Race 👊
thanks,do you have facebook page?
+Abhishek Srivastava facebook.com/structurefree
cool
can i ask your e-mail i have a question about statistically indeterminate. hope you can help me. thank you.
word or should i say, palavra!
thanks,,,,,,,do you have facebook page?
yes. facebook dot com slash structurefree
Your microphone is static xddd
I have the best method for this.............
Bleeding from the ears...
Ha, me too. 🙉