Mod-01 Lec-12 Hamiltonian dynamics (Part 3)

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  • Опубликовано: 18 окт 2024

Комментарии • 29

  • @MarthamadaySaamanu
    @MarthamadaySaamanu 10 лет назад +8

    Around 30:00 he gives an exercise with central motion in three variables where he defines a new momentum variable as p_1 - p_2. But the correct definition of the new p is mu*(v_1 - v_2) where mu is the reduced mass. His entire commentary that follows does not get affected though.

    • @jimshilleto5655
      @jimshilleto5655 7 лет назад

      Thanks for that. I knew it wasn't right but didn't know how to fix it.

    • @gangadharbehera4227
      @gangadharbehera4227 2 года назад

      @@jimshilleto5655 szzzzzzzzzzzq

  • @elamvaluthis7268
    @elamvaluthis7268 2 года назад +1

    Indeed great.spontaineity is great.

  • @elamvaluthis7268
    @elamvaluthis7268 2 года назад +1

    இயற்பியலில் கவனகர் இந்தப் பேராசிரியர்.

  • @nazishahmad1337
    @nazishahmad1337 4 года назад +2

    The relative momentum p ≠p2-p1
    But relative momentum p= (m2p1-m1p2)/(m1+m2).

  • @afreenhameed9414
    @afreenhameed9414 6 лет назад +1

    I am grateful for this lecture series, The prof is indeed amazing. What I find lacking is the lack of real life problems. Its all a bunch of theory and no analyses or case studies. This is what India always does. They make us into a walking encyclopedia.

    • @शिवहरिसेवा
      @शिवहरिसेवा 6 лет назад +7

      Afreen Hameed dude , he's teaching theoretical physics , taking most of material from land landau and lifschitz & Goldstein. These books are made for theoretical physics , the students there are well equipped and highly interested in this abstract nature of analytical mechanics. And one could actually say that until you don't clearly understand do he abstract derivation of laws in Hamiltonian and Lagrangian mechanics, you cannot " Apply ".
      And the lack of real life problems should not be much of an issue , because this course is for physics graduate students not engineers!

    • @afreenhameed9414
      @afreenhameed9414 6 лет назад

      @@शिवहरिसेवा u r right. I misunderstood what physics is. thank you for correcting me.

    • @Unexpectedthings007
      @Unexpectedthings007 4 года назад

      @@शिवहरिसेवा actually he is teaching engineers here🤣🤣🤣🤣🤣 but there ain't a lack of real life problems here if we atke a physical point of view a central force problem the harmonic oscillator problem are all real life and a great deal of them are used in quantum mechanics like the hydrogen atom problem.

    • @pafloxyq
      @pafloxyq 4 года назад +1

      Why don't you think of a real-life problem yourself...since you are acquainted with theory already...thinking of a real-life problem would be an interesting exercise

    • @Pranav_Bhamidipati
      @Pranav_Bhamidipati 2 года назад

      @@Unexpectedthings007 Are you sure he is teaching the UG program?

  • @sandeeppatidar1106
    @sandeeppatidar1106 11 месяцев назад

    Very grateful

  • @albertogotta4983
    @albertogotta4983 8 лет назад +1

    Very interesting video.

  • @Vishal-vp7pj
    @Vishal-vp7pj 10 месяцев назад

    Why square of linear momentum is not conserved in circular stadium

  • @Cb12500
    @Cb12500 5 лет назад

    how can i find out the hamiltonian equation of motion for acouple oscillator

  • @trivedeep
    @trivedeep 5 лет назад

    What happens if I add pi/10 to the circle 20 times?

  • @mjramanuj7676
    @mjramanuj7676 7 лет назад

    nice lec

  • @naveenpoonia5425
    @naveenpoonia5425 2 года назад

    why not take H , L and L_z instead of H , L^2 , L_z

    • @kushsharmusical_269
      @kushsharmusical_269 2 года назад

      For L you have to decompose it into it's components to verify the involution of Poisson bracket of L with Lz and immediately you will realise from quantum mechanical formulation that Lz aren't in involution with Lx & Ly but L^2 (=Lx^2+Ly^2+Lz^2) is.

  • @chandrababu4590
    @chandrababu4590 4 года назад

    Good

  • @live4Cha
    @live4Cha 9 лет назад

    in the context of last minutes of the lecture, what would happen if we had for pi the value 3 instead of 3.14...? if the ratio of a circle circumference C to the diameter D, or C/D = 3 instead of 3.14...? how would that affect the world?

  • @sarthaktiwari3357
    @sarthaktiwari3357 6 лет назад +1

    What does it mean by Hamilton's equations are integrable ?

    • @afreenhameed9414
      @afreenhameed9414 6 лет назад

      I wish I knew... I think he means whether Hamilton's eqs r solvable.

    • @शिवहरिसेवा
      @शिवहरिसेवा 6 лет назад

      sarthak tiwari That is to say that Hamiltons equations permit an exact solution. Which means that as Hamiltons equations are a set of ODE's and those might or might not have an exact solution . but for them to be integrable , means we need not for any approximation methods to evaluate the dynamical variables involved.