20:20 Tc=tpd+(tsetup+tpcq) tpd = d(c11) and suppose d(c12)>d(c11) so dc11 + (tsetup+ tpcq)= Tc 11 dc12+ ("+")=Tc12 we will take Tc12 as final Tc. It can accomodate the slowest path which means it can accomodate Tc11 as well as
Continuing with your brick analogy, hold time could be understood as the time the second brick should not be placed on the pedestal before the old man picks up the first brick which was already present on the pedestal.
The only lecture in the course that I wasn't able to understand. Sir please make it simple in the upcoming course. Everything was in air.
20:20 Tc=tpd+(tsetup+tpcq)
tpd = d(c11) and suppose d(c12)>d(c11) so dc11 + (tsetup+ tpcq)= Tc 11
dc12+ ("+")=Tc12 we will take Tc12 as final Tc. It can accomodate the slowest path which means it can accomodate Tc11 as well as
@16:40, can we take delay as 4.5?
Continuing with your brick analogy, hold time could be understood as the time the second brick should not be placed on the pedestal before the old man picks up the first brick which was already present on the pedestal.
notes me likhu kya ?
😊
The tale of Bricks and Oldmen🙂
19:16 cz slowest path delay i.e 6 sec
professors need to do a course on "how to teach? " , their knowledge is at sky level but teaching skills are absolute zero.
Definitely, so when are you going to take lecture on "how to teach? " . I will also join..