Defining Every Number Ever

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  • Опубликовано: 8 янв 2025

Комментарии • 746

  • @AnotherRoof
    @AnotherRoof  2 года назад +65

    Thanks for watching everyone! Don't forget to submit your questions on my subreddit for a potential 10k Q&A video. www.reddit.com/r/anotherroof/
    This concludes my series on defining numbers from the ground up, but there are plenty more videos to come.

    • @zaringers
      @zaringers 2 года назад +1

      @Spydragon Animations Simply use the definition with [(ac + bd, ad + bc)] for the integers. You can show that "negative * negative = positive". In particular, you can show that (- a) * (- b) = a * b if this is what you are unsure about

    • @NeatNit
      @NeatNit Год назад +1

      @Spydragon Animations The partition kind of "drops out" from the relation definition. Two elements are in the same partition if they are related. If you're being formal, you have to prove that (2,2) is related to (1,1) just as much as you have to prove that (-1,-1) is related to (1,1).
      I think, when he was at that part with the board and all the number pairs laid out in a grid, he was already being less formal - by that point he has shown that the definition is the same as our intuitive understanding of rational numbers, so he relied on our intuition to explain things visually without interrupting the rhythm with unnecessary proofs.
      I hope that helps, even if I'm a few months late :)

    • @i_like_treins3449
      @i_like_treins3449 Год назад

      I have learned *_e v e r y t h i n g !_*

    • @Anonymous-df8it
      @Anonymous-df8it Год назад +1

      Why didn't you define the real numbers as an integer-subset with a highest element, representing the sum of 2^(each subset-member)? This allows you to avoid the rational numbers altogether. Also, why don't you consider quaternions numbers?

    • @EmperorZelos
      @EmperorZelos Год назад

      I prefer (a,b)={a,{a,b}}

  • @huhneat1076
    @huhneat1076 2 года назад +541

    "Oh, so you like math? Name every number"
    This guy:

    • @cadekachelmeier7251
      @cadekachelmeier7251 2 года назад

    • @maximelectron9949
      @maximelectron9949 2 года назад +23

      Well... Have you heard of quaternion-surreal numbers?

    • @_wetmath_
      @_wetmath_ 2 года назад +18

      he didn't just name all the numbers. he defined all of them with axioms too

    • @FireyDeath4
      @FireyDeath4 2 года назад +12

      Yunno I kinda think someone stopped at one hundred and fifty-two meameamealokkapoowa oompa, seven googolplex and twenty-four
      :/

    • @neologicalgamer3437
      @neologicalgamer3437 Год назад +1

      @@FireyDeath4 Lmao

  • @jongy
    @jongy 2 года назад +510

    cant wait for 30 years down the line when after reviewing all of the foundations of mathematics he drops a 19 hr video proving fermats last theorem

    • @poketoscoparentesesloparen7648
      @poketoscoparentesesloparen7648 2 года назад +29

      i gennuenly don't know if you are using that as an exemple of "really hard thing to explain" or of "nobody solved this yet". If it is the second option... Someone did.

    • @jongy
      @jongy 2 года назад +57

      @@poketoscoparentesesloparen7648 the nature of his content is walking through proofs to explain really hard things.

    • @l8toriginal719
      @l8toriginal719 2 года назад

      I soooo hope he does!!!!

    • @yahhav345
      @yahhav345 2 года назад +22

      @@jongy that, and you need LOTS of math to do the proofing of Fermat's last theorem

    • @yahhav345
      @yahhav345 Год назад +2

      @@radbarij oh absolutely. I wad talking more about the requirements to even understand the proof, and only in a wishy washy, approximated way

  • @PaulJWells
    @PaulJWells 2 года назад +282

    As a graduate engineer I always thought I had a reasonable understanding of maths, now I see I was just given a box full of tools and shown how to use them, but with no explanation as to why the tools work. The biggest take for me from this video is that there is a fundamental difference between integers and naturals, the difference between the other sets being a bit easier to 'see'.

    • @pedroivog.s.6870
      @pedroivog.s.6870 Год назад +5

      Yes we usually use Z+ as a replacement for N as to unambiguously account for 0, even though these two groups just happen to represent the same numbers

    • @nHans
      @nHans Год назад +9

      Yes, engineering curricula are designed that way because you want to go out into the real world and start solving real engineering problems (and earning money) as soon as possible! You don't want to spend 4 years learning all about the fundamentals of math used in engineering, then another 4 years learning about all the physics used in engineering, then another 4 years learning about all the chemistry used in engineering ... it's turtles all the way down, and you'll die before you graduate! Besides, if you want to learn more, you can always do so later, either in your spare time (like I'm doing now), or by going back to school.

  • @bjarnivalur6330
    @bjarnivalur6330 2 года назад +73

    In Icelandic, Imaginary numbers are called _"þvertölur"_ or "Across Numbers" (It sounds a lot less awkward in Icelandic) and complex numbers are broken down to _Vertical_ and _Horizontal_ components (Or just length and angle, if that's what you prefer); Because Imaginary numbers are just as real as any other..

    • @Unknownlight
      @Unknownlight 2 года назад +16

      I like the term "lateral number" for English.

    • @angeldude101
      @angeldude101 2 года назад +6

      I personally treat complex numbers more geometrically than algebraically, so I call them "spherical numbers" due to their intrinsic connection to spherical geometry. The name also hints at the possibility of numbers for other geometries, which do in fact exist, though they lack some of the nice features of the complex numbers.

    • @gothenix
      @gothenix Год назад +8

      Polish doubles down on the imaginary and the number "i" is called "jednostka urojona" or "Deluded Unit"
      as though we've lost our marbles, and gone fucking mad square rooting negatives.

    • @Zaniahiononzenbei
      @Zaniahiononzenbei Год назад +1

      ​@@angeldude101that's really interesting, do you have a name for these other numbers? I've never heard of that, but it's really cool!

    • @angeldude101
      @angeldude101 Год назад +2

      @@Zaniahiononzenbei There are two main cousins of the spherical/complex numbers. One is called the "dual numbers," and the other is, depending on who you ask, either the "split-complex numbers," or the _"hyperbolic_ numbers." Knowing that the spherical unit squares to -1, I'll let you guess what its cousins square to.

  • @willjchill4274
    @willjchill4274 2 года назад +88

    these videos are actually some of the best educational content i've ever seen, please don't stop making content

  • @crimsondragon2677
    @crimsondragon2677 3 месяца назад +1

    30:45 “it’s like upgrading the operating system; it does everything the old one did, and more.”
    Little did he know that now upgrading your OS will remove features.

  • @phyphor
    @phyphor 2 года назад +131

    I don't know why it's said we can never fully write down pi when it's easy: π
    Sure, writing it down as a decimal number is hard, but if you pick the right base it's easy! In base π it's just 10. Now, sure, that's an absurd base for everything else but sometimes sacrifices need to be made!
    More seriously - I am loving your series so far. Thanks for the hard work you've put into it.

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +14

      You can also just write down the quantity without using the symbol for it. π is _defined_ as the integral of 1/sqrt(1 - x^2) on (-1, 1).

    • @xXJ4FARGAMERXx
      @xXJ4FARGAMERXx 2 года назад +5

      @@angelmendez-rivera351
      π = ∫ [ ̠₁ ¹] 1/√(1-x²)
      ?

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад

      @@xXJ4FARGAMERXx Yes

    • @defenestrated23
      @defenestrated23 2 года назад +1

      We can do the same tricks that we used to jump up a number system, to define pi, though it takes some steps. We need to define powers, using ordered pairs. Then we can define rotations, where powers of a complex number are equivalent if they give you the same complex number but scaled. That leads naturally to exp and ln.

    • @go-away-5555
      @go-away-5555 2 года назад +2

      Firstly, pi in base pi is not pi. It is "10". As that's how base systems work. But base pi doesn't really make sense, you end up with an unevenly spaced number line.

  • @walterkipferl6729
    @walterkipferl6729 2 года назад +145

    Okay, N to Z, Z to Q and to a lesser extent R to C have very standard definitions. I‘m really excited for what version of R you choose tho.

    • @markuspfeifer8473
      @markuspfeifer8473 2 года назад +25

      My favorite is the completion as a metric space. It requires a lot of conceptual overhead (if compared to dedekind cuts), but it’s so natural and gives a good intuition why we use reals to begin with

    • @louisreinitz5642
      @louisreinitz5642 2 года назад +4

      I like the Surreal Number construction of real numbers. I find it easier than dedekind cuts.

    • @DoIt-kz4fi
      @DoIt-kz4fi 2 года назад +4

      @@louisreinitz5642 surreal numbers define reals in pretty much the same way though;

    • @manuc.260
      @manuc.260 2 года назад +1

      Honestly opened up the video saying to myself "surely it isn't dedekind cuts", and was pleasently surprised

    • @ffc1a28c7
      @ffc1a28c7 26 дней назад

      @@markuspfeifer8473 tbf, you can directly do it without relying on the metric space definition of it (to show uniqueness, you need some of the field properties of it). It's not hard to show equivalence classes of Cauchy sequences in Q under the equivalence relation (xn)~(yn) when xn-yn goes to 0 is a field. We can take representatives that are increasing (really this is where it is identical to taking Dedekind cuts) to extract a nice ordering. There is a forced ordering on Z with -2

  • @NikBlackwell
    @NikBlackwell 7 месяцев назад +3

    2:15 Illustrating the gap between the whole numbers as being foamy is such a splendidly intuitive way of conveying that only a proportion of that space can be represented with fractions.

  • @FredTheRed27
    @FredTheRed27 2 года назад +78

    This is such an incredible video massive props to you for taking on such a massive project and such difficult concepts and explaining them in a way that I actually feel like I understand :D

  • @jaysonbunnell8097
    @jaysonbunnell8097 2 года назад +44

    oh my goodness when I saw a new proof video was out I got so excited I could hardly wait! Your channel is my comfort channel and I really appreciate the work you do, and the jokes and the math and the bricks and everything!! Thank you so much

    • @AnotherRoof
      @AnotherRoof  2 года назад +16

      Comments like these make my day, thanks so much for watching and sharing :)

  • @kenniw8053
    @kenniw8053 2 года назад +52

    "a super Saiyan set is one with cardinality greater than 9000"
    You're a fakkin mad genius

  • @wybird666
    @wybird666 2 года назад +79

    This is one of the most geeky, pedantic and "why does anyone care" videos I've found so far; but yet it is so beautiful (and nicely presented). The definition of negative numbers just drops out so easily.
    You did manage to refrain yourself from the obvious joke: "Z from the German for 'zee integers'" ;)

    • @nickmoore5105
      @nickmoore5105 Год назад +5

      “Geeky, pedantic and ’why does anyone care’” - Welcome to pure maths

    • @Tower_Of_Chaos
      @Tower_Of_Chaos Год назад +2

      Maybe it is because, as a British person, he pronounces z as "zed" instead of "zee"

    • @mmmmmmok5292
      @mmmmmmok5292 7 месяцев назад

      ​@@Tower_Of_Chaos and germans dont say zee they say die

    • @prototypeinheritance515
      @prototypeinheritance515 4 месяца назад

      For anyone who wants to now the actual answer: Z stands for Zahlen ich just means numbers

    • @user-xy5yg6se1k
      @user-xy5yg6se1k 2 месяца назад

      @@prototypeinheritance515 30:51

  • @costa_marco
    @costa_marco 2 года назад +4

    The most beautiful thing I saw in this video was that the question "why minus times minus is plus" never arises! It just is baked on the rules of the definition for the integers. Great stuff, marvelous presentation.

  • @Cammymoop
    @Cammymoop 2 года назад +50

    I'd love to see an appendix video of sorts on transcendentals, though that certainly sounds like a challenge to make. This series has been great to watch, thank you

    • @thomaspeck4537
      @thomaspeck4537 2 года назад +9

      Transcendentals are a subset of real numbers, (or maybe complex if you want) so they can be expressed in the same way. You just define it as the set of all rational numbers less than it paired with the set of rational numbers more than it.

    • @Cammymoop
      @Cammymoop 2 года назад +19

      Just realized I said transcendentals but I meant surreals. these names are getting out of hand

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +6

      @@thomaspeck4537 No, the transcendental numbers are a subset of the complex numbers, because the algebraic numbers are a subset of the complex numbers. The algebraic numbers are defined as the algebraic closure of the rational numbers, and this closure necessarily includes i. Therefore, they are not a subset of the real numbers.

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +2

      @@Cammymoop To explain the surreal numbers would require an entire video series. An appendix certainly would not be sufficient. You would need to start by changing the axioms of set theory, since in reality, if we are being rigorous, the surreal numbers do not exist in the Zermelo-Fraenkel axioms, even if you include the axiom of choice or its negation. You need axioms of set theory that are equipped with the ability to speak about proper classes, in order to define the surreal numbers.

  • @yanntal954
    @yanntal954 Год назад +5

    Here's a Dedekind cut definition of π:
    Lower set A = Union over all n in N of the sets: { r in Q : r < 4 * the sum from k = 0 to (2n + 1) of [ (-1)^k / (2k + 1) ] }
    Upper set B = Union over all n in N of the sets: { r in Q : r > 4 * the sum from k = 0 to (2n) of [ (-1)^k / (2k + 1) ] }
    You're welcome! :)

    • @acrm-sjork
      @acrm-sjork 4 месяца назад

      I'm just curious: if any finite sum of a series is a rational number, how comes that infinite sum jumps to irrationals?

    • @yanntal954
      @yanntal954 4 месяца назад

      @@acrm-sjork That's because the rationals are not complete. Real numbers have the completeness property saying that every converging series has a limit point in the set.

    • @acrm-sjork
      @acrm-sjork 4 месяца назад

      @yanntal954 not sure that I got why infinite sum of rationals MUST or even CAN be irrational? Why not all sums of rationals converge to rationals? It is not contradict your statement

  • @sphennings
    @sphennings 2 года назад +13

    You have an amazing teaching style. I really appreciate your approach of laying out a few axioms and incrementally building up to every topic covered step by step. One thing that shows up in a number of math explainer videos is the Monster group, but without a background in group theory I've never had a foundation to be able to make sese of any of the writing about it, besides "big number interesting". Given your incremental approach to explaining things a series of videos on group theory that build up to the point of having the context and understanding to make sense of statements like "monster group M is the largest sporadic simple group", would be super nifty.

    • @AnotherRoof
      @AnotherRoof  2 года назад +10

      I've mentioned this in other comments and maybe I'll go into more detail in my 10k Q&A video, but my PhD was in group theory and I would love to do a series on the various families of finite groups. That said, because it a topic so dear to me, I want to gain more experience to make sure I do the topic justice!

    • @sphennings
      @sphennings 2 года назад

      That desire to do a topic justice is seen in your work. Regardless of topic I'm excited to see what you'll work on next. :)

  • @markuspfeifer8473
    @markuspfeifer8473 2 года назад +19

    Loved the series! I don’t know how useful it is for someone who isn’t already familiar with this stuff, but I like the balance between intuition and rigor here

    • @spencersivertson9321
      @spencersivertson9321 2 года назад

      No intuition, all rigor

    • @markuspfeifer8473
      @markuspfeifer8473 2 года назад

      @@spencersivertson9321 that would be coq, but without comments

    • @pmmeurcatpics
      @pmmeurcatpics 7 месяцев назад +1

      Well, I was familiar with all the building blocks (relations, power sets etc.). The definitions of each class of numbers were completely new to me, though, but the explanations were impeccable and I understood all of them. So definitely very useful for me at least:)

  • @szymonsochacki3353
    @szymonsochacki3353 2 года назад +20

    Yessss I love your videos, nobody can explain math as good and simple as you!

  • @blacknole5034
    @blacknole5034 2 года назад +7

    This is incredible, you are the first person in my life that I help with patreon.

  • @GamezConZ
    @GamezConZ 2 года назад +8

    I've always loved educational videos, but this gets me some different levels of joy. I'm actually having popcorns right now while watching. Thanks so much for this series of videos!!

  • @Rissper.
    @Rissper. 2 года назад +21

    Really hoping to see Dedekind cuts definition of R, but it might be a bit too advanced for RUclips. Definitely gonna be a banger video though, we all know it

    • @gracenc
      @gracenc 2 года назад +5

      Me too. I don’t have the requisite knowledge to understand the formal definition, so I was hoping there would be a more intuitive way to understand them without getting rid of the complicated details; this channel seems very good at that.

    • @AnotherRoof
      @AnotherRoof  2 года назад +14

      @@gracenc Let me know how I do.

    • @markuspfeifer8473
      @markuspfeifer8473 2 года назад +9

      Dedekind‘s construction is relatively simple compared to completion of Q as a metric space. Most of the ingredients are readily available at this point in the series. But the completion thing connects most naturally to what we’re actually doing with reals

    • @strikeemblem2886
      @strikeemblem2886 2 года назад +2

      @@AnotherRoof You could perhaps take a moment to emphasize on what you wrote for the "R" block at 1:11:31, which might not be obvious from the chalkboard: That the "mother set" in this case is power_set(Q).
      .
      This is important because (1) it is a conceptual leap from the previous cases (where the "mother set" is just a cartesian pdt), and (2) R is somewhat different than N Z and Q in "size", in that its construction asks you to start from something much "larger".
      .
      (Explaining (2), "size" of infinite sets, etc... = topic for another video maybe?)

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад

      @@strikeemblem2886 The power set is not a Cartesian product.

  • @Alhyoss
    @Alhyoss 2 года назад +4

    At 59:00, you explain how to construct a Dedekind set, defining it as being all the elements of the rationals which are smaller than a given number (r). You then prove that this set will not have a maximum value, because of the density property. This implies (as you say in the video) that both m and r (in your demonstration) are part of the rationals.
    However, you then says that "this is how we define the real value r". But wasn't r supposed to be a rational? Otherwise we cannot use the density we used to construct the Dedekind set

    • @Temari_Virus
      @Temari_Virus 2 года назад +1

      Let's say that we have some rational number m that is smaller than r (which is assumed to be irrational). Then we can add a positive rational number n to m to make a new rational number that is larger than m but still smaller than r. And we can make n as small as needed because there is always another rational number between 0 and n.
      That's as far as I got, but I'm not convinced it's a complete proof since I haven't ruled out the possibility of there being a real number that is "smaller than" all the positive rational numbers but larger than 0

  • @LK90512
    @LK90512 2 года назад +1

    First of all, thank you for the massive effort you put in this video series, It's clear and very enjoyable.
    There are a few points about the construction of the reals that don't quite convince me:
    - 57:17 the definition of a dedekind cut seems incorrect. A and B should indeed be non empty and a partition of Q, and A shouldn't have a max (or B shouldn't have a min, equivalently). But the other defining characteristic is that a < b, for every a in A and b in B. This implies naturally that A and B are properly unbound without assuming it, but most importantly it prevents them from being disconnected, e.g. A=(-inf,0)u(1,2) and B = Q\A (which would satisfy your requirement).
    - 1:00:40 this is a bit more nitpicky but I think still relevant: the whole point of this construction is to define real numbers without mentioning real numbers, so the use of r is improper, because it requires us to already have a definition for it. We should simply redefine a rational number q as a cut whose B has a minimum (which is q itself), and define an irrational number as a cut whose B doesn't have a minimum. We can show how such a cut identifies a point on the real line through the examples of root2 etc, but no "point" r should appear in the initial definition.
    - 1:07:10 it seems to me that you're demonstrating that the real line is dense, not complete. It's not enough to prove that between every pair of reals there's another real (which is true also for Q). You should prove, if I remember correctly, that every upper bounded subset A of R has a supremum in R, i.e. a minimal element Sup(A) in R such that Sup(A) > a for each a in A (which is the true missing property of Q).
    We can restrict ourselves to any upper bounded halfline A in R wlg (omitting the details for simplicity), and the proof becomes almost trivial, sup(A) is exactly the number represented by the cut {A∩Q,Q\A} (minus the endpoint if included).

    • @AnotherRoof
      @AnotherRoof  2 года назад +1

      Broadly agree with the last two points -- I regret not taking greater care during the section on reals!
      Disagree with your first point though. Stipulating that A be closed downwards implies that a

    • @LK90512
      @LK90512 2 года назад

      ​@@AnotherRoof You're right I must have stopped at "goes on forever", but afterwards you actually provide a clearer definition of "closed downwards". Sorry about that.
      I saw you mentioned the upper/lower bound criteria at the end of the completeness section, but I found presenting the whole argument about the density of reals a bit misleading.
      This said, the subject is quite subtle and complex and putting it in an easily understandable way makes it even more challenging, you've made a remarkable job overall.
      Also thank you for taking the time to reply to my observations!

    • @AnotherRoof
      @AnotherRoof  2 года назад +1

      @@LK90512 Balancing making the material understandable for a more general audience versus being mathematically accurate is always a challenge, and this time I think I skewed too far to the former. Thanks for the comments though!

  • @jasmijnwellner6226
    @jasmijnwellner6226 2 года назад +3

    Your proof of the denseness of Q made me realise how denseness is related to division. It's so obvious now! Of course if a set of numbers (containing at least two members) is closed under averaging, it is dense! And if it's not closed under division of two, it's not going to be closed under averaging.

  • @rotor198
    @rotor198 Год назад +3

    im a last year student on physics and still find your channel so amazing and illustrative. keep on with this!

  • @MalcolmAkner
    @MalcolmAkner 11 месяцев назад +1

    Honestly one of the best maths channels out there. You actually go into the weeds of how it operates, and it's always a joy following you along. You never know what strange things you'll encounter.
    This idea that an equivalence induces a partition is just an excellent little nugget of how things operate. I'm trained in physics myself, but have always had a strong fondness for maths, and I can't help but see an analogy between equivalence relations and how they induce a partition, and the event of a uranium235 atom absorbing a neutron and fissioning. The job of physicists over time has been to account for all the bits, to make sure that the physics we are calculating is actually accounting for everything - and it's led us down some strange rabbit holes. It feels likely that you can derive some form of symmetry between a relation having equivalence and some conservation law in physics (like energy conservation - the way it functions is analogous to the parts of an equivalence relation, thermodynamically).
    Just speculating here, but this is what I love with this channel - you provide tools to facilitate the thinking of these kinds of thoughts!

  • @JavierRuizGonzalez
    @JavierRuizGonzalez Год назад +1

    At 52:46, when the expression is multiplied by 'q' is important to notice that q > 0, otherwise the ''.
    But we know that q is positive because we chose the right representative of the rational number.

  • @3rdand105
    @3rdand105 7 месяцев назад +1

    I'm actually proud of myself because I barely understood the information presented here. I'm going to have to binge watch your videos, I want to be sure I understand things of this nature.

  • @drippyeuler
    @drippyeuler 2 года назад +6

    At 59:35, since we want to use the Dedekind cuts to define the real numbers, if r is not a rational number (1:00:49) and not a member of Q, how can we then prove that there exists another rational number between m and r? Also, how are we certain that in the Dedekind cut, there aren't two or more irrational numbers? (great video btw)

  • @jakykong
    @jakykong 2 года назад +12

    In a very real respect, you're single-handedly undertaking what PBS Infinite Series was doing. :) I greatly appreciated that channel while they were active, but it turns out there are just not that many channels engagingly tackling topics at the foundations of mathematics outside of "headline-friendly" ones like trying to quickly explain Goedel's theorems ad nauseum. (I'm sure you'll get to those theorems, too, but if it's anything like this presentation, I expect it will be thorough and cohesive!)

    • @AnotherRoof
      @AnotherRoof  2 года назад +10

      It's funny you mention PBS infinite series, I was literally just thinking about that channel because I got a question asking if I'll ever make a video on the axiom of choice and I thought their video was good. I'm glad your enjoying my videos! A slight disclaimer: I'm not planning for every single one of my videos to be a deep dive into foundational topics, but I'll always try to approach ideas with my own style and an emphasis on rigour. Anyway thanks for watching :)

    • @jakykong
      @jakykong 2 года назад +2

      @@AnotherRoof Of course! I'm enjoying it, and it's been long enough since my university coursework that I appreciate the refresher either way. I find this stuff fascinating, even if it has very little bearing on my day to day life, but it's not at all like a bicycle; the gist of it may stick for ages, the details and practice not so much.

    • @Anonymous-df8it
      @Anonymous-df8it Год назад +3

      Why did they stop?

  • @nektariosorfanoudakis2270
    @nektariosorfanoudakis2270 Год назад +2

    Great for a start. Examples of additional stuff:
    1)Quotient systems of numbers, for example Z modulo an integer n. In particular, if n= a prime p, the only interesting case to be honest, then Z modulo p is a field, i.e. it satisfies all axioms satisfied by Q and beyond. It's an example of a finite field; it's incomparable to N, Z, Q, R, C etc. It can be shown that ANY finite field is essentially unique (i.e. unique up to isomorphism) and has q=p^n elements, where p a prime and n any integer from 1 and up. It's symbolised F_q. The prime p is called the Characteristic. Every field has a characteristic which is defined to be the smallest positive number that annihilates (i.e. if multiplied with, it zeroes out) all elements, equivalently the multiplicative unit, if such a positive number exists; otherwise the characteristic is 0. So, characteristic p means that 1+...+1 (p times) is 0, and is the first time we get 0 if we add 1 a non-zero number of times to itself, equivalently all other numbers in the list of 1+...+1 etc. are distinct. Likewise if we add any other element to itself consecutively.
    Every field has characteristic 0 or a prime number p. In the first case it contains a copy of Z, thus of Q (considering fractions), thus it's an extension of Q. In the latter it contains a copy of F_p. So basically, if we stick to only Q, R, C we miss out on plenty of action.
    2) Transcendental extensions: If F is a field and V a set of "variables" (could be finite or infinite) we can form the set of polynomials on the variables of V and call it F[V]. The elements of F[V] are called polynomials in V with coefficients in F. They are (including 0) the finite sums of monomials of F[V], who are in turn finite products of elements of V (could be empty, which gives 1), multiplied with an element of F (could be 1). If we copy the construction that gives Q from Z (it's called the "Field of Fractions" construction), we get the set of rational "functions" in F[V], symbolised as F(V). The idea is that F(V) is the smallest field containing F and the elements of V, which are considered ALGEBRAICALLY INDEPENDENT over F. This means they satisfy no non-obvious algebraic relation. In case V={x_1,...,x_n} this is just the sets of polynomials and rational "functions" in x_1,...,x_n repsectively. If furthermore n=1, then we get V={x} and we write F[x] and F(x) for the set of polynomials in x with coefficients in F and rational "functions" in x with coeffs in F. F(x) is called a simple transcendental extension. Basically, it behaves like π and e in R with rational coefficients, every algebraic relations using x and elements of F are trivial, i.e. they merely follow from the axioms of arithmetic, equivalently:
    a_nx^n+...a_0=0 => all coefficients are 0.
    3) Algebraic Extensions: We can add "algebraic relations" to F(V) above using quotient constructions (an example below), so that the images of V are no longer algebraically independent. Alternatively, if F, L fields such that F is a subfield of L (like Q in R and R in C) then L is algebraic over F if every element a in L satisfies a polynomial equation with coefficients in F.
    C is an algebraic extension of R since every complex number has a polynomial (more below), R is DEFINITELY NOT an algebraic extension of Q, in fact almost everything is transcendental over Q.
    So, in the example of F[x] x a variable over F, we can take any polynomial m(x) (a prime/irreducible polynomial for good results) and form F[x] modulo m(x). This isn't a field if m(x) isn't irreducible, in fact if m(x)=p(x)q(x) then p(x) and q(x) modulo m(x) would be non-zero, but their product m(x) is 0 mod m(x) by definition.
    If m(x) is irreducible, then F[x] modulo m(x) is a field, similar to 1), and is the "smallest" field containing F such that m(x) has a root; clearly x mod m(x) satisfies m(x) itself. If we define x mod m(x)=: ρ, then we call the above set F[ρ]=F(ρ) the simple extension defined by a root of m(x). The reason the above equality holds is that inverses of non-zero elements already exist, due to the following:
    F[ρ] is the set of all (unique) linear combinations of 1, ρ, ρ^2,..., ρ^(n-1) with coefficients in F. This is being proven by Euclidean division of polynomials. So, any such non-zero combination, corresponds to a polynomial g with a degree smaller than the one of m(x), thus it isn't being divided by m(x), and since m(x) is prime it must be relatively prime, thus there exist polynomials s,t such that sg+tm=1, which modulo m(x) gives sg=1 modulo m(x) (same proof works in 1) ).
    So we could define "square root of 2", and any other algebraic number in general, without dedekind cuts necessarily (if we aren't interested in ordering numbers on a line) as follows: Start with Q, form Q[x], then consider m(x)=x^2-2 which can be shown to be irreducible, and form Q[x] mod m(x). We could call it Q[j]=Q(j), where j is an "imaginary number" such that j^2=2 (note it could also be minus square root of 2). It contains all elements a+bj where a,b are rationals; any such writing is unique and if we have a non-zero element, we can find the inverse by multiplying and dividing with the conjugate element a-bj.
    Same construction can give us C from R, just take x^2+1 as m(x).
    In general if L is an algebraic extension of F, and a an element of L, then the polynomial of F[x] of smallest degree having a as a root is called the MINIMAL POLYNOMIAL, and it also happens to be the unique polynomial which divides all such polynomials. If it is defined to be m(x), then the smallest field containing F and a, F(a) is going to be essentially the same thing as the above construction F[x] modulo m(x). The degree of m(x) is called the degree of a. In particular F(a)=F[a]. Note that if F=L then the minimal polynomial of a is x-a which has degree 1.
    We can keep adjoining elements to a field F. If a is a root of a (w.l.o.g. irreducible) polynomial p, then we form F[a]=F(a), and then if b is a root of the (irreducible over F[a] ) polynomial q, we can form F[a,b]:=(F[a])[b]. In theory, every algebraic extension can be obtained by simple extensions, if we "take the limit" for infinite-dimensional extensions. So we can have Q[sqrt(2), sqrt(3)] etc.
    Theorem: Any field extension can be seen as a transcendental extension followed by an algebraic one.
    So, wlog for more "numbers" we can take, for example, C(x,y), C with two extra algebraically independent elements, identified by a "surface" over C if you do algebraic geometry, then you add the relation, say y^2-x=0 and you get... something.
    4) Algebraic closure. If you take the subfield of all complex numbers who are algebraic (over Q) you get the Algebraic Numbers. This is called the algebraic closure of Q, since every polynomial over Q has a root now (but without the additional transcendental elements of R and Q). You can always take the algebraic closure of any field! So, you can take e.g. F_3, the finite field with 3 elements, and form the algebraic closure of it, the smallest field with characteristic 3 s.t. every polynomial in it splits into linear factors. This is endless. You can form F_5[x,y,z], take field of fractions, then algebraic closure. The algebraic closure of C(x) deserves to be called the field of Algebraic Functions over C.
    5) p-adics. He mentions them in another video I think? You can combine them with all the other examples. "p-adics" in F(x) will end up being Laurent series in x, another example of field.
    6) Power series, Laurent series, Puiseux series, etc.
    7) Infinitesimals, that is, Levi-civita fields, Hyperreals, Surreals, etc.
    I hope I didn't forget anything!
    PS: Of course I forgot; Quaternions, Octonions and more exotic constructions like that.

  • @seejay_through_life
    @seejay_through_life Год назад +3

    wow this series was fantastic, but i was shocked at the end to see how many bricks you built up over the whole thing... amazing work

  • @SomeTomfoolery
    @SomeTomfoolery 2 года назад +3

    I had to pause this several times to revel in the mind blasts this gave me. It's insane how much sense it will makes now. Thank you for the concise explanation!

  • @ianmccullough1084
    @ianmccullough1084 3 месяца назад

    30:13 Experiencing all of the preceding videos coming together here is awesome.

  • @GinoGiotto
    @GinoGiotto 2 года назад +3

    Any comment about how much I love your videos would be an understatement

  • @cadekachelmeier7251
    @cadekachelmeier7251 2 года назад +56

    Any chance of you covering the Surreal numbers? It seems like a good place to go off of this.
    I'd also just like to say that I really like that you're using physical blocks for your axioms/theorems and stacking them together as you go. I think it's a great visual metaphor for how math concepts build off of a few foundational concepts.

    • @plopgoot5458
      @plopgoot5458 2 года назад +1

      do you mean the trancendental numbers?, or do you actually mean the surreal number that include: the number greater than every real nubmber and the rnumber less than every real muber but greater than zero?

    • @crosseyedcat1183
      @crosseyedcat1183 2 года назад +2

      @@plopgoot5458 He means numbers greater and less than any real number. Unfortunately the surreal numbers' construction require the use of transfinite ordinals and thus cannot be a set as there is no "set of all transfinite ordinals" in ZFC. They are a proper class.

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +2

      @@crosseyedcat1183 Is that an issue, that they are a proper class as opposed to a set? It is an important caveat, yes, but I fail to see what is so "unfortunate" about it.

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +2

      @@plopgoot5458 He is talking about the Conway surreal numbers, which extend the real numbers, and they are the "largest" ordered field, in the category theoretic sense.

    • @Anonymous-df8it
      @Anonymous-df8it Год назад +1

      @@angelmendez-rivera351 The non-self-containing-set collection isn't a set as it neither contains, nor excludes itself

  • @arsenypogosov7206
    @arsenypogosov7206 2 года назад +2

    Complex numbers are just the algebratic closure of the topologic closure of the groupification under multiplication of the groupification under addition of the monoidisation of natural numbers provided with the standart z-module stracture.

  • @Gebnar
    @Gebnar 2 года назад +1

    Can I just say, this is possibly one of the most societally beneficial channels on all of RUclips. Access to quality education is slipping in most of the world. You're doing the best work with this!

  • @Ezio_Beta
    @Ezio_Beta 2 года назад +4

    Wow this was an awesome culmination to an awesome series. I am not a mathematician, but I have taken some advanced courses (Real Analysis, Measure Theory, etc), so I knew more or less what you were talking about with all the "hand waving". I had never seen this conception of numbers, and I loved it! Keep up the great work!

  • @forivall
    @forivall 2 года назад +3

    I'm 10 years separated from my compsci BSci, and this video is an entertaining bit of bringing it back to the fundamental axioms of the inductive power of diagonalization. Great stuff.

  • @phrygianphreak4428
    @phrygianphreak4428 Год назад +1

    For as much as u didn't like the division demo, I liked it. It was cool to see how division creates a reflection along the zero line, literally dividing the integers in two. It reminded me of matrix transformations, and I love anything that involves transformations

  • @brendanobrien4095
    @brendanobrien4095 2 года назад +1

    Extremely well done as always. My freshman son enjoyed it with me. I think he got a little bit lost on the definition of reals but got through it. Interestingly, he struggled with complex simply because he'd never been introduced to them. As soon as I explained them he looked back at your definition and saw it immediately. Thank you so much for all the hard work!

  • @lukacsnemeth1652
    @lukacsnemeth1652 2 года назад +2

    this is becoming my go to channel on "seemingly easy things explained super thorough" section.

  • @TheQuicksilver115
    @TheQuicksilver115 2 года назад +2

    *STANDING OVATION* WOW! I am astonished at how clear this breakdown (or rather, build-up) series was! I am also flabbergasted by how incomplete my own understanding of our entire number system was. This all made so much sense and I really feel like I have a much more fundamental grasp on what all of these things, which I thought I had already understood, actually are and mean. Thank you so so much for this!! I can not imagine a world where your channel isn't as much of a cornerstone of internet mathematics as 3b1b or mathologer; you truly deserve it. Please keep up the incredible work, I really appreciate all of the time and effort that went into this as well as the risk you took on in embarking upon this journey. Can not wait to see what you do next!!

    • @AnotherRoof
      @AnotherRoof  2 года назад +4

      Thanks so much! Glad you found the videos useful -- plenty more in the pipeline!

  • @MythosHB
    @MythosHB 2 года назад +7

    "Dedekind dedicated his kind name"... lol

  • @bennobrueck9610
    @bennobrueck9610 2 года назад +4

    This is literally the best video i have ever watched. Please keep on making beautiful content like this!

  • @Joker22593
    @Joker22593 2 года назад +12

    When will you do the surreal numbers? I just learned about the (mostly) number "up the second" yesterday, and it's been a mind altering experience.

    • @diribigal
      @diribigal 2 года назад +2

      As you pointed out, something like that is a game, but doesn't have enough nice properties to even be called a number. But the surreal 1/ω^2, sure.

  • @mesplin3
    @mesplin3 2 года назад +5

    41:05
    I never saw why q != 0. I can see that if we were to include q=0 then this relation is no longer transitive.
    (p,q) ~ (r,s) : ps=rq
    => (1,1) ~ (0,0)
    (0,0) ~ (2,3)
    But
    (1,1) !~ (2,3)

    • @mrtthepianoman
      @mrtthepianoman 2 года назад +1

      There is a slight generalization of this construction in the mathematical subject known as commutative algebra. It is called the localization. However, even in this context, including 0 results in a structure that is not very interesting. en.wikipedia.org/wiki/Field_of_fractions#Localization

  • @luci1st43
    @luci1st43 2 года назад +17

    Well that title explains why it's a longer video

    • @Ekevoo
      @Ekevoo 2 года назад +2

      How do you see the video length before it's out?

    • @aurabozzi228
      @aurabozzi228 2 года назад +2

      OP has said it to his community

  • @JamesLewis2
    @JamesLewis2 Год назад +2

    I enjoy the slick example used by Walter Rudin to prove the density of the rationals: If p/q

    • @AnotherRoof
      @AnotherRoof  Год назад +3

      Yes! I contemplated using this one in the video but decided that the average of the two rationals is more intuitive but I agree regarding the elegance.

  • @henningpoppinga9381
    @henningpoppinga9381 Год назад +1

    Thank you so much! Really instructive masterpiece!
    Personally I would have added a remark on operator-preserving relation on top of equivalent relation ("congruent" relation), and on embedding (N in Z by identifying n with [(n,0)], e.g.), but I am sure that you intentionally omitted this.
    Only one high level critique: Your proof sketch of "completeness" of R appears to me to show only density rather than completeness on the real line (for every a

  • @djsmeguk
    @djsmeguk 2 года назад +46

    I was hoping you might explore how C starts to lose properties compared to R. In a sense R is the top of the "number pyramid". Because you lose ordering in C, and the other way, you lose completeness in Q. If you go to quaternions you lose more (commutativity), and octonions lose even more (associativity).

    • @stephengray1344
      @stephengray1344 2 года назад +16

      You lose any natural or intuitive ordering in C, but it would certainly be possible to define an arbitrary ordering. Start by saying that anything that is closer to the origin on the imaginary plane than x+iy is less than x+iy, and then define an arbitrary ordering for all the points that are equidistant from the origin (e.g. saying that x is the highest within that set, and then going clockwise around the circle).

    • @cadekachelmeier7251
      @cadekachelmeier7251 2 года назад +9

      @@stephengray1344 Or tile the plane with a Hilbert Curve.

    • @mrtthepianoman
      @mrtthepianoman 2 года назад +19

      You lose ordering that respects addition, sure. However, you gain algebraic closure, which is arguably a much stronger and more important property.

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +4

      @@stephengray1344 Yes, but no. In the context of fields, when we talk about ordered fields, we talk about fields with an ordering such that the field operations are isotonic (in a standard sense) with respect to the ordering. The real numbers are an order field. The complex numbers are not.

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +1

      @@stephengray1344 Also, specifying that an ordering does exist is sort of redundant, since by the well-ordering theorem, all sets can be well-ordered. I know the theorem requires the axioms of choice, but if you relax the conditions so that you only need a total order, then you can significantly weaken the axioms needed. Also, most mathematicians do accept the axiom of choice, despite it being controversial.

  • @zstrizzel
    @zstrizzel Год назад +1

    Your slight of quaternions has awakened the ghost of Sir Hamilton, who is now coming to haunt you until you make a video about hypercomplex numbers.

  • @GreatCollapsingHrung
    @GreatCollapsingHrung 2 года назад +2

    I’ve been eagerly, perhaps a bit impatiently, awaiting this video. I have to say that it was worth the wait. With the length and depth of this video, you certainly didn’t disappoint. Thank you! I can’t wait for the next one.

  • @alikaperdue
    @alikaperdue 7 месяцев назад +1

    Great. Please also do Surreal, p-adic, hyper real, hyperbolic, quaternion, octonion, sedenion and beyond.

  • @Bombito_
    @Bombito_ 5 месяцев назад +1

    43:58 i was flabbergasted

  • @tehlaser
    @tehlaser Год назад

    43:59 heh, I came back to this video after a while and noticed that you reached right through the naturals and the integers to grab the chalk to partition out the rationals, which is rather pleasing to my sense of irony.

  • @NeatNit
    @NeatNit Год назад +1

    Why do random pairs of bricks glow in the outro? For example at 1:19:12 two bricks - Function and Infinity Exists - glow magenta
    Brilliant videos all around, thank you for making such a great introduction! I've always knows that this construction existed, but I never looked up how it was actually done and it feels like a great old gap in my brain was finally filled.

  • @sdsa007
    @sdsa007 5 месяцев назад +1

    Thanks this was very thorough, and I can see how various ideas take the 'blocks' of number theory that you explain so well, and build a whole set of new theories out of them... i find this actually useful as a presrequisite to the PBS infinity series... Thanks!

  • @kruksog
    @kruksog 2 года назад +7

    I feel like you keep bumping right up against group theory and algebra. Hopeful to see some vids on those topics some day from you!
    Fantastic video as usual.

    • @AnotherRoof
      @AnotherRoof  2 года назад +10

      I mention here that my PhD was in group theory. I want to get more experience making videos before I make one on the topic I love the most!

    • @kruksog
      @kruksog 2 года назад +3

      @@AnotherRoof it's also my favorite area of mathematics, and I am REALLY enjoying your videos and style and just everything, hence my yearning for the topic.
      Whenever you do get to it, I'm sure it will be fantastic. Thanks again!

    • @brendanobrien4095
      @brendanobrien4095 2 года назад

      I've not looked at group theory at all but I kept feeling like category theory was around the corner. Not that I have a much of an understanding of that either :). I'm sure I'd enjoy your take on either/both.

    • @kruksog
      @kruksog 2 года назад

      @@brendanobrien4095 I only have an undergrad degree in mathematics so I haven't studied category theory at all (that's a graduate topic, 100 percent), but my understanding of it is that it is essentially another layer of abstraction on top of group theory/algebra (those terms are not at all interchangable, but whatever; it's fine for our purpose here.) Like, my understanding is that category theory is essentially an algebra of algebras. But again: I don't have any formal training in category theory. So if I'm wrong, that is not unexpected.
      Also, you should look at group theory. If you know what category theory is, you ought to know what group theory is :p. No judgment here, just a recommendation.
      It would be a cool video idea for sure though. Not sure how much another roof knows about category theory, but any video he wants to make is fine by me, cause he's killing it. I've rewatched every video at least twice and just loved every second of it.

    • @brendanobrien4095
      @brendanobrien4095 2 года назад +1

      @@kruksog You should understand that my path to this stuff is atypical. I am a software engineer and I took none of this in college. I came across category theory by way of lambda calculus which I was studying for applications in functional programming paradigms. This is the first I've even heard of group theory and I'm very interested if it relates to these topics.

  • @AssemblyWizard
    @AssemblyWizard 2 года назад +12

    Hoping that when going from Q to R we will also visit some other countable sets first- constructible, algebraic, computable, and definable numbers

  • @AbiGail-ok7fc
    @AbiGail-ok7fc Год назад +2

    The video omits defining the < relation for integers. It defines it for natural numbers: a < b is the same as a ∈ b, but it doesn't define it for integers. Yet, when defining < for rational numbers, it states it using < for integers.

    • @AnotherRoof
      @AnotherRoof  Год назад +2

      That's right! My original cut of this video was much longer but I wound up cutting out some stuff like this because it got a bit repetitive.

  • @vanderkarl3927
    @vanderkarl3927 2 года назад +9

    Hm, to get from a countable set to an uncountable set seems like a monumental challenge. I'm looking forward to the video!

    • @cadekachelmeier7251
      @cadekachelmeier7251 2 года назад +4

      He actually does it already at 5:00. The power set of an infinite set always has a greater cardinality than the original set.

    • @vanderkarl3927
      @vanderkarl3927 2 года назад +1

      @@cadekachelmeier7251
      I'm sure you're right, but that seems weird to me. It's just 2^(countable infinity), right? Why doesn't that just return countable infinity again?

    • @cadekachelmeier7251
      @cadekachelmeier7251 2 года назад +4

      @@vanderkarl3927 For reference, it's Cantor's Theorem. Honestly, it's pretty much the same logic as Cantor's diagonal argument. It's just more abstract because instead of reasoning about lists and numbers, you have to reason about any potential set and a set containing an infinite number of other sets. Other than that, it's just constructing an element that can't exist in any potential mapping, same as the diagonal argument.
      en.wikipedia.org/wiki/Cantor%27s_theorem

    • @diribigal
      @diribigal 2 года назад +2

      @@vanderkarl3927 Infinite Series on RUclips has a video on Cantor's theorem about why power sets get bigger, even in the infinite case.

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад

      @@vanderkarl3927 2^Aleph(0) is greater than Aleph(0). Cantor's theorem states that for all cardinal numbers κ, κ < 2^κ.

  • @sachs6
    @sachs6 2 года назад +3

    I knew you couldn't possibly be defining every number ever, but I could not imagine you would speak so fondly of Conway after leaving his surreal numbers out!

    • @AnotherRoof
      @AnotherRoof  2 года назад +4

      Maybe one day!

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 года назад +2

      In his defense, defining the surreal numbers would require an entire video series of its own.

  • @ursidaegames7605
    @ursidaegames7605 2 года назад +1

    John Conway is amazing, although I'll admit I mostly know him because of the Game of Life. As I recall, in an interview he expressed an annoyance that that was the thing for which he was known to many people (I believe it was a Numberphile video), but it's still a beautiful piece of maths (it's Turing complete too, as I recall), and exposed many people to cellular automata as a subject. Langton's Ant is another interesting automaton, and I got part way through trying to knit a scarf in the pattern of Rule 135, but never finished it.

  • @kleinesfilmroellchen
    @kleinesfilmroellchen 2 года назад +15

    Yorkshire man invents numbers. More news at 7 (which has just been invented)

    • @yshwgth
      @yshwgth 2 года назад +4

      More news at the set containing ...

    • @AnotherRoof
      @AnotherRoof  2 года назад +7

      Ey up! Ain't from Yorkshire pal.

    • @gracenc
      @gracenc 2 года назад

      *Man with an accent vaguely resembling the Yorkshire accent

    • @AnotherRoof
      @AnotherRoof  2 года назад +4

      @@gracenc vaguely Yorkshire? I'm from Lancashire -- and you're all lucky I'm not one of those proud Lancastrians who actually care about this sort of thing!

    • @kleinesfilmroellchen
      @kleinesfilmroellchen 2 года назад

      @@AnotherRoof haha that's what my friend characterized your accent as, I'm not a native speaker so 🤷‍♀

  • @patmcgibbon7263
    @patmcgibbon7263 2 года назад +1

    A really nice video. I love the sense of building on foundations, with literal examples of your building blocks. The time flew by, although I ended up watching it in a couple of bites, due to watching it during the working day. Couldn't wait until the end of the day! Really interested to see where you go next. And very happy to think that this community can be part of your escape plan. I only lasted a year as a maths teacher, and it took my wife twenty years to escape, so wishing you well in your attempt to make it out.

  • @MrRyanroberson1
    @MrRyanroberson1 Год назад

    52:37 a simpler and arguably more beautiful proof is via the ford sum. p/q = 2p/2q < (p+r)/(q+s) < 2r/2s = r/s. to prove the first < relation we cross multiply to get p(q+s) ? (p+r)q -> ps ? rq which is the p/q ? r/s relation. the same simplification happens on the second

  • @GynxShinx
    @GynxShinx 2 года назад

    1:17:07 The only way in which they would not be numbers is if you only require a number to be able to interact with others in maximum groups of pairs. Requiring numbers to be able to interact with 2 other numbers at once would create a bigger idea of what numbers are that would create more gaps. Funnily, only requiring numbers interact with 0 numbers would leave you with only the number you started with because all you can say is x exists, but not how it relates. The complex numbers complete the simplest number system that is actually usable and not just a single number.

  • @msclrhd
    @msclrhd 2 года назад +1

    I hadn't thought about constructing integers as a cartesian product over the natural numbers combined with the paired addition/subtraction relation. It's a very nice way of defining them.

  • @philb2972
    @philb2972 2 года назад +2

    great video!
    also nice glitch in the matrix at 44:00

  • @mrtthepianoman
    @mrtthepianoman 2 года назад +1

    Love the video! I wanted to point out though, that you proved that the reals are dense, not that they are complete.

  • @tastygold
    @tastygold 2 года назад +2

    This deserves WAY more views. Fantastic!!

  • @caladbolg8666
    @caladbolg8666 2 года назад +1

    An excellent overview for undergrads, presentation in amazing as always, great work!

  • @macronencer
    @macronencer Год назад +2

    17:00 I'm curious... I notice that only 4 of the 8 potential combinations of reflexive/symmetric/transitive are represented here. Do relations exist for all of the other possibilities, or are any excluded? In other words, are the three properties completely independent?

  • @solarshado
    @solarshado 2 года назад +3

    I was fairly familiar with the construction of the rationals from integers and complex numbers from rationals, but had never seen/considered the similar construction of integers from naturals! In hindsight, the parallels seem obvious, but I guess I'd never really considered "negativeness" with enough of a critical, "what _are_ you, really?" attitude.

  • @KrasBadan
    @KrasBadan 2 года назад

    This was a great series! I love everything about it, especially the requisite (like boxes for sets, thread for number line), *especially* these bricks. They are useful in a sense that they make it easier to memorize stuff and keep in mind what is currently important. Also they help create that unique style. I like that whenever you add one more it feels kind of like achievement in a videogame, and the new bricks are based on the previous ones. Please do more content like this.

  • @tejing2001
    @tejing2001 2 года назад +1

    Great build up. I'm more partial to type-theoretic foundations, myself, but set theory is the standard, and you put it all together really well, glossing over the right things, and focusing on the right things.
    A minor issue: At 1:05:08 you didn't make clear that it needs to be a *strict* subset. Technically you defined "less than or equal", not "less than", since you used a non-strict subset symbol in what you wrote down.
    A bigger issue: Your hand-wavy proof of the completeness of the reals is really only a proof of the *density* of the real numbers. One way to prove completeness would be to take dedekind cuts of the *reals* and prove that they always define an existing real number.

    • @HEHEHEIAMASUPAHSTARSAGA
      @HEHEHEIAMASUPAHSTARSAGA 2 года назад

      Yeah, the whole completeness section of the reals was pointless because it only showed density, which is a property the rationals already had.

  • @rajatchopra1411
    @rajatchopra1411 2 года назад

    16:09 After this explanation i pressed the like button so hard

  • @NStripleseven
    @NStripleseven 2 года назад +2

    The “A must have no greatest element” thing from the dedekind cut reminds me of Zeno’s dichotomy. To walk out of a room, you first have to walk halfway to the door, then half of the remaining distance, then half of the remaining distance, then half of the remaining distance, etc., etc.

    • @alexodom358
      @alexodom358 2 года назад +4

      Zeno's paradox, in whichever form it is presented, makes a number of unfounded and erroneous assumptions about both time and space that are irrelevant to the purely conceptual space of the number line.

    • @NStripleseven
      @NStripleseven 2 года назад

      @@alexodom358 oh, no, absolutely, the idea makes no physical sense, but it’s an interesting purely mathematical idea.

    • @JayTemple
      @JayTemple 2 года назад +1

      One of my high school teachers described it as getting half the distance to his girlfriend, then half of that distance, etc., with the conclusion that "Eventually I get as close as I need to," which sort of ties it into the concept of a limit.

  • @GaryFerrao
    @GaryFerrao 2 года назад +1

    you've explained this very well. and used props to its fullest use. immediate subscribe!~

  • @pedroivog.s.6870
    @pedroivog.s.6870 Год назад

    That was a journey I appreciated in every step! Thank you for the interesting explanations

  • @maxe624
    @maxe624 2 года назад +2

    You must have had RUclips experience before, your video quality is so good

    • @AnotherRoof
      @AnotherRoof  2 года назад

      Thanks! But no, apart from my livestream this is my fourth video :)

  • @EnisTuna
    @EnisTuna 2 года назад +1

    great intuition-approached explaination here master, looking forward to upcoming episodes of this series

  • @constantine6052
    @constantine6052 Год назад

    Thank you for your content!
    Saying about John Conway. In 1970s he wrote the book, "On Numbers and Games", where a new number system has been introduced. That system, as well as Conway's approach overall, was completely different from the traditional N-Z-Q-R-C. I would love to see another video on this topic :)

  • @herbie_the_hillbillie_goat
    @herbie_the_hillbillie_goat Год назад

    57:10 Dedekind Cut - named after the mathematician who dedicates his kind name. Brilliant! 🤣🤣

  • @PlaceholderAlex
    @PlaceholderAlex Год назад +1

    Dude I'd be absolutely enamored with this video if I was high. Even while sober, this is amazing. You have a great way of presenting information with a combination of tactile visuals and animation. I especially love when you give a few seconds for the viewer to apply a newly introduced concept. It builds confidence and I'm sure it helps with retention. Once I finish, I'm sending this to my old modern algebra teacher. Him teaching these concepts, where all of our assumptions are stripped away and we re-establish the fundamentals with a deep understanding is why I'm majoring in mathematics. I will be binging your vids.

  • @VaradMahashabde
    @VaradMahashabde 2 года назад +1

    This is actually amazing, I don't think any course actually goes through the building of all the number sets. Also, I noticed that if we let all numbers of the form (1,0) in rationals definition (we are never dividing after all), then we have natural notion of infinity (or rather, the point at infinity from projective planes).
    However, (0,0) still has to be excluded because it breaks transitivity of the equivalence (curse you indeterminacy).
    (1,0) + (a,b) = (1b + 0 a, 0b) = (b,0) = (1,0)
    (1,0) - (a,b) = (1b - 0a, 0b) = (b,0) = (1,0) if b is not 0 i.e. (a,b) is not (1,0)
    (a,b) - (1,0) = (a0 - b1, b0) = (-b,0) = (1,0) if b is not 0 i.e. (a,b) is not (1,0)
    (1,0) * (a,b) = (a*1, b*0) = (a,0) = (1,0) if a is not 0 i.e. (a,b) is not 0
    (1,0) * (0,b) = (1*0, 0b) = (0,0) = 0
    (a,b) / (0,c) = (a * c, 0b) = (ac,0) = (1,0)
    (a,b) / (1,0) = (a*0, b*1) = (0,1) = 0
    But the following dont work because indeterminacy
    (1,0) - (1,0) = (b,0) - (a,0) = (b*0 - 0*a, 0*0) = (0,0)
    (1,0) * (0,1) = (1*0, 0*1) = (0,0)
    Of course, addition and subtraction have lost associativity, and (1,0) has no inverse, like (0,0) = (0,1).

  • @stevenraanes4786
    @stevenraanes4786 2 года назад

    YESSS! I've been waiting for this one since that tease at the end! Thank you for all the effort you put into making these!

  • @FareSkwareGamesFSG
    @FareSkwareGamesFSG 2 года назад +2

    I don't know if he took my suggestion of laying down the bricks like a wall in his outro, but regardless of whether he did or didn't, it looks cool. It feels like we all laid the bricks together. Though with math, it took us quite a few hours to get there...

  • @Happy_Abe
    @Happy_Abe 2 года назад

    @1:05:05 it should be a proper subset. If the sets are in fact equal, then we have a less than or equal to situation, not strictly less than.

  • @Mik1604
    @Mik1604 2 года назад

    Take a bow, I loved everything about this video. Very, very well done.

  • @3snoW_
    @3snoW_ 2 года назад +6

    I was curious about the proof that the real number are continuous, at 1:06:50 you hint at it but it seems to me that all you are proving is that the real numbers are dense, as in there's never an empty gap. But the rationals share that property, you even proved it, yet there were numbers that were missing. How can we be sure that there are no numbers hiding between the real numbers?

    • @Reddles37
      @Reddles37 2 года назад +5

      Agreed, it seems like he left out the key part of the proof. As I understand it the way to prove the real numbers are continuous is to do the dedekind cut procedure again using the real numbers, and then you can show that the resulting number is just another real and doesn't give you something new.

    • @diribigal
      @diribigal 2 года назад +2

      It's very subtle. In one sense, there are numbers between the real numbers, because you can put more numbers on the line with constructions like Robinson's Hyperreals or the Surreal Numbers, etc. But in another sense, the reals are gapless in a way those things are not: for instance, if you have a nonempty set of reals that doesn't grow arbitrarily big (e.g. maybe they're all less than a million), then there is a "cap" real that is greater than or equal to everything in the set, but smaller than any other candidate. (The cap may or may not lie in the original set. Think about intervals like (0,1) and [0,1], both of which have cap 1.) This "dedekind completeness" works for the reals and stops working if you try to stuff even more numbers inside.

    • @mrtthepianoman
      @mrtthepianoman 2 года назад +1

      The short answer is, it depends what you mean by a number. There are number systems (see hyperreal numbers or surreal numbers) in which there are other numbers hiding between the real numbers. What is meant in this context is that the real numbers are "complete" (this is a technical term). There are several equivalent definitions of what this means, but perhaps the simplest one to see (relative to this video) is that if we were to repeat the process of taking Dedekind cuts we wouldn't get any new numbers. That is to say, instead of the sets A and B consisting of rational numbers, say they consisted of real numbers. Then the set of Dedekind cuts of this form would just be the reals again and wouldn't contain any new numbers.

  • @defenestrated23
    @defenestrated23 2 года назад +1

    This was amazing. I think the next logical step is to define complex numbers as the pair of pairs (matrix) [[a, -b], [b, a]]. This allows you to use the relations to define more equivalence groups, and create new kinds of numbers, like the split-complex and the dual numbers. It also allows you to define rotation, boost (hyperbolic rotation), and "dual derivatives", which are like "rotation" around a point at infinity. The latter allows you to define calculus with just sets.
    Dual numbers are really cool. Even though you just need *C* for algebraic closure, dual numbers give you a "back door" to defining calculus without needing limits or any of the usual calculus introductions. You just need ε, which is [[0,1],[0,0]] and the rules you have thus defined (though I guess you need functions first!)
    Of course, ε ties in with surreal numbers, which is also a logical extension of this video!

  • @rulojuka
    @rulojuka 6 месяцев назад

    First of all, I am loving your videos. They are exactly the kind of introduction and review that I would have loved to have during graduation.
    After that, I didn't understand what you meant by "gap" when talking about the reals and why they don't have it. For N and Z I understand that you can choose 2 elements that have nothing between them but for Q you just proved that you can't. So I got very confused there. Especifically, this jump for the "real line" was very confusing. If Q does not make a line (I assume because we know that some numbers like the root of x*x=2 are not there) then it seems to me that we can always create that non-existent element for our new set (R, C, etc..)
    (I could research for density vs completeness but the point is that I didn't understand it from the video. Also, it was the *only* thing I didn't understand so, again, very well done!)

  • @SiqueScarface
    @SiqueScarface Год назад +1

    I would like to explain the concept of negative numbers with an old joke: A mathematician leaves an empty room. He sees two people entering this room. Then five people leave the room. And the mathematician thinks: Ok. Now three more people have to enter the room, and it is empty again.

  • @MeshremMath
    @MeshremMath 2 года назад +2

    I am so excited!

  • @macronencer
    @macronencer Год назад

    1:07:46 Quick question: when you write the subset operator you draw a line beneath it. That line feels like the line in a "less than or equal to" sign, and since in this case you wanted a proper subset, why doesn't the notation for that simply remove the line, instead of forcing you to do that awkward crossing out? I actually seem to remember that the symbol without the line used to mean "proper subset" (I got my maths degree in 1986). Have I remembered that incorrectly? I know memory can play tricks!