Salamat sa effort. Helped a lot. Hoping you can come up with a clearer presentation tool. But all in all its a thumbs up sir. Kudos to you & your future tutorial videos.
I just would like to comment on the use of Kh & Kz...Kz is used in determining the qz (velocity pressure) which is variable with height(z). Whereas Kh is used in determining qh (constant velocity pressure) calculated using mean height. Normally, the windward pressure varies with height while the leeward is constant.
sir ask ko lang po ano na po next step after po makuha both burst and suction condition pressures? ano po ang pipiliin sa dalawa? gagamitin po ba yung dalawang yon for member analysis po kung sakali?
Evening po Sir Ask ko lang po sana kung ano po yung basic wind speed sa palawan? Wala po kasing nakalagay sa figure ng category 3, 4 at 5 po para po sa palawan.
Sir pwde ba malaman yung truss analysis kasi yung sa explanation nyo puro leeward yung sa roof. Nasanay kasi ako na windward lang yung kinoconsider sa analysis ng truss at yung leeward walang value.
Burst condition kasi yung ni consider ko, it shall be uniform from leeward, windward, and roof, same thing will happen pag suction naman yung ni consider mo
sir, quick question lang, sa windward portion po ng wall, diba pwedeng gawing triangular load yung pressure jan? zero sa base ng wall tas 1.074 kPa sa 4.5m, and so on and so forth? or dapat ganyan talaga na nakabloke?
sir pano po pag ganito, ang structure ko po kasi is 2 story completely open po sya sa first floor, as in wala po talagang walls then sa second floor po ang kalahati is roof deck and other half is composed of room units
may question pa ko sir gab sa Cp na ginamit mo for roof pressure coefficient yung -0.7, di ba separate Cp yun sa -0.18? bale magkakaron ng 4 design wind pressure kasi may burst at suction pa considering GCpi.
@@hudjo7913 sa roof coefficients dalawa nga yung gagamitin so paramg maliban sa burst at suction may coef 1 and 2 pa kaya mas dadami ang wind cases. Ang logic is makuha yung max tension and compression sa truss members kaya may coefficient na maliit value para pag sinama sa DL at LL magbigay ng ibang axual forces
@@gabrielgamana2456 salamat sir gab. may question pa ako. dun sa minimum design wind P sa wall and roof sabe sa code not less than 0.77kpa & 0.38kpa. kasama ba pati negative pressure sa dun sa limit ni code?
Sir, sa table po ng Roof pressure coefficient, Cp dun po sa wind ward part diba po lagi naten pipiliin yung mas mataas na value. tanong ko lang po kung tuwing kelan dapat po gamitin yung maliit na value?
Once na convert na sa concentrated force ang wind load as well nailagay narin sa frames, 1. If student ka, i will ask you to analyze every frame using Factor Method to determine the member forces 2. If designer ka, you may apply the forces sa computer model mo like STAAD then analyze to determine the member forces
Sir Gab good afternoon po, pano po pag yung ratio ng L/B sa leeward side is 1.67 round up po ba para yung Cp /coefficient is maging 2. wala po kase sa table. thank you po Sir GAB!
Sir, paano po if sa Windward roof refers to table 207 B.4-1 yong nacompute na h/L=0.825. Ang nandon lang sa table ay; 10, ano po pipiliin na condition po?
Yung suction condition po susundin b yung sign ng mkukuhang pressure? Like kung (+) is towards the surface at if (- )is away from the surface? Which means possible na same ang direction ng burst at suction sa isang surface? Thanks po.
Hello sir. yung burst and sunction pressure was already computed in the formula, P = qGCp - qi(GCpi) where Cp for coefficient of external pressure and Cpi for internal pressure where P is the difference of External pressure and Internal Pressure.
Thanks for the appreciation, unfortunately, wala since I want the students to browse the NSCP, pag na automate na kasi malamang hindi na nila buksan ang book
MWFRS are the framing system (Girder, Column, truss, etc.) while C&C are the glass walls, roof materials, windows etc. MWFRS is use kapag nagdedesign ka ng building since eto yung nag tra-transfer ng load to the ground while at the same time you are using commercialize glass walls or roof materials. C&C on the other hand, sila yung direct na tinatamaan ng wind at sila rin yung nagbibigay ng force sa MWFRS (well most of the time). Well if you are designing your own roof materials use C&C
Thank you sir Commercial buulding po kasi sir ang ginagawa ko po and also gumamit din ako ng commercialize glass walls. And sa roofing po nalilito ako kung MWFRS or C&C ang gagamitin.
Step 1 Nature of occupancy 3:52
Step 2 Basic wind speed 3:32
Step 3 wind load parameters 8:27
wind directionality factor 8:28
Exposure category 9:06
Topographic factor 12:13
Gust effect factor 13:55
Enclosure classification 16:13
Internal Pressure Coefficient 17:58
Step 4 Velocity Pressure Exposure coefficient 19:15
Step 5 Velocity Pressure 28:03
Step 6 External Pressure Coefficient 32:41
Step 7 Calculate Wind Pressure 47:05
GRABE SIR, SOLID TALAGA!!! 🥺❤ MAS NALIWANAGAN AKO AT HINDI NAKAKAINIP PANOORIN
thank you sir sobrang detailed ng pagkakaexplain mo sinalba mo ako sa aking structural theory!!!
Sir sa 23:04 , hindi po ba dapat na h=8+(23tan 10)/2 kasi mean height?
Tama ka dapat divide by 2 pa, tho tama naman yung value hindi lang nasama yung over 2
Salamat sa effort. Helped a lot. Hoping you can come up with a clearer presentation tool. But all in all its a thumbs up sir. Kudos to you & your future tutorial videos.
Napaka clear po ng explanation niyo Sir. It helps a lot, thank youuuuu🤗
Thanks Sir! Napakadaling intindihin ng explanation po ninyo :)
Nice one keep up po sir 👌
thank you sir!!!!!!!! -RESPECT from -Iloilo
Thank you po for sharing very useful lalo na sa nagsisimula pa lang sa design.
Nandito ka pla classmate haha
@@metanoia7952 opo classmate hahaha dito na lang tayo kay Engr. Gabriel Gamana galing niya magturo.
@@jadepadro3393 yes classmate. Nakaka believe siya, feel ko mag totop notcher na ako sa board exam. Haha
hay sana ikaw na lang naging prof ko sa struc theory HAHA thank you sa explanation!
thank you sir!!!
I think there are topographical errors in plus (+) sign and the multiplication (x) sign.
I just would like to comment on the use of Kh & Kz...Kz is used in determining the qz (velocity pressure) which is variable with height(z). Whereas Kh is used in determining qh (constant velocity pressure) calculated using mean height. Normally, the windward pressure varies with height while the leeward is constant.
Hello po, sir. What if yung h/L is equal to 0.97?
sir ask ko lang po ano na po next step after po makuha both burst and suction condition pressures? ano po ang pipiliin sa dalawa? gagamitin po ba yung dalawang yon for member analysis po kung sakali?
Both of them shall be analyze separately para makuha ang max tension at max compression
Evening po Sir
Ask ko lang po sana kung ano po yung basic wind speed sa palawan? Wala po kasing nakalagay sa figure ng category 3, 4 at 5 po para po sa palawan.
Napakahusay! 😍
Thank you master! kaw nagTuro sakin eh.
sir what if 0.46 yung h/L need pa po ba interpolate?
possible po ba na it's either sunction or bursting condition lang ang mareceive ng bldg?
Sir Gab, possible din po ba na maghold ng wind pressure ang roof deck? Wala po kasi ako mahanap na refernce sana masagot niyo agad. NOTIICE
mayron po ba kayo seismic load.
Sir pwde ba malaman yung truss analysis kasi yung sa explanation nyo puro leeward yung sa roof. Nasanay kasi ako na windward lang yung kinoconsider sa analysis ng truss at yung leeward walang value.
salamat ng marami sir
Sir yung 8 storey ba considered as rigid building ?
Ang definition kasi ng rigid base sa code ay any structure na may Natural Frequency above 1 Hz, mas maigi na i-check mo yan
@@gabrielgamana2456 ayun thanks po sir
Liliit po yung force pataas? 55kN ,then gamit area na (1.5*11.5) may makukuha na 29.6kN o (6*11.5) gagamitin para lumaki?
Anung specific time yan?
@@gabrielgamana2456 58:04 sa concentrated forces
@@allyce06 well technically depende yung paano mo gusto hatiin yung forces, ikaw bahala mag dictate ng tributary area
Sir, after that e check pa din yung wind pressure parallel sa roof ridge?
Sa detailed design lahat ng orientation ng wind need i-check
Pwede bang roof wind load nitong mwfrs na gamitin sa pag-design Ng purlin, truss? Medyo hassle na Kasi pag another computation for Component& cladding
Pwede
Bakit po positive yung GCpi na ginamit niyo sa leeward nung nagcocompute na ng design wind pressure?
Burst condition kasi yung ni consider ko, it shall be uniform from leeward, windward, and roof, same thing will happen pag suction naman yung ni consider mo
Sir, paano po yung sa roof pressure coefficient pag flat ang roof.. specifically slab lang po siya, thank you.
Hi, sir! Can I ask po kung pano malalaman yung Concentrated Load kapag monoslope roof?
Similar lang, multiply by tributary area
Sir tanong ko lang po kung magcocompute pa rin ba ng windward at leeward sa roof kahit naka roof slab ang structure?
Ou kasi hindi lang naman roof ang kailangan i-design sa wind pati column at girder
Paano naman po kapag North-to-South direction ng gable roof din?
Magbabago definition ng L at B so mag babago rin lahat
Hi sir, ano pong gagamitin na total wind load sa pagcompute ng factored loads. Thank you po.
Good afternoon po sir
Paano po malalaman yung roof pressure coefficient C_p kung ang h/L is 3.140 at ang roof ay merong 8°?
Ano Yung h/2 sa roof angle below 10deg
Distance mula sa unang part ng roof na unang tatamaan ng wind
@@gabrielgamana2456 mean roof height pa Rin Yung "h"?
@@allyce06 yup
Thank you sir for this video. Sir what if hindi po sya flat terrain, pano po makukuha yung topographic factor. Thank you po
I believe the correct formula should be: Kzt = (1 + K1xK2xK3)^2, see Eq. 207A.8-1
thanks
sir, quick question lang, sa windward portion po ng wall, diba pwedeng gawing triangular load yung pressure jan? zero sa base ng wall tas 1.074 kPa sa 4.5m, and so on and so forth? or dapat ganyan talaga na nakabloke?
Base sa formula na binigay ng NSCP hindi
sir pano po pag ganito,
ang structure ko po kasi is 2 story
completely open po sya sa first floor, as in wala po talagang walls
then sa second floor po ang kalahati is roof deck and other half is composed of room units
ano po kaya yung appropriate exposure category and value ng h
Hello po sir, pwedi ba mag tanong kung ano po ang gamitin na formula para makuha yung fixed end moments/forces sa bawat member?
Factor Method ang ma suggest ko na analysis ang gamitin hindi MDM
, sir pano po kung ibang shape ng roofing or kung nk roofdeck lng???
Meron naman na table ang NSCP for other shape, for Roofdeck use the theta value equal 0
@@gabrielgamana2456
thank you po
Hello sir! ask ko lang kung pano iaaply yung Wind load cases 1, 2, 3 and 4. specially yung case 2 and 4.
Anung cases ang tinutukoy mo? Can you give specific page sa NSCP
@@gabrielgamana2456 CHAPTER 2 - MINIMUM DESIGN LOADS 2-81. yan sir gab yung 4 cases.
may question pa ko sir gab sa Cp na ginamit mo for roof pressure coefficient yung -0.7, di ba separate Cp yun sa -0.18? bale magkakaron ng 4 design wind pressure kasi may burst at suction pa considering GCpi.
@@hudjo7913 sa roof coefficients dalawa nga yung gagamitin so paramg maliban sa burst at suction may coef 1 and 2 pa kaya mas dadami ang wind cases.
Ang logic is makuha yung max tension and compression sa truss members kaya may coefficient na maliit value para pag sinama sa DL at LL magbigay ng ibang axual forces
@@gabrielgamana2456 salamat sir gab. may question pa ako. dun sa minimum design wind P sa wall and roof sabe sa code not less than 0.77kpa & 0.38kpa. kasama ba pati negative pressure sa dun sa limit ni code?
Sir kelan po masasabing partially enclosed po yung building?
Merong formula sa NSCP na nilagay
Sir, sa table po ng Roof pressure coefficient, Cp dun po sa wind ward part diba po lagi naten pipiliin yung mas mataas na value. tanong ko lang po kung tuwing kelan dapat po gamitin yung maliit na value?
For our project yung pinaka malaki nalang
Pero sa actual project dapat laha considered
Good Day sir, pano po kukunin ang tributary area kapag ang frame to frame distance ng structure ay hindi uniform?
kala-kalahati lang ng bay length
Sir tanong lang po. same procedure din po ba kapag sa ibang type po ng roof? for example po sa monoslope roof or sa L-shape house po
Merong binigay si NSCP na correspoding pressure diagram per roof type
Salamat sir
pwede po ba mahingi ang powerpoint mo, sir?
Wala yata akong gamit na powerpoint dyan
Engr tanong ko lang po after po yan ano po yung next step? Hindi kasi yan tinuro samin sa school
Once na convert na sa concentrated force ang wind load as well nailagay narin sa frames,
1. If student ka, i will ask you to analyze every frame using Factor Method to determine the member forces
2. If designer ka, you may apply the forces sa computer model mo like STAAD then analyze to determine the member forces
Sir Gab good afternoon po, pano po pag yung ratio ng L/B sa leeward side is 1.67 round up po ba para yung Cp /coefficient is maging 2. wala po kase sa table. thank you po Sir GAB!
mag iinterpolate ka po ata
Sir what if open roof deck? saan mag bbase para makuha yung Cp ng roof?. Thank you
Pwede mo i-simplify nalang yung situations mo para maging compatible sa NSCP
Sir, paano po if sa Windward roof refers to table 207 B.4-1 yong nacompute na h/L=0.825. Ang nandon lang sa table ay; 10, ano po pipiliin na condition po?
Solving for external pressure coefficient, Cp po to.
Pwede ka mag interpolate
Nice
Yung suction condition po susundin b yung sign ng mkukuhang pressure? Like kung (+) is towards the surface at if (- )is away from the surface? Which means possible na same ang direction ng burst at suction sa isang surface? Thanks po.
Ou, sundin mo lang strictly yung signs
Hello po sir, hindi po ba 12.056 yung value ng h? Don sa 8+23tan10? Thank you po.
Nakalimutan ko isulat yung over 2, dapat ganito yan 8+(23tan10)/2
hello po! para saan po yung /2? hehe thank u!
@@elizabethannecanlas5801 sa tingin ko po dahil sa rise/run , since si h mean roof height ay nasa kahalati ng truss ang rise / sa 23tan10 na run
Sir,sa roof pressure coefficient, paano po kung 11.34° ang roof angle at di po exact 10°?
Pwede ka mag interpolate
May mali po ba sa bagong book ng ASEP sa chapter 4 solved problem? Sa roof nia p=qhGCp lang hindi p=qhGCp -qhGCpi.
Check mo baka naka lowrise yung provision na ginagamit nya May difference kasi yung Ng formula at table na ginagamit
sir paano po kaya pag curved roof?
Meron table sa NSCP for that
Hello sir. yung burst and sunction pressure was already computed in the formula, P = qGCp - qi(GCpi) where Cp for coefficient of external pressure and Cpi for internal pressure where P is the difference of External pressure and Internal Pressure.
Internal pressure has a positive and negative sign based on the table, that's where the burst and suction condition come into place.
height = 16 units
thank you so much sir for sharing this video. very informative. by the way sir, ,mayroon po ba kayo program nito? if mayroon how can I avail po.
Thanks for the appreciation, unfortunately, wala since I want the students to browse the NSCP, pag na automate na kasi malamang hindi na nila buksan ang book
kaso di ko ma gets bakit 4.5 m huhu
Hello po ask ko lang po paano po ulit naging 9.5 yung alpha and naging 274.32 yung zg? thank you po
This Gil Bermejo, P.E.
Hello po sir, tanong lang po ako panu po malalaman kung MWFRS or Components and Cladding ang gagamitin for design?
MWFRS are the framing system (Girder, Column, truss, etc.) while C&C are the glass walls, roof materials, windows etc.
MWFRS is use kapag nagdedesign ka ng building since eto yung nag tra-transfer ng load to the ground while at the same time you are using commercialize glass walls or roof materials.
C&C on the other hand, sila yung direct na tinatamaan ng wind at sila rin yung nagbibigay ng force sa MWFRS (well most of the time). Well if you are designing your own roof materials use C&C
Thank you sir
Commercial buulding po kasi sir ang ginagawa ko po and also gumamit din ako ng commercialize glass walls. And sa roofing po nalilito ako kung MWFRS or C&C ang gagamitin.
sa h value na nakuha ko 12.0555
same po tayo
The Formula for the Kzt = (1+K1+K2+k3)^2 is wrong see attached screen shot.
eave height shall be used for roof angle less than or equal to 10 degrees. therefore h= eave height. Sabi ng teacher ko. hahahah!
Tama, nakalagay yan sa NSCP