XRD - Bragg's Law | Peak Position, Intensity, & Width

Поделиться
HTML-код
  • Опубликовано: 5 окт 2024

Комментарии • 256

  • @andawang9403
    @andawang9403 3 года назад +37

    after hours of search I found this video...and it just contains all the things I want to know, great work sir !

  • @akshigupta8411
    @akshigupta8411 4 года назад +6

    I was really thinking from so many days to watch any video describing about XRD technique... But then I was procrastinating due to such long duration videos....
    Thanks a lot sir and u described it very well and in very easily understandable manner as usual...

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +2

      Thanks Akshi. Now i am going to make some research related videos. Please share with your friends.

    • @akshigupta8411
      @akshigupta8411 4 года назад +2

      @@AllLabExperiments I already did...

  • @arup812
    @arup812 19 дней назад +1

    best class on XRD i have ever seen

    • @AllLabExperiments
      @AllLabExperiments  19 дней назад +1

      @@arup812 thanks. One more Vidro on Raman Characterization and Analysis is also there. You can watch that too...

  • @triptofameaciddlab2909
    @triptofameaciddlab2909 3 года назад +18

    Consequent, clear, straight to the deal. You’ve made a great work!

  • @nourihsane8886
    @nourihsane8886 3 года назад +9

    Best XRD explication. Thank you sir. Your are an Angel. ❤️👍👍👍👍👍👍. Indians are genius

  • @dana5731
    @dana5731 10 месяцев назад +3

    Really a good video at least I've found on RUclips for understanding XRD method.

    • @AllLabExperiments
      @AllLabExperiments  10 месяцев назад +3

      Planning to launch more videos on characterization techniques.

  • @Freddy_Merckx
    @Freddy_Merckx 3 года назад +8

    Really, really good video for XRD beginners.
    Very much appreciated!

  • @claireb579
    @claireb579 2 года назад +5

    Great video! You nicely connected so many concepts together, specifically about strain (compressive and tensile) and what the literal peaks would do in response to that in the data! I now understand XRD better. Thank you from the US :)

    • @AllLabExperiments
      @AllLabExperiments  4 месяца назад +1

      Hi... Please watch my latest Raman Video for extended details on Raman Effect & Spectroscopy.

  • @semiconguy4467
    @semiconguy4467 3 года назад +7

    Best video I have ever seen on XRD! Thanks a lot.

    • @AllLabExperiments
      @AllLabExperiments  4 месяца назад +1

      Please Checkout my latest video on Raman Effect and Spectroscopy.

  • @muskanarora3433
    @muskanarora3433 3 года назад +7

    Excellent!!
    Very Well Explained...
    Systematic teaching and covering all the important points about the topic...
    Thank you for this video and efforts👍

  • @muhammadzubair5391
    @muhammadzubair5391 4 года назад +3

    Woderful 1st time fuly understood the XRD

  • @sudhishtsrivastava4336
    @sudhishtsrivastava4336 4 года назад +4

    An excellent explanation. Even biology people can understand this complain technique

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +4

      When DNA was discovered. Biologists struggled a lot about XRD.... unfortunately At that time my video was not present... Not even youtube...lolz

    • @akshigupta8411
      @akshigupta8411 4 года назад +2

      @@AllLabExperiments 😂👌

  • @sanamir6343
    @sanamir6343 4 года назад +5

    Thanku so much sir.... Respect from Pakistan

  • @shahzadahmed5012
    @shahzadahmed5012 4 года назад +4

    Thanks for making the wonderful video. Please add the analysis part also. Small angle and wide angle xray techniques also.

  • @pankajinimahanta9830
    @pankajinimahanta9830 2 месяца назад +1

    Thank you very much for this excellent video 🙏🙏

    • @AllLabExperiments
      @AllLabExperiments  2 месяца назад +2

      @@pankajinimahanta9830 thanks for your words. Please check out my latest videos on raman characterization and research paper writing. Those will also help you in the field of research.

  • @aftabbaig5367
    @aftabbaig5367 4 года назад +4

    Simple and crystal clear

  • @yash-sb9ec
    @yash-sb9ec 6 месяцев назад +2

    Wow really nicely explained sir

  • @dana5731
    @dana5731 9 месяцев назад +1

    Please Make a video on Reciprocal lattice and Brillouin Zone, and their application in X-ray diffraction.

  • @ShraddhaShukla-fw5lt
    @ShraddhaShukla-fw5lt Год назад +4

    Loved this video. You are an awesome teacher. Thank you. Also, can you please explain the splitting of peaks in XRD graphs?

    • @AllLabExperiments
      @AllLabExperiments  Год назад +2

      Like in Barium titanate it is tetragonal in nature. So if you look at it from three different sides from two sides there is one inter planar spacing and from one side you see a different interplanar spacing so you see 200 and 002 peaks split because of different inter planar spacing. This splitting may not be visible for lower angle peaks because they don,t get resolved properly by then but with increasing angle they resolve better and you can see them as separate peaks easily.

  • @pradroydip
    @pradroydip 4 месяца назад +1

    Peak can be broadened due to many factors, but most significantly non-uniform stress, small particle size, alloying, low incidence angle (in case of GIXRD), etc.

    • @AllLabExperiments
      @AllLabExperiments  4 месяца назад +1

      Absolutely... Also Watch my latest video on Raman Spectroscopy.

  • @MuhammadShoaib-ml1tc
    @MuhammadShoaib-ml1tc 3 года назад +1

    A very comprehensive video, easy to understand, thanks

  • @zarnaravtal7479
    @zarnaravtal7479 3 года назад +2

    Thank you so much..explained so well ..very easy to understand.

  • @shahidnaveed5408
    @shahidnaveed5408 3 года назад +2

    Very Nice Sir, ❤

  • @_The_Alchemist_
    @_The_Alchemist_ 3 года назад +3

    @11:45 As you mentioned, peak 1 & 3 will be destructive, similarly, peak 2 and will be destructive. Then, where does constructive interference will come from? It means no XRD signal whatsoever.

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +1

      Plane 1 n 3 give constructive waves .but because of the introduction of plane 2 which is at half of the path difference it cancels wave from plane 1. Similarly there will be another lattice which will cancel plane 3 contribution which is not in picture.
      The conclusion of the discussion is that what layer 2 is not present then there is a peak and because of the introduction of layer 2 it vanishes

    • @_The_Alchemist_
      @_The_Alchemist_ 3 года назад +2

      @@AllLabExperiments Yes, that's what I meant. This represents BCC. Since plane 1 wave is cancelled by mid plane. Similarly, mid plane cancels the bottom plane. So, how do we get peaks in BCC? Since the structure is periodic, we can just focus on this particular unit cell.

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +1

      @@_The_Alchemist_ This is just one condition obeying bragg's law. BCC structure will not show a peak for this respective plane. But at other angle when it obeys for other planes (@6:30) it may show peaks. And the overall pattern confirms that it is BCC (@12:00).

    • @_The_Alchemist_
      @_The_Alchemist_ 3 года назад +1

      @@AllLabExperiments No no. My question is for this unit cell which has simply these 3 planes which are going to be repeated throughout the lattice. And if you are saying that at some other angle there may be the reflection, then the systematic absences is hoax. Because when we put the crystal in the machine, it will be scanned over a range of theta. So, why to discuss systematic absences then.

  • @mkamalakkannan8327
    @mkamalakkannan8327 Год назад +1

    Very good explanation, GOD bless you.

  • @divyapruthi4312
    @divyapruthi4312 3 года назад +2

    Wow kya baat h sir,
    Sir can u tell me what is the effect of particle size on the broadening of Raman peaks
    Acc to 4-5 marks in detail......

  • @lemeii254
    @lemeii254 Год назад +1

    Great 👍,, educative

  • @temesgenyiber8614
    @temesgenyiber8614 4 года назад +2

    nice lecture

  • @hope2633cu
    @hope2633cu 9 месяцев назад +1

    pefecttttttttttt xrd concept
    Thanks

  • @priyankamaurya7480
    @priyankamaurya7480 3 года назад +1

    Very helpful video....thank you so much sir

  • @prudhviravikumar2304
    @prudhviravikumar2304 2 года назад +1

    Thank you for informative video

  • @نونوستار-ل4غ
    @نونوستار-ل4غ 3 года назад +1

    Thank you for your very good explanation finally I got it😊😊😊

  • @harshpatil4377
    @harshpatil4377 4 года назад +3

    Thank you sir

  • @najeebullahkust2708
    @najeebullahkust2708 3 года назад +1

    thanks a lot, sir to explain the XRD very well and will give very help to researchers.

  • @ajitdwivedi1069
    @ajitdwivedi1069 2 года назад +1

    Thank you for making a such type of video very well explained in a systemetic way

  • @MA-ff9th
    @MA-ff9th 3 года назад +1

    very good video sir. THANK YOU VERY MUCH

  • @cd8836
    @cd8836 2 года назад +1

    Thank you so much! I have a lab tomorrow and this helped a lot!

  • @nikhilmohanp7464
    @nikhilmohanp7464 3 года назад +1

    Brief and informative

  • @spscheckit
    @spscheckit 9 месяцев назад +1

    Amazing Video ... Loved your explanation.
    '

  • @tommasosanguettoli6808
    @tommasosanguettoli6808 5 месяцев назад +1

    Very useful video

  • @manishkshukla8548
    @manishkshukla8548 4 года назад +4

    Very clear and lucid explanation. Thanks for creating such great quality videos.

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +1

      Thanks bro. Bs aap dosto ka saath rahe to aise hi kaam chalta rhega....

  • @عبيرمحمود-د1م
    @عبيرمحمود-د1م 2 года назад +1

    Thank you its simple and clear

  • @anujbhadola2834
    @anujbhadola2834 Год назад +1

    thank you so much sir

  • @nisarga100
    @nisarga100 Год назад +1

    Really impressive, great job🎉

  • @gianodevi3782
    @gianodevi3782 2 года назад +1

    Excellent.. please make more videos with the origin of how to use the Williamson method and other parameters by XRD please.

  • @hemangvadgama5258
    @hemangvadgama5258 Год назад +1

    good video

  • @ankitanikam3804
    @ankitanikam3804 Год назад +1

    Thank you for the video, it's really helpful.👍

  • @goyenkaneelam
    @goyenkaneelam 3 года назад +1

    Very much informative. Thank you sir

  • @shaheenerabbani7687
    @shaheenerabbani7687 2 года назад +1

    Excellent explanation.........V.Good

  • @vivalaciencia1
    @vivalaciencia1 10 месяцев назад +1

    Great video! Very well explained!

  • @latifroghani857
    @latifroghani857 2 года назад +1

    very informative

  • @payam1597
    @payam1597 Год назад +1

    wonderful. Thank you

  • @him31anshu
    @him31anshu 3 года назад +1

    Thankyou Brother. Thanks a lot. This saved a lot time. Liked. Subscribed

  • @harshithadkharshithadk4031
    @harshithadkharshithadk4031 8 месяцев назад +1

    ❤ thank you so much sir

  • @achyutjagdhane9683
    @achyutjagdhane9683 Год назад +1

    VERY NICE , THANKS A LOT

  • @uzmasubhan877
    @uzmasubhan877 9 месяцев назад +1

    very welll explained Sir

  • @yaranasser3310
    @yaranasser3310 2 года назад +1

    Thank you dear

  • @pompapathipompapathi14
    @pompapathipompapathi14 6 месяцев назад +1

    Excellent explanation

  • @mgbokommesoma6271
    @mgbokommesoma6271 Год назад +1

    Thank you for the video. I love it.Can we also get a video where a proper XRD pattern is interpreted and insights are made from the plot Thank you.

  • @pralay5156
    @pralay5156 8 месяцев назад +1

    Well explained....

  • @kamnabharati2970
    @kamnabharati2970 3 года назад +1

    Thank you Sir❤️👍🙏🏻

  • @MrVedant006
    @MrVedant006 3 года назад +1

    wonderful video sir.

  • @EasyChemistryLearningwithDrAbh
    @EasyChemistryLearningwithDrAbh 3 года назад +1

    Thank you for making such a simple and informative video on XRD

  • @kassk2323
    @kassk2323 3 года назад +3

    Nice presentation! Could you please explain how can we find out the chemical structure of the particle by using the lattice parameter?

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +1

      Use literature to match that data and you can find out the chaemical and its structure

  • @viditverma4406
    @viditverma4406 3 года назад +1

    Great video

  • @hussnainshirazi6996
    @hussnainshirazi6996 2 года назад +1

    woo fine explanation

  • @amit3230
    @amit3230 3 года назад +1

    excellent explanation

  • @tamanjotsingh6848
    @tamanjotsingh6848 3 года назад +1

    appreciate your effort. it helped a lot , thanks

  • @youwilllaugh3136
    @youwilllaugh3136 2 месяца назад +1

    Can we explain for example am the dissolution of a clay mineral in terms of lattice strain?

    • @AllLabExperiments
      @AllLabExperiments  2 месяца назад +1

      @@youwilllaugh3136 i guess this is amorphous. And i think for an amouphous it is not possible to get strain.

  • @amazonphysics3455
    @amazonphysics3455 2 года назад +1

    Best explanation

  • @shenawaralikhan
    @shenawaralikhan 2 года назад +1

    Good Work, gentleman

  • @lokithaloki8780
    @lokithaloki8780 23 дня назад +1

    Do the order of diffraction changes the information about the interatomic structure

    • @AllLabExperiments
      @AllLabExperiments  23 дня назад +2

      @@lokithaloki8780 no. Its intensity is very low and for n=2 it will give the same info

  • @joelsacademy1409
    @joelsacademy1409 Год назад +1

    Excellent. God bless you abundantly.

  • @zairazara2923
    @zairazara2923 7 месяцев назад +1

    Zabardast🎉

  • @SohailAhmad-xo1ee
    @SohailAhmad-xo1ee 4 года назад +4

    Sir please do you have any vlog or any idea or if you can make any vlog about how to find dislocation density from XRD data. I will be very thankful to you

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +1

      Sorry Sohail but I don't have an experience in dislocation density. But I have found many discussions on this topic on Research Gate. You may read this. For me It may take some days to understand this and then revert accordingly.

  • @mageshwarir9914
    @mageshwarir9914 3 года назад +1

    Thank you so much sir.., understood clearly🙏

  • @niteenjawale3862
    @niteenjawale3862 7 месяцев назад +1

    very good video. one problem is that what is the value of the shape factor (K). how it is coming 0.9. If is there any calculation for 0.9 then please tell me.

    • @AllLabExperiments
      @AllLabExperiments  7 месяцев назад +1

      This is an average value taken average for all shape values because we rarely know the shape of crystallite present

  • @rajibdas1087
    @rajibdas1087 2 года назад +1

    Excellent sir

  • @MohammedIslamElshiekhElsmani
    @MohammedIslamElshiekhElsmani 2 года назад +1

    Interesting!!

  • @shwelpajadhav5905
    @shwelpajadhav5905 3 года назад +1

    excellent...thank you

  • @muraliishwar7022
    @muraliishwar7022 6 месяцев назад +1

    When will I consider a peak amorphous ? If the peak is broader , should I consider it is crystalline with very small crystallite size or an amorphous material ?

  • @MrChakrvarthy
    @MrChakrvarthy 3 года назад +1

    very nice video

  • @lolwasamet8096
    @lolwasamet8096 3 года назад

    Excellent video for XRD beginners. Thank you

  • @shivkortalwar6942
    @shivkortalwar6942 4 года назад +3

    Excellent video i like the topic and information, what is tensile strength explain, please make more videos on XRD data interpretation for identification and quantification by powder X ray diffraction.

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +1

      Thanks Shiv. I am continuously creating content in this field and soon will reach to that aspects of XRD as well. You can also find origin lab tutorial videos helpful in research field.
      Now let us talk about strain. It is caused either in the case of very small particle size or in thin films (it means high surface area causing strain) or while synthesis the bonds of your compound didn't attain its natural length of minimum potential energy. So as the inter atomic distances change, they reflect this effect in the form of XRD peak shift or peak broadening.
      The strain cause while synthesis can be tuned by your rate of heating or cooling or the pressure around.

    • @pranzz30
      @pranzz30 2 года назад +1

      @@AllLabExperiments is xray spectrometer and diffractometer same?

    • @AllLabExperiments
      @AllLabExperiments  2 года назад +1

      @@pranzz30 i have not heard of xray spectrometer... It should be diffractometer i guess...

    • @pankajinimahanta9830
      @pankajinimahanta9830 2 месяца назад +1

      @@AllLabExperiments XPS ( X- Ray photo electron spectroscopy) is there. It is similar to EDS/EDX but in XPS we measure emitted electron and in EDX emitted xray.

    • @AllLabExperiments
      @AllLabExperiments  2 месяца назад +1

      @@pankajinimahanta9830 just in output you may have similar results. On xps carbon correction there is one of my video in which i also discuss its science.

  • @YogeshPatil-ju2ls
    @YogeshPatil-ju2ls 3 года назад +1

    A very nice video that gives a clear understanding of XRD basics. I have one doubt haw to analyze peaks in terms of h k l values and plane of peaks mainly how to assign planes for particular peaks?

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +2

      Consider you xrd a random sample about which you don,t know. Then from the available peaks you get to know about all possible inter planar spacings in that structure and then you match your data with the available peak patterns of different structures or do back calculation to know about the structure...
      You must have noticed in one of the slides that simple cubic, BCC, FCC have a certain pattern of visible peaks... just that helps to identify the structure...

  • @Rughveda2358
    @Rughveda2358 3 года назад +1

    thank you sir, nice explanation

  • @akalankaekanayake1024
    @akalankaekanayake1024 Год назад +1

    nice explanation

  • @Coffeebean1985
    @Coffeebean1985 2 года назад +1

    Such a great and helpful video. Thank you!

  • @gaithhalloum2076
    @gaithhalloum2076 10 месяцев назад +1

    You did a great job ❤

  • @sheetalSonar
    @sheetalSonar 4 года назад +2

    Hello sir, you have explained very well . can you please elaborate on why we use the arbitrary unit for intensity in the XRD pattern?

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +3

      In your XRD pattern, the relative intensity of different peaks depends upon the position of atoms with in the lattice as you have seen in this presentation. Now what if you increase the intensity of your x-ray source? In case of heavy radiation the intensity of all the peaks increases proportionally and vice-versa. Additionally, If you increase or decrease the scanning rate then also the intensity varies so we write it arbitrary.
      The interesting fact is that in all cases the pattern of peaks doesn't change. for example If peak for 011 is the highest and for 012 plane it is around half of the 011 then for any x-ray source intensity or scanning rate this ratio will remain the same if the detector is capable of recording it.

    • @sheetalSonar
      @sheetalSonar 4 года назад +1

      @@AllLabExperiments Thank you very much for clearing my doubt. One more quick question if I use theta - theta goniometer then can I plot graph of intensity vs theta rather than 2 theta?

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +2

      @@sheetalSonar Sorry I missed your comment. In fact 2 theta is just a convention. There is no harm even if you plot it against theta but the reviewers of your paper may get confused by this. So in my advice don't do this unless there is a strong reason for doing this.

    • @sheetalSonar
      @sheetalSonar 4 года назад +1

      @@AllLabExperiments Thank you so much for prompt reply.

    • @kaiser434
      @kaiser434 2 года назад

      @@AllLabExperiments , hi.. I have a quick question. If increasing peak intensity results in a higher peak, is there any setting for the X-ray intensity that needs to be emitted towards the sample in order to get a good match with the fingerprint diffraction pattern of the sample ? The arbitrary unit is still somewhat confusing to me.

  • @ThanseehaSherinPAAP
    @ThanseehaSherinPAAP 2 года назад +1

    Great video!!!!!

  • @pragna4839
    @pragna4839 Год назад +1

    In XRD graph, some are high intensity and others are low intensity peaks, then what structure it can be classified?

    • @AllLabExperiments
      @AllLabExperiments  Год назад +1

      The topic is covered in the video... as structure varies the intensity of the peak change relatively but the answer is not straight forward because peaks are because of the sum of many constructive and destructive interferences.

  • @robamatariq8485
    @robamatariq8485 Год назад

    THANKS for your great effort. Can you please provide material about d-value.

  • @pranzz30
    @pranzz30 2 года назад +1

    So im going to byheart your video as my seminar in abt a week😢🙏

  • @veervikramsingh6905
    @veervikramsingh6905 3 года назад +2

    some of the materials show peak intensity at very low angle diffraction such as less than 1 degree, why

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +1

      Low angle diffraction is performed for thin films only because at higher angle it transmits and you dont get anything

  • @malomatkedunya7266
    @malomatkedunya7266 4 года назад +3

    How can i determine that this xrd pattern is of cu ic,rhombohedral and tetragonal etc
    I shall b thankful for ur answer

    • @AllLabExperiments
      @AllLabExperiments  4 года назад +2

      First check the JCPDS card of your material or match your data with the literature. You can compare your data with them and determine the shape of the crystal. Different peaks will appear for different structures by matching them you can come to a conclusion of shape... But before that your should have known the composition of your material.

    • @MA-ff9th
      @MA-ff9th 3 года назад

      @@AllLabExperiments But sir, if you know nothing about the sample, how will you proceed. Please guide me Sir.

  • @eshanjaiswal2135
    @eshanjaiswal2135 3 года назад +1

    Can you please share this presentation. BTW love your content.

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +2

      Thanks for appreciation. But Sorry, can,t share as it took a lot of efforts to prepare this and also the content is a source of earning for me. B.D. Cullity,s book on XRD contains most of the information and some of the pics. You can use that for the info

    • @eshanjaiswal2135
      @eshanjaiswal2135 3 года назад +1

      @@AllLabExperiments Ohk Thanks :)

  • @AbdulJalil-vb5iq
    @AbdulJalil-vb5iq 2 года назад

    Wow. Very precise and accurate

  • @deepamakhija1346
    @deepamakhija1346 Год назад +1

    Nice explanation.. I have one query related to peaks.If we do powder xrd on single crystals of two sets of same compound then in one set peaks coming along 00l direction and in another set peaks are coming 00l as well as hkl.
    So wht is the reason in one set getting peaks only of 00l and in another 00l+hkl? Eventhough both sets grown under same conditions..
    Will u share your views for the same?
    Thanks and regards,

    • @AllLabExperiments
      @AllLabExperiments  Год назад +1

      Sorry but i am not an expert on single crystals but yes I can look into it in my free time and reply as soon as i get the answer.

  • @hongzhang1279
    @hongzhang1279 3 года назад +2

    Thanks for the video. Is the signal intensity affected by the x-ray source power level and sample distance from the detector/or x-ray source?

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +1

      Yes but in that case all peaks will proportionally decrease or increase and their relative ratio will not change...

    • @hongzhang1279
      @hongzhang1279 3 года назад +1

      @@AllLabExperiments Thanks for your answer. Yes, I am comparing different instruments with different source power levels and the goniometer radius to see if/how the power and sample distance affect the S/N of a specific sample. Is there an equation you may share please? Thanks.

    • @AllLabExperiments
      @AllLabExperiments  3 года назад +1

      No these is no such eqn. Not just power but the placement of the sample n how much radiation a sample absorbs also matter. So it is not easy to bound all the things and derive a formula which is not even useful