Measuring Mass Moment of Inertia - Brain Waves

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  • Опубликовано: 24 авг 2016
  • It's relatively easy to measure mass moment of inertia of an object using a bifilar pendulum. Here's a description along with a derivation of the governing equation and an experiment to show how it all works.

Комментарии • 53

  • @gdogvibes1
    @gdogvibes1 6 лет назад +3

    Really enjoy your teaching style. Very informative but not dry and genuinely enjoyable to watch, thanks!

  • @tomasenrique
    @tomasenrique 7 месяцев назад

    English is not my first language, but boy your accent it PERFECT!!! I don't need any subs for these videos!

  • @tommcqueary7831
    @tommcqueary7831 6 лет назад +2

    Great Explanation
    This information will help me model my quadcopter which I am designing and building including the control board. This kind of information was lacking in my college control systems course (EE curriculum). It seems the most difficult part of controlling a system is to get an accurate model of the system so this information along with modeling the motor torque will solve major pieces of the puzzle.
    Thanks for a great effort. Only minor complaint is it seems you may need to replace one of your felt tip markers soon.

  • @cakecakeish
    @cakecakeish 7 лет назад

    Excellent video! Explained so well. Where did you get the equation to work out the mass moment of inertia from? Which textbooks are you using? Thanks!

  • @gokulkrishna2621
    @gokulkrishna2621 6 лет назад +2

    thanks a lot professor....
    you saved my day...

  • @hassanmualla3693
    @hassanmualla3693 6 лет назад

    Wow! Really helpful!

  • @alieltair5418
    @alieltair5418 4 года назад +3

    Hello, I was using this formula in my experiment to test the parallel axis theorem, however, I quickly realized that it only works when the rotational axis is at the center of mass, is there any iteration of the formula that considers having the rotational axis away from the center of mass? Help appreciated!

  • @yankeekilo
    @yankeekilo 3 года назад

    Thank You sir!

  • @nickgodden1980
    @nickgodden1980 7 лет назад

    Always great seeing an experiment to prove the maths....you'll have to apply for funding for a more comprehensive lab 😀 Thank you.

  • @feelingk
    @feelingk 2 года назад

    Thanks for very interesting video. I would like to apply this method to mesuring the mass moment of inertia (MMoI) of my robot. However, I have following questions:
    i) MMoI depends on mass (of course mass distribution) and geometry of the object. For a defined object, can be considered as a constant. This results to b^2 T^2 /L = const. Is it true?
    ii) If i) is not true, then it means that MMoI depends on b, distance from the CoG to the point where you hold the cable. So, where is that point for obtaining a good value of MMoI?

  • @taurinenrgy
    @taurinenrgy 7 лет назад

    That was amazing! so would this method work on other more complex objects as well, like your skate board or a tree branch?

    • @purdueMET
      @purdueMET  7 лет назад

      In theory, it should work on just about anything. The Air Force uses this method to find the MOI of underwing stores like fuel tanks and missiles.

    • @taurinenrgy
      @taurinenrgy 7 лет назад

      Thanks, I used this method for my physics lab along with using a turn table to find the moment of inertia and I got close to the same result both ways.

    • @nishantmishra5604
      @nishantmishra5604 10 месяцев назад

      @@purdueMET I was trying to find the MOI of my Styrofoam glider, but it is almost impossible to balance the aircraft

  • @user-yj8ji1wm3i
    @user-yj8ji1wm3i 3 года назад

    Thanks for the tutorial, and just a small question.
    What if the CG is not at the center of D. Does the derived equation still works or any modification suggested.
    Great thanks in advance

    • @BobbyBlue117
      @BobbyBlue117 3 года назад

      The derivation requires that both tensions be the same which will place the CG somewhere between the two strings and along the line connecting the two strings as well.

  • @waqasmuneer7951
    @waqasmuneer7951 2 года назад

    Sir please make a video of big idea of FEM if possible

  • @mohamedezeldin
    @mohamedezeldin 7 лет назад

    Hallo Purdue,
    I would thank you for your good explaination but I have some notes on your work:
    1- the experimental twist angle is approx more than 15° but the relation will not equal sin(°)=|=(°), if you need to apply this relation the angle should be close to zero.
    2- your derivation was M.g.b^2.theta/(2L) at time 5:28 sec but at time 12:21 was M.g.b^2.theta/(L) (2 times than before why??)

    • @lipe9567
      @lipe9567 7 лет назад +2

      I had the same doubt, but I figured out why here.
      It happened because in the first part he derived the momentum of only one cable, and in the second equation(with the thetas) we need to use the sum of momentuns. That's why it's 2 times than before.

  • @koolkataustin2961
    @koolkataustin2961 4 года назад +1

    how did you get bθ in the right angle triangle?

  • @matiassantacruz5487
    @matiassantacruz5487 4 года назад

    Damn....I was trying to find a way to derive an equation for a Bifilar Pendulum's time period based on the distance between files...

  • @brandontoledo6915
    @brandontoledo6915 6 лет назад

    What happened to the two in the denominator?

    • @Rezwan47
      @Rezwan47 6 лет назад

      Repeat the video and consider on (11:50) to (12:00)

  • @koolkataustin2961
    @koolkataustin2961 4 года назад +1

    Also, if in the equation I=(Mgb^2t^2)/(4π^2L), we keep M, b and L constant, and since g is constant, does that mean varying the T (Time Period) by increasing the angle will directly affect the I (Moment of Inertia)? Can I do an IA(Internal Assessment, basically an experimental investigation) on that?

    • @waelalghanami9093
      @waelalghanami9093 4 года назад +1

      Ah, a fellow IB student

    • @koolkataustin2961
      @koolkataustin2961 4 года назад

      @@waelalghanami9093 lol how's it going

    • @waelalghanami9093
      @waelalghanami9093 4 года назад +1

      @@koolkataustin2961 EE due in a week and I'm at 200 words. I'd say it's going pretty well.

    • @koolkataustin2961
      @koolkataustin2961 4 года назад

      @@waelalghanami9093 I have the exams that decide my predicted grade(which is what decides my uni) in 4 days, and I haven't started studying yet. Pretty good for me too.

    • @waelalghanami9093
      @waelalghanami9093 4 года назад +1

      @@koolkataustin2961 Good luck brother. What subjects are you taking?

  • @MrLennon70
    @MrLennon70 5 лет назад

    Can we get Period directly from g = 4(Pi^2)L/T^2 without measuring period manually using pendulum?

    • @koolkataustin2961
      @koolkataustin2961 4 года назад +1

      no, cause the 'g' may be inaccurate. you need to do the opposite, and confirm that g is acurate for your pendulum after measuring pendulum

  • @Joe0x7F
    @Joe0x7F 6 лет назад

    Great! Fantastic! Thank you!

  • @ovaisanwar8045
    @ovaisanwar8045 7 лет назад

    very helpful. Thank you

  • @SynytsiaAnton
    @SynytsiaAnton 7 лет назад

    Interesting!

  • @ajayjoseph4626
    @ajayjoseph4626 5 лет назад

    how do you theoretically calculate the moment of inertia of a funny shaped object? for example a quadcopter? it's not a solid piece of material. Do those suspended strings have to be parallel?

  • @magnussvommemann
    @magnussvommemann 6 лет назад

    Very good video and easily explained! Is there a reason you used so long strings?

    • @hassanmualla3693
      @hassanmualla3693 6 лет назад +1

      With long strings, you can rotate the mass more while still getting low value for α. So assuming that sinα=α is possible.

  • @chatchawanhannongbua494
    @chatchawanhannongbua494 6 лет назад

    Hello. How to measure moment of inertia of crankshaft?

  • @ahmedmasri7206
    @ahmedmasri7206 4 года назад

    How did u find the uncertainty in the moment of inertia?

  • @user-jv4nm4bt3d
    @user-jv4nm4bt3d 4 года назад

    if I want to measure the moment of inertia of a irregular shaped object , then how I can find the two points to connect the strings at the beginning? do I need to find the center of gravity first? if the center of gravity is not on the middle axis of the two strings, can we still use this math model?

    • @koolkataustin2961
      @koolkataustin2961 4 года назад

      You need to find the center of mass. You can use this math model, but the distance b must be measured from the center of mass. Refer to this image: www.google.com/url?sa=i&source=images&cd=&ved=2ahUKEwim7baK1oflAhUIi3AKHS21DHMQjRx6BAgBEAQ&url=https%3A%2F%2Fwww.researchgate.net%2Ffigure%2FUsing-the-bifilar-pendulum-method-to-measure-the-moment-of-inertia_fig2_2358471&psig=AOvVaw0tiWS_FGzyE_NVK1unHbUd&ust=1570452627778261

  • @davidwhitford4286
    @davidwhitford4286 6 лет назад

    can I ask during the start of the proof when he uses the triangle why does b(\)/L=tan(a). Where does b(\) come from?

    • @rohitraj-ie2tk
      @rohitraj-ie2tk 4 года назад

      b(/) is the arc length which by L is approximately sin (/)

  • @ctnry5190
    @ctnry5190 5 лет назад

    Where did the theta=Ae^iwt come from?

    • @CompassionOverFear94
      @CompassionOverFear94 5 лет назад

      He assumed sinusoidal motion, of which can be described as theta=Ae^iwt. You don't have to know A or theta; it's just helpful for deriving the expression (A cancels out when these terms are inserted into the M=I(alpha) expression.

  • @waelalghanami9093
    @waelalghanami9093 4 года назад

    What are some real-life applications of bifilar pendulums?

    • @koolkataustin2961
      @koolkataustin2961 4 года назад

      finding the moment of inertia of Unmanned Air Vehicles (UAVs). Are you doing your Internal Assessment (IA) on Bifilar Pendulums? I am.

    • @waelalghanami9093
      @waelalghanami9093 4 года назад

      @@koolkataustin2961 No, I'm doing it for my EE. I'm investigating how geometry affects moment of inertia.

    • @koolkataustin2961
      @koolkataustin2961 4 года назад

      @@waelalghanami9093 cool.