Linear Density, Planar Density, Atomic Packing Factor {Texas A&M: Intro to Materials (MSEN 201)}

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  • Опубликовано: 19 дек 2024

Комментарии • 27

  • @j.s.s9108
    @j.s.s9108 7 лет назад +11

    for the linear density ,can we say that the line pass through an 1/2(1/8) atom ? cuz the corner atoms are shared by 1/8th of their volumes ? why did we just consider it as half a full atom in the first example

    • @yesyouareright7076
      @yesyouareright7076 6 лет назад +3

      J.S.S same doubt

    • @nimes664
      @nimes664 4 года назад +2

      Yeh,same doubt

    • @francescobandozzi7708
      @francescobandozzi7708 4 года назад +2

      Same doubt for me

    • @ay-pn8jy
      @ay-pn8jy 2 года назад

      @@francescobandozzi7708 same 🤣

    • @yazeedalmakahlah9564
      @yazeedalmakahlah9564 Год назад

      well, after 6 years, No .
      Because you are considering your density along line, so ask yourself how it is shared along a line ? Not by volume.

  • @ilaydanur8426
    @ilaydanur8426 3 года назад

    this video the best explained than others thanks

  • @MumenRider78
    @MumenRider78 9 лет назад +6

    Why are the number of atoms for those small corner bits a half, in the linear density and a quarter for the planar density?

    • @pjshamberger
      @pjshamberger  9 лет назад +13

      Miah We only count that fraction of atoms within the line/area/volume of interest. So if we take planar density, the question is "how many atoms are there per unit area?" where the area is a square. if an atom is sitting exactly on the edge of a square, half of that atom is in one square region, the other half is in the neighboring region. Similarly, if the atom is sitting exactly on the corner of a square, it's evenly split between the for squares touching at that corner. This is the only way to make sure that the planar density is independent of where the square is located (picture shifting that square a little to the left or the right). Try this with a simple square lattice, and hopefully it should make a bit more sense!

  • @AkashDave11
    @AkashDave11 10 лет назад +5

    your videos are well explained thanks

  • @damny0utoobe
    @damny0utoobe 3 года назад

    Great vide this explained FCC for me

  • @anouaryousfi6087
    @anouaryousfi6087 9 лет назад +6

    the voice is low , otherwise great video (y)

  • @SouravKumar-fy8ff
    @SouravKumar-fy8ff 5 лет назад

    Excellent, thanks from india

  • @blank_ec828
    @blank_ec828 4 года назад +1

    why is that 1/6? in (111)

    • @aysenhsnv
      @aysenhsnv 4 года назад +4

      1 1 1 triangle sides will be equal to each other. so 60 degress for each angle. 60 is 1/6 part of 360

  • @hafidzazharjakaria2615
    @hafidzazharjakaria2615 7 лет назад

    very well explained

  • @joshuaval4590
    @joshuaval4590 4 года назад

    Wow .... Gracia's really learnt a lot

  • @Mnzmanzmz
    @Mnzmanzmz 3 года назад

    Thank you💕💕

  • @vicky-leehenning7536
    @vicky-leehenning7536 7 лет назад

    How do you calculate whether it is a fcc or bcc crystal structure

  • @arjundas3314
    @arjundas3314 2 года назад

    This video is confusing,why we took half in calculating linear density and why we took 1/6 while calculating fcc planar density ? Not explained properly. And the voice is also low. We need a headphone to listen.

  • @emir650
    @emir650 3 года назад

    Thanks so much

  • @sfindaa8523
    @sfindaa8523 8 лет назад +1

    I think it's less confusing in the Linear density to say # of radii rather than # of atoms. Because it's definitely one quarter of an atom on each edge for the LD

    • @zzztttsss
      @zzztttsss 8 лет назад +2

      i think you mean 1/8 of an atom at the corners. and the # of radii is the # of atoms. if you pass a vector through one radius of an atom, then the vector passed through one half of that atom. if you pass a vector through two radii of an atom, then the vector passed through that entire atom.

  • @IvanOooooooze
    @IvanOooooooze 10 лет назад +1

    Sweeeeet! Thanks!

  • @Robmex10
    @Robmex10 4 года назад

    I understand that {111} and {111} w/ all negatives have the same outcome, but its extremely misleading, and doesn't follow the axis assumed,

  • @bishalghimire1211
    @bishalghimire1211 4 года назад +2

    This video creates more confusion