Honestly well done, After watching this i am convinced that my 'Professor' explaining the lesson has no idea what he is talking about, he literally just follows the marking scheme in his explanation without justifying what he is doing - like a robot - copy and paste without brain Wish all lecturers were like you , you deserve more appreciation for the content you are providing Keep up the good work 10/10
This is amazing. Thank you so much for uploading these videos. Also the way you clearly format your video description is incredible! Thank you so very much!!
So I guess even though there's two nails, because the second is on the bottom and acting on a different interface you wouldn't multiply the allowable force by 2? I got double your answer because it is allowable force per nail and there were two nails XD
I was wondering the same thing. I think it is because the calculated max shear force is specific to that interface. Imagine holding the centre of the beam still and pushing just the top section sideways. Only the top nails are needed to resist that motion. I could be wrong.
Even if the bottom section were held in place, the top nails would still be required to transmit the shear force through to the centre of the beam. So the bottom nails may have an equal shear, but they can’t share the load.
Honestly well done,
After watching this i am convinced that my 'Professor' explaining the lesson has no idea what he is talking about, he literally just follows the marking scheme in his explanation without justifying what he is doing - like a robot - copy and paste without brain
Wish all lecturers were like you , you deserve more appreciation for the content you are providing
Keep up the good work
10/10
I really appreciate your comments! Thank you.
This is amazing. Thank you so much for uploading these videos. Also the way you clearly format your video description is incredible! Thank you so very much!!
Glad you like them! Share with others!
Thank you sir..
Shortly & perfectly explained the concept
This is 10 times better than our teacher
Nice and understandble explanation of engineering stuff. Very usefull in my work as engineer and refresh som theory.
YOU ARE AMAZING I SWEAR GOD THANK YOU
You are amazing. thank you Very much!
Thanks so much for your videos. Can you make a video on fluid mechanics - flow measurement - PLEASE
Thank you so much for these videos!
Thank you so much
Thank you for this video! May I ask though what app is it that you are using to illustrate your answers? Thank you!
So I guess even though there's two nails, because the second is on the bottom and acting on a different interface you wouldn't multiply the allowable force by 2? I got double your answer because it is allowable force per nail and there were two nails XD
I was wondering the same thing. I think it is because the calculated max shear force is specific to that interface. Imagine holding the centre of the beam still and pushing just the top section sideways. Only the top nails are needed to resist that motion. I could be wrong.
Even if the bottom section were held in place, the top nails would still be required to transmit the shear force through to the centre of the beam. So the bottom nails may have an equal shear, but they can’t share the load.
Life saver
Great
I love you
why are you talking so fast?
It’s less than 10 minutes…..