According to CBSE MARKING SCHEME, they have solved the question by taking 90 instead of 60 that makes the answer different from the one you get from by using 60 instead of 90. If u use 90, answer is 69.23 cm2 and if you use 60, answer is 17.9 cm2
@@Me_Indian_Maratha oopsies i did this way not mentioning theta everywhere given sin+cos=1 square both sides sin^2+cos^2+2sincos=1 write one on rhs as sin^+cos^2 which is 1 and send 2sincos from lhs to rhs so sin^+cos^2=sin^2+cos^2-2sincos rhs can be written as (a-b)^2 sin^2+cos^2=(sin-cos)^2 1=(sin-cos)^2 sin-cos=+-1
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Bhai mere school me Pre bord ho gayee hai School walo ne pora ka pora Sample paper hi print kara ke dediya Kash mene sample paper pora solve kara hota 😢😢
Question - 30B Answer
Area of minor segment = Ar. Sector OAB- Ar. Triangle OAB
= 90/360 x 22/7 x 14x14 - √3/4 x 14x14
= 69.23 cm2
Sir mid term ka hai ya final year ka????
Mera
Mid term ki hai 😊@@sta50
According to CBSE MARKING SCHEME, they have solved the question by taking 90 instead of 60 that makes the answer different from the one you get from by using 60 instead of 90. If u use 90, answer is 69.23 cm2 and if you use 60, answer is 17.9 cm2
Sir apka answer galat hai
Apne angle 90 liya hai par angle 60 hai
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2:46:11 Sir but CBSE ke Marking scheme me different method use kiya hai? How to solve with that method ? So which to Follow?
it is literally the same , it is multiplied by 7 so that we get 210 degree ,same method and same formula
@@Anshika-ui1jo. I was asking for 29th Question
@@Me_Indian_Maratha oopsies
i did this way
not mentioning theta everywhere
given sin+cos=1
square both sides
sin^2+cos^2+2sincos=1
write one on rhs as sin^+cos^2 which is 1
and send 2sincos from lhs to rhs
so sin^+cos^2=sin^2+cos^2-2sincos
rhs can be written as (a-b)^2
sin^2+cos^2=(sin-cos)^2
1=(sin-cos)^2
sin-cos=+-1
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Q38 (b) 11.78m²
Best explanation ever on youtube 😊😊😊😊
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Tomorrow is my term 1 of maths thanks once again
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Sample paper h 2024 25 issued by CBSE
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Mid term ka hi h
19:30
4:44:19 Ans 38(B)-54.214
4:39:49 ans - 11.7750 😅
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Sir aapka 30b pura galat h
Question - 30B Answer
Area of minor segment = Ar. Sector OAB- Ar. Triangle OAB
= 90/360 x 22/7 x 14x14 - √3/4 x 14x14
= 69.23 cm2
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