A Nice Equation With Trigonometry

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  • Опубликовано: 4 ноя 2024

Комментарии • 12

  • @SweetSorrow777
    @SweetSorrow777 6 дней назад +2

    Definitely used the 1st method.
    How is 3*PI over 4 not a solution since sine is positive in the 1st and 2nd quadrants?

  • @dan-florinchereches4892
    @dan-florinchereches4892 6 дней назад +3

    Why do people like the arcane functions like sec and csc. Isn't the whole thing simply just 1/sinx=√2 so the solutions are
    x€{y+2kπ, π-y+2kπ|k€Z} where y=arcsin(√2/2)=π/4

    • @StuartSimon
      @StuartSimon 6 дней назад +1

      In calculus, knowing them leads to being able to solve more integrals. Secant actually shows up in a lot of identities when paired with tangent.

    • @dan-florinchereches4892
      @dan-florinchereches4892 6 дней назад

      @StuartSimon in my country of origin ( tanx)'=1/cos^2(X) nice and simple
      1/cos^2(X)=(1+tan^2(X)) very useful especially for Weierstrass substitution
      I know the definition for sec and stuff just never used them

    • @mikecaetano
      @mikecaetano 5 дней назад

      Secant and cosecant figure into cartography and navigation. For arcane trig functions check out versine and haversine and related friends.

  • @cyruschang1904
    @cyruschang1904 5 дней назад

    (secx)/(tanx) = (1/cosx)/(sinx/cosx) = 1/sinx = ✓2
    sinx = 1/✓2
    x = π/4 + 2πn or 3π/4 + 2πn
    x = 45° + 2πn or 135° + 2πn
    n = 0, 1, 2, 3 ...

  • @michaelschmitt2427
    @michaelschmitt2427 6 дней назад

    The correct values are pi/4 and 3pi/4 as shown in the graphs and in the first method presented. For some reasons, SyberMath said "5pi/4" -- just a slip of the tongue.

    • @ShortsOfSyber
      @ShortsOfSyber  5 дней назад

      Ah, you are right! It seems I made a mistake! Thanks for pointing it out 🙂

  • @unonovezero
    @unonovezero 6 дней назад +4

    5π/4 or 3π/4 ?

    • @dan-florinchereches4892
      @dan-florinchereches4892 6 дней назад +1

      Should be 3π/4 he was thinking 1 thing and saying another. How some people would say it's a pointer error

    • @unonovezero
      @unonovezero 6 дней назад

      @dan-florinchereches4892 yeah, I think so