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( ...) is called parenthesis - ses in prularBracket -s is [. ]
این خیلی راحت بود
Same videos was uploaded 2 weeks ago!!!I want your reply for the same question as above in other videos.
I appreciate you letting me know! I'm always working on improving my content.Thanks for watching! 💯🙏🤩💕
(x-2)^2 (x+2)^2 = x+2(x-2)^2 (x+2) = 1(x-2) (x^2 - 2) = 1x^3 - 2x^2 - 2x + 3 = 0(x-1)(x^2 - x - 3) = 0roots are 1, (1±√ 13)/2
x^4+/-x^3-4x^2-x+2=0 , (x+1)(x^3-x^2-3x+2)=0 , x^3-x^2-3x+2=0 , ()()=0 , (x-2)(x^2+x-1)=0 , x^2+x-1=0 , x=(-1+/-V5)/2 , 1 1 1 -2 -1 -1 1 -2 solu , x= -1 , 2 , (-1+V5)/2 , (-1+V5)/2 , -3 -3 -1 2 2 2
( ...) is called parenthesis - ses in prular
Bracket -s is [. ]
این خیلی راحت بود
Same videos was uploaded 2 weeks ago!!!
I want your reply for the same question as above in other videos.
I appreciate you letting me know! I'm always working on improving my content.Thanks for watching! 💯🙏🤩💕
(x-2)^2 (x+2)^2 = x+2
(x-2)^2 (x+2) = 1
(x-2) (x^2 - 2) = 1
x^3 - 2x^2 - 2x + 3 = 0
(x-1)(x^2 - x - 3) = 0
roots are 1, (1±√ 13)/2
x^4+/-x^3-4x^2-x+2=0 , (x+1)(x^3-x^2-3x+2)=0 , x^3-x^2-3x+2=0 , ()()=0 , (x-2)(x^2+x-1)=0 , x^2+x-1=0 , x=(-1+/-V5)/2 ,
1 1 1 -2
-1 -1 1 -2 solu , x= -1 , 2 , (-1+V5)/2 , (-1+V5)/2 ,
-3 -3 -1 2
2 2