Relaxing Math Puzzle: Can You Calculate the Area of the Square?

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  • Опубликовано: 17 янв 2025

Комментарии • 26

  • @mattiasneuman7593
    @mattiasneuman7593 2 дня назад +1

    You can solve this without calculation when you realise that x=s/2. If you draw a square with 10 as a side you can fill it with 4 green triangles and a square with x as a side. This shows that the square with s as a side is 4/5 as big as a square with 100 as a side so the answer is 80.

  • @DJAK792
    @DJAK792 4 дня назад +2

    It’s pretty funny that I’m watching this while making my maths homework for my test Wednesday

  • @zawatsky
    @zawatsky 4 дня назад +1

    Из коэффициента подобия треугольников ½ делаем два полезных вывода: во-первых, их стык находится на середине стороны квадрата, во-вторых, это также пропорция катетов (как и в большом, у которого оба на виду). Ну всё, задача, считай, решена: сторона квадрата 2*10/√5=2*2*5/√5=4√5, откуда площадь 16*5=80.

    • @ThePhantomoftheMath
      @ThePhantomoftheMath  3 дня назад

      Отличная работа! Очень красиво и логично всё расписали. Приятно видеть такое точное и аккуратное решение. 😊

  • @Bheeshma-l2g
    @Bheeshma-l2g 4 часа назад

    👍👍👍

  • @paparmar
    @paparmar 4 дня назад

    You can generalize the set-up in this problem to derive the area of the square for any pair of the lengths: Area = (b^4)/(b^2 + (b-a)^2). In this case, a = 5 and b = 10, so: Area = 10^4 / (10^2 + 5^2) = 10,000/125 = 80.

  • @andersmartinson1750
    @andersmartinson1750 4 дня назад

    I’m not sure how it will relax me, but I think I see some similar triangles.

  • @santiagoarosam430
    @santiagoarosam430 4 дня назад +1

    Tenemos dos triángulos de esquina, de lados: a/b/10 y c/(b-a)/c---> Razón de semejanza entre ambos triángulos =s=5/10=1/2---> (b-a)=b*s=b/2---> a=b/2 ---> b²+(b²/4)=10²=5b²/4--->b²=400/5=80 u2²
    Gracias y saludos

  • @bpark10001
    @bpark10001 4 дня назад

    If you construct the hypotenuse of the the 5-10 triangle (draw line from upper left corner of square to lower intersection of 5 line & right side of square), this triangle is similar to the 2 other triangles & to triangle of sides 1/2/√5. So you can assign lengths starting at lower triangle's short leg & going counterclockwise: X, 2X, 2X, 4X. So X² + (2X)² = 5². X = √5
    square side = 4X = 4√5. Square area = (4√5)² = 80.

  • @mariokajin
    @mariokajin 3 дня назад

    Draw it in autocad.

  • @KaitlynDimas-z4y
    @KaitlynDimas-z4y 4 дня назад

    Thanks for the forecast! Just a quick off-topic question: My OKX wallet holds some USDT, and I have the seed phrase. (air carpet target dish off jeans toilet sweet piano spoil fruit essay). How can I transfer them to Binance?

  • @wasimahmad-t6c
    @wasimahmad-t6c 4 дня назад

    8.9443×8.9443=80area

  • @nenetstree914
    @nenetstree914 4 дня назад

    80

  • @Ron_DeForest
    @Ron_DeForest 3 дня назад

    I have to ask. Do you have a different channel where you do math problems with your son? You sound so much like him.

  • @elliotlambert3817
    @elliotlambert3817 2 дня назад

    The answer is 80 but its not a square s = 10 and one side is 8

  • @devondevon4366
    @devondevon4366 4 дня назад

    80
    let the side of the square =n
    , and the side of the similar triangle =? Both triangles are similar
    then n/10 = ?/5
    5/10 n =?
    1/2 n=?
    Hence, the dimensions of largest triangle are 10, n, and 1/2n
    10^2 = n^2 + 1/4 n^2
    100= 5/4n^2
    100 * 4/5 =n^2
    80 = ANSWER