Tidal Patterns

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  • Опубликовано: 8 сен 2024

Комментарии • 21

  • @lori6411
    @lori6411 2 года назад +1

    This is SO GOOD! Answered so many questions.

  • @steffandevischeybergen2704
    @steffandevischeybergen2704 4 года назад +1

    Normally I'm left with to many questions because the info is incomplete. Now I only have few questions left because new questions come up when you learn things.
    Well done! Allso the manner in which you present the matter, I find excellent!

  • @quadruplerain452
    @quadruplerain452 2 года назад +1

    Very informative and interesting stuff.

  • @hunati31
    @hunati31 Год назад

    This channel Rocks! No pun intended.

  • @maverickss3236
    @maverickss3236 4 года назад

    Lot of clarity in your explanation,thank you!

  • @KatesArchiveLol
    @KatesArchiveLol 4 месяца назад

    This video is good.

  • @Dr.Scorpio
    @Dr.Scorpio 2 года назад

    Beautiful lecture 👌🏼👌🏼👏🏼👏🏼

  • @TElle-oo8kn
    @TElle-oo8kn 3 года назад

    very insightful

  • @rafaelmolinanavas8862
    @rafaelmolinanavas8862 2 года назад

    I’ve realized that just with the title “Tidal Patterns”, its not easy to find they site I mentioned on my previous post.
    What I had posted on that site was:
    “Farther parts of the Earth are NOT SUFFICIENTLY attracted by the Moon in order to follow an orbit equal to the one of Earth´s C.M. (if they could move independently from the rest of the planet).
    Due to that, they try to get a farther orbit.
    They rest of they planet prevents that, exerting a "moonward" force. And those farther parts exert an opposite reaction force ...
    All those forces stretch farther solid Earth´s parts, and where water they so called hide tide bulge builds, trying to reach an equilibrium with own Earth´s attraction (not fully achievable due to they daily Earth´s quick rotation, what also is the cause of the some couple of hours gap between high tide meridian and Moon´s actual position).
    A "mirror" phenomenon happens at closer half of the Earth, because its parts are attracted by the Moon TOO MUCH for the average orbit, they try to get a closer orbit, but the rest of they planet prevents it ... “
    And if anybody wants to see more about previous discussion, the link to mentioned RUclips site is:
    Tidal Patterns

  • @OfficerKD-637
    @OfficerKD-637 7 лет назад

    thank you. much appreciated.

  • @rafaelmolinanavas8862
    @rafaelmolinanavas8862 6 лет назад +1

    I´ll try and put it in a simpler, shorter (I hope) way.
    In its movement due to Moon´s influence, any portion of Earth is following an identical circular path around Moon-Earth barycenter, as it´s revolving, not rotating.
    All of them have same centripetal acceleration, "expected" to be caused by Moon´s pull at considered portion position.
    But the distribution of the later is not uniform. From Earth´s C.G. (where local pull is equal to the average) towards the Moon the pull increases, and the opposite from C.G. towards farther side.
    Dismissing other forces not intervening in Moon-Earth dynamics, net total force acting on each portion has to be equal to their common centripetal acceleration times its mass.
    That requires the rest of the planet, that is "forcing" the considered portion to have the uniform acceleration, to supply a force (in one or the opposite sense) to the considered portion ... The internal stresses I referred to in my last post.
    That force has to be the the result os deducting the local Moon´s pull per unit of mass from the uniform centripetal force per unit of mass (equal to centripetal acceleration).
    At closer half that is a vector towards Earth´s C.G. (rest of the planet prevents the portion to get bigger acceleration), and the same at farther half (rest of planet "forces" considered portion to get an acceleration bigger than what it´d correspond to the smaller Moon´s pull there).
    In both cases that means the bulk of the planet kind of tries and keeps all parts moving "together".
    But, following 3rd Newton´s Motion Law, each of all those portions exert an equal but opposite force on the rest of the planet, through contiguous material (internal stresses).
    Where solid Earth, that stretches it. Where water, that makes it move towards closest and farthest extremes, until an equilibrium with water "normal" weight is reached, being the result the so called high tide bulges.

    • @lori6411
      @lori6411 2 года назад

      That….was not simpler. Maybe for a physics major, but definitely not for the rest of us.

    • @rafaelmolinanavas8862
      @rafaelmolinanavas8862 2 года назад

      @@lori6411 Sorry ... In a shorter and simpler way:
      Farther parts of the Earth are NOT SUFFICIENTLY attracted by the Moon in order to follow an orbit equal to the Earth´s C.M. (if they could move independently from the rest of the planet).
      Due to that, they try to get a farther orbit.
      Rest of they planet prevents that, exerting a "moonward" force. And those farther parts exert an opposite reaction force ...
      All those forces stretch farther solid Earth´s parts, and where water they so called hide tide bulge build (until an equilibrium with own Earth´s attraction is reached).
      A "mirror" phenomenon happens at closer half of the Earth, because its parts are attracted by the Moon TOO MUCH, they try to get closer, but the rest of they planet prevents it ...

  • @atulgupta3750
    @atulgupta3750 5 лет назад

    Amazing explaination. However, I think the answer for bridge question and tide pooling will be Neap tide.

    • @EarthRocks
      @EarthRocks  5 лет назад +1

      Tidepooling happens when tides are at their lowest (spring low tides). Going under a bridge, same thing, when water level is lowest (spring low tides). During neap tides, the tidal range is lowest, but that just means the difference between high and low tide are the lowest -- these are closest together -- low tide is highest and high tide is lowest in month.

    • @EarthRocks
      @EarthRocks  5 лет назад +1

      Moon always dominates. Just a question of how much solar impacts (phases of moon) + the latitude, which effects the part of the bulge that is experienced.

  • @edwardmallon4646
    @edwardmallon4646 3 года назад

    Excel's FFT can be applied to tidal data but there was one aspect of the tool that I found surprising: The key to getting better resolution from the Fourier when you are limited to a fixed number of data points is to decrease the sample frequency (and thus increase the overall sampling time) Here's a video demonstrating that optimization to derive a tidal frequency spectrum: ruclips.net/video/0VzX-3erjPI/видео.html

  • @rafaelmolinanavas8862
    @rafaelmolinanavas8862 6 лет назад

    If we imagined our planet cut into perpendicular to Moon-Earth line slices, Moon pull would be the same across each of them. Closer to the Moon slices would experience a stronger pull.
    If each slice were "free" to move (no other forces acting on them), obeying 2nd Newton´s Motion Law they would get an acceleration, the closer to the Moon the bigger.
    But they are kind of glued together, and all have to accelerate the same.
    Apart from daily Earth rotation, which has nothing to do with Moon, our planet is actually slowly revolving around Moon-Éarth barycenter: all its parts experience identical circular movements, and required centripetal force is uniform, as if all Earth mass were concentrated in its C.G.
    So, at closer slices there is an excess of pull, because Moon´s attraction is bigger than required centripetal force. And al farther slices the opposite occurs.
    2nd Newton´s Law applies for each slice too. Excess of pull on the closest slice is transferred to contiguous one (a parallel can be drawn with the case of pull transference from chain to hammer in hammer throwing).
    But 3rd Newton´s Law also applies: farther contiguous slice pulls on closest one outwards with same force.
    Something similar happens between each pair of contiguous slices at closer Earth half, but being necessary to consider both opposite (but different) pulls from contiguous slices, apart from Moon´s actual pull there, in order to apply 2nd Newton´s Law.
    At slice through Earth´s C.G. actual Moon´s pull is exactly the required centripetal force: all of it is used to cause the revolving movement.
    From C.G. to farthest extreme, the opposite happens: Moon´s pull is insufficient to produce the required, uniform centripetal acceleration. Each slice "helps" contiguous farther one to get required centripetal acceleration transferring to it part of the pull "accumulated" from closer slices …
    All those opposite pulls between contiguous slices stretch the Earth, both at solid part and where water … THAT is actually what directly causes the tides. Logically, as water can move, tides are much more visible at oceans, and the equilibrium between those internal stresses and own water "normal" weight all around the globe is reached with the formation of the two so called high tide bulges.
    And though globally we shouldn´t talk about centrifugal force (the reaction to Moon´s global pull is the attraction exerted by the Earth ON THE MOON), half of all those pair of opposite pulls between contiguous slices are CENTRIFUGAL forces … If you like, we could add the adjective "internal": internal centrifugal forces, but REAL, acting on our planet as a consequence of its interaction with the Moon.

  • @melkdube
    @melkdube 2 года назад

    Great video, but I´d just like to point out that the highest tides in the world are in the Bay of Fundy between New Brunswick and Nova Scotia, Canada, at around 12meters, not in Alaska.

    • @EarthRocks
      @EarthRocks  2 года назад

      Yes, you're absolutely correct! This video is all about reading tidal charts and as such presented "tidal patterns from four different locations across the United States." I did mention that a few times. I wasn't trying to compare world wide, so the questions about biggest and smallest were just about those four patterns. Sorry it wasn't clear. If you watch my video: Living With Tides, you'll hear my description of the Bay of Fundy as the largest tidal range in the world.
      ruclips.net/video/VXemZXoBvlk/видео.html

  • @rafaelmolinanavas8862
    @rafaelmolinanavas8862 6 лет назад

    In another site, somebody replied to my comment of three days ago:
    ".... trying to understand tides can breake ur brain if u dont know the real model of earth . Its imposible to explain the opossite tide on the oficial spinnBallEarth".
    My further post may interest some of you:
    "If you are afraid reading my explanation could "break" your brain, let me propose you just a simple analogy.
    Imagine an athlete rotating the hammer to be thrown. To create the necessary centripetal force, he has to lean backwards, and rotate himself too. If he has a ponytail, instead of hanging down vertically, it will lean further back ...
    Earth pull on the Moon similarly produces the necessary centripetal force for Moon´s rotation. An Earth has to do something similar to what the athlete does: it revolves around the C.G. of the "couple", the barycenter.
    There is an important difference: in hammer throwing pull is transmited kind of "linearly", as through a chain. But Earth´s pull on the Moon is exerted independently by each massive particle of our planet, the closer to Moon the higher the pull.
    But, without mentioning again Newton´s Laws, internal stresses, real centrifugal forces as reactions to certain centripetal ones ... what is clear is that water farther from the Moon than Earth´ C.G. will "try" to go "backwards", as the ponytail does. Until own water weight makes it "stop". By the way, also similarly to the ponytail case ...