Short trick for K.E when P increased by 50 percent ... (5×5)+ (50+50) = 125 percent .. Similarly when P is increased by 100 percent .. (10×10)+(100+100) = 300 percent ..
Sir. I am from balochistan i start my phyiscs journey with you and allhamdullilah so my soncepts now are good and sir your videos help me alott. in kips prep and grip book
finally i'm at the best place for understanding and clearing my all concepts for physics. you're literally such a great teacher 😊 kindly upload more video lectures for mdcat
Sir,, 2nd last question= 100KW ( option À) Last question= 40KW ( option A) ❤ Sir,, I'll wait for your answer. Sir,,, My physics are weak but when I started to watch your lectures I have got confidence to tackle any query regarding problems. Sir,, u r true motivate for me💞 Aaapka yeh lecture aaaj hii dekha tha toh issilye HW bhi abhi kya
Thanks sir after l learn physics questions from you l have no tension of paper of physics in mdcat because your teaching method is easily understandable .Thank you so much may God bless you😊😊
Wese yeh dosra formula yeh mere teacher ne btaya tha.. but agar aap sir Arafat k formula se krna chahte hn tw plus ki jagah B's minus lgaden tw Woh decrease Mai chala jayega . Jahan increase Hoga wahan formula Mai plus sign ayega jahan decrease pooocha jayega wahan minus sign ayega
Sir % increase in kinetic energy find karna ka ak short cut 2[% increase in momentum]+saqure of n[ n is the first digit of momentum which is increased]
sir i think 1st year physics is difficult but when i watched your video it will become easy for me thank you dear sir your teaching style amazing powerful💕
i discovered your channel yesterday i may not be able to attend all of your lectures i wish i had found your lectures earlier but sir you"ve really shown some level equal to wajid ali kamboh sir may god bless you two and all of us all .
sir I am studying mdcat at kips the teacher who has taught the solution of momentum percentage was very difficult but u have made everything simple 🍉🍓🍓🍓🍓🍓🍓
What a fabulous teacher..🎉🎉🎉🎉🎉 thank you sir for this awesome lecture...love from India..❤..sir yehi questions practice ke session aur laiye chapters ke.. improvement hogi achii phir..aur..
Thank you so much for these videos they are super helpful....we are looking forward for more videos like these....and hope you cover the entire physics syllabus by before our entrance tests
mashallah bht madad hue hai is lecture sy .Allah apko is ki jaza dy ameeen. bht asaan banadi physics apny sir .. or apka busy routine sy hat ker hamary liye vedios banana .. bht shukr guzar ho apki main .bht shukria sir ... Allah apko bht taraqqi dy ameen .
Sir can you plz upload the rest of McQ videos before our test plzz We have just 8 days left for our test so if you plz upload the rest of MCQ's videos so it will be vary helpful to us sir
Very informative thank you plz solve this problem two forces f1=5N and f2=15N are acting on body in opposite direction the body is displaced in the direction of net force then work done by f1 willbe
Second last ka answer 100KW hai, Because jab ham 100 ko multiply karengy 10 se tou 1000 ayega then 1000 ko multiply karenge 100 se tou 100000 ayega, yani P=100000 watt, aur sir ne bataya tha previous questions main ke Kilo main convert karny ke liye hamesha 3 zero remove karty hain, jab 3 zero remove karengy tou 100KW answer ayega, Last question ka answer 40KW hai, iska solution bhi second last question ke solution ki tarha hoga. Yani jab multiplication karky 400000 ayega tou usy 10 se divide karengy then P=40000 watt ayega, phir kilo main convert karny ke liye 3 zero remove karengy then 40KW answer ayega!
Asalam u alaikum sir Allah apko hr mushkil se or nzr e bad se bachae pr mene apse zyda koi acha sir wo bhi physics ka kbhi nhi dekha hy ap hmre lia ek success ki key hy sach me ap boht Kamal hy sir
Lec is Amazing sir👌👌👌👌👌...Thank u sir....... you are THE BEST TEACHER OF PHYSICS in my history of life...... ALLAH tawah khe sadaien khush rakhe...Aameen...😊❤❤❤
Aoa sir salamat rahen Ap meray favourite tareen sir han Ap ki wajah se physics mien jan aa jati hai May you live long You are a live wire May Allah bless you with HIS love ameen❤
Sir your method of explanation is extraordinary!! Keep up the good work and Allah will for sure give you great rewards for this ❤. Sir kindly also upload such mcqs lectures for the whole pmdc syllabus and all the chapters included in it.. it will be really helpful for us ❤❤
Sir Alhumdullilah All video xi ki maine apki watch ki or Allah ka karam sa boat faida howa har jaga sir kindly ab inter hai to inter ka be full course update kardo
A body is falling freely under gravity. How much distance does it fall during an interval of time between 1st and 2nd seconds of its motion, taking g=10? Sir kindly iska answer bta dain..
Sir mai ne abi fsc clear kia or mai ne first year or second year ki physics pori ap se pari or ab mai mdcat ki tayari b ap k lectures se karae hu or ab allumdulilah meri physics both achi ogae hai or mai ne ap k sary lectures ko like b kia hai or ap k Chanel ko subscribe b kia hai.... thank you sir 🥰🥰 Allah ap ko hamesha khush rakey🤲... ameen ♥️♥️
Thankyou so muchh sir,,, you are the great,, really problems me bohot masla horaha thaa but AAP kiii mehnat AAP ne hamare liya waqt nikaala sab appreciable he ❣️✨
Sir you are great we want a teacher like you your way of teaching 👍👍may Allah give you long life and give more more more success and million millions of subscribers and views❤️❤️
Exams are near
Nothing is clear
But No need to fear
When arafat khan is here❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
100% right 🎉🎉
The answer to last two questions which you just gave as home work is 100 KW and 40 KW.
how 100 please please batao
Apply the power formula like p=mgh/t and the value is given 10 cm divide by 100 kro ho jaega
100kw Kesy arh h ? Can u plz tell me?
Agr hum 100 sy divide krengy to 100W ayega 100KW nh arh
@@rabiaperveen8656firstly convert the cm into meter then apply it in formula
1..100KW
2..40KW
Thank you sir may Allah bless you 🌺❤️
How
1st 100 kw & 2nd ka 400 kw
10 kw
2 ka 400 kw hai
Or 1 ka 100 kw
May knowledge always persist among us, thank you sir, we need teachers like you to make us compatible to compete with the growing world.
Short trick for K.E when P increased by 50 percent ...
(5×5)+ (50+50) = 125 percent ..
Similarly when P is increased by 100 percent ..
(10×10)+(100+100) = 300 percent ..
First time concept clear howa physics me just because of your best way of teaching thank you sir stay blessed.
Thank you sir ap ke waja se hm ne bohot kuch seekaa 💓💓💓
Allah ap k zindagi may barkat atta farmayeee
Sir. I am from balochistan i start my phyiscs journey with you and allhamdullilah so my soncepts now are good and sir your videos help me alott. in kips prep and grip book
Short trick to find k.E when momentum increase by 50%
5×5(50+50)=125%
Similarlu for 100%increase
10×10(100+100)=300%
😮 And for decreasing formula
22% k leya ye trick kesay use karengay
@@Drdani723 48%
Ye tirck sare percentage ke Sare wala lu pe apply nai huga
finally i'm at the best place for understanding and clearing my all concepts for physics. you're literally such a great teacher 😊 kindly upload more video lectures
for mdcat
Sir,, 2nd last question= 100KW ( option À)
Last question=
40KW ( option A)
❤
Sir,, I'll wait for your answer.
Sir,,, My physics are weak but when I started to watch your lectures I have got confidence to tackle any query regarding problems.
Sir,, u r true motivate for me💞
Aaapka yeh lecture aaaj hii dekha tha toh issilye HW bhi abhi kya
bhi 40 kasa ata hay
❤️🌹🤗 thank you so much for making physics understandable to me ❤️ Allah bless u amen
Thanks sir after l learn physics questions from you l have no tension of paper of physics in mdcat because your teaching method is easily understandable .Thank you so much may God bless you😊😊
thanks alot sir your lectures are really helpful to us
May Allah you live long. Sir, I am highly embarrassfull about his ecat but you give me a tremendous lecture, it help me
Salute to your passion for teaching 👏
Amazing sir g
You are really a physics teacher whom I want in my life 😍
Bundle Of Thanks Sir ❤❤❤
May Allah keep you blessed with his blessings 🤲
1:21:45 sir what will be the formula if we have to find % decrease in momentum?
√n - 100 / 100 - 1 × 100
n se Leke divided by 100 tk poori value underroot Mai hai.. uske Baad - 1 alag hai or × 100 alag.
Wese yeh dosra formula yeh mere teacher ne btaya tha.. but agar aap sir Arafat k formula se krna chahte hn tw plus ki jagah B's minus lgaden tw Woh decrease Mai chala jayega .
Jahan increase Hoga wahan formula Mai plus sign ayega jahan decrease pooocha jayega wahan minus sign ayega
Sir you are the grand father of physics ❤❤❤
😂grand father?
Abba reyyy🤣 ado wado compliment😅
Best teacher ever❤the one we all need, JAZAKALLAH Sir for your efforts that makes our concepts easier ❤❤
Thank u so much for boosting my knowledge 1) 100×100×10÷1=100kwatt. 2nd mcqs 200×200×10÷10=40kwatt
Sir I'm extremely waiting for your next video and now wait is over 😍
Was*
Sir % increase in kinetic energy find karna ka ak short cut 2[% increase in momentum]+saqure of n[ n is the first digit of momentum which is increased]
Thanks for your hard work Sir.Your passion and dedication is beyond words 👏.
U are 💯 right aizaz bhai
sir i think 1st year physics is difficult but when i watched your video it will become easy for me thank you dear sir your teaching style amazing powerful💕
Sir I am very grateful to you .your videos play a great role in my preparation of mdcat🥰❤️
Thank you sir you explain well ❤❤ I liked your teaching style 👍👍
Thanks Sir for clearing our concepts❤
Thinks sir you teaching method is so easy and i enjoy all the lectures
Thank you sir , your lacture is so amazing and intresting
Sir your lecture so helpful for me I am thankful of you 🙏
Kindly upload more lectures like this ...❤
i discovered your channel yesterday i may not be able to attend all of your lectures i wish i had found your lectures earlier but sir you"ve really shown some level equal to wajid ali kamboh sir may god bless you two and all of us all .
Your lectures are so amazing 👏
sir I am studying mdcat at kips the teacher who has taught the solution of momentum percentage was very difficult but u have made everything simple 🍉🍓🍓🍓🍓🍓🍓
Thanks u Sir for boost our cencepts ❤,
A. 100 kw & A. 40 wk
Acha
Thank you sir you helped alot in my preparation of this chapter 😊
Sir thank you sooo much... These lectures are really really very helpful😍
sir i did not do coment for your polishing but i realy love u thanks for these type of amazing mcqs lecture inshallah i will share it
Thank you sir ☺️
Sir make as soon as possible the vedio on ch# "waves " numericals as last year most of the numerical based mcqs was from this chapter
1st question >Ans> 100kw and 2nd 40kw .............THANKS
Sir later make on video how does solved problem without calaculator
Yes sir plz
yes sir please bhot problem hoti .... Bina calculator k kasy kara q k test waghara ma to alow ni hota calculator
Sir you doing brilliant job❤may Allah bless you with endless happiness❤❤❤❤
2nd last mcq: a) 100Kw
Last mcq : a) 40Kw
Same bro🤣
2nd last ka solution smjha dein
Samee
2nd last mcq answer should be 10KW.
Same here👍
What a fabulous teacher..🎉🎉🎉🎉🎉 thank you sir for this awesome lecture...love from India..❤..sir yehi questions practice ke session aur laiye chapters ke.. improvement hogi achii phir..aur..
Well done sir 👍👍 you are the great
Can't thank you enough for these seriesss. Will always be greatful to you sir. 💗💗Allah apko iss mehnat ka sila dain ameennn❤️❤️❤️
Thank you so much for these videos they are super helpful....we are looking forward for more videos like these....and hope you cover the entire physics syllabus by before our entrance tests
Sis . Plz Biology ka RUclips channel batane plz. Lekin. Jo achy teacher ho.
@@umarbhatti5438sir Dr Hadi is the best teacher of bio
@@umarbhatti5438 steps ke lectures dekhlen
Your ability to explain complex concepts is as effortless as a frictionless surface.🌸
Thank you so much for such an amazing video ♥️
great sir....the way you taught is very helpful. thank you sir
Amazing vedio its very helpful thank you sir
Best clarifying concept thanks you sir
Great teacher bht acha smjhaty hain waiting for next lacture❤
jazakAllah Sir
May Allah give you reward for this
mashallah bht madad hue hai is lecture sy .Allah apko is ki jaza dy ameeen. bht asaan banadi physics apny sir .. or apka busy routine sy hat ker hamary liye vedios banana .. bht shukr guzar ho apki main .bht shukria sir ... Allah apko bht taraqqi dy ameen .
Sir can you plz upload the rest of McQ videos before our test plzz
We have just 8 days left for our test so if you plz upload the rest of MCQ's videos so it will be vary helpful to us sir
Allah pak Ahp ka balah kare .❤❤
Umayd ay k.sub unit ka McQs Ahp upload kary🙏🙏
Very informative thank you plz solve this problem two forces f1=5N and f2=15N are acting on body in opposite direction the body is displaced in the direction of net force then work done by f1 willbe
Second last ka answer 100KW hai,
Because jab ham 100 ko multiply karengy 10 se tou 1000 ayega then 1000 ko multiply karenge 100 se tou 100000 ayega, yani P=100000 watt, aur sir ne bataya tha previous questions main ke Kilo main convert karny ke liye hamesha 3 zero remove karty hain, jab 3 zero remove karengy tou 100KW answer ayega,
Last question ka answer 40KW hai, iska solution bhi second last question ke solution ki tarha hoga. Yani jab multiplication karky 400000 ayega tou usy 10 se divide karengy then P=40000 watt ayega, phir kilo main convert karny ke liye 3 zero remove karengy then 40KW answer ayega!
Allah ap ko lambee zendagee dy Allah apko hamisha khosh raky. Ameen
Thank you so much sir Ap it i mushkil se video banaaty hen thak b jaty hongy.....
Allah apko iska jaza e khair de....❤ Ameen❤
Last two questions answers will 100kw and 40kw sir you are a good teacher
Sir you are great person and I LIKE your videos and I gain so much knowledge by the help of your ..
..❤ Thank you Sir 😊
Asalam u alaikum sir Allah apko hr mushkil se or nzr e bad se bachae pr mene apse zyda koi acha sir wo bhi physics ka kbhi nhi dekha hy ap hmre lia ek success ki key hy sach me ap boht Kamal hy sir
May Allah give you a long life for those students who can't afford expensive academies
Ist ka A (100kwh)
2nd ka A (40kwh)
Thankyou so much sir ❤❤❤❤
Sir app academy se acha parha rahy ho MashaAllah plz sare 2023 test k mutabik Mcqs lecture upload kardein🥹
Thank A lot Sir Stay blessed❤️The answer for 2 last is 100KW and for last is 40 KW
Sir aap ko salute karti hun ma bht acha clear karte haun aap
Your teaching way is good and concepts of this chapters are cleared
Lec is Amazing sir👌👌👌👌👌...Thank u sir.......
you are THE BEST TEACHER OF PHYSICS in my history of life......
ALLAH tawah khe sadaien khush rakhe...Aameen...😊❤❤❤
Thanku sir...apki vedios bht helpful hoti hai🥺❤️❤️❤️❤️❤️❤️🫀
2nd last ans is 100kW and that of last is 40k W
Good sir G
Max MCQs PMC practice test me yahan se the 😱
Thank you sir G
And I watched video again to comment and encourage students
Which board?is this for punjab board?
Sure plz nmdcat tak sary chapter Ka mcqs lecture upload kr day nmdcat syallabus Ka mutabiq
happy independence Day,🇵🇰 you and your family 👩❤️👨 ❤️
Aoa sir salamat rahen
Ap meray favourite tareen sir han
Ap ki wajah se physics mien jan aa jati hai
May you live long
You are a live wire
May Allah bless you with HIS love ameen❤
Very helpful video .... JazakAllah sir
King of physics ❤❤❤ Please upload mcqs on thermodynamics especially applications of first law of thermodynamics ❤❤❤❤❤
Jazakallah o kair kaseera
Allah ap ko dunya akrat mi kamyab kary
Sir apky mcqs bht ache hn plz sir in ki pdf ak video MN sari dal den discrption MN video se samjh kr phir khud se practice hojae gi
Sir your method of explanation is extraordinary!! Keep up the good work and Allah will for sure give you great rewards for this ❤. Sir kindly also upload such mcqs lectures for the whole pmdc syllabus and all the chapters included in it.. it will be really helpful for us ❤❤
Asalamwalikum sir
Sir kindly upload the mcq's vedio for the remaining chapters as they are really helpful to us
Mery dono ans a gye sai thank you so much sir for amazing tricks
Thank you sir ❤bhoot achey sy explain kiya ap ny ❤❤❤
Sir hum ap ky new lectures ka w8 kar rahey hy sir plzz last 2 chapter bhi parha dey 😊❤❤❤we are waiting for your new lecture #Arafat Einstein sir❤❤
Sir Alhumdullilah All video xi ki maine apki watch ki or Allah ka karam sa boat faida howa har jaga sir kindly ab inter hai to inter ka be full course update kardo
Thank you very much sir you are amazing sir ❤❤❤may Allah bless you
Sir ,for 2nd last question
The answer is 100 kw and the answer of last question is 40kw
Allah bless your Nobel profession
A body is falling freely under gravity. How much distance does it fall during an interval of time between 1st and 2nd seconds of its motion, taking g=10?
Sir kindly iska answer bta dain..
Answer of second last is 100 Kw
And of last one is 40KW
Sir mai ne abi fsc clear kia or mai ne first year or second year ki physics pori ap se pari or ab mai mdcat ki tayari b ap k lectures se karae hu or ab allumdulilah meri physics both achi ogae hai or mai ne ap k sary lectures ko like b kia hai or ap k Chanel ko subscribe b kia hai.... thank you sir 🥰🥰 Allah ap ko hamesha khush rakey🤲... ameen ♥️♥️
Sir sabhi chapters ke.. questions practice series laye na..bhaut hi beneficial lectures h apke ❤🎉
Thankyou so muchh sir,,, you are the great,, really problems me bohot masla horaha thaa but AAP kiii mehnat AAP ne hamare liya waqt nikaala sab appreciable he ❣️✨
Good work Sir it is very helpful 👍🏻
Assalam o alaikum sir second last A and last A option
Thank youu Soo muchh sir For this lecture 💖
Sir you are great we want a teacher like you your way of teaching 👍👍may Allah give you long life and give more more more success and million millions of subscribers and views❤️❤️