Per Unit System - part 1

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  • Опубликовано: 24 дек 2024

Комментарии • 39

  • @myidentity222
    @myidentity222 7 лет назад +7

    well explained sir... your videos are great, and easy to understand, Thank you...

  • @jahjah7208
    @jahjah7208 7 лет назад +3

    thanks a lot for your vedio i learn and refresh my mind regarding electrical engineering

  • @marien1991
    @marien1991 5 лет назад +2

    Just after 13:22 minutes, I feel, I owe you a nice comment and a like. Now that it is done, let me continue listerning to you up to the end. Thank you for your video.

  • @vipinrajk1
    @vipinrajk1 3 года назад +1

    Correct me if wrong- 4kW @0.8pf lag is wrong statement . Correct statement - Load 4kVA@0.8laf :-). many thanks

  • @sarigubonsri2091
    @sarigubonsri2091 7 лет назад +1

    Excellent of series in EE .God bless you.

  • @1973jdmc
    @1973jdmc 5 лет назад

    Thank you so so much for such a brilliant lecture- truly appreciated

  • @angelitomacasero6968
    @angelitomacasero6968 7 лет назад +1

    where did you get the 6 square? i know 6 is the trans ratio.

    • @pradeepyemula6015
      @pradeepyemula6015  7 лет назад

      can you mention at what time in the video is your question about?

    • @AKShah1
      @AKShah1 7 лет назад

      Pradeep Yemula hello sir i have a doubt Can i get your email id

    • @aks5436
      @aks5436 5 лет назад

      @@pradeepyemula6015 55 20

    • @sihlesimelane4267
      @sihlesimelane4267 3 года назад

      @@aks5436 (1/6)^2 is a^2......a=turns ratio. To move impedence from the secondary side to the primary side we multiply the impedence on the secondary side by the turns ratio squared

  • @johnvann4450
    @johnvann4450 7 лет назад +1

    When discussing translation of per unit impedance from one base to another. Could clarify a lot by stating
    Actual impedance does not change regardless of base system

  • @aks5436
    @aks5436 5 лет назад +1

    PLEASE EXPLAIN (55:25 ) dividing by 6 square

  • @BilalBilal-cu4zr
    @BilalBilal-cu4zr 7 лет назад

    Very nice idea having PU system lecteurs , I was stuck until I saw this videos

  • @achaljoshi007
    @achaljoshi007 6 лет назад

    Isn't it wrong to cancel kVA & KW @ 18:09 and before that, I mean how can we cancel out apparent power and real power without knowing if ckt is AC or DC? I really don't get it how kW and kVA cancellation is taking place. Sir, please explain.

  • @kingsleyakpeji5447
    @kingsleyakpeji5447 4 года назад

    Thank you Pradeep for your videos. Are there copyright restrictions on their re-use, say to facillitate an online course?

    • @pradeepyemula6015
      @pradeepyemula6015  4 года назад

      Hi Kingsley. You can use the videos for online courses without any restrictions. Please donate any amount you wish to support my channel. My PayPal link is. paypal.me/pradeepyemula?locale.x=en_GB

  • @VinodKumar-ff2li
    @VinodKumar-ff2li 7 лет назад

    Thank you sir your lecture is very good

  • @iamArrwa
    @iamArrwa 5 лет назад

    I’m a little bit confused.. are you solving for single phase or three phase ?
    Because as i know the apparent power of 3phase = sqrt(3)*|V|*|I|

    • @pradeepyemula6015
      @pradeepyemula6015  5 лет назад

      BTSaddicted this calculation is for 1 phase

    • @pradeepyemula6015
      @pradeepyemula6015  5 лет назад +1

      I have made a separate video on how to work with per unit system with 3phase. Please search later videos in this playlist.

    • @iamArrwa
      @iamArrwa 5 лет назад

      Pradeep Yemula 👌🏼 thank you so much your videos are helpful

  • @princemenon8864
    @princemenon8864 6 лет назад

    Sir....complex power should be in KVA right???

  • @jvenkatesh6810
    @jvenkatesh6810 6 лет назад

    you are an amazing teacher

  • @kaseidkerlstein4194
    @kaseidkerlstein4194 6 лет назад

    Why is it again the Z actual is divided to 6 squared? please some could tell me because i cant seem to grasp the idea of it.

  • @edwinicogo5022
    @edwinicogo5022 2 года назад

    Hi sir, do you have a pdf copy of this lecture?

  • @rajarapunagarajuyadav8686
    @rajarapunagarajuyadav8686 7 лет назад +1

    nice video thanks sir

  • @oratilemarope2480
    @oratilemarope2480 6 лет назад

    simply brilliant.

  • @esc10
    @esc10 5 лет назад

    Hello sir,
    In starting of lecture you define per unit as any quantity's value in out of one is per unit but in your starting examples your per unit values exceeds their maximum value i.e. 1!
    How's this possible?

  • @mrgreatzzz7438
    @mrgreatzzz7438 7 лет назад

    Well Explained

  • @CourseMedia01
    @CourseMedia01 3 года назад

    thnk you very much.

  • @husseinshutari5209
    @husseinshutari5209 7 лет назад

    thank you so much, actually, your manner is very clear and useful.
    could you tell me how can I get all lectures about power system analysis presented by you?

  • @akileshkumar4479
    @akileshkumar4479 6 лет назад

    Sir at 29:29 for percentage losses you’ve to multiply by 100 because you said percentage

  • @sirendrakunche3492
    @sirendrakunche3492 7 лет назад

    Sir please upload a video on equal area criterionand, swing equation

    • @pradeepyemula6015
      @pradeepyemula6015  7 лет назад +2

      i have already uploaded videos on the topic of equal area criteria, kindly search on my channel you will find.

  • @subhash5122
    @subhash5122 6 лет назад

    Please provide more videos sir🙏

  • @khanabadosh1031
    @khanabadosh1031 7 лет назад

    thank you sir

  • @adityaabhishek9742
    @adityaabhishek9742 7 лет назад

    Can put be greater than 1