95% huh? I know that's just a wild guess of a number to make a point, but the irony of you using the language of statistics to try and say that hardly anyone needs anything beyond basic math is giving me a chuckle.
That’s a complete lie, when I went through engineering, many students started in college algebra, some in lower math courses to build themselves up, there’s no shame in it, but that 95% is so not true and I’d actually say it’s a quite obtuse to make such a preposterous blanket statement.
I took college algebra twice myself. I made a 69 the first time and cried because I was taking the greyhound to school in a different city. I took college again and made 102 for the course!!!
@Frank Brown: Your estimate is only for the positive half of the solution: x = ±√10 . Also, you can get a much better approximate: 3 < √10 < 4 because their squares are 9 < 10 < 16 . And you can easily get another digit by writing √10 as √1000/10 and estimate √1000: 31 < √1000 < 32 because 961 < 1000 < 1024 . Thus, 3.1 < √1000/10 < 3.2 . If fact, I know √10 ≈ 3.162277660168379…
I was horrible with math in high school. Mainly because I just didn't understand its relevance. Later, as I was introduced to mathematical applications on the job, I came to understand the importance of mathematics. I went to college and successfully completed algebra and trigonometry. Later I completed Calculus I, II, and III along with differential equations, combinatorics, and matrices, and got a degree in Computer Science. It is so important for a teacher to instruct so the student knows the procedures and processes, to recognize the application of mathematics. Especially in high school, students need to be exposed to the power of mathematics, to not see it as a chore but as a challenge. Often, in college, I sought out the answers I needed and worked the problems step by step to understand the solution.
So proud of you!!! Honestly I know that took a lot of work. I was also terrible at math in hs (1st period every year w terrible teachers. Flunked them all) I really hope I can turn the tables this time going back to college and can pass college algebra.
I’m about to start college at 26 and I am so rusty with my math…but I love math so I’m excited! Will be checking back on this channel for the next few years 😅
i love love love how you use mathematical terminology like “quadratic equation” or “exponential equation” it makes things so much easier. yesterday was my first day in my college math class and it was essentially a review. and the teacher was just throwing equations up onto the board and he expected us to know already what they were called. and when i asked what type of equation was on the board, he basically told me that it should be general knowledge and i should already know what its called :/ i think that the math class that im in might be too advanced if i can barely keep up and if i cant tell the different between an exp. equation and a quad. equation and especially if i have a teacher not willing to teach me the difference lol
Same my professor starting writing equations etc. and i was clueless on the first day!! I keep thinking i should of reviewed algebra 1, geometry and algebra 2 before college algebra
@@anunknownperson4018 That's gotta feel crazy. Can I ask what class this was? I teach math and I'm trying to get some ideas to be more helpful to my students.
Math experts like to form cliques to try to prove their superiority. This dude refused to answer proving he is more anxious to restrict learning than teaching.
A teacher should not answer like that. With the waste amount of videos today on the internet, you can, as a student, search for these things and get a better understanding. Searching for the right topic, becomes so much easier, if you in fact knows what it is called, the thing you are searching for.
I could study, take notes, and do everything right to pass basic algebra, and i would still fail. I am just a moron when it comes to math. I wish that was not the case, but it just is.
x² = 10 [ x =±√(10) ] 2˟ = 10 [ x = ln(10)/ln(2) ] Honestly, I don't remember covering logarithms in College Algebra. Of course, I took it during the summer where the material was covered at a much faster pace than normal. I do remember covering logarithms in Precalculus and don't ever recall revisiting the material again even after I completed Differential Equations 😊
@@Rudenbehr Calculus tends to use natural logs as the numbers they give are "easier" to handle (and are related to pi and e ) , useful in rotational mechanics and electicity (inc light / radio / audio circuits) for phase / power and similar changes - rotations of dynamos/ motors including frequency syncing and some telecoms systems.
@@RPSchonherr While I have forgotton more about logs than I was ever taught , we had it as "filler" because we had completed the syallabus for the year and slide rules (which are based in part on logs) were going out of use in favour of calculators and I think the cirriculum was dropping the use of log tables at least. So we were shown log tables ( base 10) with the comment that the tables were basically thanks to someone else doing the hard crunching previously but needed still for the addition and finding the anti-log for the result. From memory log10 in base 10 is defined as =1 and thus from that (log100 = 2) the numbers can all be calculated by a form of division. Once we had got the general idea of using log tables for problem solving I decided to create log tables for base 2 , base 5 and base 12 for the fun of it (only the first few natural numbers !!!) cannot remember how to do that (quickly) now
My high school desk had large log tables laminated into the top. Graphing calculators were just starting to hit the market, so most of us didn't have one yet, and had to use the handy-dandy table on our desks. :)
What confused me here was the base of the log 10 and log 2. On my calculator I had to do x=log(10,2)/log(2,2) for the expression to properly solve. Thanks for the walk through, it was very helpful once I learned the bases have to align. 👍
For anyone finding this after the fact: the number in the base actually doesn't matter, as long as it is the same on both sides. In the video they used the common logarithm, or the log to base 10, but any other base also wouldve worked, as long as, again, it is the same on both sides.
Do they still teach analog computing in college? I understand why not used in automotive electronics. To easy to fix and adjust. Part of the design involves solving for a unknown in in fractional power. The analog computer function can also be done with a lot of 1s and 0s. As long as the clock is running in the gigahertz region. It may be just as fast. And as accurate. One method uses digital approximation and the other uses a screwdriver. Both measure and source from analog.
In this example you'd either want to use log(base 2) or log(base 10), or log by default. You can use any base, even e, or natural log (ln) but if I can get one of the figures in the expression to = 1 then I'll use that base. log-base2(2) = 1 log-base10(10) = 1 So, I like: x = logbase2(10) x = 1/log(2)
Technically, a number when contained inside a square root symbol (radical sign) always evaluates as positive. For example, the square root of 4 evaluates to 2, not plus or minus 2. This is so the radical can be used as a function (one output) in different mathematical operations.
My basic Problem is that #1 doesn't look like it is solved to me. I was thinking the solution is more like 3.16...... (and a probably endless amount of decimals to get as close as possible to 10. 😬 This is how I always try to figure out algebra and fail time and time again. 🤷🏻♀️
I think of that as testing ones recollection of the two postive AND negative real number solutions for the expression. Calling it a quadratic when effectively it is x^2 +/-0x +/- 0 = 10 is a bit cheeky and also you can use your log tables here for the days when you dont have a babbage machine / calculator / google calc to hand. 2logX=log 10. LogX = (log10)/2 - which you can look up . calculate and then take find the anti log. It would also come up in multiple choice questions with saying for postive solutions in x^2 =10 is X closer to 1, 2, 3, 4 ?. or a question to approximate x to two significant digits or similar kinds of questions.
Well done. You might explain that log 10 = 1, and why that is true. Also that a log IS an exponent. That is, log base b of a is the exponent you have to put on b to get a. For example log 1000 = 3, because 10 cubed is 1000.
i’m going to be taking college algebra as i enter ninth grade next year and i am so scared. i flunked algebra pretty hard due to my mental health at the time but currently i’ve been getting the highest grades in geometry throughout my school, but math isn’t something that comes naturally to me but moreover something i study often to help me get to where i need to be. any suggestions before i enter college algebra?
The fact you’re doing it at 9th grade means you’re doing something right 😂. I’m on the same boat where I’m nervous to take it, but honestly learning key words, taking notes about key words and formulas you look over every day seems like a great way to stay ontop of it! Good job you got this!
Brain teasers, brain excercise. Love these simple nibbles. I'm now wanting to do some simple calculus...just for the brain. For anyone who GaF... HP (Moravia) have introduced a new HP15C CE... get them grey cells moving. Best
I'm a high schooler in a college algebra class, it's one semester and my final is tomorrow. Since it's only 3 units I feel like I know less than I should, but this made me feel much more confident in my abilities!!
@captaingreatvalue3176 It must be that if you're struggling to complete college algebra at the age forurty, that it mist be a pretty difficult course. Have you tried to speak with any other adults your age who are doing something similar? And, or have you tried thinking about what motivations you have about your interest in mathematics?
I understand on the problem you did for the quad equation that you said for the problem x2=10 that 8 would have to be the closest that it wasn't the aczact number cause didn't have your calculator could you possibly give me the right answer cause I'm learning for algebra please and thank you I'm taking notes to understand it
You have your info mixed up. He was referring to 2^x. Consider guessing for x in x² = 10. x = 3 means 3² = 9 x = 4 means 4² = 16 9 is closer to 10 than 16, so x is closer to 3 than 4. Now consider guessing for x in 2^x = 10. x = 3 means 2^3 = 8 x = 4 means 2^4 = 16 8 is closer to 10 than 16, so x is closer to 3 than 4.
I took it 3 times to get a D :) they give you different things to play around with, soon it gets : you making your own numbers and giving them the value you need to call it solved. factoring
The guessing for the second one is actually a good idea to check your precise answer makes sense. But why not just say it ends up as one over log2 and give the actual result?
log(x) is typically defined as the logarithm function, base 10, but it can be used for an unspecified base. When the base is e, the function is commonly written as ln(x), the natural logarithm. In the generic form of log(x), the solution for 2^x=10 is log(10)/log(2), which works for any base, be it 10, e, 2, 3, etc. This form also translates to log2(10).
So, now you are using the radical sign when you should be using X^(1/2). As you pointed out in your other video (just a mind game), the radical sign only gives the "principle root" and you did not allow for the negative root. Now however, you are not following your the rules and further confusing the matter. Is it really so hard to write x^(1/2)?
Looking at the first one X squared = 10 so X = the square root of 10 which I just happen to remember (from school) is 3.162277 and, of course, it could be + or - The second one is harder .. and I am going to have to watch your video !
10:35am I have never had Algebra I'm in college and I am behind in my class man I have been trying to understand but I'm not getting it ! Table math has helped me so much ! 😊 Thank you!
I have a 9gh grade education. I made a d- in algebra and now I'm 51 and trying to go to college at ASU and was told I have to take college algebra to major in psychology I'm lost and need help please
I commend you for going back to school. However, I'm a high school dropout. My advice is don't sweat it. I'm 76 and ran a high tech engineering company for 41 years. Taught myself enough algebra to use a calculater and geometry was actually more useful and easy for me. I have no idea why you would need algebra for a degree in psychology other than statiscally figuring out why phsychologists are more nuts than normal people. That's an opinion I got from a brilliant radiologist I know. I retired 5 years ago with several million in the bank. Education, in my opinion is for people that can't figure things out about life on their own, or want to make some mark on the world through the "system". I have another brilliant friend of mine who said, "Those who can, do. Those who can't, treach." One can be "smart" without a formal education. Just read about people like Henry Ford, William Herschel, even Einstein's father was told by Albert's teacher that he would never amount to anything.
0:24 x isn't a "variable" in those equations, it's an unknown. A common mistake if you write code but one that'll you'll definitely get picked up on (at least here in the UK). Also it's a different unknown in each equation; you're just using the same symbol.
@@xl000 Well go and tell my uni lecturers that - they're the ones who mark stuff and this video purports to help you pass academic courses in the subject.
It has two solutions: 0 and 0. I'm sort of kidding, but only sort of. In this case, 0 would be an example of what we call a "double root," or a solution with multiplicity 2. Quadratic equations have two solutions COUNTING MULTIPLICITY, but not necessarily two distinct solutions.
If log10 = 1, does that mean that since x = log10/log2 then that is the same as x = 1/log2 ? And if so, do you then write it in some other, more reduced way?
Only if they were said to be a "system of equations", but the obvious x=2 result is quickly seen to be extraneous because 2^2 is 4 not 10. If you go back to the beginning of the video, they were said to be two separate problems, therefore X does not represent the same variable. Would have been clearer if it was X^2 = 10 and 2^Z =10
if x^2 is equal to 10 and 2^x is equal to 10 then 2^(x^2=10) equal 10 that means somehow 2^(sqrt 10) equal 10, but that does not equal 10 it is equal 8.95. because sqrt of 10 is 3.162. 2 ^3..235 is equal to 10. . Are these equation exclusive?
I passed with a D in algebra 1 and a b in geometry. I haven't taken any math classes since now I am starting college and I don't think I can pass any of it. I don't understand any of this and I just can't seem to grasp it.
My advice is to take all your general education courses and major courses that do not require a math prerequisite first. Once you've got those out of the way then you can devote more time to your math requirement. I suggest pick a math class that you feel comfortable taking and buy a used textbook for that course and study for it by watching RUclips tutorials or tutoring before you pay to take the class. Once you got it down only then should you enroll in the class and you shouldn't have a hard time getting by with a "C" ( passing grade).
The topics in this video might not be a good start for you, but I bet you can still do it. I want to help people just like you and I'm working on videos to help. Do you mind answering some questions so I have a better idea of how to help? Don't give up.
Calculater? I am too old. I was not even allowd a slide rule. Had to use log tables. England and Scotland still have adder snakes; but not Ireland. The Scots and Brits built sturdy tables out of logs so that the adders could multiply. ;-)
I truly wish that I dah an algebra instructor like you when I took high school algebra in 1969. My instructor was a b**ch, (sorry), but she didn't deserve to teach. I diligently tried to take notes, but she criticized me for taking notes and not paying attention. I gradually fell further behind in class until it came to a point where she didn't even call on me. She also failed to tell me that I could have dropped the class to avoid an F grade. Later in high school, I took the same class in summer school and received a B grade, and this instructor at a different high school took his time and thoroughly explained and the class was enjoyable.
Im resorting to videos because in my math i only got a week before another test is there and we only get grades by tests and not homework and im doing terrible at understanding it because its so fast so this helps
You write down the multiply symbol and you "see" the addition symbol. Perhaps you should learn what the symbols actually mean rather than just what you "see".
took me 8 years to graduate to achieve my associates degree becaue i could never pass the state math college exam. i still dont know how the heck i passed and was able to graduate.
No. 2^x = 10 x*log(2) = log(10) x = log(10)/log(2) If your log function is base 10 (common log), then log(10) = 1, which you can use to simplify to: x = 1/log(2)
They're different equations that happen to use the same symbol for the unknown. (He even said something similar at the start.) If you try to make them a system of equations, then there's no solution because each part has a different solution; that is, ±√10 ≠ 1/log(2) : x² = 10 x = ±√10 x ≈ ±3.162277660168379… 2^x = 10 x*log(2) = log(10) x = 1/log(2) = log2(10) x ≈ 3.321928094887362…
Since those things that are equal to the same thing afre equal to one another then x ^ 2 = 2 ^ x = 10 then again those things.... thus x = 2 appears to be a unique solution. Checking by substitution in the original 2 ^ 2 = 2 ^ 2 but does not equal 10 so there is something wrong with this original asumption and those things equal to the same thing arfe not equal to one another in this situation. Lets look at the individual equations as they have only one unknown and can be solved without reference to the other equation [thus assuming that the unknown x used in both equations may not be the same solution number]. Now using the .equation then x ^ 2 = 10 Lets rename the unknown x as y to avoid confusion of the two conditions of the two equations. Taking logs of both sides [ what you do to one side you do to the other and thus lhs still equals rhs] so that 2.log y = log 10 =1 and thus log y = 1/2 [0.5] thus y = antilog of 2 [cant do this on my phone calculator but appears to be about Using 2 ^ x = 10 [rename x as z for same reasons as above] then do the same to both sides and the equality remains so that 2 ^ z =10 and thus zlog2 =log 10 =1 so that z = 1 divided by log2 = 1/ 0.3010299957 = Not sure if variance in calculator solutions can account for this but then y is almost equal to z [about 3 and a bit] but clearly not equal within 2 decimal places of accuracy] .So my conclusion are that this does not provide a solution using these assumptions and I am tending to consider that if x represents the same quantitiy in both equations then this looks like it can not be solved [at least by me] and indeed i.e. y does not equal z . Just as was demonstrated in my first paragraph " those things equal to the same thing are equal to one another" [ but only if the unknowns x as stated are also the same thing]. So where do we go from here? Are we trying to equate oranges to apples? or is the antilog of 2 = to the log of 10 divided by the log2 ?
Love your videos, but I I have a small complaint, you mention ‘principal’ values. Please expand on such statements, you went complex w/o giving background. Just give some hints on how much can be explored 🤩
I find that this is so stupid that I need this for my college degree. I’m 41 now and do not understand college algebra and in my field job I would not need this to become HR. This is ridiculous.😊
Really? log10/log2?? You didn't then go, and since log10 (assuming base of 10, which you can define when taking the initial logs) is 1, the answer is 1/log2
Fortunately 95% of students do not need this level of math. What they do need is a excellent knowledge of basic math.
95% huh? I know that's just a wild guess of a number to make a point, but the irony of you using the language of statistics to try and say that hardly anyone needs anything beyond basic math is giving me a chuckle.
That’s a complete lie, when I went through engineering, many students started in college algebra, some in lower math courses to build themselves up, there’s no shame in it, but that 95% is so not true and I’d actually say it’s a quite obtuse to make such a preposterous blanket statement.
This isn't even close to basic math.
It's prep for the course you need to take in prep for basic math.
@@Lemuraiit obviously depends on what major you’re pursuing 🙄
It takes a good teacher to make sure students understand the process. Its not all about notes but patience & attention to students.
I’m gonna try college algebra for the 4th time and I’m 40 so I’m hoping this is my last time wasting money on remedial classes 😅
I took college algebra twice myself. I made a 69 the first time and cried because I was taking the greyhound to school in a different city. I took college again and made 102 for the course!!!
May be that you need to start out by reviewing basic math and algebra first 🤷♂️
Congrats on making that decision! My brother had the same issues with doing remedial classes over and over again. You can definitely do it!
@@btbmath1229 thanks my dude
@@captaingreatvalue3176 I teach remedial classes. Can I ask is there anything you wish the teachers would do to help you more?
I remember using my log book before the days of calculator.
Thanks a lot, great to bring back old memories, 72 yrs old Mechanical Engineer with a Master Thesis in Calculus.,
what kind of master's is in calculus? that's uni or highschool where I am at. Do you mean analysis?
Oh wow...much respect to you sir, that's an impressive skill set!
Were you born in 1950?
1Q. X= + or -- square root of 10 which is between 3 and 5
2Q X = 1/ log(2)
@Frank Brown: Your estimate is only for the positive half of the solution: x = ±√10 . Also, you can get a much better approximate: 3 < √10 < 4 because their squares are 9 < 10 < 16 . And you can easily get another digit by writing √10 as √1000/10 and estimate √1000: 31 < √1000 < 32 because 961 < 1000 < 1024 . Thus, 3.1 < √1000/10 < 3.2 . If fact, I know √10 ≈ 3.162277660168379…
I was horrible with math in high school. Mainly because I just didn't understand its relevance. Later, as I was introduced to mathematical applications on the job, I came to understand the importance of mathematics. I went to college and successfully completed algebra and trigonometry. Later I completed Calculus I, II, and III along with differential equations, combinatorics, and matrices, and got a degree in Computer Science.
It is so important for a teacher to instruct so the student knows the procedures and processes, to recognize the application of mathematics. Especially in high school, students need to be exposed to the power of mathematics, to not see it as a chore but as a challenge. Often, in college, I sought out the answers I needed and worked the problems step by step to understand the solution.
That was big-headed of you 😅
So proud of you!!! Honestly I know that took a lot of work. I was also terrible at math in hs (1st period every year w terrible teachers. Flunked them all) I really hope I can turn the tables this time going back to college and can pass college algebra.
Love your channel it’s incredibly helpful
I struggle with math and this has been extremely helpful. I am committed to know moore on college algebra.
Excellent demonstration Sir !
I’m about to start college at 26 and I am so rusty with my math…but I love math so I’m excited! Will be checking back on this channel for the next few years 😅
Good luck in college! You got this!
@@Chloe-tz3kw Thanks :) Khan Academy is suuuper helpful.
Aww how funny! I’m 26 and starting college this fall. Taking college algebra. I’m considering tutoring as well.
@@Aniexo_ Good luck :) What is your major?
Don't worry. The solution is not dependent on being in a certain college class or not. Mathematics is mathematics. You will do well. Have fun!
Appreciate the help I really need this
For those of us who wrote assembly language the rule of thumb was 3 1/3 bits per decimal digit. So log 10/log 2 ~ 3.3
OK but it applies to all languages.
This presentation is excellent and brought back many enjoyable memories of my algebra classes.
Amazing teacher-love your style! Thank you!
i love love love how you use mathematical terminology like “quadratic equation” or “exponential equation” it makes things so much easier.
yesterday was my first day in my college math class and it was essentially a review. and the teacher was just throwing equations up onto the board and he expected us to know already what they were called. and when i asked what type of equation was on the board, he basically told me that it should be general knowledge and i should already know what its called :/
i think that the math class that im in might be too advanced if i can barely keep up and if i cant tell the different between an exp. equation and a quad. equation
and especially if i have a teacher not willing to teach me the difference lol
Same my professor starting writing equations etc. and i was clueless on the first day!! I keep thinking i should of reviewed algebra 1, geometry and algebra 2 before college algebra
@@anunknownperson4018 That's gotta feel crazy. Can I ask what class this was? I teach math and I'm trying to get some ideas to be more helpful to my students.
average fucking loser math teacher with a big ass ego
Math experts like to form cliques to try to prove their superiority. This dude refused to answer proving he is more anxious to restrict learning than teaching.
A teacher should not answer like that. With the waste amount of videos today on the internet, you can, as a student, search for these things and get a better understanding. Searching for the right topic, becomes so much easier, if you in fact knows what it is called, the thing you are searching for.
Important matter for us and thank you !
I passed college algebra in 2004 and had no idea how to solve this.
Great overview my man.
The first two minutes brought back my worst memories of HS. Giving up on math 50 yrs ago was the right choice.
Just subscribed! Love your work!
I could study, take notes, and do everything right to pass basic algebra, and i would still fail. I am just a moron when it comes to math. I wish that was not the case, but it just is.
same, already lost halfway into this video, took the class twice
x² = 10 [ x =±√(10) ]
2˟ = 10 [ x = ln(10)/ln(2) ]
Honestly, I don't remember covering logarithms in College Algebra. Of course, I took it during the summer where the material was covered at a much faster pace than normal.
I do remember covering logarithms in Precalculus and don't ever recall revisiting the material again even after I completed Differential Equations 😊
I remember because I asked the instructor how do we calculate logs and he didn't know. "Just use the tables," was his answer.
Same experience too. Common logs covered extensively in algebra. But calculus seemed to just use natural log.
@@Rudenbehr Calculus tends to use natural logs as the numbers they give are "easier" to handle (and are related to pi and e ) , useful in rotational mechanics and electicity (inc light / radio / audio circuits) for phase / power and similar changes - rotations of dynamos/ motors including frequency syncing and some telecoms systems.
@@RPSchonherr While I have forgotton more about logs than I was ever taught , we had it as "filler" because we had completed the syallabus for the year and slide rules (which are based in part on logs) were going out of use in favour of calculators and I think the cirriculum was dropping the use of log tables at least. So we were shown log tables ( base 10) with the comment that the tables were basically thanks to someone else doing the hard crunching previously but needed still for the addition and finding the anti-log for the result. From memory log10 in base 10 is defined as =1 and thus from that (log100 = 2) the numbers can all be calculated by a form of division. Once we had got the general idea of using log tables for problem solving I decided to create log tables for base 2 , base 5 and base 12 for the fun of it (only the first few natural numbers !!!) cannot remember how to do that (quickly) now
Well done John.
My high school desk had large log tables laminated into the top. Graphing calculators were just starting to hit the market, so most of us didn't have one yet, and had to use the handy-dandy table on our desks. :)
What confused me here was the base of the log 10 and log 2. On my calculator I had to do x=log(10,2)/log(2,2) for the expression to properly solve. Thanks for the walk through, it was very helpful once I learned the bases have to align. 👍
For anyone finding this after the fact: the number in the base actually doesn't matter, as long as it is the same on both sides. In the video they used the common logarithm, or the log to base 10, but any other base also wouldve worked, as long as, again, it is the same on both sides.
Do they still teach analog computing in college? I understand why not used in automotive electronics. To easy to fix and adjust.
Part of the design involves solving for a unknown in in fractional power.
The analog computer function can also be done with a lot of 1s and 0s.
As long as the clock is running in the gigahertz region. It may be just as fast. And as accurate.
One method uses digital approximation and the other uses a screwdriver. Both measure and source from analog.
Just use e as the base
In this example you'd either want to use log(base 2) or log(base 10), or log by default. You can use any base, even e, or natural log (ln) but if I can get one of the figures in the expression to = 1 then I'll use that base.
log-base2(2) = 1
log-base10(10) = 1
So, I like:
x = logbase2(10)
x = 1/log(2)
Just use natural log and you don’t have to worry about the base
thank you!
If using base 10, log(10) = 1, so you can simplify as x = 1/log (2)
How did you get the four to come into the equation?
Been out if college over 40yrs... And this was good. Didnt have anything like this. 😮 thank you.
My genious son helped me pass college algebra, but this guy is a good teacher if anyone needs help!
ALERT:None of this will help you at the racetrack.
Hi. I'm a bit puzzled why you say that SQRT(4) = +/-2 - isnt it only "The principal square root" (eg:2) unless advised otherwise?
Is log10=1? When I was learning this stuff, there was no calculator. We had to look up the tables or draw a chart.
Fortunately, I was able to substitute two years of Latin for 1 year of math in college. I enjoyed Latin.
Do you teach how to write the equation of a function in your course
X^2 = 10 square root each side X =+/- SQRT(10)
Technically, a number when contained inside a square root symbol (radical sign) always evaluates as positive. For example, the square root of 4 evaluates to 2, not plus or minus 2. This is so the radical can be used as a function (one output) in different mathematical operations.
for the exponential equation the simple answer is x=(log(2))^-1. (log(10) =1)
My basic Problem is that #1 doesn't look like it is solved to me. I was thinking the solution is more like 3.16...... (and a probably endless amount of decimals to get as close as possible to 10. 😬 This is how I always try to figure out algebra and fail time and time again. 🤷🏻♀️
I think of that as testing ones recollection of the two postive AND negative real number solutions for the expression. Calling it a quadratic when effectively it is x^2 +/-0x +/- 0 = 10 is a bit cheeky and also you can use your log tables here for the days when you dont have a babbage machine / calculator / google calc to hand. 2logX=log 10. LogX = (log10)/2 - which you can look up . calculate and then take find the anti log. It would also come up in multiple choice questions with saying for postive solutions in x^2 =10 is X closer to 1, 2, 3, 4 ?. or a question to approximate x to two significant digits or similar kinds of questions.
Can you explain WHY? My algebra teacher in high school couldn't.
is there a way to do this without brute force and without a calculator?
Well done. You might explain that log 10 = 1, and why that is true.
Also that a log IS an exponent. That is, log base b of a is the exponent you have to put on b to get a.
For example log 1000 = 3, because 10 cubed is 1000.
Logarithm is the inverse operation of exponentiation
Here is how to do so:
Take natural logarithm of both sides of the 2nd eq gives:
ln 2^x = ln10 -----> x = ln10 / ln 2
You're done
Thank you
i’m going to be taking college algebra as i enter ninth grade next year and i am so scared. i flunked algebra pretty hard due to my mental health at the time but currently i’ve been getting the highest grades in geometry throughout my school, but math isn’t something that comes naturally to me but moreover something i study often to help me get to where i need to be. any suggestions before i enter college algebra?
The fact you’re doing it at 9th grade means you’re doing something right 😂. I’m on the same boat where I’m nervous to take it, but honestly learning key words, taking notes about key words and formulas you look over every day seems like a great way to stay ontop of it! Good job you got this!
Trig.
x = + or - sqrt(10) and x = log(10)/log(2). Does not matter base of the log as long as they are the same.
Brain teasers, brain excercise. Love these simple nibbles. I'm now wanting to do some simple calculus...just for the brain.
For anyone who GaF... HP (Moravia) have introduced a new HP15C CE... get them grey cells moving.
Best
you can do two solutions that x = +-sqrt(10) but another got one solution that 1/log2
I'm a high schooler in a college algebra class, it's one semester and my final is tomorrow. Since it's only 3 units I feel like I know less than I should, but this made me feel much more confident in my abilities!!
@captaingreatvalue3176 It must be that if you're struggling to complete college algebra at the age forurty, that it mist be a pretty difficult course. Have you tried to speak with any other adults your age who are doing something similar? And, or have you tried thinking about what motivations you have about your interest in mathematics?
Why don’t you find the square root of 10 then right that down with plus or minus?
You can use a calculator for a good approximation.
I understand on the problem you did for the quad equation that you said for the problem x2=10 that 8 would have to be the closest that it wasn't the aczact number cause didn't have your calculator could you possibly give me the right answer cause I'm learning for algebra please and thank you I'm taking notes to understand it
You have your info mixed up. He was referring to 2^x.
Consider guessing for x in x² = 10.
x = 3 means 3² = 9
x = 4 means 4² = 16
9 is closer to 10 than 16, so x is closer to 3 than 4.
Now consider guessing for x in 2^x = 10.
x = 3 means 2^3 = 8
x = 4 means 2^4 = 16
8 is closer to 10 than 16, so x is closer to 3 than 4.
You can put log base 2 of 10 in most scientific calculators
I took it 3 times to get a D :) they give you different things to play around with, soon it gets : you making your own numbers and giving them the value you need to call it solved. factoring
Ummm okay, what tutorial do I go to if I didn’t understand this at all
The guessing for the second one is actually a good idea to check your precise answer makes sense. But why not just say it ends up as one over log2 and give the actual result?
log(x) is typically defined as the logarithm function, base 10, but it can be used for an unspecified base. When the base is e, the function is commonly written as ln(x), the natural logarithm. In the generic form of log(x), the solution for 2^x=10 is log(10)/log(2), which works for any base, be it 10, e, 2, 3, etc. This form also translates to log2(10).
since log10=1, the solution is 1/log2 about 3.32
Why quad? when there are two solutions quad to me implies 4... Thanks
So, now you are using the radical sign when you should be using X^(1/2). As you pointed out in your other video (just a mind game), the radical sign only gives the "principle root" and you did not allow for the negative root. Now however, you are not following your the rules and further confusing the matter. Is it really so hard to write x^(1/2)?
He's being sloppy here. When he wrote the radical without "±" before it, I laughed.
Looking at the first one X squared = 10 so X = the square root of 10
which I just happen to remember (from school) is 3.162277
and, of course, it could be + or -
The second one is harder .. and I am going to have to watch your video !
im still lost. idk if im ever going to understand alegbra i have a proficiency intermedite alegbra test and i already failed the basic math one
Amazing style of teaching math.
10:35am I have never had Algebra I'm in college and I am behind in my class man I have been trying to understand but I'm not getting it ! Table math has helped me so much ! 😊 Thank you!
why wouldnt x for the log be sq of 10
I love you man
I have a 9gh grade education. I made a d- in algebra and now I'm 51 and trying to go to college at ASU and was told I have to take college algebra to major in psychology I'm lost and need help please
I commend you for going back to school. However, I'm a high school dropout. My advice is don't sweat it. I'm 76 and ran a high tech engineering company for 41 years. Taught myself enough algebra to use a calculater and geometry was actually more useful and easy for me. I have no idea why you would need algebra for a degree in psychology other than statiscally figuring out why phsychologists are more nuts than normal people. That's an opinion I got from a brilliant radiologist I know.
I retired 5 years ago with several million in the bank. Education, in my opinion is for people that can't figure things out about life on their own, or want to make some mark on the world through the "system".
I have another brilliant friend of mine who said, "Those who can, do. Those who can't, treach."
One can be "smart" without a formal education. Just read about people like Henry Ford, William Herschel, even Einstein's father was told by Albert's teacher that he would never amount to anything.
0:24 x isn't a "variable" in those equations, it's an unknown. A common mistake if you write code but one that'll you'll definitely get picked up on (at least here in the UK). Also it's a different unknown in each equation; you're just using the same symbol.
This is nitpicking
@@xl000 Well go and tell my uni lecturers that - they're the ones who mark stuff and this video purports to help you pass academic courses in the subject.
Thank you 🙏
x is a variable in each equation.also it's pretty obvious they are separate equations, so using x in both is not confusing!
In USA, AN UNKNOWN IS A VARIABLE!
You said that quad èq has ‚always always always’ two sollutions. What about x^2=0? How many solutions?
Consider x^2 = k .
For k > 0, 2 real solutions. For k = 0, 2 dependent solutions. For k < 0, 2 complex solutions.
It has two solutions: 0 and 0.
I'm sort of kidding, but only sort of. In this case, 0 would be an example of what we call a "double root," or a solution with multiplicity 2. Quadratic equations have two solutions COUNTING MULTIPLICITY, but not necessarily two distinct solutions.
did not need both expressions to solve . each one was solvable .
If log10 = 1, does that mean that since x = log10/log2 then that is the same as x = 1/log2 ? And if so, do you then write it in some other, more reduced way?
Since log b(C) = 1 / log c(B), then can’t 1/log2 be written as log2(10)? So in the above answer wouldn’t x=log2(10) ?
both ways you mention are correct. log_10(10) / log_10(2) = log_2(10)
Log(10) is 1 only on base 10. Logs can be in any base. When you write log(10)/log(2) the base does not matter.
Sure but if you use log base 10, it simplifies to 1/log(2), and you only have to look up on log.
Solve for x=3.321 I think it is
I guess my question would be an example of where this would be useful in life and how it would be used
Get,s into the problems at 2:53
there are two elements that are both equal to 10. Therefore they are equal to each other as well.
Only if they were said to be a "system of equations", but the obvious x=2 result is quickly seen to be extraneous because 2^2 is 4 not 10.
If you go back to the beginning of the video, they were said to be two separate problems, therefore X does not represent the same variable. Would have been clearer if it was X^2 = 10 and 2^Z =10
You had me cracking up when you said 2^1= 4 😂
Kod mene zadatak drugi je nedovršen jer treba uvažiti da log ima bazu 10 i da je log10=1, pa je konačni rezultat x=1/(log2).
if x^2 is equal to 10 and 2^x is equal to 10 then 2^(x^2=10) equal 10 that means somehow 2^(sqrt 10) equal 10, but that does not equal 10 it is equal 8.95. because sqrt of 10 is 3.162. 2 ^3..235 is equal to 10. . Are these equation exclusive?
I passed with a D in algebra 1 and a b in geometry. I haven't taken any math classes since now I am starting college and I don't think I can pass any of it. I don't understand any of this and I just can't seem to grasp it.
My advice is to take all your general education courses and major courses that do not require a math prerequisite first. Once you've got those out of the way then you can devote more time to your math requirement. I suggest pick a math class that you feel comfortable taking and buy a used textbook for that course and study for it by watching RUclips tutorials or tutoring before you pay to take the class. Once you got it down only then should you enroll in the class and you shouldn't have a hard time getting by with a "C" ( passing grade).
The topics in this video might not be a good start for you, but I bet you can still do it. I want to help people just like you and I'm working on videos to help. Do you mind answering some questions so I have a better idea of how to help? Don't give up.
@@btbmath1229 I don't mind answering questions
x^2 = 10 = 2^x seems to imply that x^2 = 2^x so x = 2. The 10 is superfluous?
No, he wrote separate equations that look similar, but are really different.
Calculater? I am too old. I was not even allowd a slide rule. Had to use log tables. England and Scotland still have adder snakes; but not Ireland. The Scots and Brits built sturdy tables out of logs so that the adders could multiply. ;-)
I truly wish that I dah an algebra instructor like you when I took high school algebra in 1969. My instructor was a b**ch, (sorry), but she didn't deserve to teach. I diligently tried to take notes, but she criticized me for taking notes and not paying attention. I gradually fell further behind in class until it came to a point where she didn't even call on me. She also failed to tell me that I could have dropped the class to avoid an F grade. Later in high school, I took the same class in summer school and received a B grade, and this instructor at a different high school took his time and thoroughly explained and the class was enjoyable.
I’m lost as hell and not excited to take math this semester 😢 English major
Im resorting to videos because in my math i only got a week before another test is there and we only get grades by tests and not homework and im doing terrible at understanding it because its so fast so this helps
Im studying my ass off cause I need to do well on this test tomorrow
Ahh the reason 95% of people who wanted to go to college end up not going, myself included.
The only thing i got out of algebra was a migraine ...............
X = log_2(10)
Hold on how did you get 8 from 2x2x2? Im seeing 6. And then 2x2x2x2=16? I'm seeing 8.
You'll get 6 when you add 2+2+2.
Youll get 8 when you multiply 2 times 2 times 2.
You write down the multiply symbol and you "see" the addition symbol.
Perhaps you should learn what the symbols actually mean rather than just what you "see".
2 times 2 is 4 and then 4 times 2 is 8
Pop goes the weasel song to remember the quadratic formula..y=-b+-sqrrt of 4ab/2a
How do you teach this to someone with dyscalculia? I think you're just making this up.
took me 8 years to graduate to achieve my associates degree becaue i could never pass the state math college exam. i still dont know how the heck i passed and was able to graduate.
Is Log10/ log2= log5?
No.
2^x = 10
x*log(2) = log(10)
x = log(10)/log(2)
If your log function is base 10 (common log), then log(10) = 1, which you can use to simplify to:
x = 1/log(2)
X=10^½, 2=10^(1/x)
figure its pretty obvious that its the Square Root of 10 (ie, 10^0.5) which is roughly 3.16
Since both are equal to 10, why can't you just set x^2 equal to 2^x, and solve for x?
They're different equations that happen to use the same symbol for the unknown. (He even said something similar at the start.) If you try to make them a system of equations, then there's no solution because each part has a different solution; that is, ±√10 ≠ 1/log(2) :
x² = 10
x = ±√10
x ≈ ±3.162277660168379…
2^x = 10
x*log(2) = log(10)
x = 1/log(2) = log2(10)
x ≈ 3.321928094887362…
@@oahuhawaii2141 Thank you!
huh? 10 = 2 ^x => x = ln base 2 of 10 ... which is the same answer
Quadratic equations have
Two solutions.
X*x=0
or just one solution...
Since those things that are equal to the same thing afre equal to one another then x ^ 2 = 2 ^ x = 10 then again those things.... thus x = 2 appears to be a unique solution. Checking by substitution in the original 2 ^ 2 = 2 ^ 2 but does not equal 10 so there is something wrong with this original asumption and those things equal to the same thing arfe not equal to one another in this situation.
Lets look at the individual equations as they have only one unknown and can be solved without reference to the other equation [thus assuming that the unknown x used in both equations may not be the same solution number].
Now using the .equation then x ^ 2 = 10 Lets rename the unknown x as y to avoid confusion of the two conditions of the two equations. Taking logs of both sides [ what you do to one side you do to the other and thus lhs still equals rhs] so that 2.log y = log 10 =1 and thus log y = 1/2 [0.5] thus y = antilog of 2 [cant do this on my phone calculator but appears to be about
Using 2 ^ x = 10 [rename x as z for same reasons as above] then do the same to both sides and the equality remains so that 2 ^ z =10 and thus zlog2 =log 10 =1 so that z = 1 divided by log2 = 1/ 0.3010299957 =
Not sure if variance in calculator solutions can account for this but then y is almost equal to z [about 3 and a bit] but clearly not equal within 2 decimal places of accuracy] .So my conclusion are that this does not provide a solution using these assumptions and I am tending to consider that if x represents the same quantitiy in both equations then this looks like it can not be solved [at least by me] and indeed i.e. y does not equal z .
Just as was demonstrated in my first paragraph " those things equal to the same thing are equal to one another" [ but only if the unknowns x as stated are also the same thing]. So where do we go from here? Are we trying to equate oranges to apples? or is the antilog of 2 = to the log of 10 divided by the log2 ?
Love your videos, but I I have a small complaint, you mention ‘principal’ values. Please expand on such statements, you went complex w/o giving background. Just give some hints on how much can be explored 🤩
I find that this is so stupid that I need this for my college degree. I’m 41 now and do not understand college algebra and in my field job I would not need this to become HR. This is ridiculous.😊
Really? log10/log2?? You didn't then go, and since log10 (assuming base of 10, which you can define when taking the initial logs) is 1, the answer is 1/log2
I was good at this 50 years ago.