Wow it's crazy to see someone answering the questions from my A level paper! It's funny, at the time I don't actually remember finding this to be the worst question and answered it pretty well. In hindsight, it was definitely the toughest one on the paper
For the final part, the identity: tan(pi-x) = -tan(x) is useful. It can be derived from the formula for tan(A+B). From that, we have: tan(3pi/5) = tan(pi-2pi/5) = -tan(2pi/5) tan(4pi/5) = tan(pi-pi/5) = -tan(pi/5) Certainly a fairly challenging question.
@@NeilDoesMaths Right. It's very useful to be able to derive a result in as many ways as possible. And, of course, being able to deduce results from e.g. graphical symmetry, as you did, is a very useful skill for the aspiring mathematician.
@ that’s a completely wrong analogy. Everyone is “really strong” given that they are doing further maths A level and have gotten this far without dropping out. More like “understanding the perfect technique” will make it much easier for some than others, even if everyone is strong. That’s to say, understand WHY the method works instead of just blindly following the method, which is why so many struggle with A level (and any other level of) math
Wow it's crazy to see someone answering the questions from my A level paper! It's funny, at the time I don't actually remember finding this to be the worst question and answered it pretty well. In hindsight, it was definitely the toughest one on the paper
Further maths!!! Thank the lords, im dying in school
I got'chu bruh
I just found this question in the aqa year 2 further pure book back on Thursday and thought it seemed tricky. Glad to have gotten it correct though
Koioioioidoesmaths
For the final part, the identity:
tan(pi-x) = -tan(x)
is useful. It can be derived from the formula for tan(A+B). From that, we have:
tan(3pi/5) = tan(pi-2pi/5) = -tan(2pi/5)
tan(4pi/5) = tan(pi-pi/5) = -tan(pi/5)
Certainly a fairly challenging question.
Can be derived in a couple ways which is super cool
@@NeilDoesMathssince tan is an odd function, tan(-x)=-tan(x). Adding the pi doesn’t alter the value of tan(x)
@@NeilDoesMaths Right. It's very useful to be able to derive a result in as many ways as possible.
And, of course, being able to deduce results from e.g. graphical symmetry, as you did, is a very useful skill for the aspiring mathematician.
what was the range for part b??
do u do further maths ? since when? thought u only do videos on a level math, u should def do more further maths
FM is my favourite thing to teach. I just tailor to the masses mostly. DW more videos coming soon
I wish i could do this schmancy theorem question?
It really isn’t too hard if you actually understand what you are studying
Benching 140kg isn't actually hard if you're just really really strong
@ that’s a completely wrong analogy. Everyone is “really strong” given that they are doing further maths A level and have gotten this far without dropping out. More like “understanding the perfect technique” will make it much easier for some than others, even if everyone is strong.
That’s to say, understand WHY the method works instead of just blindly following the method, which is why so many struggle with A level (and any other level of) math
@@adw1z He was joking mate..
DeMonford is cold
Simon de Montford
He was a cool guy tbf
I just don’t get how u deduce all the roots. Once you have the quadratic are I saying that equals tan5theta which equals zero. Then what?
Remember the roots repeat themselves so we stop at 4
if you take a look at HSC extension 2 demoivre questions i can guarantee they get harder than this.
never heard of HSC... might check it out
It takes 30 sec to solve