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Explanation is very good 😊
Good teaching method
Very nice
nice explaination maam
Very well done
Perfect teaching maam
❤❤
😅😅
X=(log3/log2)
M values are correct in all the steps
let u=2^x , u^3 + u^2 +/- u - 36=0 , u^2(u-3)+4u(u-3)+12(u-3)=0 , (u-3)(u^2+4u+12)=0 , u-3=0 , u=3 , 2^x=3 , x=ln3/ln2 , +1 -3 u^2+4u+12=0 , u=(-4+/-V(16-48))/2 , u= -2 +/- i*V8 , --> for complex , +4 -12 test real solu , x=ln3/ln2 , 8^(ln3/ln2) + 4^(ln3/ln2)=27+9 , --> 36 , OK , +12 - 36=0 ,
The logarithm of 3 to the base of 2 is 1.5849625007212.
Explanation is very good 😊
Good teaching method
Very nice
nice explaination maam
Very well done
Perfect teaching maam
❤❤
😅😅
X=(log3/log2)
M values are correct in all the steps
let u=2^x , u^3 + u^2 +/- u - 36=0 , u^2(u-3)+4u(u-3)+12(u-3)=0 , (u-3)(u^2+4u+12)=0 , u-3=0 , u=3 , 2^x=3 , x=ln3/ln2 ,
+1 -3 u^2+4u+12=0 , u=(-4+/-V(16-48))/2 , u= -2 +/- i*V8 , --> for complex ,
+4 -12 test real solu , x=ln3/ln2 , 8^(ln3/ln2) + 4^(ln3/ln2)=27+9 , --> 36 , OK ,
+12 - 36=0 ,
The logarithm of 3 to the base of 2 is 1.5849625007212.