الله يدخلك الجنه من أوسع ابوابها there are doctors gain more than 300 SR (nearly 80$ ) to teach us for an hour what you said in this video ! Thank you so much
ofc its better than textbooks thats why teachers exits. Now the majority of uni teachers are people without the gift of education and with 3 phds so they tend to complicate even the most simple shit.
This explanation saved me where teachers failed. They keep redirecting me to formulas that are of no use and refuse to give a greater in depth explaination... So sad that college tuition is being wasted like that.
A Fluid Mechanics problem that I'm trying to work out. A viscometer of the Redwood type has an oil-containing cylinder 4.75cm in diam and an agate tube 0.17 cm in diameter and 1.2 cm long. The oil surface, when flow starts, is 9 cm above the outlet from the agate tube. To allow for the sudden contractions at entry to the tube, the effective length of the tube may be taken as the actual length plus the tube radius. Making allowance for the decreasing head of oil, the viscous resistance through the tube, and the KE (kinetic energy) of discharge, calculate using arithmetical integration, the time required for 50 cm3 of an oil of viscosity 0.5 poise and specific gravity 0.92 to flow through the viscometer. How do you find the time? From this question, I have tried to use quadratic equation to solve for v, but it is proving more difficult than I thought
The viscosity is generally a material property, depending on the temperature and other relevant state factors. Whether you pull fast or slowly does not change this material property. (This is only true for Newtonian fluids. Non-newtonian fluids act differently and are really cool. I suggest you look up videos on them)
Wouldn't the viscous force be equal to the force applied because Newton said opposite and equal reaction to an action? Please can someone explain me that why can't we just say that the viscous force is equal to the force applied to the lid.
Equal and opposite reactions wouldn't resign every action to inaction, that is to say things can still move and not be stopped by the so called opposite force. Assuming the edges of the box were frictionless you could determine to a decent degree the viscosity by applying an increasing force to the plank and seeing at what point it began to move. If we do in fact know the coefficient of friction between the edges and the plank then we can estimate the viscosity by looking at the rate of deceleration when the box is full and when it is empty. The opposite force in this case is that the water pushes back, but more of the water will be pushed forward in the plank's direction. TLDR: We know the forces aren't equal because the plank is moving. The breaking point between where it begins to move and is stationary would be an equal force to the viscosity.
Attempting to learn fluid dynamics and this is awesome, thanks. Makes me ponder how far reaching studying medicine is
In the exact same place right now, our textbooks are complete shit, but thanks to this I just started understanding it.
الله يدخلك الجنه من أوسع ابوابها
there are doctors gain more than 300 SR (nearly 80$ ) to teach us for an hour what you said in this video ! Thank you so much
Ok dude... 😒
@P Ä yep
it's awesome ..... better than textbooks
ofc its better than textbooks thats why teachers exits. Now the majority of uni teachers are people without the gift of education and with 3 phds so they tend to complicate even the most simple shit.
literally. i couldnt understand a thing from my textbook so I had to come here.
Brilliant, no idea why this video has so little views
I will name my first born after you.
Also, someone just prayed for you to go to paradise in Arabic. This video literally creates world peace!
This explanation saved me where teachers failed. They keep redirecting me to formulas that are of no use and refuse to give a greater in depth explaination... So sad that college tuition is being wasted like that.
I relate. Some schools are scam. 😅
I m in love with your teaching.. U taught so nicely thanks.
~a new fan and subscriber
A Fluid Mechanics problem that I'm trying to work out. A viscometer of the Redwood type has an oil-containing cylinder 4.75cm in diam and an agate tube 0.17 cm in diameter and 1.2 cm long. The oil surface, when flow starts, is 9 cm above the outlet from the agate tube. To allow for the sudden contractions at entry to the tube, the effective length of the tube may be taken as the actual length plus the tube radius. Making allowance for the decreasing head of oil, the viscous resistance through the tube, and the KE (kinetic energy) of discharge, calculate using arithmetical integration, the time required for 50 cm3 of an oil of viscosity 0.5 poise and specific gravity 0.92 to flow through the viscometer. How do you find the time? From this question, I have tried to use quadratic equation to solve for v, but it is proving more difficult than I thought
Highly appreciated, thank you so much
Amazingly explained!
10:50 draws that smile 😂
I love your way of teaching 😭😭😭😭😭💓
excellent video
The explanation is so clear, and interesting
It helped me a lot ✌
This guy, whoever he is, is great 😂😂😂
It's Rick
This was really helpful. Well explained :)
Nice. Excellent!!!
Someone give this guy Money
Very helpful thanks😍
LIFE SAVER
as always
Thanku so much sir you and your way of teaching is just amazing
How we can consider fluid that is in contact with pipe is stationary?
Very good example and explanation for understanding. Thank you
In MCAT, is the Poiseuille formula provided?
Is the first flow called Couette-flow?
Incomparable explanations awsome.....
Amazing video, best Ive found thanks
Whats the formula for viscosity in a newtonian fluid?? How do we "ignore" the "v" thats already present in the formula???
Try watching "why is ketchup so hard to pour" by TED ... it is kinda helpful with this speed matter
Thankyou
Good stuff
How would n not depend on velocity when n=f*d/A*v?
Mike Smith Because F is also in the equation, and when v changes, so does the force, which compensates for the change in velocity.
The viscosity is generally a material property, depending on the temperature and other relevant state factors. Whether you pull fast or slowly does not change this material property. (This is only true for Newtonian fluids. Non-newtonian fluids act differently and are really cool. I suggest you look up videos on them)
Try watching "why is ketchup so hard to pour" by TED it explained this speed thing
Thank you for this amazing video helped me a lot ❤
Please can you write back me or give me ling of this question 👉on the view of viscosity and type of flow explane flood
There isnt in your videos translated in turkish can you add?
Wouldn't the viscous force be equal to the force applied because Newton said opposite and equal reaction to an action?
Please can someone explain me that why can't we just say that the viscous force is equal to the force applied to the lid.
And please if I have left some basics don't mock me just answer me
Equal and opposite reactions wouldn't resign every action to inaction, that is to say things can still move and not be stopped by the so called opposite force. Assuming the edges of the box were frictionless you could determine to a decent degree the viscosity by applying an increasing force to the plank and seeing at what point it began to move. If we do in fact know the coefficient of friction between the edges and the plank then we can estimate the viscosity by looking at the rate of deceleration when the box is full and when it is empty. The opposite force in this case is that the water pushes back, but more of the water will be pushed forward in the plank's direction.
TLDR: We know the forces aren't equal because the plank is moving. The breaking point between where it begins to move and is stationary would be an equal force to the viscosity.
why did u consider velocity as speed in unit? Only that portion is not understood..same thing done in the book.
you are amazing thank u so much
thats a dope box brah
If you play it on 2x speed the mannerisms of speech sound like Rick from Rick and Morty
HAHAHA
perfect.
Why is P not cP??? When it’s 1/10th of Pa*s ???????
Is unit of coefficient of viscocity is
Kg/ms ?
F = n A v/d
n = Fd/Av
= kg m s^-2 * m / m^2 * m s^-1
= kg m^-1 s^-1
This is also an acceptable unit for viscosity coefficient, yes (see en.wikipedia.org/wiki/Viscosity). -Engineering student at Purdue
Soothing accent
🎂Jean Poiseuille 04-22-2022
3:14 what I know you’re all here for
Thanks man.
"What is a viscous fluid ?"
It's *T H I C C K*
Can you add subtitle in turkish.because I wanna improve my English
Poise is not longer allowed as unit for viscosity.
Keep scrolling guys, I just randomly watched this at 3 a.m
check out this empty box! now check out this lid I can put on empty box!
Wait...You're not Sal (but just as cool)
Plz add Arabic language in subtitles 🙏🗣️