Since it's a multiple-choice question, I'd just calculate the perimeter given the possible lengths of the leg. P=L*(2+sqrt(2)). (A) is too small, and C and D are too large.
By estimation, the perimeter is ~225. B is about 65. That's the only choice even close. This problem could be simplified by expressing the givens and answer choices in decimal numbers. That would test the student's estimation skills, which are of much more real-world relevance than working a lot of algebra.
Kids who take advantage of using their calculator on SAT Math (yes, it's allowed) are going to solve this problem is a fraction of the time shown in this video.
![Seungmin "그렇게, 천천히, 우리(As we are)" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/kAzmhLHePqU/mqdefault.jpg)
![Felix "Unfair" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/Oswujxm2Ag0/mqdefault.jpg)
Since it's a multiple-choice question, I'd just calculate the perimeter given the possible lengths of the leg. P=L*(2+sqrt(2)). (A) is too small, and C and D are too large.
By estimation, the perimeter is ~225. B is about 65. That's the only choice even close. This problem could be simplified by expressing the givens and answer choices in decimal numbers. That would test the student's estimation skills, which are of much more real-world relevance than working a lot of algebra.
@@pbierre I like your approach.
Kids who take advantage of using their calculator on SAT Math (yes, it's allowed) are going to solve this problem is a fraction of the time shown in this video.
You are right. What about without multiple choices. Real math! Thank you for participating.